How do I check if the three last characters of a variable match another variable?

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up vote
4
down vote

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I have %var1% and %var2%

var1="UserInput"
var2=file.log

If a user types %var1% as "file.txt", how can I (if possible) check only the three last characters (Or the file format if that's possible) to see if it matches %var2%'s three last characters or file format?

Another method that does the same thing is also welcome (But the user-input variable must be there)

windows-7 command-line batch script environment-variables

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edited 24 mins ago

phuclv

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asked 13 hours ago

Tom

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up vote
4
down vote

favorite

I have %var1% and %var2%

var1="UserInput"
var2=file.log

If a user types %var1% as "file.txt", how can I (if possible) check only the three last characters (Or the file format if that's possible) to see if it matches %var2%'s three last characters or file format?

Another method that does the same thing is also welcome (But the user-input variable must be there)

windows-7 command-line batch script environment-variables

share|improve this question

edited 24 mins ago

phuclv

8,47663488

asked 13 hours ago

Tom

235

New contributor

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

up vote
4
down vote

favorite

up vote
4
down vote

favorite

I have %var1% and %var2%

var1="UserInput"
var2=file.log

If a user types %var1% as "file.txt", how can I (if possible) check only the three last characters (Or the file format if that's possible) to see if it matches %var2%'s three last characters or file format?

Another method that does the same thing is also welcome (But the user-input variable must be there)

windows-7 command-line batch script environment-variables

share|improve this question

edited 24 mins ago

phuclv

8,47663488

asked 13 hours ago

Tom

235

New contributor

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

I have %var1% and %var2%

var1="UserInput"
var2=file.log

If a user types %var1% as "file.txt", how can I (if possible) check only the three last characters (Or the file format if that's possible) to see if it matches %var2%'s three last characters or file format?

Another method that does the same thing is also welcome (But the user-input variable must be there)

windows-7 command-line batch script environment-variables

windows-7 command-line batch script environment-variables

share|improve this question

edited 24 mins ago

phuclv

8,47663488

asked 13 hours ago

Tom

235

New contributor

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 24 mins ago

phuclv

8,47663488

asked 13 hours ago

Tom

235

New contributor

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

share|improve this question

edited 24 mins ago

phuclv

8,47663488

edited 24 mins ago

phuclv

8,47663488

edited 24 mins ago

phuclv

8,47663488

8,47663488

asked 13 hours ago

Tom

235

New contributor

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 13 hours ago

Tom

235

asked 13 hours ago

Tom

235

235

New contributor

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

New contributor

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Tom is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

add a comment | 

2 Answers
2

active

oldest

votes

up vote
5
down vote

How do I check if the three last characters of a variable match another variable?

Use variable substring syntax to extract the last 3 characters of each variable.

Example batch file:

@echo off
setlocal
set /p var1="UserInput: "
set var1last3=%var1:~-3%
set var2=file.log
set var2last3=%var2:~-3%
if %var1last3% == %var2last3% (
 echo Match
 ) else (
 echo No Match
 )
endlocal

---

Further Reading

• An A-Z Index of the Windows CMD command line | SS64.com


• Windows CMD Commands (categorized) - Windows CMD - SS64.com


• If - Conditionally perform command - Windows CMD - SS64.com


• Set - Environment Variable - Windows CMD - SS64.com


• variable substring - Windows CMD - SS64.com

share|improve this answer

edited 10 hours ago

answered 12 hours ago

DavidPostill♦

101k25213249

• 
  
  
  

  
  

  
  
  
  
  
  

  
  It doesn't affect your answer's functionality, but why have you set enabledelayedexpansion when you don't use any !var! expansions?
  – AFH
  12 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @AFH Force of habit. I've removed it to avoid any confusion:)
  – DavidPostill♦
  10 hours ago
  
  

  
  
  
  

add a comment | 

up vote
4
down vote

If you are going to check a fixed number of characters, then you should check the last 4, else "file.Log" will match "file.myLog".

But the best option is to get the actual extension, regardless the length:

@echo off
setlocal
set "var1=file.Log"
set "var2=file.myLog"

:: Option 1 using FOR loops
for %%A in ("%var1%") do for %%B in ("%var2%") do if "%%~xA"=="%%~xB" (
 echo Match
) else (
 echo No Match
)

: Option 2 using CALL parameters
call :matchExtension "%var1%" "%var2%" &&echo Match||echo No Match
exit /b

:matchExtension file1 fil2 --> returns 0 (success) if match, 1 (error) if no match
if "%~x1"=="%~x2" exit /b 0
exit /b 1

share|improve this answer

answered 12 hours ago

dbenham

7,48631828

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
5
down vote

How do I check if the three last characters of a variable match another variable?

Use variable substring syntax to extract the last 3 characters of each variable.

Example batch file:

@echo off
setlocal
set /p var1="UserInput: "
set var1last3=%var1:~-3%
set var2=file.log
set var2last3=%var2:~-3%
if %var1last3% == %var2last3% (
 echo Match
 ) else (
 echo No Match
 )
endlocal

---

Further Reading

• An A-Z Index of the Windows CMD command line | SS64.com


• Windows CMD Commands (categorized) - Windows CMD - SS64.com


• If - Conditionally perform command - Windows CMD - SS64.com


• Set - Environment Variable - Windows CMD - SS64.com


• variable substring - Windows CMD - SS64.com

share|improve this answer

edited 10 hours ago

answered 12 hours ago

DavidPostill♦

101k25213249

• 
  
  
  

  
  

  
  
  
  
  
  

  
  It doesn't affect your answer's functionality, but why have you set enabledelayedexpansion when you don't use any !var! expansions?
  – AFH
  12 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @AFH Force of habit. I've removed it to avoid any confusion:)
  – DavidPostill♦
  10 hours ago
  
  

  
  
  
  

add a comment | 

up vote
5
down vote

How do I check if the three last characters of a variable match another variable?

Use variable substring syntax to extract the last 3 characters of each variable.

Example batch file:

@echo off
setlocal
set /p var1="UserInput: "
set var1last3=%var1:~-3%
set var2=file.log
set var2last3=%var2:~-3%
if %var1last3% == %var2last3% (
 echo Match
 ) else (
 echo No Match
 )
endlocal

---

Further Reading

• An A-Z Index of the Windows CMD command line | SS64.com


• Windows CMD Commands (categorized) - Windows CMD - SS64.com


• If - Conditionally perform command - Windows CMD - SS64.com


• Set - Environment Variable - Windows CMD - SS64.com


• variable substring - Windows CMD - SS64.com

share|improve this answer

edited 10 hours ago

answered 12 hours ago

DavidPostill♦

101k25213249

• 
  
  
  

  
  

  
  
  
  
  
  

  
  It doesn't affect your answer's functionality, but why have you set enabledelayedexpansion when you don't use any !var! expansions?
  – AFH
  12 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @AFH Force of habit. I've removed it to avoid any confusion:)
  – DavidPostill♦
  10 hours ago
  
  

  
  
  
  

add a comment | 

up vote
5
down vote

up vote
5
down vote

How do I check if the three last characters of a variable match another variable?

Use variable substring syntax to extract the last 3 characters of each variable.

Example batch file:

@echo off
setlocal
set /p var1="UserInput: "
set var1last3=%var1:~-3%
set var2=file.log
set var2last3=%var2:~-3%
if %var1last3% == %var2last3% (
 echo Match
 ) else (
 echo No Match
 )
endlocal

---

Further Reading

• An A-Z Index of the Windows CMD command line | SS64.com


• Windows CMD Commands (categorized) - Windows CMD - SS64.com


• If - Conditionally perform command - Windows CMD - SS64.com


• Set - Environment Variable - Windows CMD - SS64.com


• variable substring - Windows CMD - SS64.com

share|improve this answer

edited 10 hours ago

answered 12 hours ago

DavidPostill♦

101k25213249

How do I check if the three last characters of a variable match another variable?

Use variable substring syntax to extract the last 3 characters of each variable.

Example batch file:

@echo off
setlocal
set /p var1="UserInput: "
set var1last3=%var1:~-3%
set var2=file.log
set var2last3=%var2:~-3%
if %var1last3% == %var2last3% (
 echo Match
 ) else (
 echo No Match
 )
endlocal

---

Further Reading

• An A-Z Index of the Windows CMD command line | SS64.com


• Windows CMD Commands (categorized) - Windows CMD - SS64.com


• If - Conditionally perform command - Windows CMD - SS64.com


• Set - Environment Variable - Windows CMD - SS64.com


• variable substring - Windows CMD - SS64.com

share|improve this answer

edited 10 hours ago

answered 12 hours ago

DavidPostill♦

101k25213249

share|improve this answer

share|improve this answer

edited 10 hours ago

edited 10 hours ago

edited 10 hours ago

answered 12 hours ago

DavidPostill♦

101k25213249

answered 12 hours ago

DavidPostill♦

101k25213249

answered 12 hours ago

DavidPostill♦

101k25213249

101k25213249

• 
  
  
  

  
  

  
  
  
  
  
  

  
  It doesn't affect your answer's functionality, but why have you set enabledelayedexpansion when you don't use any !var! expansions?
  – AFH
  12 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @AFH Force of habit. I've removed it to avoid any confusion:)
  – DavidPostill♦
  10 hours ago
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  It doesn't affect your answer's functionality, but why have you set enabledelayedexpansion when you don't use any !var! expansions?
  – AFH
  12 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @AFH Force of habit. I've removed it to avoid any confusion:)
  – DavidPostill♦
  10 hours ago
  
  

  
  
  
  

It doesn't affect your answer's functionality, but why have you set enabledelayedexpansion when you don't use any !var! expansions?
– AFH
12 hours ago

It doesn't affect your answer's functionality, but why have you set enabledelayedexpansion when you don't use any !var! expansions?
– AFH
12 hours ago

@AFH Force of habit. I've removed it to avoid any confusion:)
– DavidPostill♦
10 hours ago

@AFH Force of habit. I've removed it to avoid any confusion:)
– DavidPostill♦
10 hours ago

add a comment | 

up vote
4
down vote

If you are going to check a fixed number of characters, then you should check the last 4, else "file.Log" will match "file.myLog".

But the best option is to get the actual extension, regardless the length:

@echo off
setlocal
set "var1=file.Log"
set "var2=file.myLog"

:: Option 1 using FOR loops
for %%A in ("%var1%") do for %%B in ("%var2%") do if "%%~xA"=="%%~xB" (
 echo Match
) else (
 echo No Match
)

: Option 2 using CALL parameters
call :matchExtension "%var1%" "%var2%" &&echo Match||echo No Match
exit /b

:matchExtension file1 fil2 --> returns 0 (success) if match, 1 (error) if no match
if "%~x1"=="%~x2" exit /b 0
exit /b 1

share|improve this answer

answered 12 hours ago

dbenham

7,48631828

add a comment | 

up vote
4
down vote

If you are going to check a fixed number of characters, then you should check the last 4, else "file.Log" will match "file.myLog".

But the best option is to get the actual extension, regardless the length:

@echo off
setlocal
set "var1=file.Log"
set "var2=file.myLog"

:: Option 1 using FOR loops
for %%A in ("%var1%") do for %%B in ("%var2%") do if "%%~xA"=="%%~xB" (
 echo Match
) else (
 echo No Match
)

: Option 2 using CALL parameters
call :matchExtension "%var1%" "%var2%" &&echo Match||echo No Match
exit /b

:matchExtension file1 fil2 --> returns 0 (success) if match, 1 (error) if no match
if "%~x1"=="%~x2" exit /b 0
exit /b 1

share|improve this answer

answered 12 hours ago

dbenham

7,48631828

add a comment | 

up vote
4
down vote

up vote
4
down vote

If you are going to check a fixed number of characters, then you should check the last 4, else "file.Log" will match "file.myLog".

But the best option is to get the actual extension, regardless the length:

@echo off
setlocal
set "var1=file.Log"
set "var2=file.myLog"

:: Option 1 using FOR loops
for %%A in ("%var1%") do for %%B in ("%var2%") do if "%%~xA"=="%%~xB" (
 echo Match
) else (
 echo No Match
)

: Option 2 using CALL parameters
call :matchExtension "%var1%" "%var2%" &&echo Match||echo No Match
exit /b

:matchExtension file1 fil2 --> returns 0 (success) if match, 1 (error) if no match
if "%~x1"=="%~x2" exit /b 0
exit /b 1

share|improve this answer

answered 12 hours ago

dbenham

7,48631828

If you are going to check a fixed number of characters, then you should check the last 4, else "file.Log" will match "file.myLog".

But the best option is to get the actual extension, regardless the length:

@echo off
setlocal
set "var1=file.Log"
set "var2=file.myLog"

:: Option 1 using FOR loops
for %%A in ("%var1%") do for %%B in ("%var2%") do if "%%~xA"=="%%~xB" (
 echo Match
) else (
 echo No Match
)

: Option 2 using CALL parameters
call :matchExtension "%var1%" "%var2%" &&echo Match||echo No Match
exit /b

:matchExtension file1 fil2 --> returns 0 (success) if match, 1 (error) if no match
if "%~x1"=="%~x2" exit /b 0
exit /b 1

share|improve this answer

answered 12 hours ago

dbenham

7,48631828

share|improve this answer

share|improve this answer

answered 12 hours ago

dbenham

7,48631828

answered 12 hours ago

dbenham

7,48631828

answered 12 hours ago

dbenham

7,48631828

7,48631828

add a comment | 

add a comment | 

Tom is a new contributor. Be nice, and check out our Code of Conduct.

 

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