Find out the correct number

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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favorite
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enter image description here



Find out the correct number to replace the question mark.



Source: Beijing Aidi International School summer test (2018-08-21). Author: 坦途国际教育










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  • Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
    – Jaap Scherphuis
    5 hours ago










  • The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
    – JimM
    3 hours ago











  • Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
    – DEEM
    2 hours ago














up vote
6
down vote

favorite
2












enter image description here



Find out the correct number to replace the question mark.



Source: Beijing Aidi International School summer test (2018-08-21). Author: 坦途国际教育










share|improve this question









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Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
    – Jaap Scherphuis
    5 hours ago










  • The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
    – JimM
    3 hours ago











  • Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
    – DEEM
    2 hours ago












up vote
6
down vote

favorite
2









up vote
6
down vote

favorite
2






2





enter image description here



Find out the correct number to replace the question mark.



Source: Beijing Aidi International School summer test (2018-08-21). Author: 坦途国际教育










share|improve this question









New contributor




Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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enter image description here



Find out the correct number to replace the question mark.



Source: Beijing Aidi International School summer test (2018-08-21). Author: 坦途国际教育







mathematics calculation-puzzle






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edited 8 mins ago









xhienne

3,157529




3,157529






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asked 14 hours ago









Unza

371




371




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  • Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
    – Jaap Scherphuis
    5 hours ago










  • The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
    – JimM
    3 hours ago











  • Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
    – DEEM
    2 hours ago
















  • Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
    – Jaap Scherphuis
    5 hours ago










  • The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
    – JimM
    3 hours ago











  • Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
    – DEEM
    2 hours ago















Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago




Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago












The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago





The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago













Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago




Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago










5 Answers
5






active

oldest

votes

















up vote
15
down vote














You are correct. The answer is 9.




Explanation




The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.




Then




The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.




Then




Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.




Then




Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)




Thus




A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.







share|improve this answer
















  • 1




    Apparently, this is the earliest correct answer. It deserves more votes.
    – xhienne
    13 hours ago











  • Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
    – gabbo1092
    9 hours ago

















up vote
7
down vote













Adding neater formatting but here is solution:




The key to this puzzle is attention to detail about what each image truly is




For the first line:




We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.




Next we have to look at the third line:




In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).




Back to the second line now:




There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.




Value of a hat:




Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.




Final Line:




To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.







share|improve this answer










New contributor




gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • Nope you didn't notice the last equation properly. Bear is hatless
    – Unza
    14 hours ago











  • I found a different error fixing in updated solution
    – gabbo1092
    14 hours ago










  • If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
    – Unza
    14 hours ago











  • Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
    – gabbo1092
    14 hours ago







  • 1




    Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
    – xhienne
    13 hours ago

















up vote
2
down vote













Let t be the number of teddy bears, h hats and b buses. Then the equations are:




$3t+3h=21 tag1$

$3t+h+2b=19 tag2$

$2t+2h+b=15 tag3$




and we want to know:




$t+(2htimes b)=t+2hb$




Gaussian elimination tells us the answer is:




$t=5, h=2, b=1$, therefore $t+2hb=9$.




but there is a quick way:




From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.







share|improve this answer





























    up vote
    0
    down vote













    The answer is:




    Seven




    Reasoning:
    Bear With Hat




    Seven gained from three additions equaling 21.




    Bus with Bear:




    Six Subtract the bear from 19 then divide by two.




    Hat:




    Two; subtract Bear with hat and bus with bear from 15.




    Bear minus hat:




    Five




    Bus minus Bear




    One




    Final problem:




    Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)







    share|improve this answer


















    • 1




      Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
      – PerpetualJ
      13 hours ago











    • I just didn’t see the second hat at first.
      – PerpetualJ
      9 hours ago

















    up vote
    0
    down vote














    Pig (with a hat) = 7

    Bus (with a pig) = 6

    Hat = 2

    Pig = 5

    Bus = 1

    Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9







    share|improve this answer










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      Your Answer




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      5 Answers
      5






      active

      oldest

      votes








      5 Answers
      5






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      15
      down vote














      You are correct. The answer is 9.




      Explanation




      The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.




      Then




      The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.




      Then




      Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.




      Then




      Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)




      Thus




      A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.







      share|improve this answer
















      • 1




        Apparently, this is the earliest correct answer. It deserves more votes.
        – xhienne
        13 hours ago











      • Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
        – gabbo1092
        9 hours ago














      up vote
      15
      down vote














      You are correct. The answer is 9.




      Explanation




      The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.




      Then




      The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.




      Then




      Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.




      Then




      Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)




      Thus




      A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.







      share|improve this answer
















      • 1




        Apparently, this is the earliest correct answer. It deserves more votes.
        – xhienne
        13 hours ago











      • Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
        – gabbo1092
        9 hours ago












      up vote
      15
      down vote










      up vote
      15
      down vote










      You are correct. The answer is 9.




      Explanation




      The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.




      Then




      The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.




      Then




      Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.




      Then




      Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)




      Thus




      A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.







      share|improve this answer













      You are correct. The answer is 9.




      Explanation




      The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.




      Then




      The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.




      Then




      Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.




      Then




      Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)




      Thus




      A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.








      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered 14 hours ago









      Luke C. J. Currie

      92514




      92514







      • 1




        Apparently, this is the earliest correct answer. It deserves more votes.
        – xhienne
        13 hours ago











      • Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
        – gabbo1092
        9 hours ago












      • 1




        Apparently, this is the earliest correct answer. It deserves more votes.
        – xhienne
        13 hours ago











      • Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
        – gabbo1092
        9 hours ago







      1




      1




      Apparently, this is the earliest correct answer. It deserves more votes.
      – xhienne
      13 hours ago





      Apparently, this is the earliest correct answer. It deserves more votes.
      – xhienne
      13 hours ago













      Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
      – gabbo1092
      9 hours ago




      Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
      – gabbo1092
      9 hours ago










      up vote
      7
      down vote













      Adding neater formatting but here is solution:




      The key to this puzzle is attention to detail about what each image truly is




      For the first line:




      We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.




      Next we have to look at the third line:




      In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).




      Back to the second line now:




      There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.




      Value of a hat:




      Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.




      Final Line:




      To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.







      share|improve this answer










      New contributor




      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.

















      • Nope you didn't notice the last equation properly. Bear is hatless
        – Unza
        14 hours ago











      • I found a different error fixing in updated solution
        – gabbo1092
        14 hours ago










      • If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
        – Unza
        14 hours ago











      • Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
        – gabbo1092
        14 hours ago







      • 1




        Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
        – xhienne
        13 hours ago














      up vote
      7
      down vote













      Adding neater formatting but here is solution:




      The key to this puzzle is attention to detail about what each image truly is




      For the first line:




      We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.




      Next we have to look at the third line:




      In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).




      Back to the second line now:




      There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.




      Value of a hat:




      Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.




      Final Line:




      To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.







      share|improve this answer










      New contributor




      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.

















      • Nope you didn't notice the last equation properly. Bear is hatless
        – Unza
        14 hours ago











      • I found a different error fixing in updated solution
        – gabbo1092
        14 hours ago










      • If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
        – Unza
        14 hours ago











      • Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
        – gabbo1092
        14 hours ago







      • 1




        Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
        – xhienne
        13 hours ago












      up vote
      7
      down vote










      up vote
      7
      down vote









      Adding neater formatting but here is solution:




      The key to this puzzle is attention to detail about what each image truly is




      For the first line:




      We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.




      Next we have to look at the third line:




      In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).




      Back to the second line now:




      There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.




      Value of a hat:




      Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.




      Final Line:




      To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.







      share|improve this answer










      New contributor




      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      Adding neater formatting but here is solution:




      The key to this puzzle is attention to detail about what each image truly is




      For the first line:




      We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.




      Next we have to look at the third line:




      In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).




      Back to the second line now:




      There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.




      Value of a hat:




      Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.




      Final Line:




      To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.








      share|improve this answer










      New contributor




      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this answer



      share|improve this answer








      edited 14 hours ago





















      New contributor




      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      answered 14 hours ago









      gabbo1092

      62611




      62611




      New contributor




      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor





      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      • Nope you didn't notice the last equation properly. Bear is hatless
        – Unza
        14 hours ago











      • I found a different error fixing in updated solution
        – gabbo1092
        14 hours ago










      • If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
        – Unza
        14 hours ago











      • Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
        – gabbo1092
        14 hours ago







      • 1




        Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
        – xhienne
        13 hours ago
















      • Nope you didn't notice the last equation properly. Bear is hatless
        – Unza
        14 hours ago











      • I found a different error fixing in updated solution
        – gabbo1092
        14 hours ago










      • If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
        – Unza
        14 hours ago











      • Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
        – gabbo1092
        14 hours ago







      • 1




        Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
        – xhienne
        13 hours ago















      Nope you didn't notice the last equation properly. Bear is hatless
      – Unza
      14 hours ago





      Nope you didn't notice the last equation properly. Bear is hatless
      – Unza
      14 hours ago













      I found a different error fixing in updated solution
      – gabbo1092
      14 hours ago




      I found a different error fixing in updated solution
      – gabbo1092
      14 hours ago












      If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
      – Unza
      14 hours ago





      If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
      – Unza
      14 hours ago













      Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
      – gabbo1092
      14 hours ago





      Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
      – gabbo1092
      14 hours ago





      1




      1




      Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
      – xhienne
      13 hours ago




      Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
      – xhienne
      13 hours ago










      up vote
      2
      down vote













      Let t be the number of teddy bears, h hats and b buses. Then the equations are:




      $3t+3h=21 tag1$

      $3t+h+2b=19 tag2$

      $2t+2h+b=15 tag3$




      and we want to know:




      $t+(2htimes b)=t+2hb$




      Gaussian elimination tells us the answer is:




      $t=5, h=2, b=1$, therefore $t+2hb=9$.




      but there is a quick way:




      From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.







      share|improve this answer


























        up vote
        2
        down vote













        Let t be the number of teddy bears, h hats and b buses. Then the equations are:




        $3t+3h=21 tag1$

        $3t+h+2b=19 tag2$

        $2t+2h+b=15 tag3$




        and we want to know:




        $t+(2htimes b)=t+2hb$




        Gaussian elimination tells us the answer is:




        $t=5, h=2, b=1$, therefore $t+2hb=9$.




        but there is a quick way:




        From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.







        share|improve this answer
























          up vote
          2
          down vote










          up vote
          2
          down vote









          Let t be the number of teddy bears, h hats and b buses. Then the equations are:




          $3t+3h=21 tag1$

          $3t+h+2b=19 tag2$

          $2t+2h+b=15 tag3$




          and we want to know:




          $t+(2htimes b)=t+2hb$




          Gaussian elimination tells us the answer is:




          $t=5, h=2, b=1$, therefore $t+2hb=9$.




          but there is a quick way:




          From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.







          share|improve this answer














          Let t be the number of teddy bears, h hats and b buses. Then the equations are:




          $3t+3h=21 tag1$

          $3t+h+2b=19 tag2$

          $2t+2h+b=15 tag3$




          and we want to know:




          $t+(2htimes b)=t+2hb$




          Gaussian elimination tells us the answer is:




          $t=5, h=2, b=1$, therefore $t+2hb=9$.




          but there is a quick way:




          From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 7 hours ago

























          answered 7 hours ago









          JonMark Perry

          14.6k52972




          14.6k52972




















              up vote
              0
              down vote













              The answer is:




              Seven




              Reasoning:
              Bear With Hat




              Seven gained from three additions equaling 21.




              Bus with Bear:




              Six Subtract the bear from 19 then divide by two.




              Hat:




              Two; subtract Bear with hat and bus with bear from 15.




              Bear minus hat:




              Five




              Bus minus Bear




              One




              Final problem:




              Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)







              share|improve this answer


















              • 1




                Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
                – PerpetualJ
                13 hours ago











              • I just didn’t see the second hat at first.
                – PerpetualJ
                9 hours ago














              up vote
              0
              down vote













              The answer is:




              Seven




              Reasoning:
              Bear With Hat




              Seven gained from three additions equaling 21.




              Bus with Bear:




              Six Subtract the bear from 19 then divide by two.




              Hat:




              Two; subtract Bear with hat and bus with bear from 15.




              Bear minus hat:




              Five




              Bus minus Bear




              One




              Final problem:




              Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)







              share|improve this answer


















              • 1




                Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
                – PerpetualJ
                13 hours ago











              • I just didn’t see the second hat at first.
                – PerpetualJ
                9 hours ago












              up vote
              0
              down vote










              up vote
              0
              down vote









              The answer is:




              Seven




              Reasoning:
              Bear With Hat




              Seven gained from three additions equaling 21.




              Bus with Bear:




              Six Subtract the bear from 19 then divide by two.




              Hat:




              Two; subtract Bear with hat and bus with bear from 15.




              Bear minus hat:




              Five




              Bus minus Bear




              One




              Final problem:




              Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)







              share|improve this answer














              The answer is:




              Seven




              Reasoning:
              Bear With Hat




              Seven gained from three additions equaling 21.




              Bus with Bear:




              Six Subtract the bear from 19 then divide by two.




              Hat:




              Two; subtract Bear with hat and bus with bear from 15.




              Bear minus hat:




              Five




              Bus minus Bear




              One




              Final problem:




              Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)








              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 13 hours ago

























              answered 13 hours ago









              PerpetualJ

              2,190227




              2,190227







              • 1




                Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
                – PerpetualJ
                13 hours ago











              • I just didn’t see the second hat at first.
                – PerpetualJ
                9 hours ago












              • 1




                Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
                – PerpetualJ
                13 hours ago











              • I just didn’t see the second hat at first.
                – PerpetualJ
                9 hours ago







              1




              1




              Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
              – PerpetualJ
              13 hours ago





              Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
              – PerpetualJ
              13 hours ago













              I just didn’t see the second hat at first.
              – PerpetualJ
              9 hours ago




              I just didn’t see the second hat at first.
              – PerpetualJ
              9 hours ago










              up vote
              0
              down vote














              Pig (with a hat) = 7

              Bus (with a pig) = 6

              Hat = 2

              Pig = 5

              Bus = 1

              Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9







              share|improve this answer










              New contributor




              Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





















                up vote
                0
                down vote














                Pig (with a hat) = 7

                Bus (with a pig) = 6

                Hat = 2

                Pig = 5

                Bus = 1

                Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9







                share|improve this answer










                New contributor




                Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.



















                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote










                  Pig (with a hat) = 7

                  Bus (with a pig) = 6

                  Hat = 2

                  Pig = 5

                  Bus = 1

                  Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9







                  share|improve this answer










                  New contributor




                  Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.










                  Pig (with a hat) = 7

                  Bus (with a pig) = 6

                  Hat = 2

                  Pig = 5

                  Bus = 1

                  Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9








                  share|improve this answer










                  New contributor




                  Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|improve this answer



                  share|improve this answer








                  edited 1 hour ago









                  Shahriar Mahmud Sajid

                  2,759526




                  2,759526






                  New contributor




                  Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered 1 hour ago









                  Deepak Gopal

                  1




                  1




                  New contributor




                  Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  New contributor





                  Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.




















                      Unza is a new contributor. Be nice, and check out our Code of Conduct.









                       

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