What is the time unit that strace uses when displaying time spent in syscalls?

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When using the command strace with the flag -T, I would like to know what is the time unit used to display time spent in syscalls? I assume it should be in seconds, but I am not quite sure and it seems to be omitted from the manual.

edited 16 mins ago

Goro

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edited 16 mins ago

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edited 16 mins ago

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linux process system-calls strace syscalls

edited 16 mins ago

Goro

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edited 16 mins ago

Goro

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asked 48 mins ago

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edited 16 mins ago

Goro

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edited 16 mins ago

Goro

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edited 16 mins ago

Goro

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asked 48 mins ago

user311285

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asked 48 mins ago

user311285

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asked 48 mins ago

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3 Answers
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From the source code:

if (Tflag) 
 ts_sub(ts, ts, &tcp->etime);
 tprintf(" <%ld.%06ld>",
 (long) ts->tv_sec, (long) ts->tv_nsec / 1000);

This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.

answered 40 mins ago

Stephen Kitt

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4
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If you run

strace -T sleep 2

you will see

nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>

so it looks like the time spent is in seconds.

answered 41 mins ago

meuh

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If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:

strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total

from strace's man

-c

Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.

answered 34 mins ago

Goro

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
5
down vote

accepted

From the source code:

if (Tflag) 
 ts_sub(ts, ts, &tcp->etime);
 tprintf(" <%ld.%06ld>",
 (long) ts->tv_sec, (long) ts->tv_nsec / 1000);

This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.

answered 40 mins ago

Stephen Kitt

145k22318383

add a commentÂ |Â

up vote
5
down vote

accepted

From the source code:

if (Tflag) 
 ts_sub(ts, ts, &tcp->etime);
 tprintf(" <%ld.%06ld>",
 (long) ts->tv_sec, (long) ts->tv_nsec / 1000);

This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.

answered 40 mins ago

Stephen Kitt

145k22318383

add a commentÂ |Â

up vote
5
down vote

accepted

From the source code:

if (Tflag) 
 ts_sub(ts, ts, &tcp->etime);
 tprintf(" <%ld.%06ld>",
 (long) ts->tv_sec, (long) ts->tv_nsec / 1000);

This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.

answered 40 mins ago

Stephen Kitt

145k22318383

From the source code:

if (Tflag) 
 ts_sub(ts, ts, &tcp->etime);
 tprintf(" <%ld.%06ld>",
 (long) ts->tv_sec, (long) ts->tv_nsec / 1000);

This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.

answered 40 mins ago

Stephen Kitt

145k22318383

answered 40 mins ago

Stephen Kitt

145k22318383

answered 40 mins ago

Stephen Kitt

145k22318383

answered 40 mins ago

Stephen Kitt

145k22318383

add a commentÂ |Â

up vote
4
down vote

If you run

strace -T sleep 2

you will see

nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>

so it looks like the time spent is in seconds.

answered 41 mins ago

meuh

29.9k11751

add a commentÂ |Â

up vote
4
down vote

If you run

strace -T sleep 2

you will see

nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>

so it looks like the time spent is in seconds.

answered 41 mins ago

meuh

29.9k11751

add a commentÂ |Â

up vote
4
down vote

If you run

strace -T sleep 2

you will see

nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>

so it looks like the time spent is in seconds.

answered 41 mins ago

meuh

29.9k11751

If you run

strace -T sleep 2

you will see

nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>

so it looks like the time spent is in seconds.

answered 41 mins ago

meuh

29.9k11751

answered 41 mins ago

meuh

29.9k11751

answered 41 mins ago

meuh

29.9k11751

answered 41 mins ago

meuh

29.9k11751

add a commentÂ |Â

up vote
4
down vote

If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:

strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total

from strace's man

-c

Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.

answered 34 mins ago

Goro

2,55141849

add a commentÂ |Â

up vote
4
down vote

If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:

strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total

from strace's man

-c

Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.

answered 34 mins ago

Goro

2,55141849

add a commentÂ |Â

up vote
4
down vote

If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:

strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total

from strace's man

-c

Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.

answered 34 mins ago

Goro

2,55141849

If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:

strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total

from strace's man

-c

Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.

answered 34 mins ago

Goro

2,55141849

answered 34 mins ago

Goro

2,55141849

answered 34 mins ago

Goro

2,55141849

answered 34 mins ago

Goro

2,55141849

add a commentÂ |Â

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