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Black hole slingshot?
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1
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I have read this question:
Gravitational slingshot of light using a black hole/massive object
But that is talking about photons around a black hole.
Now I am interested in macro objects. I would like to know if a spaceship can theoretically use a black hole for a slingshot.
Spaceships can even with nowadays technology do slingshots around Jupiter.
I was wondering if they can do theoretically the same slingshot around a black hole?
Question:
- Can a spaceship theoretically use a black hole for a slingshot?
general-relativity special-relativity black-holes
asked 3 hours ago
Ãrpád Szendrei
3,1221421
add a comment |Â
up vote
1
down vote
favorite
I have read this question:
Gravitational slingshot of light using a black hole/massive object
But that is talking about photons around a black hole.
Now I am interested in macro objects. I would like to know if a spaceship can theoretically use a black hole for a slingshot.
Spaceships can even with nowadays technology do slingshots around Jupiter.
I was wondering if they can do theoretically the same slingshot around a black hole?
Question:
- Can a spaceship theoretically use a black hole for a slingshot?
general-relativity special-relativity black-holes
asked 3 hours ago
Ãrpád Szendrei
3,1221421
Isn't this question essentially the same as all the questions asking what would happen if the sun (or any other object in space) suddenly became a black hole? At any significant distance, the gravitational fields would be unaffected.
– D. Halsey
3 hours ago
The only difference is the angle. With weaker gravity like stars and planets, the incoming object can be turned by up to 360 degrees, but no more than one full turn. With a black hole, the object can be turned by more than a full turn. I don't think this offers any advantage though. Also, keep in mind that the concept of the slingshot is mostly helpful in the gravity of a third body. For example to fly to the Sun, a probe should burn the fuel to first decelerate on the Earth orbit and then to accelerate toward the Sun. Or just use the Venus to turn the probe's direction and save the fuel.
– safesphere
3 hours ago
You also can jump into the future by doing a slingshot close enough to the event horizon. Although there is a danger of being spagnetified by the tide forces and also a danger to never return, if you slightly miscalculate the orbit. Not counting violent x-ray emissions of ionized gases falling into the black hole. If you hit Sagittarius $textA^*$ in the center of Milky Way head on, then, depending on your speed, you would have about a minute or less of personal time to live.
– safesphere
2 hours ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have read this question:
Gravitational slingshot of light using a black hole/massive object
But that is talking about photons around a black hole.
Now I am interested in macro objects. I would like to know if a spaceship can theoretically use a black hole for a slingshot.
Spaceships can even with nowadays technology do slingshots around Jupiter.
I was wondering if they can do theoretically the same slingshot around a black hole?
Question:
- Can a spaceship theoretically use a black hole for a slingshot?
general-relativity special-relativity black-holes
asked 3 hours ago
Ãrpád Szendrei
3,1221421
I have read this question:
Gravitational slingshot of light using a black hole/massive object
But that is talking about photons around a black hole.
Now I am interested in macro objects. I would like to know if a spaceship can theoretically use a black hole for a slingshot.
Spaceships can even with nowadays technology do slingshots around Jupiter.
I was wondering if they can do theoretically the same slingshot around a black hole?
Question:
- Can a spaceship theoretically use a black hole for a slingshot?
general-relativity special-relativity black-holes
general-relativity special-relativity black-holes
asked 3 hours ago
Ãrpád Szendrei
3,1221421
asked 3 hours ago
Ãrpád Szendrei
3,1221421
asked 3 hours ago
Ãrpád Szendrei
3,1221421
asked 3 hours ago
Ãrpád Szendrei
3,1221421
asked 3 hours ago
Ãrpád Szendrei
3,1221421
3,1221421
Isn't this question essentially the same as all the questions asking what would happen if the sun (or any other object in space) suddenly became a black hole? At any significant distance, the gravitational fields would be unaffected.
– D. Halsey
3 hours ago
The only difference is the angle. With weaker gravity like stars and planets, the incoming object can be turned by up to 360 degrees, but no more than one full turn. With a black hole, the object can be turned by more than a full turn. I don't think this offers any advantage though. Also, keep in mind that the concept of the slingshot is mostly helpful in the gravity of a third body. For example to fly to the Sun, a probe should burn the fuel to first decelerate on the Earth orbit and then to accelerate toward the Sun. Or just use the Venus to turn the probe's direction and save the fuel.
– safesphere
3 hours ago
You also can jump into the future by doing a slingshot close enough to the event horizon. Although there is a danger of being spagnetified by the tide forces and also a danger to never return, if you slightly miscalculate the orbit. Not counting violent x-ray emissions of ionized gases falling into the black hole. If you hit Sagittarius $textA^*$ in the center of Milky Way head on, then, depending on your speed, you would have about a minute or less of personal time to live.
– safesphere
2 hours ago
add a comment |Â
Isn't this question essentially the same as all the questions asking what would happen if the sun (or any other object in space) suddenly became a black hole? At any significant distance, the gravitational fields would be unaffected.
– D. Halsey
3 hours ago
The only difference is the angle. With weaker gravity like stars and planets, the incoming object can be turned by up to 360 degrees, but no more than one full turn. With a black hole, the object can be turned by more than a full turn. I don't think this offers any advantage though. Also, keep in mind that the concept of the slingshot is mostly helpful in the gravity of a third body. For example to fly to the Sun, a probe should burn the fuel to first decelerate on the Earth orbit and then to accelerate toward the Sun. Or just use the Venus to turn the probe's direction and save the fuel.
– safesphere
3 hours ago
You also can jump into the future by doing a slingshot close enough to the event horizon. Although there is a danger of being spagnetified by the tide forces and also a danger to never return, if you slightly miscalculate the orbit. Not counting violent x-ray emissions of ionized gases falling into the black hole. If you hit Sagittarius $textA^*$ in the center of Milky Way head on, then, depending on your speed, you would have about a minute or less of personal time to live.
– safesphere
2 hours ago
Isn't this question essentially the same as all the questions asking what would happen if the sun (or any other object in space) suddenly became a black hole? At any significant distance, the gravitational fields would be unaffected.
– D. Halsey
3 hours ago
Isn't this question essentially the same as all the questions asking what would happen if the sun (or any other object in space) suddenly became a black hole? At any significant distance, the gravitational fields would be unaffected.
– D. Halsey
3 hours ago
The only difference is the angle. With weaker gravity like stars and planets, the incoming object can be turned by up to 360 degrees, but no more than one full turn. With a black hole, the object can be turned by more than a full turn. I don't think this offers any advantage though. Also, keep in mind that the concept of the slingshot is mostly helpful in the gravity of a third body. For example to fly to the Sun, a probe should burn the fuel to first decelerate on the Earth orbit and then to accelerate toward the Sun. Or just use the Venus to turn the probe's direction and save the fuel.
– safesphere
3 hours ago
The only difference is the angle. With weaker gravity like stars and planets, the incoming object can be turned by up to 360 degrees, but no more than one full turn. With a black hole, the object can be turned by more than a full turn. I don't think this offers any advantage though. Also, keep in mind that the concept of the slingshot is mostly helpful in the gravity of a third body. For example to fly to the Sun, a probe should burn the fuel to first decelerate on the Earth orbit and then to accelerate toward the Sun. Or just use the Venus to turn the probe's direction and save the fuel.
– safesphere
3 hours ago
You also can jump into the future by doing a slingshot close enough to the event horizon. Although there is a danger of being spagnetified by the tide forces and also a danger to never return, if you slightly miscalculate the orbit. Not counting violent x-ray emissions of ionized gases falling into the black hole. If you hit Sagittarius $textA^*$ in the center of Milky Way head on, then, depending on your speed, you would have about a minute or less of personal time to live.
– safesphere
2 hours ago
You also can jump into the future by doing a slingshot close enough to the event horizon. Although there is a danger of being spagnetified by the tide forces and also a danger to never return, if you slightly miscalculate the orbit. Not counting violent x-ray emissions of ionized gases falling into the black hole. If you hit Sagittarius $textA^*$ in the center of Milky Way head on, then, depending on your speed, you would have about a minute or less of personal time to live.
– safesphere
2 hours ago
add a comment |Â
4 Answers
4
active
oldest
votes
up vote
2
down vote
The answer is trivially yes: if you can do a slingshot around, say, the Sun, you can do it around a black hole, because the far field of a BH is the same as the far field of any other massive object.
The interesting question is whether there are tricks you can do by passing rather close to the event horizon: I'm not sure but I suspect there are not any easy ones, or possibly any, because slingshots are not extracting energy from the object itself but rather from its translational kinetic energy (in Newtonian terms).
There is one thing you can do with a spinning BH, which is called the Penrose process. This is not a slingshot but involves throwing part of your mass into the BH and extract some of its rotational momentum.
answered 3 hours ago
tfb
13.7k42746
add a comment |Â
up vote
1
down vote
We have to distinguish between a passive gravity assist and an active one using the Oberth effect.
The question you linked to is about passive gravity assists. In this situation, the math is the same for a black hole as for any other object, because it's just a matter of velocity addition. If the speeds are relativistic, then you have to use special-relativistic velocity addition. In the simplest case, where the scattering is at 180 degrees, you just need one-dimensional velocity addition. You don't need any general relativity, basically because the spacetime is asymptotically flat and the initial and final states have the spacecraft at infinity. The only difference between the case of a black hole and that of any other body is that a black hole is able to effect, e.g., a 180-degree course change for a spacecraft that is moving at highly relativistic speeds, whereas for a less compact orbit that wouldn't work.
The Oberth effect with a black hole might in principle allow extremely impressive maneuvers. Nonrelativistically, the effect comes about because work goes like $Fcdot v$, and $v$ can be very large at periapsis. Relativistically, the details will be different, but we would basically expect an analogous effect, and it could be large because $v$ can be so large.
answered 1 hour ago
Ben Crowell
44.6k3146271
add a comment |Â
up vote
0
down vote
I'm giving you a short and simple answer:
As already mentioned by @D.Halsey in the comment above that, it does't matter whether your doing a slingshot around a black hole or a massive object like dead star or a hypothetical giant massive object, what matters is that how strong is the gravitational field of that object(spacetime curvature around the object) and the surrounding.
Assuming simplest Swarzschild's black hole:
If your spaceship can achieve enormous speeds then theoritically you can slingshot just like jupiter's case but there will be additional consequences of gravitational plus relativistic time dilations.
answered 2 hours ago
Aman pawar
306
add a comment |Â
up vote
0
down vote
For a non-spinning (or slowly spinning) black hole with zero (or minimal) charge, we can evaluate the trajectory using the Schwarzschild metric. A black hole can be used to slingshot around just like any massive object. But the Schwarzschild metric indicates 3 notes of caution:
There are no stable (circular) orbits below 3 times the Schwarzschild radius. Below that level, you would spiral into the black hole. Even light can only orbit at 1.5 times the Schwarzchild radius.
The Schwarzschild radius is measured as the circumference divided by 2 * pi, not the actual radial distance.
The tidal forces from a black hole might destroy your craft by stretching and squeezing, even if past 3 times the Schwarzschild radius for a smaller black hole.
All that to say, a black hole can be used to slingshot around, but don't get too close!
answered 1 hour ago
Stuart Van Horne
122
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
The answer is trivially yes: if you can do a slingshot around, say, the Sun, you can do it around a black hole, because the far field of a BH is the same as the far field of any other massive object.
The interesting question is whether there are tricks you can do by passing rather close to the event horizon: I'm not sure but I suspect there are not any easy ones, or possibly any, because slingshots are not extracting energy from the object itself but rather from its translational kinetic energy (in Newtonian terms).
There is one thing you can do with a spinning BH, which is called the Penrose process. This is not a slingshot but involves throwing part of your mass into the BH and extract some of its rotational momentum.
answered 3 hours ago
tfb
13.7k42746
add a comment |Â
up vote
2
down vote
The answer is trivially yes: if you can do a slingshot around, say, the Sun, you can do it around a black hole, because the far field of a BH is the same as the far field of any other massive object.
The interesting question is whether there are tricks you can do by passing rather close to the event horizon: I'm not sure but I suspect there are not any easy ones, or possibly any, because slingshots are not extracting energy from the object itself but rather from its translational kinetic energy (in Newtonian terms).
There is one thing you can do with a spinning BH, which is called the Penrose process. This is not a slingshot but involves throwing part of your mass into the BH and extract some of its rotational momentum.
answered 3 hours ago
tfb
13.7k42746
add a comment |Â
up vote
2
down vote
up vote
2
down vote
The answer is trivially yes: if you can do a slingshot around, say, the Sun, you can do it around a black hole, because the far field of a BH is the same as the far field of any other massive object.
The interesting question is whether there are tricks you can do by passing rather close to the event horizon: I'm not sure but I suspect there are not any easy ones, or possibly any, because slingshots are not extracting energy from the object itself but rather from its translational kinetic energy (in Newtonian terms).
There is one thing you can do with a spinning BH, which is called the Penrose process. This is not a slingshot but involves throwing part of your mass into the BH and extract some of its rotational momentum.
answered 3 hours ago
tfb
13.7k42746
The answer is trivially yes: if you can do a slingshot around, say, the Sun, you can do it around a black hole, because the far field of a BH is the same as the far field of any other massive object.
The interesting question is whether there are tricks you can do by passing rather close to the event horizon: I'm not sure but I suspect there are not any easy ones, or possibly any, because slingshots are not extracting energy from the object itself but rather from its translational kinetic energy (in Newtonian terms).
There is one thing you can do with a spinning BH, which is called the Penrose process. This is not a slingshot but involves throwing part of your mass into the BH and extract some of its rotational momentum.
answered 3 hours ago
tfb
13.7k42746
answered 3 hours ago
tfb
13.7k42746
answered 3 hours ago
tfb
13.7k42746
answered 3 hours ago
tfb
13.7k42746
13.7k42746
add a comment |Â
add a comment |Â
up vote
1
down vote
We have to distinguish between a passive gravity assist and an active one using the Oberth effect.
The question you linked to is about passive gravity assists. In this situation, the math is the same for a black hole as for any other object, because it's just a matter of velocity addition. If the speeds are relativistic, then you have to use special-relativistic velocity addition. In the simplest case, where the scattering is at 180 degrees, you just need one-dimensional velocity addition. You don't need any general relativity, basically because the spacetime is asymptotically flat and the initial and final states have the spacecraft at infinity. The only difference between the case of a black hole and that of any other body is that a black hole is able to effect, e.g., a 180-degree course change for a spacecraft that is moving at highly relativistic speeds, whereas for a less compact orbit that wouldn't work.
The Oberth effect with a black hole might in principle allow extremely impressive maneuvers. Nonrelativistically, the effect comes about because work goes like $Fcdot v$, and $v$ can be very large at periapsis. Relativistically, the details will be different, but we would basically expect an analogous effect, and it could be large because $v$ can be so large.
answered 1 hour ago
Ben Crowell
44.6k3146271
add a comment |Â
up vote
1
down vote
We have to distinguish between a passive gravity assist and an active one using the Oberth effect.
The question you linked to is about passive gravity assists. In this situation, the math is the same for a black hole as for any other object, because it's just a matter of velocity addition. If the speeds are relativistic, then you have to use special-relativistic velocity addition. In the simplest case, where the scattering is at 180 degrees, you just need one-dimensional velocity addition. You don't need any general relativity, basically because the spacetime is asymptotically flat and the initial and final states have the spacecraft at infinity. The only difference between the case of a black hole and that of any other body is that a black hole is able to effect, e.g., a 180-degree course change for a spacecraft that is moving at highly relativistic speeds, whereas for a less compact orbit that wouldn't work.
The Oberth effect with a black hole might in principle allow extremely impressive maneuvers. Nonrelativistically, the effect comes about because work goes like $Fcdot v$, and $v$ can be very large at periapsis. Relativistically, the details will be different, but we would basically expect an analogous effect, and it could be large because $v$ can be so large.
answered 1 hour ago
Ben Crowell
44.6k3146271
add a comment |Â
up vote
1
down vote
up vote
1
down vote
We have to distinguish between a passive gravity assist and an active one using the Oberth effect.
The question you linked to is about passive gravity assists. In this situation, the math is the same for a black hole as for any other object, because it's just a matter of velocity addition. If the speeds are relativistic, then you have to use special-relativistic velocity addition. In the simplest case, where the scattering is at 180 degrees, you just need one-dimensional velocity addition. You don't need any general relativity, basically because the spacetime is asymptotically flat and the initial and final states have the spacecraft at infinity. The only difference between the case of a black hole and that of any other body is that a black hole is able to effect, e.g., a 180-degree course change for a spacecraft that is moving at highly relativistic speeds, whereas for a less compact orbit that wouldn't work.
The Oberth effect with a black hole might in principle allow extremely impressive maneuvers. Nonrelativistically, the effect comes about because work goes like $Fcdot v$, and $v$ can be very large at periapsis. Relativistically, the details will be different, but we would basically expect an analogous effect, and it could be large because $v$ can be so large.
answered 1 hour ago
Ben Crowell
44.6k3146271
We have to distinguish between a passive gravity assist and an active one using the Oberth effect.
The question you linked to is about passive gravity assists. In this situation, the math is the same for a black hole as for any other object, because it's just a matter of velocity addition. If the speeds are relativistic, then you have to use special-relativistic velocity addition. In the simplest case, where the scattering is at 180 degrees, you just need one-dimensional velocity addition. You don't need any general relativity, basically because the spacetime is asymptotically flat and the initial and final states have the spacecraft at infinity. The only difference between the case of a black hole and that of any other body is that a black hole is able to effect, e.g., a 180-degree course change for a spacecraft that is moving at highly relativistic speeds, whereas for a less compact orbit that wouldn't work.
The Oberth effect with a black hole might in principle allow extremely impressive maneuvers. Nonrelativistically, the effect comes about because work goes like $Fcdot v$, and $v$ can be very large at periapsis. Relativistically, the details will be different, but we would basically expect an analogous effect, and it could be large because $v$ can be so large.
answered 1 hour ago
Ben Crowell
44.6k3146271
answered 1 hour ago
Ben Crowell
44.6k3146271
answered 1 hour ago
Ben Crowell
44.6k3146271
answered 1 hour ago
Ben Crowell
44.6k3146271
44.6k3146271
add a comment |Â
add a comment |Â
up vote
0
down vote
I'm giving you a short and simple answer:
As already mentioned by @D.Halsey in the comment above that, it does't matter whether your doing a slingshot around a black hole or a massive object like dead star or a hypothetical giant massive object, what matters is that how strong is the gravitational field of that object(spacetime curvature around the object) and the surrounding.
Assuming simplest Swarzschild's black hole:
If your spaceship can achieve enormous speeds then theoritically you can slingshot just like jupiter's case but there will be additional consequences of gravitational plus relativistic time dilations.
answered 2 hours ago
Aman pawar
306
add a comment |Â
up vote
0
down vote
I'm giving you a short and simple answer:
As already mentioned by @D.Halsey in the comment above that, it does't matter whether your doing a slingshot around a black hole or a massive object like dead star or a hypothetical giant massive object, what matters is that how strong is the gravitational field of that object(spacetime curvature around the object) and the surrounding.
Assuming simplest Swarzschild's black hole:
If your spaceship can achieve enormous speeds then theoritically you can slingshot just like jupiter's case but there will be additional consequences of gravitational plus relativistic time dilations.
answered 2 hours ago
Aman pawar
306
add a comment |Â
up vote
0
down vote
up vote
0
down vote
I'm giving you a short and simple answer:
As already mentioned by @D.Halsey in the comment above that, it does't matter whether your doing a slingshot around a black hole or a massive object like dead star or a hypothetical giant massive object, what matters is that how strong is the gravitational field of that object(spacetime curvature around the object) and the surrounding.
Assuming simplest Swarzschild's black hole:
If your spaceship can achieve enormous speeds then theoritically you can slingshot just like jupiter's case but there will be additional consequences of gravitational plus relativistic time dilations.
answered 2 hours ago
Aman pawar
306
I'm giving you a short and simple answer:
As already mentioned by @D.Halsey in the comment above that, it does't matter whether your doing a slingshot around a black hole or a massive object like dead star or a hypothetical giant massive object, what matters is that how strong is the gravitational field of that object(spacetime curvature around the object) and the surrounding.
Assuming simplest Swarzschild's black hole:
If your spaceship can achieve enormous speeds then theoritically you can slingshot just like jupiter's case but there will be additional consequences of gravitational plus relativistic time dilations.
answered 2 hours ago
Aman pawar
306
answered 2 hours ago
Aman pawar
306
answered 2 hours ago
Aman pawar
306
answered 2 hours ago
Aman pawar
306
306
add a comment |Â
add a comment |Â
up vote
0
down vote
For a non-spinning (or slowly spinning) black hole with zero (or minimal) charge, we can evaluate the trajectory using the Schwarzschild metric. A black hole can be used to slingshot around just like any massive object. But the Schwarzschild metric indicates 3 notes of caution:
There are no stable (circular) orbits below 3 times the Schwarzschild radius. Below that level, you would spiral into the black hole. Even light can only orbit at 1.5 times the Schwarzchild radius.
The Schwarzschild radius is measured as the circumference divided by 2 * pi, not the actual radial distance.
The tidal forces from a black hole might destroy your craft by stretching and squeezing, even if past 3 times the Schwarzschild radius for a smaller black hole.
All that to say, a black hole can be used to slingshot around, but don't get too close!
answered 1 hour ago
Stuart Van Horne
122
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
0
down vote
For a non-spinning (or slowly spinning) black hole with zero (or minimal) charge, we can evaluate the trajectory using the Schwarzschild metric. A black hole can be used to slingshot around just like any massive object. But the Schwarzschild metric indicates 3 notes of caution:
There are no stable (circular) orbits below 3 times the Schwarzschild radius. Below that level, you would spiral into the black hole. Even light can only orbit at 1.5 times the Schwarzchild radius.
The Schwarzschild radius is measured as the circumference divided by 2 * pi, not the actual radial distance.
The tidal forces from a black hole might destroy your craft by stretching and squeezing, even if past 3 times the Schwarzschild radius for a smaller black hole.
All that to say, a black hole can be used to slingshot around, but don't get too close!
answered 1 hour ago
Stuart Van Horne
122
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
For a non-spinning (or slowly spinning) black hole with zero (or minimal) charge, we can evaluate the trajectory using the Schwarzschild metric. A black hole can be used to slingshot around just like any massive object. But the Schwarzschild metric indicates 3 notes of caution:
There are no stable (circular) orbits below 3 times the Schwarzschild radius. Below that level, you would spiral into the black hole. Even light can only orbit at 1.5 times the Schwarzchild radius.
The Schwarzschild radius is measured as the circumference divided by 2 * pi, not the actual radial distance.
The tidal forces from a black hole might destroy your craft by stretching and squeezing, even if past 3 times the Schwarzschild radius for a smaller black hole.
All that to say, a black hole can be used to slingshot around, but don't get too close!
answered 1 hour ago
Stuart Van Horne
122
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
For a non-spinning (or slowly spinning) black hole with zero (or minimal) charge, we can evaluate the trajectory using the Schwarzschild metric. A black hole can be used to slingshot around just like any massive object. But the Schwarzschild metric indicates 3 notes of caution:
There are no stable (circular) orbits below 3 times the Schwarzschild radius. Below that level, you would spiral into the black hole. Even light can only orbit at 1.5 times the Schwarzchild radius.
The Schwarzschild radius is measured as the circumference divided by 2 * pi, not the actual radial distance.
The tidal forces from a black hole might destroy your craft by stretching and squeezing, even if past 3 times the Schwarzschild radius for a smaller black hole.
All that to say, a black hole can be used to slingshot around, but don't get too close!
answered 1 hour ago
Stuart Van Horne
122
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 1 hour ago
Stuart Van Horne
122
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 1 hour ago
Stuart Van Horne
122
answered 1 hour ago
Stuart Van Horne
122
122
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Stuart Van Horne is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
add a comment |Â
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Isn't this question essentially the same as all the questions asking what would happen if the sun (or any other object in space) suddenly became a black hole? At any significant distance, the gravitational fields would be unaffected.
– D. Halsey
3 hours ago
The only difference is the angle. With weaker gravity like stars and planets, the incoming object can be turned by up to 360 degrees, but no more than one full turn. With a black hole, the object can be turned by more than a full turn. I don't think this offers any advantage though. Also, keep in mind that the concept of the slingshot is mostly helpful in the gravity of a third body. For example to fly to the Sun, a probe should burn the fuel to first decelerate on the Earth orbit and then to accelerate toward the Sun. Or just use the Venus to turn the probe's direction and save the fuel.
– safesphere
3 hours ago
You also can jump into the future by doing a slingshot close enough to the event horizon. Although there is a danger of being spagnetified by the tide forces and also a danger to never return, if you slightly miscalculate the orbit. Not counting violent x-ray emissions of ionized gases falling into the black hole. If you hit Sagittarius $textA^*$ in the center of Milky Way head on, then, depending on your speed, you would have about a minute or less of personal time to live.
– safesphere
2 hours ago