how can i move lines in mulitple text files?

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0
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Hi assume I have a files that look like:

x
x
x
A
B
C
1
2
3
D
E
F
x
x
x

and what need the files to look like:

x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

I know I could do this with a few sed -i s/search/replace/g lines but am wondering if there's a better, easier way to move x number of rows by y numbers in either direction?

edited 37 mins ago

Kusalananda

110k14213337

asked 1 hour ago

cerr

66382239

add a commentÂ |Â

up vote
0
down vote

favorite

Hi assume I have a files that look like:

x
x
x
A
B
C
1
2
3
D
E
F
x
x
x

and what need the files to look like:

x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

I know I could do this with a few sed -i s/search/replace/g lines but am wondering if there's a better, easier way to move x number of rows by y numbers in either direction?

edited 37 mins ago

Kusalananda

110k14213337

asked 1 hour ago

cerr

66382239

add a commentÂ |Â

up vote
0
down vote

favorite

Hi assume I have a files that look like:

x
x
x
A
B
C
1
2
3
D
E
F
x
x
x

and what need the files to look like:

x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

I know I could do this with a few sed -i s/search/replace/g lines but am wondering if there's a better, easier way to move x number of rows by y numbers in either direction?

edited 37 mins ago

Kusalananda

110k14213337

asked 1 hour ago

cerr

66382239

Hi assume I have a files that look like:

x
x
x
A
B
C
1
2
3
D
E
F
x
x
x

and what need the files to look like:

x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

I know I could do this with a few sed -i s/search/replace/g lines but am wondering if there's a better, easier way to move x number of rows by y numbers in either direction?

text-processing

edited 37 mins ago

Kusalananda

110k14213337

asked 1 hour ago

cerr

66382239

edited 37 mins ago

Kusalananda

110k14213337

asked 1 hour ago

cerr

66382239

edited 37 mins ago

Kusalananda

110k14213337

edited 37 mins ago

Kusalananda

110k14213337

edited 37 mins ago

Kusalananda

110k14213337

asked 1 hour ago

cerr

66382239

asked 1 hour ago

cerr

66382239

asked 1 hour ago

cerr

66382239

add a commentÂ |Â

2 Answers
2

active

oldest

votes

up vote
0
down vote

accepted

echo -e '7,9m12n,p' | ed -s file.txt

answered 51 mins ago

ColinSeligSmith

24415

1

this solution works only under bash, it doesn't work under other environments
â€“Â TNT
28 mins ago

add a commentÂ |Â

up vote
6
down vote

Using sed (moving rows down, because that's easiest with stream editors):

$ sed '7,9H;d;; 12G;s/n//;' <file
x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

You may read the sed script as "move lines 7 through to 9 to after line 12".

The script annotated:

7,9 # These are the lines we'd like to move
 H; # Append them to the hold space (separated by newlines)
 d; # Delete from pattern space, start next cycle

12 # This is where we'd like to move those lines
 G; # Append the hold space
 s/n//; # Remove the newline that the above command inserted

 # (implicit print)

Since lines may be addressed by regular expressions (not just line numbers), the following would work too (on this particular data):

sed '/^1/,/^3/H;d;; /^F/G;s/n//;' <file

I.e., "move the lines from the one starting with 1 through to the one starting with 3 to after the line that starts with F".

A direct translation of the above into awk:

awk '/^1/,/^3/ hold = hold ORS $0; next 
 /^F/ $0 = $0 hold 
 print ' <file

Using "line numbers" (record numbers in awk):

awk 'NR == 7, NR == 9 hold = hold ORS $0; next 
 NR == 12 $0 = $0 hold 
 print ' <file

The condition NR == 7, NR == 9 could also be written NR >= 7 && NR <= 9.

To be 100% faithful to the sed code, the second block should read $0 = $0 ORS hold; sub(ORS, "", $0) but it's a bit silly to insert the output record separator (a newline by default) only to remove it immediately afterwards.

edited 16 mins ago

answered 39 mins ago

Kusalananda

110k14213337

1

robust solution thumb up!
â€“Â TNT
28 mins ago

add a commentÂ |Â

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

accepted

echo -e '7,9m12n,p' | ed -s file.txt

answered 51 mins ago

ColinSeligSmith

24415

1

this solution works only under bash, it doesn't work under other environments
â€“Â TNT
28 mins ago

add a commentÂ |Â

up vote
0
down vote

accepted

echo -e '7,9m12n,p' | ed -s file.txt

answered 51 mins ago

ColinSeligSmith

24415

1

this solution works only under bash, it doesn't work under other environments
â€“Â TNT
28 mins ago

add a commentÂ |Â

up vote
0
down vote

accepted

echo -e '7,9m12n,p' | ed -s file.txt

answered 51 mins ago

ColinSeligSmith

24415

echo -e '7,9m12n,p' | ed -s file.txt

answered 51 mins ago

ColinSeligSmith

24415

answered 51 mins ago

ColinSeligSmith

24415

answered 51 mins ago

ColinSeligSmith

24415

answered 51 mins ago

ColinSeligSmith

24415

1

this solution works only under bash, it doesn't work under other environments
â€“Â TNT
28 mins ago

add a commentÂ |Â

1

this solution works only under bash, it doesn't work under other environments
â€“Â TNT
28 mins ago

this solution works only under bash, it doesn't work under other environments
â€“Â TNT
28 mins ago

add a commentÂ |Â

up vote
6
down vote

Using sed (moving rows down, because that's easiest with stream editors):

$ sed '7,9H;d;; 12G;s/n//;' <file
x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

You may read the sed script as "move lines 7 through to 9 to after line 12".

The script annotated:

7,9 # These are the lines we'd like to move
 H; # Append them to the hold space (separated by newlines)
 d; # Delete from pattern space, start next cycle

12 # This is where we'd like to move those lines
 G; # Append the hold space
 s/n//; # Remove the newline that the above command inserted

 # (implicit print)

Since lines may be addressed by regular expressions (not just line numbers), the following would work too (on this particular data):

sed '/^1/,/^3/H;d;; /^F/G;s/n//;' <file

I.e., "move the lines from the one starting with 1 through to the one starting with 3 to after the line that starts with F".

A direct translation of the above into awk:

awk '/^1/,/^3/ hold = hold ORS $0; next 
 /^F/ $0 = $0 hold 
 print ' <file

Using "line numbers" (record numbers in awk):

awk 'NR == 7, NR == 9 hold = hold ORS $0; next 
 NR == 12 $0 = $0 hold 
 print ' <file

The condition NR == 7, NR == 9 could also be written NR >= 7 && NR <= 9.

edited 16 mins ago

answered 39 mins ago

Kusalananda

110k14213337

1

robust solution thumb up!
â€“Â TNT
28 mins ago

add a commentÂ |Â

up vote
6
down vote

Using sed (moving rows down, because that's easiest with stream editors):

$ sed '7,9H;d;; 12G;s/n//;' <file
x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

You may read the sed script as "move lines 7 through to 9 to after line 12".

The script annotated:

7,9 # These are the lines we'd like to move
 H; # Append them to the hold space (separated by newlines)
 d; # Delete from pattern space, start next cycle

12 # This is where we'd like to move those lines
 G; # Append the hold space
 s/n//; # Remove the newline that the above command inserted

 # (implicit print)

Since lines may be addressed by regular expressions (not just line numbers), the following would work too (on this particular data):

sed '/^1/,/^3/H;d;; /^F/G;s/n//;' <file

I.e., "move the lines from the one starting with 1 through to the one starting with 3 to after the line that starts with F".

A direct translation of the above into awk:

awk '/^1/,/^3/ hold = hold ORS $0; next 
 /^F/ $0 = $0 hold 
 print ' <file

Using "line numbers" (record numbers in awk):

awk 'NR == 7, NR == 9 hold = hold ORS $0; next 
 NR == 12 $0 = $0 hold 
 print ' <file

The condition NR == 7, NR == 9 could also be written NR >= 7 && NR <= 9.

edited 16 mins ago

answered 39 mins ago

Kusalananda

110k14213337

1

robust solution thumb up!
â€“Â TNT
28 mins ago

add a commentÂ |Â

up vote
6
down vote

Using sed (moving rows down, because that's easiest with stream editors):

$ sed '7,9H;d;; 12G;s/n//;' <file
x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

You may read the sed script as "move lines 7 through to 9 to after line 12".

The script annotated:

7,9 # These are the lines we'd like to move
 H; # Append them to the hold space (separated by newlines)
 d; # Delete from pattern space, start next cycle

12 # This is where we'd like to move those lines
 G; # Append the hold space
 s/n//; # Remove the newline that the above command inserted

 # (implicit print)

Since lines may be addressed by regular expressions (not just line numbers), the following would work too (on this particular data):

sed '/^1/,/^3/H;d;; /^F/G;s/n//;' <file

I.e., "move the lines from the one starting with 1 through to the one starting with 3 to after the line that starts with F".

A direct translation of the above into awk:

awk '/^1/,/^3/ hold = hold ORS $0; next 
 /^F/ $0 = $0 hold 
 print ' <file

Using "line numbers" (record numbers in awk):

awk 'NR == 7, NR == 9 hold = hold ORS $0; next 
 NR == 12 $0 = $0 hold 
 print ' <file

The condition NR == 7, NR == 9 could also be written NR >= 7 && NR <= 9.

edited 16 mins ago

answered 39 mins ago

Kusalananda

110k14213337

Using sed (moving rows down, because that's easiest with stream editors):

$ sed '7,9H;d;; 12G;s/n//;' <file
x
x
x
A
B
C
D
E
F
1
2
3
x
x
x

You may read the sed script as "move lines 7 through to 9 to after line 12".

The script annotated:

7,9 # These are the lines we'd like to move
 H; # Append them to the hold space (separated by newlines)
 d; # Delete from pattern space, start next cycle

12 # This is where we'd like to move those lines
 G; # Append the hold space
 s/n//; # Remove the newline that the above command inserted

 # (implicit print)

Since lines may be addressed by regular expressions (not just line numbers), the following would work too (on this particular data):

sed '/^1/,/^3/H;d;; /^F/G;s/n//;' <file

I.e., "move the lines from the one starting with 1 through to the one starting with 3 to after the line that starts with F".

A direct translation of the above into awk:

awk '/^1/,/^3/ hold = hold ORS $0; next 
 /^F/ $0 = $0 hold 
 print ' <file

Using "line numbers" (record numbers in awk):

awk 'NR == 7, NR == 9 hold = hold ORS $0; next 
 NR == 12 $0 = $0 hold 
 print ' <file

The condition NR == 7, NR == 9 could also be written NR >= 7 && NR <= 9.

edited 16 mins ago

answered 39 mins ago

Kusalananda

110k14213337

edited 16 mins ago

answered 39 mins ago

Kusalananda

110k14213337

answered 39 mins ago

Kusalananda

110k14213337

answered 39 mins ago

Kusalananda

110k14213337

1

robust solution thumb up!
â€“Â TNT
28 mins ago

add a commentÂ |Â

1

robust solution thumb up!
â€“Â TNT
28 mins ago

robust solution thumb up!
â€“Â TNT
28 mins ago

add a commentÂ |Â

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