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What is the time unit that strace uses when displaying time spent in syscalls?
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When using the command strace with the flag -T, I would like to know what is the time unit used to display time spent in syscalls? I assume it should be in seconds, but I am not quite sure and it seems to be omitted from the manual.
linux process system-calls strace syscalls
edited 16 mins ago
Goro
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up vote
4
down vote
favorite
When using the command strace with the flag -T, I would like to know what is the time unit used to display time spent in syscalls? I assume it should be in seconds, but I am not quite sure and it seems to be omitted from the manual.
linux process system-calls strace syscalls
edited 16 mins ago
Goro
2,55141849
asked 48 mins ago
user311285
232
New contributor
user311285 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
4
down vote
favorite
up vote
4
down vote
favorite
When using the command strace with the flag -T, I would like to know what is the time unit used to display time spent in syscalls? I assume it should be in seconds, but I am not quite sure and it seems to be omitted from the manual.
linux process system-calls strace syscalls
edited 16 mins ago
Goro
2,55141849
asked 48 mins ago
user311285
232
New contributor
user311285 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
When using the command strace with the flag -T, I would like to know what is the time unit used to display time spent in syscalls? I assume it should be in seconds, but I am not quite sure and it seems to be omitted from the manual.
linux process system-calls strace syscalls
linux process system-calls strace syscalls
edited 16 mins ago
Goro
2,55141849
asked 48 mins ago
user311285
232
New contributor
user311285 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 16 mins ago
Goro
2,55141849
asked 48 mins ago
user311285
232
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user311285 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 16 mins ago
Goro
2,55141849
edited 16 mins ago
Goro
2,55141849
edited 16 mins ago
Goro
2,55141849
2,55141849
asked 48 mins ago
user311285
232
New contributor
user311285 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 48 mins ago
user311285
232
asked 48 mins ago
user311285
232
232
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user311285 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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3 Answers
3
active
oldest
votes
up vote
5
down vote
accepted
From the source code:
if (Tflag)
ts_sub(ts, ts, &tcp->etime);
tprintf(" <%ld.%06ld>",
(long) ts->tv_sec, (long) ts->tv_nsec / 1000);
This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.
answered 40 mins ago
Stephen Kitt
145k22318383
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up vote
4
down vote
If you run
strace -T sleep 2
you will see
nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>
so it looks like the time spent is in seconds.
answered 41 mins ago
meuh
29.9k11751
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up vote
4
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If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:
strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total
from strace's man
-c
Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.
answered 34 mins ago
Goro
2,55141849
add a comment |Â
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
From the source code:
if (Tflag)
ts_sub(ts, ts, &tcp->etime);
tprintf(" <%ld.%06ld>",
(long) ts->tv_sec, (long) ts->tv_nsec / 1000);
This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.
answered 40 mins ago
Stephen Kitt
145k22318383
add a comment |Â
up vote
5
down vote
accepted
From the source code:
if (Tflag)
ts_sub(ts, ts, &tcp->etime);
tprintf(" <%ld.%06ld>",
(long) ts->tv_sec, (long) ts->tv_nsec / 1000);
This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.
answered 40 mins ago
Stephen Kitt
145k22318383
add a comment |Â
up vote
5
down vote
accepted
up vote
5
down vote
accepted
From the source code:
if (Tflag)
ts_sub(ts, ts, &tcp->etime);
tprintf(" <%ld.%06ld>",
(long) ts->tv_sec, (long) ts->tv_nsec / 1000);
This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.
answered 40 mins ago
Stephen Kitt
145k22318383
From the source code:
if (Tflag)
ts_sub(ts, ts, &tcp->etime);
tprintf(" <%ld.%06ld>",
(long) ts->tv_sec, (long) ts->tv_nsec / 1000);
This means that the time is shown in seconds, with microseconds (calculated from the nanosecond value) after the decimal point.
answered 40 mins ago
Stephen Kitt
145k22318383
answered 40 mins ago
Stephen Kitt
145k22318383
answered 40 mins ago
Stephen Kitt
145k22318383
answered 40 mins ago
Stephen Kitt
145k22318383
145k22318383
add a comment |Â
add a comment |Â
up vote
4
down vote
If you run
strace -T sleep 2
you will see
nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>
so it looks like the time spent is in seconds.
answered 41 mins ago
meuh
29.9k11751
add a comment |Â
up vote
4
down vote
If you run
strace -T sleep 2
you will see
nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>
so it looks like the time spent is in seconds.
answered 41 mins ago
meuh
29.9k11751
add a comment |Â
up vote
4
down vote
up vote
4
down vote
If you run
strace -T sleep 2
you will see
nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>
so it looks like the time spent is in seconds.
answered 41 mins ago
meuh
29.9k11751
If you run
strace -T sleep 2
you will see
nanosleep(tv_sec=2, tv_nsec=0, NULL) = 0 <2.000230>
so it looks like the time spent is in seconds.
answered 41 mins ago
meuh
29.9k11751
answered 41 mins ago
meuh
29.9k11751
answered 41 mins ago
meuh
29.9k11751
answered 41 mins ago
meuh
29.9k11751
29.9k11751
add a comment |Â
add a comment |Â
up vote
4
down vote
If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:
strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total
from strace's man
-c
Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.
answered 34 mins ago
Goro
2,55141849
add a comment |Â
up vote
4
down vote
If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:
strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total
from strace's man
-c
Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.
answered 34 mins ago
Goro
2,55141849
add a comment |Â
up vote
4
down vote
up vote
4
down vote
If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:
strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total
from strace's man
-c
Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.
answered 34 mins ago
Goro
2,55141849
If you run the command strace using the "flag -c" it will show you a table and the time is reported in seconds:
strace -c -p 3569 # 3569 is PID
strace: Process 3569 attached
^Cstrace: Process 3569 detached
% time seconds usecs/call calls errors syscall
------ ----------- ----------- --------- --------- ----------------
99.73 0.016000 8 1971 poll
0.16 0.000025 0 509 75 futex
0.06 0.000010 0 1985 1966 recvmsg
0.06 0.000009 0 2336 mprotect
0.00 0.000000 0 478 read
0.00 0.000000 0 13 write
0.00 0.000000 0 29 mmap
0.00 0.000000 0 9 munmap
0.00 0.000000 0 18 writev
0.00 0.000000 0 351 madvise
0.00 0.000000 0 1 restart_syscall
------ ----------- ----------- --------- --------- ----------------
100.00 0.016044 7700 2041 total
from strace's man
-c
Count time, calls, and errors for each system call and report a
summary on program exit. On Linux, this attempts to show system time
(CPU time spent running in the kernel) independent of wall clock time.
If -c is used with -f or -F (below), only aggregate totals for all
traced processes are kept.
answered 34 mins ago
Goro
2,55141849
answered 34 mins ago
Goro
2,55141849
answered 34 mins ago
Goro
2,55141849
answered 34 mins ago
Goro
2,55141849
2,55141849
add a comment |Â
add a comment |Â
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