How to solve functions by having in-function equations (bad explanation, but read body)
Clash Royale CLAN TAG#URR8PPP
up vote
2
down vote
favorite
Thinking about this all day, still don't know how to solve it:
Find $f(x)$ if
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
........
algebra-precalculus functions
New contributor
add a comment |Â
up vote
2
down vote
favorite
Thinking about this all day, still don't know how to solve it:
Find $f(x)$ if
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
........
algebra-precalculus functions
New contributor
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
Thinking about this all day, still don't know how to solve it:
Find $f(x)$ if
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
........
algebra-precalculus functions
New contributor
Thinking about this all day, still don't know how to solve it:
Find $f(x)$ if
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
........
algebra-precalculus functions
algebra-precalculus functions
New contributor
New contributor
edited 1 hour ago
Avinash N
1909
1909
New contributor
asked 1 hour ago
Aleksa
182
182
New contributor
New contributor
add a comment |Â
add a comment |Â
4 Answers
4
active
oldest
votes
up vote
5
down vote
accepted
Write $t = (x+1)/(x-2)$ then $x= (2t+1)/(t-1)$ and $$f(t)+2f(1over t) = 2t+1over t-1$$
Replaceing $t$ with $1/t$ we get $$f(1over t)+2f(t) = 2+tover 1-t$$
Solving this system on $f(t)$ we get:
$$ 22+tover 1-t-2t+1over t-1 =3f(t)$$
and we are done...
I don't get what you did at the second step, the replacing of t and t/1, could you explain it?
â Aleksa
1 hour ago
Everywhere in first equation replace t with 1/t
â greedoid
1 hour ago
I'm not sure what you don't understand.
â greedoid
1 hour ago
add a comment |Â
up vote
2
down vote
Hint
Solve:
$$
f(y) +2fleft(frac 1yright) = phi(y)\
fleft(frac 1yright)+2f(y) = psi(y)
$$
with $y = fracx+1x-2$
add a comment |Â
up vote
1
down vote
If
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
Then I got,
$f(x)=$$1over x-1$
add a comment |Â
up vote
0
down vote
By making the transformation $x to 1-x$ this may be seen as follows:
For
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
let $x to 1-x$ to obtain
$$fleft(x-2 over x+1right)-2fleft(x+1 over x-2right)=1-x,$$
or
$$fleft(fracx-2x+1right) = 2 , fleft(fracx+1x-2right) + 1-x.$$
From this it is seen that
$$fleft(fracx+1x-2right) = fracx-23 = frac1left(fracx+1x-2right) - 1.$$
This leads to
$$f(t) = frac1t-1.$$
add a comment |Â
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
Write $t = (x+1)/(x-2)$ then $x= (2t+1)/(t-1)$ and $$f(t)+2f(1over t) = 2t+1over t-1$$
Replaceing $t$ with $1/t$ we get $$f(1over t)+2f(t) = 2+tover 1-t$$
Solving this system on $f(t)$ we get:
$$ 22+tover 1-t-2t+1over t-1 =3f(t)$$
and we are done...
I don't get what you did at the second step, the replacing of t and t/1, could you explain it?
â Aleksa
1 hour ago
Everywhere in first equation replace t with 1/t
â greedoid
1 hour ago
I'm not sure what you don't understand.
â greedoid
1 hour ago
add a comment |Â
up vote
5
down vote
accepted
Write $t = (x+1)/(x-2)$ then $x= (2t+1)/(t-1)$ and $$f(t)+2f(1over t) = 2t+1over t-1$$
Replaceing $t$ with $1/t$ we get $$f(1over t)+2f(t) = 2+tover 1-t$$
Solving this system on $f(t)$ we get:
$$ 22+tover 1-t-2t+1over t-1 =3f(t)$$
and we are done...
I don't get what you did at the second step, the replacing of t and t/1, could you explain it?
â Aleksa
1 hour ago
Everywhere in first equation replace t with 1/t
â greedoid
1 hour ago
I'm not sure what you don't understand.
â greedoid
1 hour ago
add a comment |Â
up vote
5
down vote
accepted
up vote
5
down vote
accepted
Write $t = (x+1)/(x-2)$ then $x= (2t+1)/(t-1)$ and $$f(t)+2f(1over t) = 2t+1over t-1$$
Replaceing $t$ with $1/t$ we get $$f(1over t)+2f(t) = 2+tover 1-t$$
Solving this system on $f(t)$ we get:
$$ 22+tover 1-t-2t+1over t-1 =3f(t)$$
and we are done...
Write $t = (x+1)/(x-2)$ then $x= (2t+1)/(t-1)$ and $$f(t)+2f(1over t) = 2t+1over t-1$$
Replaceing $t$ with $1/t$ we get $$f(1over t)+2f(t) = 2+tover 1-t$$
Solving this system on $f(t)$ we get:
$$ 22+tover 1-t-2t+1over t-1 =3f(t)$$
and we are done...
edited 1 hour ago
answered 1 hour ago
greedoid
30.4k94183
30.4k94183
I don't get what you did at the second step, the replacing of t and t/1, could you explain it?
â Aleksa
1 hour ago
Everywhere in first equation replace t with 1/t
â greedoid
1 hour ago
I'm not sure what you don't understand.
â greedoid
1 hour ago
add a comment |Â
I don't get what you did at the second step, the replacing of t and t/1, could you explain it?
â Aleksa
1 hour ago
Everywhere in first equation replace t with 1/t
â greedoid
1 hour ago
I'm not sure what you don't understand.
â greedoid
1 hour ago
I don't get what you did at the second step, the replacing of t and t/1, could you explain it?
â Aleksa
1 hour ago
I don't get what you did at the second step, the replacing of t and t/1, could you explain it?
â Aleksa
1 hour ago
Everywhere in first equation replace t with 1/t
â greedoid
1 hour ago
Everywhere in first equation replace t with 1/t
â greedoid
1 hour ago
I'm not sure what you don't understand.
â greedoid
1 hour ago
I'm not sure what you don't understand.
â greedoid
1 hour ago
add a comment |Â
up vote
2
down vote
Hint
Solve:
$$
f(y) +2fleft(frac 1yright) = phi(y)\
fleft(frac 1yright)+2f(y) = psi(y)
$$
with $y = fracx+1x-2$
add a comment |Â
up vote
2
down vote
Hint
Solve:
$$
f(y) +2fleft(frac 1yright) = phi(y)\
fleft(frac 1yright)+2f(y) = psi(y)
$$
with $y = fracx+1x-2$
add a comment |Â
up vote
2
down vote
up vote
2
down vote
Hint
Solve:
$$
f(y) +2fleft(frac 1yright) = phi(y)\
fleft(frac 1yright)+2f(y) = psi(y)
$$
with $y = fracx+1x-2$
Hint
Solve:
$$
f(y) +2fleft(frac 1yright) = phi(y)\
fleft(frac 1yright)+2f(y) = psi(y)
$$
with $y = fracx+1x-2$
edited 1 hour ago
answered 1 hour ago
Cesareo
6,4292413
6,4292413
add a comment |Â
add a comment |Â
up vote
1
down vote
If
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
Then I got,
$f(x)=$$1over x-1$
add a comment |Â
up vote
1
down vote
If
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
Then I got,
$f(x)=$$1over x-1$
add a comment |Â
up vote
1
down vote
up vote
1
down vote
If
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
Then I got,
$f(x)=$$1over x-1$
If
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
Then I got,
$f(x)=$$1over x-1$
answered 1 hour ago
Avinash N
1909
1909
add a comment |Â
add a comment |Â
up vote
0
down vote
By making the transformation $x to 1-x$ this may be seen as follows:
For
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
let $x to 1-x$ to obtain
$$fleft(x-2 over x+1right)-2fleft(x+1 over x-2right)=1-x,$$
or
$$fleft(fracx-2x+1right) = 2 , fleft(fracx+1x-2right) + 1-x.$$
From this it is seen that
$$fleft(fracx+1x-2right) = fracx-23 = frac1left(fracx+1x-2right) - 1.$$
This leads to
$$f(t) = frac1t-1.$$
add a comment |Â
up vote
0
down vote
By making the transformation $x to 1-x$ this may be seen as follows:
For
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
let $x to 1-x$ to obtain
$$fleft(x-2 over x+1right)-2fleft(x+1 over x-2right)=1-x,$$
or
$$fleft(fracx-2x+1right) = 2 , fleft(fracx+1x-2right) + 1-x.$$
From this it is seen that
$$fleft(fracx+1x-2right) = fracx-23 = frac1left(fracx+1x-2right) - 1.$$
This leads to
$$f(t) = frac1t-1.$$
add a comment |Â
up vote
0
down vote
up vote
0
down vote
By making the transformation $x to 1-x$ this may be seen as follows:
For
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
let $x to 1-x$ to obtain
$$fleft(x-2 over x+1right)-2fleft(x+1 over x-2right)=1-x,$$
or
$$fleft(fracx-2x+1right) = 2 , fleft(fracx+1x-2right) + 1-x.$$
From this it is seen that
$$fleft(fracx+1x-2right) = fracx-23 = frac1left(fracx+1x-2right) - 1.$$
This leads to
$$f(t) = frac1t-1.$$
By making the transformation $x to 1-x$ this may be seen as follows:
For
$$fleft(x+1 over x-2right)-2fleft(x-2 over x+1right)=x$$
let $x to 1-x$ to obtain
$$fleft(x-2 over x+1right)-2fleft(x+1 over x-2right)=1-x,$$
or
$$fleft(fracx-2x+1right) = 2 , fleft(fracx+1x-2right) + 1-x.$$
From this it is seen that
$$fleft(fracx+1x-2right) = fracx-23 = frac1left(fracx+1x-2right) - 1.$$
This leads to
$$f(t) = frac1t-1.$$
answered 23 mins ago
Leucippus
19.2k102869
19.2k102869
add a comment |Â
add a comment |Â
Aleksa is a new contributor. Be nice, and check out our Code of Conduct.
Aleksa is a new contributor. Be nice, and check out our Code of Conduct.
Aleksa is a new contributor. Be nice, and check out our Code of Conduct.
Aleksa is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2941223%2fhow-to-solve-functions-by-having-in-function-equations-bad-explanation-but-rea%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password