Replacing Strings at specific locations

Clash Royale CLAN TAG#URR8PPP

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1
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text = "Donc", "j'obtiens", "<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
[Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", 
"<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", "Donc en particulier", 
"ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
<i>c</i>"

Now my question is:

1. How can I get the position of in the list of every object that starts with <i>?




2. How can I replace the <i> at the start of that object and the </i> at the end of that object by another string ?

By "object" I really mean a list object: for instance, I don't want the <i> and </i> to be replaced in "ça veut dire que si je multiplie par <i>c</i>", since this object of the list does not start with an <i>.

EDIT: To clear any confusion, here is how the text could look like afterwards:

"Donc", "j'obtiens", "REPLACE([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
 [Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", 
 "REPLACEaᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
 aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", "Donc en particulier", 
 "ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
 <i>c</i>"

string-manipulation

share|improve this question

edited 9 mins ago

asked 27 mins ago

james

639418

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Could try something like Position[text, s_String /; StringMatchQ[s, "<i>*</i>"]], but that won't catch the last two items with italics tags since they don't actually "start with <i>", as the criterion you mentioned.
  – J. M. is computer-less♦
  20 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less That's actually perfect ! Maybe I was not clear enough, but I don't want to catch "<i>" where the sentence does not start with "<i>". Can you post it as an answer ? Then I can accept it, if you also know how to replace the "<i>" and "</i>" in the found sentences.
  – james
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  If just for replacement, it seems no need to get their positions.
  – Î‘λέξανδρος Ζεγγ
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @ΑλέξανδροςΖεγγ Okay, interesting. How would you do it then ?
  – james
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  You did not mention what kind of replacement you wanted to do. Is it derived from the matching string, or something completely different?
  – J. M. is computer-less♦
  12 mins ago
  

  
  
  
  

 | 
show 2 more comments

up vote
1
down vote

favorite

text = "Donc", "j'obtiens", "<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
[Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", 
"<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", "Donc en particulier", 
"ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
<i>c</i>"

Now my question is:

1. How can I get the position of in the list of every object that starts with <i>?




2. How can I replace the <i> at the start of that object and the </i> at the end of that object by another string ?

By "object" I really mean a list object: for instance, I don't want the <i> and </i> to be replaced in "ça veut dire que si je multiplie par <i>c</i>", since this object of the list does not start with an <i>.

EDIT: To clear any confusion, here is how the text could look like afterwards:

"Donc", "j'obtiens", "REPLACE([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
 [Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", 
 "REPLACEaᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
 aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", "Donc en particulier", 
 "ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
 <i>c</i>"

string-manipulation

share|improve this question

edited 9 mins ago

asked 27 mins ago

james

639418

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Could try something like Position[text, s_String /; StringMatchQ[s, "<i>*</i>"]], but that won't catch the last two items with italics tags since they don't actually "start with <i>", as the criterion you mentioned.
  – J. M. is computer-less♦
  20 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less That's actually perfect ! Maybe I was not clear enough, but I don't want to catch "<i>" where the sentence does not start with "<i>". Can you post it as an answer ? Then I can accept it, if you also know how to replace the "<i>" and "</i>" in the found sentences.
  – james
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  If just for replacement, it seems no need to get their positions.
  – Î‘λέξανδρος Ζεγγ
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @ΑλέξανδροςΖεγγ Okay, interesting. How would you do it then ?
  – james
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  You did not mention what kind of replacement you wanted to do. Is it derived from the matching string, or something completely different?
  – J. M. is computer-less♦
  12 mins ago
  

  
  
  
  

 | 
show 2 more comments

up vote
1
down vote

favorite

up vote
1
down vote

favorite

text = "Donc", "j'obtiens", "<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
[Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", 
"<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", "Donc en particulier", 
"ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
<i>c</i>"

Now my question is:

1. How can I get the position of in the list of every object that starts with <i>?




2. How can I replace the <i> at the start of that object and the </i> at the end of that object by another string ?

By "object" I really mean a list object: for instance, I don't want the <i> and </i> to be replaced in "ça veut dire que si je multiplie par <i>c</i>", since this object of the list does not start with an <i>.

EDIT: To clear any confusion, here is how the text could look like afterwards:

"Donc", "j'obtiens", "REPLACE([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
 [Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", 
 "REPLACEaᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
 aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", "Donc en particulier", 
 "ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
 <i>c</i>"

string-manipulation

share|improve this question

edited 9 mins ago

asked 27 mins ago

james

639418

text = "Donc", "j'obtiens", "<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
[Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", 
"<i>aᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.</i>", "Donc en particulier", 
"ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
<i>c</i>"

Now my question is:

1. How can I get the position of in the list of every object that starts with <i>?




2. How can I replace the <i> at the start of that object and the </i> at the end of that object by another string ?

By "object" I really mean a list object: for instance, I don't want the <i> and </i> to be replaced in "ça veut dire que si je multiplie par <i>c</i>", since this object of the list does not start with an <i>.

EDIT: To clear any confusion, here is how the text could look like afterwards:

"Donc", "j'obtiens", "REPLACE([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - 
 [Beta]₂) + ... + aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", 
 "REPLACEaᵢ₁([Alpha]₁ - [Beta]₁) + aᵢ₂([Alpha]₂ - [Beta]₂) + ... + 
 aₙ₁([Alpha]ₙ - [Beta]ₙ) = bᵢ - bᵢ = 0.REPLACE", "Donc en particulier", 
 "ça veut dire que si je multiplie par <i>c</i>", "pour tout nombre réel 
 <i>c</i>"

string-manipulation

string-manipulation

share|improve this question

edited 9 mins ago

asked 27 mins ago

james

639418

share|improve this question

edited 9 mins ago

asked 27 mins ago

james

639418

share|improve this question

share|improve this question

edited 9 mins ago

edited 9 mins ago

edited 9 mins ago

asked 27 mins ago

james

639418

asked 27 mins ago

james

639418

asked 27 mins ago

james

639418

639418

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Could try something like Position[text, s_String /; StringMatchQ[s, "<i>*</i>"]], but that won't catch the last two items with italics tags since they don't actually "start with <i>", as the criterion you mentioned.
  – J. M. is computer-less♦
  20 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less That's actually perfect ! Maybe I was not clear enough, but I don't want to catch "<i>" where the sentence does not start with "<i>". Can you post it as an answer ? Then I can accept it, if you also know how to replace the "<i>" and "</i>" in the found sentences.
  – james
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  If just for replacement, it seems no need to get their positions.
  – Î‘λέξανδρος Ζεγγ
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @ΑλέξανδροςΖεγγ Okay, interesting. How would you do it then ?
  – james
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  You did not mention what kind of replacement you wanted to do. Is it derived from the matching string, or something completely different?
  – J. M. is computer-less♦
  12 mins ago
  

  
  
  
  

 | 
show 2 more comments

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Could try something like Position[text, s_String /; StringMatchQ[s, "<i>*</i>"]], but that won't catch the last two items with italics tags since they don't actually "start with <i>", as the criterion you mentioned.
  – J. M. is computer-less♦
  20 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less That's actually perfect ! Maybe I was not clear enough, but I don't want to catch "<i>" where the sentence does not start with "<i>". Can you post it as an answer ? Then I can accept it, if you also know how to replace the "<i>" and "</i>" in the found sentences.
  – james
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  If just for replacement, it seems no need to get their positions.
  – Î‘λέξανδρος Ζεγγ
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @ΑλέξανδροςΖεγγ Okay, interesting. How would you do it then ?
  – james
  15 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  You did not mention what kind of replacement you wanted to do. Is it derived from the matching string, or something completely different?
  – J. M. is computer-less♦
  12 mins ago
  

  
  
  
  

Could try something like Position[text, s_String /; StringMatchQ[s, "<i>*</i>"]], but that won't catch the last two items with italics tags since they don't actually "start with <i>", as the criterion you mentioned.
– J. M. is computer-less♦
20 mins ago

Could try something like Position[text, s_String /; StringMatchQ[s, "<i>*</i>"]], but that won't catch the last two items with italics tags since they don't actually "start with <i>", as the criterion you mentioned.
– J. M. is computer-less♦
20 mins ago

@J.M.iscomputer-less That's actually perfect ! Maybe I was not clear enough, but I don't want to catch "<i>" where the sentence does not start with "<i>". Can you post it as an answer ? Then I can accept it, if you also know how to replace the "<i>" and "</i>" in the found sentences.
– james
16 mins ago

@J.M.iscomputer-less That's actually perfect ! Maybe I was not clear enough, but I don't want to catch "<i>" where the sentence does not start with "<i>". Can you post it as an answer ? Then I can accept it, if you also know how to replace the "<i>" and "</i>" in the found sentences.
– james
16 mins ago

If just for replacement, it seems no need to get their positions.
– Î‘λέξανδρος Ζεγγ
15 mins ago

If just for replacement, it seems no need to get their positions.
– Î‘λέξανδρος Ζεγγ
15 mins ago

@ΑλέξανδροςΖεγγ Okay, interesting. How would you do it then ?
– james
15 mins ago

@ΑλέξανδροςΖεγγ Okay, interesting. How would you do it then ?
– james
15 mins ago

You did not mention what kind of replacement you wanted to do. Is it derived from the matching string, or something completely different?
– J. M. is computer-less♦
12 mins ago

You did not mention what kind of replacement you wanted to do. Is it derived from the matching string, or something completely different?
– J. M. is computer-less♦
12 mins ago

 | 
show 2 more comments

3 Answers
3

active

oldest

votes

up vote
2
down vote



accepted

Cases[text, _String?(StringMatchQ["<i>*"]), Infinity]

"aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.", "aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0."

StringReplace[text, 
 StartOfString ~~ "<i>" ~~ s__ ~~ "</i>" ~~ EndOfString :> "REPLACE" <> s <> "REPLACE"]

"Donc", "j'obtiens", "REPLACEaᵢ₁(α₁ - β₁) +
aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ
= 0.REPLACE", "REPLACEaᵢ₁(α₁ - β₁) + aᵢ₂(α₂ -
β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.REPLACE",
"Donc en particulier", "ça veut dire que si je multiplie par
c", "pour tout nombre réel c"

share|improve this answer

edited 8 mins ago

answered 13 mins ago

kglr

165k8188388

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot ! This works nicely and is comprehensible.
  – james
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, my pleasure. Thank you for the accept.
  – kglr
  3 mins ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

For replacement, (e.g., below is just to delete them)

StringReplace[text, RegularExpression["^<i>(.*)</i>$"] -> "$1"]

The key point is to locate the (sub)strings (but not by knowing the positions explicitly), having achieved which, one can do whatever one wants to them :).

share|improve this answer

edited 3 mins ago

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces the "<i>" and "<i/>" but kills the rest of the text.
  – james
  10 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james StringReplace is better here, which leaves strings unmatched untouched. I modified it.
  – Î‘λέξανδρος Ζεγγ
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your answer !
  – james
  3 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

StringReplace["this is the <i>old text</i>" , 
 "<i>" ~~ ___ ~~ "</i>" -> "new text"]

share

answered 8 mins ago

LouisB

4,1941616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces everything in between "<i>" and "<i/>". Please have a look at my example in the question.
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  That's what I was asking you about earlier @james. So, what you want is a derived string and not an independent string. That's because replacing <i>stuff</i> with stuff and replacing <i>stuff</i> with something needs different approaches.
  – J. M. is computer-less♦
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less I see. I guess I miscommunicated my answer. Thank you for the information.
  – james
  2 mins ago
  

  
  
  
  

add a comment | 

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
2
down vote



accepted

Cases[text, _String?(StringMatchQ["<i>*"]), Infinity]

"aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.", "aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0."

StringReplace[text, 
 StartOfString ~~ "<i>" ~~ s__ ~~ "</i>" ~~ EndOfString :> "REPLACE" <> s <> "REPLACE"]

"Donc", "j'obtiens", "REPLACEaᵢ₁(α₁ - β₁) +
aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ
= 0.REPLACE", "REPLACEaᵢ₁(α₁ - β₁) + aᵢ₂(α₂ -
β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.REPLACE",
"Donc en particulier", "ça veut dire que si je multiplie par
c", "pour tout nombre réel c"

share|improve this answer

edited 8 mins ago

answered 13 mins ago

kglr

165k8188388

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot ! This works nicely and is comprehensible.
  – james
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, my pleasure. Thank you for the accept.
  – kglr
  3 mins ago
  

  
  
  
  

add a comment | 

up vote
2
down vote



accepted

Cases[text, _String?(StringMatchQ["<i>*"]), Infinity]

"aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.", "aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0."

StringReplace[text, 
 StartOfString ~~ "<i>" ~~ s__ ~~ "</i>" ~~ EndOfString :> "REPLACE" <> s <> "REPLACE"]

"Donc", "j'obtiens", "REPLACEaᵢ₁(α₁ - β₁) +
aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ
= 0.REPLACE", "REPLACEaᵢ₁(α₁ - β₁) + aᵢ₂(α₂ -
β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.REPLACE",
"Donc en particulier", "ça veut dire que si je multiplie par
c", "pour tout nombre réel c"

share|improve this answer

edited 8 mins ago

answered 13 mins ago

kglr

165k8188388

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot ! This works nicely and is comprehensible.
  – james
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, my pleasure. Thank you for the accept.
  – kglr
  3 mins ago
  

  
  
  
  

add a comment | 

up vote
2
down vote



accepted

up vote
2
down vote



accepted

Cases[text, _String?(StringMatchQ["<i>*"]), Infinity]

"aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.", "aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0."

StringReplace[text, 
 StartOfString ~~ "<i>" ~~ s__ ~~ "</i>" ~~ EndOfString :> "REPLACE" <> s <> "REPLACE"]

"Donc", "j'obtiens", "REPLACEaᵢ₁(α₁ - β₁) +
aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ
= 0.REPLACE", "REPLACEaᵢ₁(α₁ - β₁) + aᵢ₂(α₂ -
β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.REPLACE",
"Donc en particulier", "ça veut dire que si je multiplie par
c", "pour tout nombre réel c"

share|improve this answer

edited 8 mins ago

answered 13 mins ago

kglr

165k8188388

Cases[text, _String?(StringMatchQ["<i>*"]), Infinity]

"aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.", "aᵢ₁(α₁ - β₁) + aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0."

StringReplace[text, 
 StartOfString ~~ "<i>" ~~ s__ ~~ "</i>" ~~ EndOfString :> "REPLACE" <> s <> "REPLACE"]

"Donc", "j'obtiens", "REPLACEaᵢ₁(α₁ - β₁) +
aᵢ₂(α₂ - β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ
= 0.REPLACE", "REPLACEaᵢ₁(α₁ - β₁) + aᵢ₂(α₂ -
β₂) + ... + aₙ₁(αₙ - βₙ) = bᵢ - bᵢ = 0.REPLACE",
"Donc en particulier", "ça veut dire que si je multiplie par
c", "pour tout nombre réel c"

share|improve this answer

edited 8 mins ago

answered 13 mins ago

kglr

165k8188388

share|improve this answer

share|improve this answer

edited 8 mins ago

edited 8 mins ago

edited 8 mins ago

answered 13 mins ago

kglr

165k8188388

answered 13 mins ago

kglr

165k8188388

answered 13 mins ago

kglr

165k8188388

165k8188388

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot ! This works nicely and is comprehensible.
  – james
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, my pleasure. Thank you for the accept.
  – kglr
  3 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot ! This works nicely and is comprehensible.
  – james
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, my pleasure. Thank you for the accept.
  – kglr
  3 mins ago
  

  
  
  
  

Thanks a lot ! This works nicely and is comprehensible.
– james
4 mins ago

Thanks a lot ! This works nicely and is comprehensible.
– james
4 mins ago

@james, my pleasure. Thank you for the accept.
– kglr
3 mins ago

@james, my pleasure. Thank you for the accept.
– kglr
3 mins ago

add a comment | 

up vote
2
down vote

For replacement, (e.g., below is just to delete them)

StringReplace[text, RegularExpression["^<i>(.*)</i>$"] -> "$1"]

The key point is to locate the (sub)strings (but not by knowing the positions explicitly), having achieved which, one can do whatever one wants to them :).

share|improve this answer

edited 3 mins ago

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces the "<i>" and "<i/>" but kills the rest of the text.
  – james
  10 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james StringReplace is better here, which leaves strings unmatched untouched. I modified it.
  – Î‘λέξανδρος Ζεγγ
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your answer !
  – james
  3 mins ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

For replacement, (e.g., below is just to delete them)

StringReplace[text, RegularExpression["^<i>(.*)</i>$"] -> "$1"]

The key point is to locate the (sub)strings (but not by knowing the positions explicitly), having achieved which, one can do whatever one wants to them :).

share|improve this answer

edited 3 mins ago

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces the "<i>" and "<i/>" but kills the rest of the text.
  – james
  10 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james StringReplace is better here, which leaves strings unmatched untouched. I modified it.
  – Î‘λέξανδρος Ζεγγ
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your answer !
  – james
  3 mins ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

up vote
2
down vote

For replacement, (e.g., below is just to delete them)

StringReplace[text, RegularExpression["^<i>(.*)</i>$"] -> "$1"]

The key point is to locate the (sub)strings (but not by knowing the positions explicitly), having achieved which, one can do whatever one wants to them :).

share|improve this answer

edited 3 mins ago

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

For replacement, (e.g., below is just to delete them)

StringReplace[text, RegularExpression["^<i>(.*)</i>$"] -> "$1"]

The key point is to locate the (sub)strings (but not by knowing the positions explicitly), having achieved which, one can do whatever one wants to them :).

share|improve this answer

edited 3 mins ago

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

share|improve this answer

share|improve this answer

edited 3 mins ago

edited 3 mins ago

edited 3 mins ago

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

answered 13 mins ago

Αλέξανδρος Ζεγγ

2,5241826

2,5241826

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces the "<i>" and "<i/>" but kills the rest of the text.
  – james
  10 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james StringReplace is better here, which leaves strings unmatched untouched. I modified it.
  – Î‘λέξανδρος Ζεγγ
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your answer !
  – james
  3 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces the "<i>" and "<i/>" but kills the rest of the text.
  – james
  10 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james StringReplace is better here, which leaves strings unmatched untouched. I modified it.
  – Î‘λέξανδρος Ζεγγ
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your answer !
  – james
  3 mins ago
  

  
  
  
  

This replaces the "<i>" and "<i/>" but kills the rest of the text.
– james
10 mins ago

This replaces the "<i>" and "<i/>" but kills the rest of the text.
– james
10 mins ago

@james StringReplace is better here, which leaves strings unmatched untouched. I modified it.
– Î‘λέξανδρος Ζεγγ
9 mins ago

@james StringReplace is better here, which leaves strings unmatched untouched. I modified it.
– Î‘λέξανδρος Ζεγγ
9 mins ago

Thank you very much for your answer !
– james
3 mins ago

Thank you very much for your answer !
– james
3 mins ago

add a comment | 

up vote
1
down vote

StringReplace["this is the <i>old text</i>" , 
 "<i>" ~~ ___ ~~ "</i>" -> "new text"]

share

answered 8 mins ago

LouisB

4,1941616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces everything in between "<i>" and "<i/>". Please have a look at my example in the question.
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  That's what I was asking you about earlier @james. So, what you want is a derived string and not an independent string. That's because replacing <i>stuff</i> with stuff and replacing <i>stuff</i> with something needs different approaches.
  – J. M. is computer-less♦
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less I see. I guess I miscommunicated my answer. Thank you for the information.
  – james
  2 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

StringReplace["this is the <i>old text</i>" , 
 "<i>" ~~ ___ ~~ "</i>" -> "new text"]

share

answered 8 mins ago

LouisB

4,1941616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces everything in between "<i>" and "<i/>". Please have a look at my example in the question.
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  That's what I was asking you about earlier @james. So, what you want is a derived string and not an independent string. That's because replacing <i>stuff</i> with stuff and replacing <i>stuff</i> with something needs different approaches.
  – J. M. is computer-less♦
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less I see. I guess I miscommunicated my answer. Thank you for the information.
  – james
  2 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

up vote
1
down vote

StringReplace["this is the <i>old text</i>" , 
 "<i>" ~~ ___ ~~ "</i>" -> "new text"]

share

answered 8 mins ago

LouisB

4,1941616

StringReplace["this is the <i>old text</i>" , 
 "<i>" ~~ ___ ~~ "</i>" -> "new text"]

share

answered 8 mins ago

LouisB

4,1941616

share

share

answered 8 mins ago

LouisB

4,1941616

answered 8 mins ago

LouisB

4,1941616

answered 8 mins ago

LouisB

4,1941616

4,1941616

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces everything in between "<i>" and "<i/>". Please have a look at my example in the question.
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  That's what I was asking you about earlier @james. So, what you want is a derived string and not an independent string. That's because replacing <i>stuff</i> with stuff and replacing <i>stuff</i> with something needs different approaches.
  – J. M. is computer-less♦
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less I see. I guess I miscommunicated my answer. Thank you for the information.
  – james
  2 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This replaces everything in between "<i>" and "<i/>". Please have a look at my example in the question.
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  That's what I was asking you about earlier @james. So, what you want is a derived string and not an independent string. That's because replacing <i>stuff</i> with stuff and replacing <i>stuff</i> with something needs different approaches.
  – J. M. is computer-less♦
  4 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @J.M.iscomputer-less I see. I guess I miscommunicated my answer. Thank you for the information.
  – james
  2 mins ago
  

  
  
  
  

This replaces everything in between "<i>" and "<i/>". Please have a look at my example in the question.
– james
6 mins ago

This replaces everything in between "<i>" and "<i/>". Please have a look at my example in the question.
– james
6 mins ago

That's what I was asking you about earlier @james. So, what you want is a derived string and not an independent string. That's because replacing <i>stuff</i> with stuff and replacing <i>stuff</i> with something needs different approaches.
– J. M. is computer-less♦
4 mins ago

That's what I was asking you about earlier @james. So, what you want is a derived string and not an independent string. That's because replacing <i>stuff</i> with stuff and replacing <i>stuff</i> with something needs different approaches.
– J. M. is computer-less♦
4 mins ago

@J.M.iscomputer-less I see. I guess I miscommunicated my answer. Thank you for the information.
– james
2 mins ago

@J.M.iscomputer-less I see. I guess I miscommunicated my answer. Thank you for the information.
– james
2 mins ago

add a comment | 

 

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