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How would the water flow if you were to have a shower in centrifugal force equivalent to 1 g on a rotating space station?
Clash Royale CLAN TAG#URR8PPP
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Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?
science-based space-colonization
asked 2 hours ago
Chairman Yang
183
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Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
3
down vote
favorite
Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?
science-based space-colonization
asked 2 hours ago
Chairman Yang
183
New contributor
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago
2
I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago
6
Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago
Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago
add a comment |Â
up vote
3
down vote
favorite
up vote
3
down vote
favorite
Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?
science-based space-colonization
asked 2 hours ago
Chairman Yang
183
New contributor
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Someone showering after exercise aboard a rotating space station spinning to simulate 1 gravity. How might Coriolis affect jets of water falling within a cubicle of 2 metres in height?
science-based space-colonization
science-based space-colonization
asked 2 hours ago
Chairman Yang
183
New contributor
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Chairman Yang
183
New contributor
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Chairman Yang
183
New contributor
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Chairman Yang
183
asked 2 hours ago
Chairman Yang
183
183
New contributor
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Chairman Yang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago
2
I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago
6
Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago
Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago
add a comment |Â
3
Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago
2
I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago
6
Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago
Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago
3
3
Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago
Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago
2
2
I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago
I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago
6
6
Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago
Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago
Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago
Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
7
down vote
accepted
As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.
The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.
For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.
[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.
answered 1 hour ago
Josh King
22.2k35589
Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago
Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago
@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
7
down vote
accepted
As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.
The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.
For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.
[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.
answered 1 hour ago
Josh King
22.2k35589
Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago
Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago
@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago
add a comment |Â
up vote
7
down vote
accepted
As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.
The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.
For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.
[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.
answered 1 hour ago
Josh King
22.2k35589
Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago
Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago
@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago
add a comment |Â
up vote
7
down vote
accepted
up vote
7
down vote
accepted
As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.
The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.
For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.
[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.
answered 1 hour ago
Josh King
22.2k35589
As the water "falls" from shower head height towards the drain at the floor, it would be moving at a fixed velocity and be rotating slower than it should at the increased radius of the bottom of the shower, so it would tend to lag the rotation and bend backwards to the direction of spin.
The relative strength of this effect would be dependant on the overall habitat diameter. Larger habitats spin slower to simulate 1g, making the velocity gradient over a normal shower height smaller.
For example a 500 meter radius station (with 1g at 500 meters) with shower bottom at 500 meters and top at 498 meters, would have tangential velocity of 70.02 and
69.74 m/s at the bottom and top respectively. So the water leaving the shower would move anti spinward at ~0.28 meters/second. Given that the water would only take ~0.6 seconds to fall 2 meters it would move ~0.17 meters sideways. This distance could be noticable, but angling the showerhead or other simple design solutions could completely overcome the issue.
[Math done via SpinCalc provide by Binary Worrier's comment]
Set radius at 500m and 1g, set radius to 498m and use the same angular velocity from the previous calculation.
answered 1 hour ago
Josh King
22.2k35589
edited 17 mins ago
answered 1 hour ago
Josh King
22.2k35589
answered 1 hour ago
Josh King
22.2k35589
answered 1 hour ago
Josh King
22.2k35589
22.2k35589
Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago
Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago
@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago
add a comment |Â
Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago
Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago
@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago
Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago
Wow thanks for the diagram and explanation @Josh King, that's super useful
– Chairman Yang
21 mins ago
Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago
Radius & Diameter both 500 m. in answer. Also, tangential velocity for 498 meters is not correct. Cleanup on aisle 3.
– Gary Walker
19 mins ago
@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago
@GaryWalker, thanks for the corrections, fixed the diameter vs radius. The tangential for 498m radius is based on angular velocity from a 500 m radius and 1g so it is less than 1g at 498m giving the tangential velocity cited.
– Josh King
14 mins ago
add a comment |Â
Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.
Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.
Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.
Chairman Yang is a new contributor. Be nice, and check out our Code of Conduct.
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3
Welcome to Worldbuilding! Please have a look at the tour! In regards to your question: This depends heavily on the radius of the space station because the radius dictates the speed of rotation, which is dictating the force of the coriolis-effect.
– DarthDonut
2 hours ago
2
I see, thanks, would you mind telling me how I can calculate that? If say the station were like a Kalpana but with a radius of 500m? And thanks for the welcome!
– Chairman Yang
2 hours ago
6
Here's a site that does the calculation for you. artificial-gravity.com/sw/SpinCalc
– Binary Worrier
1 hour ago
Thanks @BinaryWorrier!
– Chairman Yang
23 mins ago