data manipulation

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3
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I have to plot the data below:

x,y,z=0.1,0.013070604,1.00015,0.6,0.078698955,1.0054247,1.1,0.14552025,1.0184426,1.6,0.21458577,1.0398293,2.1,0.28706229,1.0712175,2.6,0.3643249,1.1155575

I am new in data manipulation. Please how to plot column x vs column z and z vs y.

plotting data

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asked 1 hour ago

Gallagher

565

add a comment | 

up vote
3
down vote

favorite

I have to plot the data below:

x,y,z=0.1,0.013070604,1.00015,0.6,0.078698955,1.0054247,1.1,0.14552025,1.0184426,1.6,0.21458577,1.0398293,2.1,0.28706229,1.0712175,2.6,0.3643249,1.1155575

I am new in data manipulation. Please how to plot column x vs column z and z vs y.

plotting data

share|improve this question

asked 1 hour ago

Gallagher

565

add a comment | 

up vote
3
down vote

favorite

up vote
3
down vote

favorite

I have to plot the data below:

x,y,z=0.1,0.013070604,1.00015,0.6,0.078698955,1.0054247,1.1,0.14552025,1.0184426,1.6,0.21458577,1.0398293,2.1,0.28706229,1.0712175,2.6,0.3643249,1.1155575

I am new in data manipulation. Please how to plot column x vs column z and z vs y.

plotting data

share|improve this question

asked 1 hour ago

Gallagher

565

I have to plot the data below:

x,y,z=0.1,0.013070604,1.00015,0.6,0.078698955,1.0054247,1.1,0.14552025,1.0184426,1.6,0.21458577,1.0398293,2.1,0.28706229,1.0712175,2.6,0.3643249,1.1155575

I am new in data manipulation. Please how to plot column x vs column z and z vs y.

plotting data

plotting data

share|improve this question

asked 1 hour ago

Gallagher

565

share|improve this question

asked 1 hour ago

Gallagher

565

share|improve this question

share|improve this question

asked 1 hour ago

Gallagher

565

asked 1 hour ago

Gallagher

565

asked 1 hour ago

Gallagher

565

565

add a comment | 

add a comment | 

3 Answers
3

active

oldest

votes

up vote
5
down vote

How about this

data = Flatten /@ 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575;

ListPlot[data[[All, 3, 1]], data[[All, 2 ;;]]]

share|improve this answer

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @Αλέξανδρος Ζεγγ.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
5
down vote

This is also a good place to apply patterns to re-arrange the elements of the data.

list = 0.1, 0.013070604, 1.00015, 0.6, 0.078698955,1.0054247, 
 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577,1.0398293,
 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249,1.1155575;

ListPlot[list /. x_, y_, z_ -> x, z, list /. x_, y_, z_ -> z, y]

share|improve this answer

answered 1 hour ago

bill s

50.9k373144

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @bill s.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
0
down vote

Here is another way:

a = 
 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575
 ; 
x, y, z = MapAt[Transpose, Transpose[a], 2];
ListPlot[Transpose[x, z], Transpose[z, y]]

share|improve this answer

answered 23 mins ago

Henrik Schumacher

38.4k251111

add a comment | 

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
5
down vote

How about this

data = Flatten /@ 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575;

ListPlot[data[[All, 3, 1]], data[[All, 2 ;;]]]

share|improve this answer

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @Αλέξανδρος Ζεγγ.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
5
down vote

How about this

data = Flatten /@ 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575;

ListPlot[data[[All, 3, 1]], data[[All, 2 ;;]]]

share|improve this answer

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @Αλέξανδρος Ζεγγ.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
5
down vote

up vote
5
down vote

How about this

data = Flatten /@ 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575;

ListPlot[data[[All, 3, 1]], data[[All, 2 ;;]]]

share|improve this answer

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

How about this

data = Flatten /@ 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575;

ListPlot[data[[All, 3, 1]], data[[All, 2 ;;]]]

share|improve this answer

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

share|improve this answer

share|improve this answer

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

answered 1 hour ago

Αλέξανδρος Ζεγγ

1,803720

1,803720

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @Αλέξανδρος Ζεγγ.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @Αλέξανδρος Ζεγγ.
  – Gallagher
  1 hour ago
  

  
  
  
  

yes that's it, thank you @Αλέξανδρος Ζεγγ.
– Gallagher
1 hour ago

yes that's it, thank you @Αλέξανδρος Ζεγγ.
– Gallagher
1 hour ago

add a comment | 

up vote
5
down vote

This is also a good place to apply patterns to re-arrange the elements of the data.

list = 0.1, 0.013070604, 1.00015, 0.6, 0.078698955,1.0054247, 
 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577,1.0398293,
 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249,1.1155575;

ListPlot[list /. x_, y_, z_ -> x, z, list /. x_, y_, z_ -> z, y]

share|improve this answer

answered 1 hour ago

bill s

50.9k373144

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @bill s.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
5
down vote

This is also a good place to apply patterns to re-arrange the elements of the data.

list = 0.1, 0.013070604, 1.00015, 0.6, 0.078698955,1.0054247, 
 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577,1.0398293,
 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249,1.1155575;

ListPlot[list /. x_, y_, z_ -> x, z, list /. x_, y_, z_ -> z, y]

share|improve this answer

answered 1 hour ago

bill s

50.9k373144

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @bill s.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
5
down vote

up vote
5
down vote

This is also a good place to apply patterns to re-arrange the elements of the data.

list = 0.1, 0.013070604, 1.00015, 0.6, 0.078698955,1.0054247, 
 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577,1.0398293,
 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249,1.1155575;

ListPlot[list /. x_, y_, z_ -> x, z, list /. x_, y_, z_ -> z, y]

share|improve this answer

answered 1 hour ago

bill s

50.9k373144

This is also a good place to apply patterns to re-arrange the elements of the data.

list = 0.1, 0.013070604, 1.00015, 0.6, 0.078698955,1.0054247, 
 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577,1.0398293,
 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249,1.1155575;

ListPlot[list /. x_, y_, z_ -> x, z, list /. x_, y_, z_ -> z, y]

share|improve this answer

answered 1 hour ago

bill s

50.9k373144

share|improve this answer

share|improve this answer

answered 1 hour ago

bill s

50.9k373144

answered 1 hour ago

bill s

50.9k373144

answered 1 hour ago

bill s

50.9k373144

50.9k373144

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @bill s.
  – Gallagher
  1 hour ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  yes that's it, thank you @bill s.
  – Gallagher
  1 hour ago
  

  
  
  
  

yes that's it, thank you @bill s.
– Gallagher
1 hour ago

yes that's it, thank you @bill s.
– Gallagher
1 hour ago

add a comment | 

up vote
0
down vote

Here is another way:

a = 
 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575
 ; 
x, y, z = MapAt[Transpose, Transpose[a], 2];
ListPlot[Transpose[x, z], Transpose[z, y]]

share|improve this answer

answered 23 mins ago

Henrik Schumacher

38.4k251111

add a comment | 

up vote
0
down vote

Here is another way:

a = 
 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575
 ; 
x, y, z = MapAt[Transpose, Transpose[a], 2];
ListPlot[Transpose[x, z], Transpose[z, y]]

share|improve this answer

answered 23 mins ago

Henrik Schumacher

38.4k251111

add a comment | 

up vote
0
down vote

up vote
0
down vote

Here is another way:

a = 
 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575
 ; 
x, y, z = MapAt[Transpose, Transpose[a], 2];
ListPlot[Transpose[x, z], Transpose[z, y]]

share|improve this answer

answered 23 mins ago

Henrik Schumacher

38.4k251111

Here is another way:

a = 
 0.1, 0.013070604, 1.00015, 0.6, 0.078698955, 
 1.0054247, 1.1, 0.14552025, 1.0184426, 1.6, 0.21458577, 
 1.0398293, 2.1, 0.28706229, 1.0712175, 2.6, 0.3643249, 
 1.1155575
 ; 
x, y, z = MapAt[Transpose, Transpose[a], 2];
ListPlot[Transpose[x, z], Transpose[z, y]]

share|improve this answer

answered 23 mins ago

Henrik Schumacher

38.4k251111

share|improve this answer

share|improve this answer

answered 23 mins ago

Henrik Schumacher

38.4k251111

answered 23 mins ago

Henrik Schumacher

38.4k251111

answered 23 mins ago

Henrik Schumacher

38.4k251111

38.4k251111

add a comment | 

add a comment | 

 

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