Which one is magnet, which one is iron?
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My question is, one of them is iron and the other is a magnet. It is forbidden to break. However, it is desired to determine the magnet without using any other objects. How can I find , which is iron or magnet?
I learned that the following method is wrong.
My method:
1) To bring the $ S-$pole of the magnet on the left to the $S-$pole of the right magnet.
2) Then bring the $ S-$pole of the magnet on the left to the $N-$pole of the right-hand magnet.
If both are attractive, then it is iron on the left.
Is my method correct?
magnetic-fields
New contributor
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up vote
1
down vote
favorite
My question is, one of them is iron and the other is a magnet. It is forbidden to break. However, it is desired to determine the magnet without using any other objects. How can I find , which is iron or magnet?
I learned that the following method is wrong.
My method:
1) To bring the $ S-$pole of the magnet on the left to the $S-$pole of the right magnet.
2) Then bring the $ S-$pole of the magnet on the left to the $N-$pole of the right-hand magnet.
If both are attractive, then it is iron on the left.
Is my method correct?
magnetic-fields
New contributor
can you break the magnet with the iron :)
â user2312512851
2 hours ago
@user2312512851 It is forbidden to break.
â Beginner
2 hours ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
My question is, one of them is iron and the other is a magnet. It is forbidden to break. However, it is desired to determine the magnet without using any other objects. How can I find , which is iron or magnet?
I learned that the following method is wrong.
My method:
1) To bring the $ S-$pole of the magnet on the left to the $S-$pole of the right magnet.
2) Then bring the $ S-$pole of the magnet on the left to the $N-$pole of the right-hand magnet.
If both are attractive, then it is iron on the left.
Is my method correct?
magnetic-fields
New contributor
My question is, one of them is iron and the other is a magnet. It is forbidden to break. However, it is desired to determine the magnet without using any other objects. How can I find , which is iron or magnet?
I learned that the following method is wrong.
My method:
1) To bring the $ S-$pole of the magnet on the left to the $S-$pole of the right magnet.
2) Then bring the $ S-$pole of the magnet on the left to the $N-$pole of the right-hand magnet.
If both are attractive, then it is iron on the left.
Is my method correct?
magnetic-fields
magnetic-fields
New contributor
New contributor
edited 2 hours ago
New contributor
asked 3 hours ago
Beginner
63
63
New contributor
New contributor
can you break the magnet with the iron :)
â user2312512851
2 hours ago
@user2312512851 It is forbidden to break.
â Beginner
2 hours ago
add a comment |Â
can you break the magnet with the iron :)
â user2312512851
2 hours ago
@user2312512851 It is forbidden to break.
â Beginner
2 hours ago
can you break the magnet with the iron :)
â user2312512851
2 hours ago
can you break the magnet with the iron :)
â user2312512851
2 hours ago
@user2312512851 It is forbidden to break.
â Beginner
2 hours ago
@user2312512851 It is forbidden to break.
â Beginner
2 hours ago
add a comment |Â
4 Answers
4
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up vote
1
down vote
If you have another magnet, one end of that will repel one end of the magnet, but it will attract both ends of the iron.
If you have another piece of iron, it will be be attracted to the magnet, but not the iron.
If you have neither, you will have to resort to destructive testing: cut one of the items in two. If the two parts attract and repel each other, you have cut the magnet. If not, you have cut the iron.
New contributor
it is desired to determine the magnet without using any other objects...
â Beginner
2 hours ago
add a comment |Â
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Place the bar "magnet" between the poles of the horseshoe "magnet", perpendicular to the plane that contains it.
Now move the bar along its axis. If the bar is actually a magnet, the field is the strongest at the tips of the bar, so the greatest magnetization of the horseshoe bar (and therefore lowest energy state, by E = - m . B) will be roughly when either tip of the straight bar is closest to the horseshoe bar.
If, otherwise, the horseshoe bar is a magnet, the magnetization is greatest, roughly, when you maximize the volume of metal between the poles, so the lowest energy state will be when the straight bar is in the midpoint.
If the straight bar, constrained to move only along its axis, is pulled into the middle, the horseshoe bar is a magnet. If instead, either end of the bar is pulled into the middle, the straight bar is the magnet.
add a comment |Â
up vote
0
down vote
You can't say that using this method. Iron will be attracted by any pole of magnet. Using your method only determines that one of these is made of iron. So this is not a good idea. Instead use them on any other non magnetized object made of ferromagnetic material. The one which doesn't attract the object is made of iron.
I thought of the right as a magnet. Yeah, I think I understand my mistake.
â Beginner
3 hours ago
But the question needs to be determined without using anything else.
â Beginner
3 hours ago
@Beginner it's not mentioned in the question and I don't think you can do that without using anything else.
â Mechanic7
3 hours ago
Thank you so much for answer. You are right. I edited question. Thank you again for answer.
â Beginner
2 hours ago
add a comment |Â
up vote
0
down vote
Too bad that you can't use any other objects. Otherwise, I would simply put both of the items into any nearby dirt or sand and rub them around for a minute or two. Whichever of them comes back coated in little pieces of iron--which is present in almost any amounts of natural detritus that would have broken down into those natural substances--that would be the magnet.
add a comment |Â
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
If you have another magnet, one end of that will repel one end of the magnet, but it will attract both ends of the iron.
If you have another piece of iron, it will be be attracted to the magnet, but not the iron.
If you have neither, you will have to resort to destructive testing: cut one of the items in two. If the two parts attract and repel each other, you have cut the magnet. If not, you have cut the iron.
New contributor
it is desired to determine the magnet without using any other objects...
â Beginner
2 hours ago
add a comment |Â
up vote
1
down vote
If you have another magnet, one end of that will repel one end of the magnet, but it will attract both ends of the iron.
If you have another piece of iron, it will be be attracted to the magnet, but not the iron.
If you have neither, you will have to resort to destructive testing: cut one of the items in two. If the two parts attract and repel each other, you have cut the magnet. If not, you have cut the iron.
New contributor
it is desired to determine the magnet without using any other objects...
â Beginner
2 hours ago
add a comment |Â
up vote
1
down vote
up vote
1
down vote
If you have another magnet, one end of that will repel one end of the magnet, but it will attract both ends of the iron.
If you have another piece of iron, it will be be attracted to the magnet, but not the iron.
If you have neither, you will have to resort to destructive testing: cut one of the items in two. If the two parts attract and repel each other, you have cut the magnet. If not, you have cut the iron.
New contributor
If you have another magnet, one end of that will repel one end of the magnet, but it will attract both ends of the iron.
If you have another piece of iron, it will be be attracted to the magnet, but not the iron.
If you have neither, you will have to resort to destructive testing: cut one of the items in two. If the two parts attract and repel each other, you have cut the magnet. If not, you have cut the iron.
New contributor
New contributor
answered 2 hours ago
Søren Lassen
163
163
New contributor
New contributor
it is desired to determine the magnet without using any other objects...
â Beginner
2 hours ago
add a comment |Â
it is desired to determine the magnet without using any other objects...
â Beginner
2 hours ago
it is desired to determine the magnet without using any other objects...
â Beginner
2 hours ago
it is desired to determine the magnet without using any other objects...
â Beginner
2 hours ago
add a comment |Â
up vote
1
down vote
Place the bar "magnet" between the poles of the horseshoe "magnet", perpendicular to the plane that contains it.
Now move the bar along its axis. If the bar is actually a magnet, the field is the strongest at the tips of the bar, so the greatest magnetization of the horseshoe bar (and therefore lowest energy state, by E = - m . B) will be roughly when either tip of the straight bar is closest to the horseshoe bar.
If, otherwise, the horseshoe bar is a magnet, the magnetization is greatest, roughly, when you maximize the volume of metal between the poles, so the lowest energy state will be when the straight bar is in the midpoint.
If the straight bar, constrained to move only along its axis, is pulled into the middle, the horseshoe bar is a magnet. If instead, either end of the bar is pulled into the middle, the straight bar is the magnet.
add a comment |Â
up vote
1
down vote
Place the bar "magnet" between the poles of the horseshoe "magnet", perpendicular to the plane that contains it.
Now move the bar along its axis. If the bar is actually a magnet, the field is the strongest at the tips of the bar, so the greatest magnetization of the horseshoe bar (and therefore lowest energy state, by E = - m . B) will be roughly when either tip of the straight bar is closest to the horseshoe bar.
If, otherwise, the horseshoe bar is a magnet, the magnetization is greatest, roughly, when you maximize the volume of metal between the poles, so the lowest energy state will be when the straight bar is in the midpoint.
If the straight bar, constrained to move only along its axis, is pulled into the middle, the horseshoe bar is a magnet. If instead, either end of the bar is pulled into the middle, the straight bar is the magnet.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Place the bar "magnet" between the poles of the horseshoe "magnet", perpendicular to the plane that contains it.
Now move the bar along its axis. If the bar is actually a magnet, the field is the strongest at the tips of the bar, so the greatest magnetization of the horseshoe bar (and therefore lowest energy state, by E = - m . B) will be roughly when either tip of the straight bar is closest to the horseshoe bar.
If, otherwise, the horseshoe bar is a magnet, the magnetization is greatest, roughly, when you maximize the volume of metal between the poles, so the lowest energy state will be when the straight bar is in the midpoint.
If the straight bar, constrained to move only along its axis, is pulled into the middle, the horseshoe bar is a magnet. If instead, either end of the bar is pulled into the middle, the straight bar is the magnet.
Place the bar "magnet" between the poles of the horseshoe "magnet", perpendicular to the plane that contains it.
Now move the bar along its axis. If the bar is actually a magnet, the field is the strongest at the tips of the bar, so the greatest magnetization of the horseshoe bar (and therefore lowest energy state, by E = - m . B) will be roughly when either tip of the straight bar is closest to the horseshoe bar.
If, otherwise, the horseshoe bar is a magnet, the magnetization is greatest, roughly, when you maximize the volume of metal between the poles, so the lowest energy state will be when the straight bar is in the midpoint.
If the straight bar, constrained to move only along its axis, is pulled into the middle, the horseshoe bar is a magnet. If instead, either end of the bar is pulled into the middle, the straight bar is the magnet.
edited 1 hour ago
answered 1 hour ago
someone_else
235
235
add a comment |Â
add a comment |Â
up vote
0
down vote
You can't say that using this method. Iron will be attracted by any pole of magnet. Using your method only determines that one of these is made of iron. So this is not a good idea. Instead use them on any other non magnetized object made of ferromagnetic material. The one which doesn't attract the object is made of iron.
I thought of the right as a magnet. Yeah, I think I understand my mistake.
â Beginner
3 hours ago
But the question needs to be determined without using anything else.
â Beginner
3 hours ago
@Beginner it's not mentioned in the question and I don't think you can do that without using anything else.
â Mechanic7
3 hours ago
Thank you so much for answer. You are right. I edited question. Thank you again for answer.
â Beginner
2 hours ago
add a comment |Â
up vote
0
down vote
You can't say that using this method. Iron will be attracted by any pole of magnet. Using your method only determines that one of these is made of iron. So this is not a good idea. Instead use them on any other non magnetized object made of ferromagnetic material. The one which doesn't attract the object is made of iron.
I thought of the right as a magnet. Yeah, I think I understand my mistake.
â Beginner
3 hours ago
But the question needs to be determined without using anything else.
â Beginner
3 hours ago
@Beginner it's not mentioned in the question and I don't think you can do that without using anything else.
â Mechanic7
3 hours ago
Thank you so much for answer. You are right. I edited question. Thank you again for answer.
â Beginner
2 hours ago
add a comment |Â
up vote
0
down vote
up vote
0
down vote
You can't say that using this method. Iron will be attracted by any pole of magnet. Using your method only determines that one of these is made of iron. So this is not a good idea. Instead use them on any other non magnetized object made of ferromagnetic material. The one which doesn't attract the object is made of iron.
You can't say that using this method. Iron will be attracted by any pole of magnet. Using your method only determines that one of these is made of iron. So this is not a good idea. Instead use them on any other non magnetized object made of ferromagnetic material. The one which doesn't attract the object is made of iron.
answered 3 hours ago
Mechanic7
415115
415115
I thought of the right as a magnet. Yeah, I think I understand my mistake.
â Beginner
3 hours ago
But the question needs to be determined without using anything else.
â Beginner
3 hours ago
@Beginner it's not mentioned in the question and I don't think you can do that without using anything else.
â Mechanic7
3 hours ago
Thank you so much for answer. You are right. I edited question. Thank you again for answer.
â Beginner
2 hours ago
add a comment |Â
I thought of the right as a magnet. Yeah, I think I understand my mistake.
â Beginner
3 hours ago
But the question needs to be determined without using anything else.
â Beginner
3 hours ago
@Beginner it's not mentioned in the question and I don't think you can do that without using anything else.
â Mechanic7
3 hours ago
Thank you so much for answer. You are right. I edited question. Thank you again for answer.
â Beginner
2 hours ago
I thought of the right as a magnet. Yeah, I think I understand my mistake.
â Beginner
3 hours ago
I thought of the right as a magnet. Yeah, I think I understand my mistake.
â Beginner
3 hours ago
But the question needs to be determined without using anything else.
â Beginner
3 hours ago
But the question needs to be determined without using anything else.
â Beginner
3 hours ago
@Beginner it's not mentioned in the question and I don't think you can do that without using anything else.
â Mechanic7
3 hours ago
@Beginner it's not mentioned in the question and I don't think you can do that without using anything else.
â Mechanic7
3 hours ago
Thank you so much for answer. You are right. I edited question. Thank you again for answer.
â Beginner
2 hours ago
Thank you so much for answer. You are right. I edited question. Thank you again for answer.
â Beginner
2 hours ago
add a comment |Â
up vote
0
down vote
Too bad that you can't use any other objects. Otherwise, I would simply put both of the items into any nearby dirt or sand and rub them around for a minute or two. Whichever of them comes back coated in little pieces of iron--which is present in almost any amounts of natural detritus that would have broken down into those natural substances--that would be the magnet.
add a comment |Â
up vote
0
down vote
Too bad that you can't use any other objects. Otherwise, I would simply put both of the items into any nearby dirt or sand and rub them around for a minute or two. Whichever of them comes back coated in little pieces of iron--which is present in almost any amounts of natural detritus that would have broken down into those natural substances--that would be the magnet.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Too bad that you can't use any other objects. Otherwise, I would simply put both of the items into any nearby dirt or sand and rub them around for a minute or two. Whichever of them comes back coated in little pieces of iron--which is present in almost any amounts of natural detritus that would have broken down into those natural substances--that would be the magnet.
Too bad that you can't use any other objects. Otherwise, I would simply put both of the items into any nearby dirt or sand and rub them around for a minute or two. Whichever of them comes back coated in little pieces of iron--which is present in almost any amounts of natural detritus that would have broken down into those natural substances--that would be the magnet.
answered 2 hours ago
Ace Hall
311
311
add a comment |Â
add a comment |Â
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can you break the magnet with the iron :)
â user2312512851
2 hours ago
@user2312512851 It is forbidden to break.
â Beginner
2 hours ago