What type of operation is /#/- in “$my_array[@]/#/-”?

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The accepted answer to Transform an array into arguments of a command? uses the following Bash command:




command "$my_array[@]/#/-" "$1"



I'm trying to figure out what the /#/- part does, exactly. Unfortunately, I don't know what to call it, so I'm having trouble finding any documentation. I've looked through the Bash man page section on arrays and a few websites, but can't find anything.






bash array







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    up vote
    4
    down vote

    favorite












    The accepted answer to Transform an array into arguments of a command? uses the following Bash command:




    command "$my_array[@]/#/-" "$1"



    I'm trying to figure out what the /#/- part does, exactly. Unfortunately, I don't know what to call it, so I'm having trouble finding any documentation. I've looked through the Bash man page section on arrays and a few websites, but can't find anything.






    bash array







    share|improve this question







    New contributor




    Justin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      The accepted answer to Transform an array into arguments of a command? uses the following Bash command:




      command "$my_array[@]/#/-" "$1"



      I'm trying to figure out what the /#/- part does, exactly. Unfortunately, I don't know what to call it, so I'm having trouble finding any documentation. I've looked through the Bash man page section on arrays and a few websites, but can't find anything.






      bash array







      share|improve this question







      New contributor




      Justin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      The accepted answer to Transform an array into arguments of a command? uses the following Bash command:




      command "$my_array[@]/#/-" "$1"



      I'm trying to figure out what the /#/- part does, exactly. Unfortunately, I don't know what to call it, so I'm having trouble finding any documentation. I've looked through the Bash man page section on arrays and a few websites, but can't find anything.






      bash array




      bash array






      share|improve this question







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      Justin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







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      Justin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          This is an instance of pattern replacement in shell parameter expansion: $parameter/pattern/replacement expands $parameter, replacing the first instance of pattern with replacement. In the context of a pattern of this kind, # is special: it anchors the pattern to the start of the parameter. The end result of all this is to expand all the values in the my_array array, prepending - to each one (by replacing the empty pattern at the start of each parameter).






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            1 Answer
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            active

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            active

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            up vote
            7
            down vote



            accepted










            This is an instance of pattern replacement in shell parameter expansion: $parameter/pattern/replacement expands $parameter, replacing the first instance of pattern with replacement. In the context of a pattern of this kind, # is special: it anchors the pattern to the start of the parameter. The end result of all this is to expand all the values in the my_array array, prepending - to each one (by replacing the empty pattern at the start of each parameter).






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              up vote
              7
              down vote



              accepted










              This is an instance of pattern replacement in shell parameter expansion: $parameter/pattern/replacement expands $parameter, replacing the first instance of pattern with replacement. In the context of a pattern of this kind, # is special: it anchors the pattern to the start of the parameter. The end result of all this is to expand all the values in the my_array array, prepending - to each one (by replacing the empty pattern at the start of each parameter).






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                up vote
                7
                down vote



                accepted







                up vote
                7
                down vote



                accepted






                This is an instance of pattern replacement in shell parameter expansion: $parameter/pattern/replacement expands $parameter, replacing the first instance of pattern with replacement. In the context of a pattern of this kind, # is special: it anchors the pattern to the start of the parameter. The end result of all this is to expand all the values in the my_array array, prepending - to each one (by replacing the empty pattern at the start of each parameter).






                share|improve this answer














                This is an instance of pattern replacement in shell parameter expansion: $parameter/pattern/replacement expands $parameter, replacing the first instance of pattern with replacement. In the context of a pattern of this kind, # is special: it anchors the pattern to the start of the parameter. The end result of all this is to expand all the values in the my_array array, prepending - to each one (by replacing the empty pattern at the start of each parameter).







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                edited 36 mins ago

























                answered 43 mins ago









                Stephen Kitt

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