Problem with intersection of two paths

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
2
down vote

favorite












I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf







share|improve this question





















  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago














up vote
2
down vote

favorite












I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf







share|improve this question





















  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf







share|improve this question













I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf




tikz-pgf






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 50 mins ago









Fabrice

1,3411822




1,3411822











  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago
















  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago















Off-topic but anchors have no meaning if the node is just a coordinate.
– marmot
30 mins ago




Off-topic but anchors have no meaning if the node is just a coordinate.
– marmot
30 mins ago




2




2




You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
– marmot
22 mins ago




You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
– marmot
22 mins ago












@marmot, your solution is much easier using rectangle.
– Sigur
18 mins ago





@marmot, your solution is much easier using rectangle.
– Sigur
18 mins ago













@sigur but you were much faster +1 (my internet is really slow these days... )
– marmot
15 mins ago




@sigur but you were much faster +1 (my internet is really slow these days... )
– marmot
15 mins ago










2 Answers
2






active

oldest

votes

















up vote
4
down vote



accepted










Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer


















  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago

















up vote
4
down vote













Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer


















  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
4
down vote



accepted










Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer


















  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago














up vote
4
down vote



accepted










Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer


















  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago












up vote
4
down vote



accepted







up vote
4
down vote



accepted






Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer














Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 20 mins ago

























answered 26 mins ago









Sigur

22.3k350132




22.3k350132







  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago












  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago







1




1




You could also fix begintikzpicture... to begintikzpicture[...].
– Torbjørn T.
22 mins ago




You could also fix begintikzpicture... to begintikzpicture[...].
– Torbjørn T.
22 mins ago












@TorbjørnT. good point. Done!
– Sigur
19 mins ago




@TorbjørnT. good point. Done!
– Sigur
19 mins ago










up vote
4
down vote













Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer


















  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago














up vote
4
down vote













Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer


















  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago












up vote
4
down vote










up vote
4
down vote









Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer














Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 13 mins ago

























answered 16 mins ago









marmot

65.4k471141




65.4k471141







  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago












  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago







1




1




@manooooh added (really slow internet in Mexico.. )
– marmot
12 mins ago




@manooooh added (really slow internet in Mexico.. )
– marmot
12 mins ago




2




2




Not too slow. I was preparing the output for you, but you were faster... lol
– Sigur
12 mins ago




Not too slow. I was preparing the output for you, but you were faster... lol
– Sigur
12 mins ago




1




1




@Sigur Thanks a lot!
– marmot
9 mins ago




@Sigur Thanks a lot!
– marmot
9 mins ago

















 

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Installing NextGIS Connect into QGIS 3?

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Clash Royale CLAN TAG #URR8PPP .everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0; up vote 1 down vote favorite Just acquired free version of NEXTGIS and trying to install the plugin for QGIS. It tells me it was not designed for version 3 of QGIS. How do I set up the QGIS-NEXTGIS interface then? qgis qgis-plugins nextgis share | improve this question edited 3 hours ago PolyGeo ♦ 51.9k 17 77 233 asked 4 hours ago IanGS 16 4 New contributor IanGS is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct. add a comment  |  up vote 1 down vote favorite Just acquired free version of NEXTGIS and trying to install the plugin for QGIS. It tells me it was not designed for version 3 of QGIS. How do I set up the QGIS-NEXTGIS interface then? qgis qgis-plugin...
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One-line joke

A one-liner is a joke that is delivered in a single line. A good one-liner is said to be pithy - concise and meaningful. [1] Comedians and actors use this comedic method as part of their act, e.g. Jimmy Carr, Tommy Cooper, Rodney Dangerfield, Norm Macdonald, Ken Dodd, Stewart Francis, Zach Galifianakis, Mitch Hedberg, Anthony Jeselnik, Milton Jones, Shappi Khorsandi, Jay London, Mark Linn-Baker, Demetri Martin, Groucho Marx, Dan Mintz, Emo Philips, Tim Vine, Steven Wright and Henny Youngman and Arnold Schwarzenegger. [ citation needed ] Many fictional characters are also known to deliver one-liners, including James Bond, who usually includes pithy and laconic quips after disposing of a villain. [ citation needed ] Examples "A baby seal walks into a club." "A dyslexic man walks into a bra." (Anonymous) "There are three types of people, those who can count and those who can't." "Venison's dear, isn't it?" (Jimmy Carr) "An escala...
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