Problem with intersection of two paths

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
2
down vote

favorite












I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf







share|improve this question





















  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago














up vote
2
down vote

favorite












I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf







share|improve this question





















  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf







share|improve this question













I can not get the attached figure.



enter image description here



documentclass[tikz,11pt,border=5mm]standalone
usepackagetikz
usepackagegeometry
usetikzlibrarypositioning,calc,intersections


begindocument

begintikzpicturethick,x=0.5cm,y=0.5cm

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);

path[name path=line1] (C.east) -- (C.east-|B.west)coordinate[pos=0.6](N) ;
path[name path=line2] (A) -- (B);
path[name path=line3]($(A)!(N)!(B)$) -- (N);
path[name path=line4]($(C)!(N)!(A)$) -- (N);
path[name path=line5] (A) -- (C);

path[name intersections=of=line1 and line3,by=P];
path[name intersections=of=line1 and line5,by=M];

draw[fill=green] (A-|P) --(N) -- (C-|M) -- (A) --cycle;
draw (A)--(B)--(C)--cycle;

node[above] at (N)$N$;
node[below] at (P)$P$;

endtikzpicture

enddocument


enter image description here






tikz-pgf




tikz-pgf






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 50 mins ago









Fabrice

1,3411822




1,3411822











  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago
















  • Off-topic but anchors have no meaning if the node is just a coordinate.
    – marmot
    30 mins ago






  • 2




    You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
    – marmot
    22 mins ago










  • @marmot, your solution is much easier using rectangle.
    – Sigur
    18 mins ago











  • @sigur but you were much faster +1 (my internet is really slow these days... )
    – marmot
    15 mins ago















Off-topic but anchors have no meaning if the node is just a coordinate.
– marmot
30 mins ago




Off-topic but anchors have no meaning if the node is just a coordinate.
– marmot
30 mins ago




2




2




You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
– marmot
22 mins ago




You only need path (C) -- (B)coordinate[pos=0.6](N) ; draw[fill=green] (A) rectangle (N);
– marmot
22 mins ago












@marmot, your solution is much easier using rectangle.
– Sigur
18 mins ago





@marmot, your solution is much easier using rectangle.
– Sigur
18 mins ago













@sigur but you were much faster +1 (my internet is really slow these days... )
– marmot
15 mins ago




@sigur but you were much faster +1 (my internet is really slow these days... )
– marmot
15 mins ago










2 Answers
2






active

oldest

votes

















up vote
4
down vote



accepted










Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer


















  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago

















up vote
4
down vote













Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer


















  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
4
down vote



accepted










Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer


















  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago














up vote
4
down vote



accepted










Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer


















  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago












up vote
4
down vote



accepted







up vote
4
down vote



accepted






Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here






share|improve this answer














Just control the position of P between A and B. I used 60%.



documentclass[tikz,11pt]standalone
usetikzlibrarypositioning,calc,intersections

begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]

coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=left : $C$](C) at (0,5);
coordinate [label=below : $P$](P) at ($(A)!.6!(B)$);

path[name path=hipo] (C) -- (B);
path[name path=rightVertical] (P) -- (P|-C) ;
path[name path=leftVertical] (A) -- (C);

path[name intersections=of=rightVertical and hipo,by=N];
path[name path=horizontal] (N) -- (N-|C) ;
path[name intersections=of=horizontal and leftVertical,by=M];

draw[fill=green] (P)--(N)--(M)--(A)--cycle;
draw (A)--(B)--(C)--cycle;
node[above] at (N)$N$;
node[left] at (M)$M$;
endtikzpicture

enddocument


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 20 mins ago

























answered 26 mins ago









Sigur

22.3k350132




22.3k350132







  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago












  • 1




    You could also fix begintikzpicture... to begintikzpicture[...].
    – Torbjørn T.
    22 mins ago










  • @TorbjørnT. good point. Done!
    – Sigur
    19 mins ago







1




1




You could also fix begintikzpicture... to begintikzpicture[...].
– Torbjørn T.
22 mins ago




You could also fix begintikzpicture... to begintikzpicture[...].
– Torbjørn T.
22 mins ago












@TorbjørnT. good point. Done!
– Sigur
19 mins ago




@TorbjørnT. good point. Done!
– Sigur
19 mins ago










up vote
4
down vote













Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer


















  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago














up vote
4
down vote













Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer


















  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago












up vote
4
down vote










up vote
4
down vote









Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here






share|improve this answer














Similar to @Sigur but there are no intersections used (as not needed).



documentclass[tikz,11pt,border=5mm]standalone
usetikzlibrarypositioning,calc


begindocument

begintikzpicture[thick,x=0.5cm,y=0.5cm]
coordinate [label=below left : $A$](A) at (0,0);
coordinate [label=below right : $B$](B) at (10,0);
coordinate [label=above left : $C$] (C) at (0,5);
path (C) -- (B)coordinate[pos=0.6,label=above right:$N$](N) ;
draw[fill=green] (A) rectangle (N);
coordinate[label=above left:$M$] (M) at (A|-N);
draw (A) -- (B) -- (C) -- cycle;
endtikzpicture
enddocument


Output as your desired screen shot.



enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 13 mins ago

























answered 16 mins ago









marmot

65.4k471141




65.4k471141







  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago












  • 1




    @manooooh added (really slow internet in Mexico.. )
    – marmot
    12 mins ago






  • 2




    Not too slow. I was preparing the output for you, but you were faster... lol
    – Sigur
    12 mins ago






  • 1




    @Sigur Thanks a lot!
    – marmot
    9 mins ago







1




1




@manooooh added (really slow internet in Mexico.. )
– marmot
12 mins ago




@manooooh added (really slow internet in Mexico.. )
– marmot
12 mins ago




2




2




Not too slow. I was preparing the output for you, but you were faster... lol
– Sigur
12 mins ago




Not too slow. I was preparing the output for you, but you were faster... lol
– Sigur
12 mins ago




1




1




@Sigur Thanks a lot!
– marmot
9 mins ago




@Sigur Thanks a lot!
– marmot
9 mins ago

















 

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Is the Concept of Multiple Fantasy Races Scientifically Flawed? [closed]

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Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite Many fantasy worlds have multiple humanoid species (elves, orcs, humans, etc) living in the same world, in addition to that, they often have the ability to interbreed. And I can't help but question their believability... fantasy-races reproduction interspecies-relations share | improve this question edited Aug 9 at 14:46 Michael Kjörling ♦ 21.1k 10 85 161 asked Aug 9 at 13:13 Chlodio 118 6 closed as unclear what you're asking by MichaelK, Gryphon, John, Vincent, Frostfyre Aug 9 at 15:25 Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question. 3 Stack Exchange exist to
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Confectionery

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Prepared foods made with a lot of sugar or other cabohydrates "Sweetmeat" redirects here. For the racehorse, see Sweetmeat (horse). Not to be confused with Sweetbread. This Kransekake is a traditional Scandinavian baker's confection. Confectionery is the art of making confections , which are food items that are rich in sugar and carbohydrates. Exact definitions are difficult. [1] In general, though, confectionery is divided into two broad and somewhat overlapping categories, bakers' confections and sugar confections. [2] Bakers' confectionery, also called flour confections , includes principally sweet pastries, cakes, and similar baked goods. Sugar confectionery includes candies ( sweets in British English), candied nuts, chocolates, chewing gum, bubble gum, pastillage, and other confections that are made primarily of sugar. In some cases, chocolate confections (confections made of chocolate) are treated as a separate category, as are sugar-free versions of
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