Find out the correct number
Clash Royale CLAN TAG#URR8PPP
up vote
6
down vote
favorite
Find out the correct number to replace the question mark.
Source: Beijing Aidi International School summer test (2018-08-21). Author: å¦途国际教育
mathematics calculation-puzzle
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Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
6
down vote
favorite
Find out the correct number to replace the question mark.
Source: Beijing Aidi International School summer test (2018-08-21). Author: å¦途国际教育
mathematics calculation-puzzle
New contributor
Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago
The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago
Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago
add a comment |Â
up vote
6
down vote
favorite
up vote
6
down vote
favorite
Find out the correct number to replace the question mark.
Source: Beijing Aidi International School summer test (2018-08-21). Author: å¦途国际教育
mathematics calculation-puzzle
New contributor
Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Find out the correct number to replace the question mark.
Source: Beijing Aidi International School summer test (2018-08-21). Author: å¦途国际教育
mathematics calculation-puzzle
mathematics calculation-puzzle
New contributor
Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 8 mins ago
xhienne
3,157529
3,157529
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Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 14 hours ago
Unza
371
371
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Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Unza is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago
The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago
Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago
add a comment |Â
Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago
The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago
Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago
Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago
Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago
The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago
The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago
Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago
Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago
add a comment |Â
5 Answers
5
active
oldest
votes
up vote
15
down vote
You are correct. The answer is 9.
Explanation
The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.
Then
The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.
Then
Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.
Then
Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)
Thus
A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.
1
Apparently, this is the earliest correct answer. It deserves more votes.
– xhienne
13 hours ago
Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
– gabbo1092
9 hours ago
add a comment |Â
up vote
7
down vote
Adding neater formatting but here is solution:
The key to this puzzle is attention to detail about what each image truly is
For the first line:
We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.
Next we have to look at the third line:
In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).
Back to the second line now:
There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.
Value of a hat:
Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.
Final Line:
To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.
New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Nope you didn't notice the last equation properly. Bear is hatless
– Unza
14 hours ago
I found a different error fixing in updated solution
– gabbo1092
14 hours ago
If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
– Unza
14 hours ago
Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
– gabbo1092
14 hours ago
1
Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
– xhienne
13 hours ago
 |Â
show 1 more comment
up vote
2
down vote
Let t be the number of teddy bears, h hats and b buses. Then the equations are:
$3t+3h=21 tag1$
$3t+h+2b=19 tag2$
$2t+2h+b=15 tag3$
and we want to know:
$t+(2htimes b)=t+2hb$
Gaussian elimination tells us the answer is:
$t=5, h=2, b=1$, therefore $t+2hb=9$.
but there is a quick way:
From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.
add a comment |Â
up vote
0
down vote
The answer is:
Seven
Reasoning:
Bear With Hat
Seven gained from three additions equaling 21.
Bus with Bear:
Six Subtract the bear from 19 then divide by two.
Hat:
Two; subtract Bear with hat and bus with bear from 15.
Bear minus hat:
Five
Bus minus Bear
One
Final problem:
Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)
1
Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
– PerpetualJ
13 hours ago
I just didn’t see the second hat at first.
– PerpetualJ
9 hours ago
add a comment |Â
up vote
0
down vote
Pig (with a hat) = 7
Bus (with a pig) = 6
Hat = 2
Pig = 5
Bus = 1
Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
15
down vote
You are correct. The answer is 9.
Explanation
The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.
Then
The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.
Then
Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.
Then
Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)
Thus
A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.
1
Apparently, this is the earliest correct answer. It deserves more votes.
– xhienne
13 hours ago
Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
– gabbo1092
9 hours ago
add a comment |Â
up vote
15
down vote
You are correct. The answer is 9.
Explanation
The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.
Then
The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.
Then
Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.
Then
Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)
Thus
A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.
1
Apparently, this is the earliest correct answer. It deserves more votes.
– xhienne
13 hours ago
Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
– gabbo1092
9 hours ago
add a comment |Â
up vote
15
down vote
up vote
15
down vote
You are correct. The answer is 9.
Explanation
The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.
Then
The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.
Then
Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.
Then
Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)
Thus
A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.
You are correct. The answer is 9.
Explanation
The first line has 3 bears with hats totaling 21. So a bear with a hat is 21/3 = 7.
Then
The next line is 2 sets of a bear in a bus plus a bear in a hat totaling 19. So we know a bear in a bus is (19-7)/2 = 6.
Then
Next is a hat, a bear in a bus, and a bear in a hat totaling 15. So we know a hat is 15-6-7=2.
Then
Now that we know a hat is 2, a bear must be 5 (7-2). If a bear is 5, than a bus is 1 (6-5)
Thus
A hat is 2, a bear is 5, and a bus is 1. That makes the last line 5 + 4*1 which does equal 9.
answered 14 hours ago
Luke C. J. Currie
92514
92514
1
Apparently, this is the earliest correct answer. It deserves more votes.
– xhienne
13 hours ago
Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
– gabbo1092
9 hours ago
add a comment |Â
1
Apparently, this is the earliest correct answer. It deserves more votes.
– xhienne
13 hours ago
Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
– gabbo1092
9 hours ago
1
1
Apparently, this is the earliest correct answer. It deserves more votes.
– xhienne
13 hours ago
Apparently, this is the earliest correct answer. It deserves more votes.
– xhienne
13 hours ago
Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
– gabbo1092
9 hours ago
Yeah I think the asker saw I had left a comment before his was posted saying I’d found the error and was fixing it and was just doing formatting so that’s why it was posted before and hadn’t decided who to give it to. Or maybe I’m just reading into things too much. I am fine either way fair is fair.
– gabbo1092
9 hours ago
add a comment |Â
up vote
7
down vote
Adding neater formatting but here is solution:
The key to this puzzle is attention to detail about what each image truly is
For the first line:
We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.
Next we have to look at the third line:
In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).
Back to the second line now:
There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.
Value of a hat:
Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.
Final Line:
To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.
New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Nope you didn't notice the last equation properly. Bear is hatless
– Unza
14 hours ago
I found a different error fixing in updated solution
– gabbo1092
14 hours ago
If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
– Unza
14 hours ago
Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
– gabbo1092
14 hours ago
1
Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
– xhienne
13 hours ago
 |Â
show 1 more comment
up vote
7
down vote
Adding neater formatting but here is solution:
The key to this puzzle is attention to detail about what each image truly is
For the first line:
We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.
Next we have to look at the third line:
In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).
Back to the second line now:
There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.
Value of a hat:
Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.
Final Line:
To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.
New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Nope you didn't notice the last equation properly. Bear is hatless
– Unza
14 hours ago
I found a different error fixing in updated solution
– gabbo1092
14 hours ago
If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
– Unza
14 hours ago
Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
– gabbo1092
14 hours ago
1
Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
– xhienne
13 hours ago
 |Â
show 1 more comment
up vote
7
down vote
up vote
7
down vote
Adding neater formatting but here is solution:
The key to this puzzle is attention to detail about what each image truly is
For the first line:
We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.
Next we have to look at the third line:
In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).
Back to the second line now:
There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.
Value of a hat:
Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.
Final Line:
To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.
New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Adding neater formatting but here is solution:
The key to this puzzle is attention to detail about what each image truly is
For the first line:
We have 3 bears and 3 hats. This adds up to 21 meaning a bear + a hat = 7.
Next we have to look at the third line:
In this line we have a bear with a hat (7), a hat and a bus with a bear. In total then we have a bus of unknown value and 2 bears with hats valued at 7 each. To get the total sum of 15 an empty bus must equal 1 (15-(2x7)).
Back to the second line now:
There are 2 buses with a hat-less bear and one bear with a hat (7). Since each bus is worth 1 and the bear with hat is worth 7, subtracting 9 from 19 leaves 10 for the value of two bears and 5 for the value of each individual bear.
Value of a hat:
Since a hat and a bear is 7 and a bear is 5, a hat is worth 2.
Final Line:
To recap: A bear without hat is 5, two hats will be 4 and a bus is 1. 1x4 (BEDMAS/PEDMAS) is still 4. All that is left is 4 + 5 which equals 9.
New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 14 hours ago
New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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answered 14 hours ago
gabbo1092
62611
62611
New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
gabbo1092 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Nope you didn't notice the last equation properly. Bear is hatless
– Unza
14 hours ago
I found a different error fixing in updated solution
– gabbo1092
14 hours ago
If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
– Unza
14 hours ago
Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
– gabbo1092
14 hours ago
1
Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
– xhienne
13 hours ago
 |Â
show 1 more comment
Nope you didn't notice the last equation properly. Bear is hatless
– Unza
14 hours ago
I found a different error fixing in updated solution
– gabbo1092
14 hours ago
If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
– Unza
14 hours ago
Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
– gabbo1092
14 hours ago
1
Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
– xhienne
13 hours ago
Nope you didn't notice the last equation properly. Bear is hatless
– Unza
14 hours ago
Nope you didn't notice the last equation properly. Bear is hatless
– Unza
14 hours ago
I found a different error fixing in updated solution
– gabbo1092
14 hours ago
I found a different error fixing in updated solution
– gabbo1092
14 hours ago
If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
– Unza
14 hours ago
If the individual bear is worth 4 then according to the second line the sum should have been 17 not 19. (4×3)+2+3=17
– Unza
14 hours ago
Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
– gabbo1092
14 hours ago
Yeah as I mentioned in my more recent comment I caught and was fixing that. That was fixed in my most recent update.
– gabbo1092
14 hours ago
1
1
Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
– xhienne
13 hours ago
Let me object: the total of the two hats on last line is 22 (youtube.com/watch?v=Zh3Yz3PiXZw)
– xhienne
13 hours ago
 |Â
show 1 more comment
up vote
2
down vote
Let t be the number of teddy bears, h hats and b buses. Then the equations are:
$3t+3h=21 tag1$
$3t+h+2b=19 tag2$
$2t+2h+b=15 tag3$
and we want to know:
$t+(2htimes b)=t+2hb$
Gaussian elimination tells us the answer is:
$t=5, h=2, b=1$, therefore $t+2hb=9$.
but there is a quick way:
From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.
add a comment |Â
up vote
2
down vote
Let t be the number of teddy bears, h hats and b buses. Then the equations are:
$3t+3h=21 tag1$
$3t+h+2b=19 tag2$
$2t+2h+b=15 tag3$
and we want to know:
$t+(2htimes b)=t+2hb$
Gaussian elimination tells us the answer is:
$t=5, h=2, b=1$, therefore $t+2hb=9$.
but there is a quick way:
From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.
add a comment |Â
up vote
2
down vote
up vote
2
down vote
Let t be the number of teddy bears, h hats and b buses. Then the equations are:
$3t+3h=21 tag1$
$3t+h+2b=19 tag2$
$2t+2h+b=15 tag3$
and we want to know:
$t+(2htimes b)=t+2hb$
Gaussian elimination tells us the answer is:
$t=5, h=2, b=1$, therefore $t+2hb=9$.
but there is a quick way:
From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.
Let t be the number of teddy bears, h hats and b buses. Then the equations are:
$3t+3h=21 tag1$
$3t+h+2b=19 tag2$
$2t+2h+b=15 tag3$
and we want to know:
$t+(2htimes b)=t+2hb$
Gaussian elimination tells us the answer is:
$t=5, h=2, b=1$, therefore $t+2hb=9$.
but there is a quick way:
From (1) $t+h=7$. From (3) $b=1$. From (2) and (3), $t-h=3 implies t=5, h=2$.
edited 7 hours ago
answered 7 hours ago


JonMark Perry
14.6k52972
14.6k52972
add a comment |Â
add a comment |Â
up vote
0
down vote
The answer is:
Seven
Reasoning:
Bear With Hat
Seven gained from three additions equaling 21.
Bus with Bear:
Six Subtract the bear from 19 then divide by two.
Hat:
Two; subtract Bear with hat and bus with bear from 15.
Bear minus hat:
Five
Bus minus Bear
One
Final problem:
Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)
1
Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
– PerpetualJ
13 hours ago
I just didn’t see the second hat at first.
– PerpetualJ
9 hours ago
add a comment |Â
up vote
0
down vote
The answer is:
Seven
Reasoning:
Bear With Hat
Seven gained from three additions equaling 21.
Bus with Bear:
Six Subtract the bear from 19 then divide by two.
Hat:
Two; subtract Bear with hat and bus with bear from 15.
Bear minus hat:
Five
Bus minus Bear
One
Final problem:
Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)
1
Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
– PerpetualJ
13 hours ago
I just didn’t see the second hat at first.
– PerpetualJ
9 hours ago
add a comment |Â
up vote
0
down vote
up vote
0
down vote
The answer is:
Seven
Reasoning:
Bear With Hat
Seven gained from three additions equaling 21.
Bus with Bear:
Six Subtract the bear from 19 then divide by two.
Hat:
Two; subtract Bear with hat and bus with bear from 15.
Bear minus hat:
Five
Bus minus Bear
One
Final problem:
Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)
The answer is:
Seven
Reasoning:
Bear With Hat
Seven gained from three additions equaling 21.
Bus with Bear:
Six Subtract the bear from 19 then divide by two.
Hat:
Two; subtract Bear with hat and bus with bear from 15.
Bear minus hat:
Five
Bus minus Bear
One
Final problem:
Bear (5) + Hat(2) * Bus without Bear(1) = Bear with Hat(7)
edited 13 hours ago
answered 13 hours ago


PerpetualJ
2,190227
2,190227
1
Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
– PerpetualJ
13 hours ago
I just didn’t see the second hat at first.
– PerpetualJ
9 hours ago
add a comment |Â
1
Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
– PerpetualJ
13 hours ago
I just didn’t see the second hat at first.
– PerpetualJ
9 hours ago
1
1
Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
– PerpetualJ
13 hours ago
Good point; just noticed that. Pretty sneaky. There’s already a correct answer in that case so I’ll leave this one be! Good puzzle!
– PerpetualJ
13 hours ago
I just didn’t see the second hat at first.
– PerpetualJ
9 hours ago
I just didn’t see the second hat at first.
– PerpetualJ
9 hours ago
add a comment |Â
up vote
0
down vote
Pig (with a hat) = 7
Bus (with a pig) = 6
Hat = 2
Pig = 5
Bus = 1
Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
0
down vote
Pig (with a hat) = 7
Bus (with a pig) = 6
Hat = 2
Pig = 5
Bus = 1
Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Pig (with a hat) = 7
Bus (with a pig) = 6
Hat = 2
Pig = 5
Bus = 1
Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Pig (with a hat) = 7
Bus (with a pig) = 6
Hat = 2
Pig = 5
Bus = 1
Hence pig (without hat) + (2 * hat) * bus (without a pig) = 5 + 4 * 1 = 9
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Shahriar Mahmud Sajid
2,759526
2,759526
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 1 hour ago


Deepak Gopal
1
1
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Deepak Gopal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
add a comment |Â
Unza is a new contributor. Be nice, and check out our Code of Conduct.
Unza is a new contributor. Be nice, and check out our Code of Conduct.
Unza is a new contributor. Be nice, and check out our Code of Conduct.
Unza is a new contributor. Be nice, and check out our Code of Conduct.
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Can you please edit the puzzle's title? It isn't a riddle, and the title is not very descriptive.
– Jaap Scherphuis
5 hours ago
The hats on the third row and the hat on the fourth row are different. Is that intentional? Oh hang on: its two hats isn't it.
– JimM
3 hours ago
Hello Is this an original puzzle designed by you? If yes great design. If no please reference where it came from.
– DEEM
2 hours ago