How would the water flow if you were to have a shower in centrifugal force equivalent to 1 g on a rotating space station?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
3
down vote

favorite












Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?






science-based space-colonization







share|improve this question







New contributor




Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 3




    Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
    – DarthDonut
    2 hours ago







  • 2




    I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
    – Chairman Yang
    2 hours ago







  • 6




    Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
    – Binary Worrier
    1 hour ago










  • Thanks @BinaryWorrier!
    – Chairman Yang
    23 mins ago














up vote
3
down vote

favorite












Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?






science-based space-colonization







share|improve this question







New contributor




Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 3




    Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
    – DarthDonut
    2 hours ago







  • 2




    I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
    – Chairman Yang
    2 hours ago







  • 6




    Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
    – Binary Worrier
    1 hour ago










  • Thanks @BinaryWorrier!
    – Chairman Yang
    23 mins ago












up vote
3
down vote

favorite









up vote
3
down vote

favorite











Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?






science-based space-colonization







share|improve this question







New contributor




Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?






science-based space-colonization




science-based space-colonization






share|improve this question







New contributor




Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 2 hours ago









Chairman Yang

183




183




New contributor




Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 3




    Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
    – DarthDonut
    2 hours ago







  • 2




    I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
    – Chairman Yang
    2 hours ago







  • 6




    Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
    – Binary Worrier
    1 hour ago










  • Thanks @BinaryWorrier!
    – Chairman Yang
    23 mins ago












  • 3




    Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
    – DarthDonut
    2 hours ago







  • 2




    I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
    – Chairman Yang
    2 hours ago







  • 6




    Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
    – Binary Worrier
    1 hour ago










  • Thanks @BinaryWorrier!
    – Chairman Yang
    23 mins ago







3




3




Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago





Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago





2




2




I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago





I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago





6




6




Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago




Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago












Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago




Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago










1 Answer
1






active

oldest

votes

















up vote
7
down vote



accepted










As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.



The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.



Paint circle of velocity



For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.



[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.






share|improve this answer






















  • Wow thanks for the diagram and explanation @Josh King, that's super useful
    – Chairman Yang
    21 mins ago










  • Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
    – Gary Walker
    19 mins ago










  • @GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
    – Josh King
    14 mins ago










Your Answer




StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "579"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);






Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.









 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fworldbuilding.stackexchange.com%2fquestions%2f127620%2fhow-would-the-water-flow-if-you-were-to-have-a-shower-in-centrifugal-force-equiv%23new-answer', 'question_page');

);

Post as a guest

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
7
down vote



accepted










As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.



The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.



Paint circle of velocity



For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.



[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.






share|improve this answer






















  • Wow thanks for the diagram and explanation @Josh King, that's super useful
    – Chairman Yang
    21 mins ago










  • Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
    – Gary Walker
    19 mins ago










  • @GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
    – Josh King
    14 mins ago














up vote
7
down vote



accepted










As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.



The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.



Paint circle of velocity



For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.



[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.






share|improve this answer






















  • Wow thanks for the diagram and explanation @Josh King, that's super useful
    – Chairman Yang
    21 mins ago










  • Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
    – Gary Walker
    19 mins ago










  • @GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
    – Josh King
    14 mins ago












up vote
7
down vote



accepted







up vote
7
down vote



accepted






As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.



The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.



Paint circle of velocity



For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.



[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.






share|improve this answer














As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.



The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.



Paint circle of velocity



For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.



[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.







share|improve this answer














share|improve this answer



share|improve this answer








edited 17 mins ago

























answered 1 hour ago









Josh King

22.2k35589




22.2k35589











  • Wow thanks for the diagram and explanation @Josh King, that's super useful
    – Chairman Yang
    21 mins ago










  • Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
    – Gary Walker
    19 mins ago










  • @GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
    – Josh King
    14 mins ago
















  • Wow thanks for the diagram and explanation @Josh King, that's super useful
    – Chairman Yang
    21 mins ago










  • Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
    – Gary Walker
    19 mins ago










  • @GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
    – Josh King
    14 mins ago















Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago




Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago












Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago




Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago












@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago




@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago










Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.









 

draft saved


draft discarded


















Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.












Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.











Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.













 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fworldbuilding.stackexchange.com%2fquestions%2f127620%2fhow-would-the-water-flow-if-you-were-to-have-a-shower-in-centrifugal-force-equiv%23new-answer', 'question_page');

);

Post as a guest
































































Comments

Post a Comment

Popular posts from this blog

What does second last employer means? [closed]

Image
Clash Royale CLAN TAG #URR8PPP .everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0; up vote -3 down vote favorite Say, for example I have worked in the following companies, Company A => 2010 - 2011 Company B => 2011 - 2012 Company C => 2012 - Till Date Company D => Have offer Now assume Company D is asking to submit documents from my second last employer. So from the list of companies given, which company would be qualified as second last employer? software-industry employer share | improve this question asked Aug 10 '14 at 5:16 Rajaprabhu Aravindasamy 559 1 6 13 closed as off-topic by Jim G., jmort253 ♦ Aug 11 '14 at 1:58 This question appears to be off-topic. The users who voted to close gave this specific reason: "Questions seeking advice on company-specific regulations, agreements, or policies should be directed to your manager or HR department. Questions that address...
Read more

Installing NextGIS Connect into QGIS 3?

Image
Clash Royale CLAN TAG #URR8PPP .everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0; up vote 1 down vote favorite Just acquired free version of NEXTGIS and trying to install the plugin for QGIS. It tells me it was not designed for version 3 of QGIS. How do I set up the QGIS-NEXTGIS interface then? qgis qgis-plugins nextgis share | improve this question edited 3 hours ago PolyGeo ♦ 51.9k 17 77 233 asked 4 hours ago IanGS 16 4 New contributor IanGS is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct. add a comment  |  up vote 1 down vote favorite Just acquired free version of NEXTGIS and trying to install the plugin for QGIS. It tells me it was not designed for version 3 of QGIS. How do I set up the QGIS-NEXTGIS interface then? qgis qgis-plugin...
Read more

One-line joke

A one-liner is a joke that is delivered in a single line. A good one-liner is said to be pithy - concise and meaningful. [1] Comedians and actors use this comedic method as part of their act, e.g. Jimmy Carr, Tommy Cooper, Rodney Dangerfield, Norm Macdonald, Ken Dodd, Stewart Francis, Zach Galifianakis, Mitch Hedberg, Anthony Jeselnik, Milton Jones, Shappi Khorsandi, Jay London, Mark Linn-Baker, Demetri Martin, Groucho Marx, Dan Mintz, Emo Philips, Tim Vine, Steven Wright and Henny Youngman and Arnold Schwarzenegger. [ citation needed ] Many fictional characters are also known to deliver one-liners, including James Bond, who usually includes pithy and laconic quips after disposing of a villain. [ citation needed ] Examples "A baby seal walks into a club." "A dyslexic man walks into a bra." (Anonymous) "There are three types of people, those who can count and those who can't." "Venison's dear, isn't it?" (Jimmy Carr) "An escala...
Read more