Pgfplots: embedding a line in a surface

up vote
3
down vote

favorite

I want to draw an identity across a surface plot. This identity should start at the bottom left, and end at the top right (from tip to tip). With the axis I've given (see below), the v_1=2(v_2-20). This becomes y=2(x-20) given the way the axes are defined. I've tried plotting this in various ways, but it does not seem to work on top of the 3d surface.

beginfigure[h]
begintikzpicture[scale=2]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 ((y^2/(0.5*(x+y))/20);
endaxis
endtikzpicture

enter image description here

edited 7 mins ago

asked 3 hours ago

pafnuti

2517

I am sorry, I do not understand the question. Could you please make more explicit what you mean? What does "This becomes y=2(x-20) given the way the axes are defined. " mean? Do you just want to plot (x,2*(x-20))? But this is a 3d plot.
â€“Â marmot
3 hours ago

@marmot Sorry for it being unclear. I would like to plot the identity that maps across the surface diagonally from v_2=20 to v_1=10. This would be a single function, not a surface, as it is defined at one particular intersection of the v_2 and v_1 axes.
â€“Â pafnuti
3 hours ago

You want a one-dimensional plot, i.e a line, then? At which z-value should this line be? Should it really be v_1=2(v_2-20), i.e. at v_1=0 v_2 will be -40, ie. far off from the surface?
â€“Â marmot
3 hours ago

@marmot Yes one-dimensional, at the z-value of the surface.
â€“Â pafnuti
2 hours ago

Could you perhaps consider changing the title of your nice question such that it is easier to find for others? My request is triggered by this discussion. One possible title might be "pgfplots: embedding a line in a surface".
â€“Â marmot
11 mins ago

add a commentÂ |Â

up vote
3
down vote

favorite

beginfigure[h]
begintikzpicture[scale=2]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 ((y^2/(0.5*(x+y))/20);
endaxis
endtikzpicture

enter image description here

edited 7 mins ago

asked 3 hours ago

pafnuti

2517

I am sorry, I do not understand the question. Could you please make more explicit what you mean? What does "This becomes y=2(x-20) given the way the axes are defined. " mean? Do you just want to plot (x,2*(x-20))? But this is a 3d plot.
â€“Â marmot
3 hours ago

@marmot Sorry for it being unclear. I would like to plot the identity that maps across the surface diagonally from v_2=20 to v_1=10. This would be a single function, not a surface, as it is defined at one particular intersection of the v_2 and v_1 axes.
â€“Â pafnuti
3 hours ago

You want a one-dimensional plot, i.e a line, then? At which z-value should this line be? Should it really be v_1=2(v_2-20), i.e. at v_1=0 v_2 will be -40, ie. far off from the surface?
â€“Â marmot
3 hours ago

@marmot Yes one-dimensional, at the z-value of the surface.
â€“Â pafnuti
2 hours ago

Could you perhaps consider changing the title of your nice question such that it is easier to find for others? My request is triggered by this discussion. One possible title might be "pgfplots: embedding a line in a surface".
â€“Â marmot
11 mins ago

add a commentÂ |Â

up vote
3
down vote

favorite

beginfigure[h]
begintikzpicture[scale=2]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 ((y^2/(0.5*(x+y))/20);
endaxis
endtikzpicture

enter image description here

edited 7 mins ago

asked 3 hours ago

pafnuti

2517

beginfigure[h]
begintikzpicture[scale=2]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 ((y^2/(0.5*(x+y))/20);
endaxis
endtikzpicture

enter image description here

tikz-pgf pgfplots

edited 7 mins ago

asked 3 hours ago

pafnuti

2517

edited 7 mins ago

asked 3 hours ago

pafnuti

2517

edited 7 mins ago

asked 3 hours ago

pafnuti

2517

asked 3 hours ago

pafnuti

2517

asked 3 hours ago

pafnuti

2517

I am sorry, I do not understand the question. Could you please make more explicit what you mean? What does "This becomes y=2(x-20) given the way the axes are defined. " mean? Do you just want to plot (x,2*(x-20))? But this is a 3d plot.
â€“Â marmot
3 hours ago

@marmot Sorry for it being unclear. I would like to plot the identity that maps across the surface diagonally from v_2=20 to v_1=10. This would be a single function, not a surface, as it is defined at one particular intersection of the v_2 and v_1 axes.
â€“Â pafnuti
3 hours ago

You want a one-dimensional plot, i.e a line, then? At which z-value should this line be? Should it really be v_1=2(v_2-20), i.e. at v_1=0 v_2 will be -40, ie. far off from the surface?
â€“Â marmot
3 hours ago

@marmot Yes one-dimensional, at the z-value of the surface.
â€“Â pafnuti
2 hours ago

Could you perhaps consider changing the title of your nice question such that it is easier to find for others? My request is triggered by this discussion. One possible title might be "pgfplots: embedding a line in a surface".
â€“Â marmot
11 mins ago

add a commentÂ |Â

I am sorry, I do not understand the question. Could you please make more explicit what you mean? What does "This becomes y=2(x-20) given the way the axes are defined. " mean? Do you just want to plot (x,2*(x-20))? But this is a 3d plot.
â€“Â marmot
3 hours ago

@marmot Sorry for it being unclear. I would like to plot the identity that maps across the surface diagonally from v_2=20 to v_1=10. This would be a single function, not a surface, as it is defined at one particular intersection of the v_2 and v_1 axes.
â€“Â pafnuti
3 hours ago

You want a one-dimensional plot, i.e a line, then? At which z-value should this line be? Should it really be v_1=2(v_2-20), i.e. at v_1=0 v_2 will be -40, ie. far off from the surface?
â€“Â marmot
3 hours ago

@marmot Yes one-dimensional, at the z-value of the surface.
â€“Â pafnuti
2 hours ago

Could you perhaps consider changing the title of your nice question such that it is easier to find for others? My request is triggered by this discussion. One possible title might be "pgfplots: embedding a line in a surface".
â€“Â marmot
11 mins ago

I am sorry, I do not understand the question. Could you please make more explicit what you mean? What does "This becomes y=2(x-20) given the way the axes are defined. " mean? Do you just want to plot (x,2*(x-20))? But this is a 3d plot.
â€“Â marmot
3 hours ago

@marmot Sorry for it being unclear. I would like to plot the identity that maps across the surface diagonally from v_2=20 to v_1=10. This would be a single function, not a surface, as it is defined at one particular intersection of the v_2 and v_1 axes.
â€“Â pafnuti
3 hours ago

You want a one-dimensional plot, i.e a line, then? At which z-value should this line be? Should it really be v_1=2(v_2-20), i.e. at v_1=0 v_2 will be -40, ie. far off from the surface?
â€“Â marmot
3 hours ago

@marmot Yes one-dimensional, at the z-value of the surface.
â€“Â pafnuti
2 hours ago

Could you perhaps consider changing the title of your nice question such that it is easier to find for others? My request is triggered by this discussion. One possible title might be "pgfplots: embedding a line in a surface".
â€“Â marmot
11 mins ago

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
8
down vote

accepted

I hope I guess correctly.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,point meta=0] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,point meta=0.5] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

Of course, you can choose whatever color you like for those lines.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,color=red] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,color=black] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

edited 1 hour ago

answered 2 hours ago

marmot

57.5k462124

That's exactly what I want, but from the left-most point at (v_1=0,v_2=20,z=0) to the rightmost (v_1=10,v_2=0, z approx 1). Will change it myself :)
â€“Â pafnuti
2 hours ago

@pafnuti I add that one. There is one potential piftfall: you need to use mesh since otherwise there will be a closed cycle.
â€“Â marmot
2 hours ago

Does this mean I can't choose an arbitrary colour for the line? Because of the point meta colour map?
â€“Â pafnuti
2 hours ago

@pafnuti You can choose whatever color you like, I added an update.
â€“Â marmot
1 hour ago

add a commentÂ |Â

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
8
down vote

accepted

I hope I guess correctly.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,point meta=0] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,point meta=0.5] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

Of course, you can choose whatever color you like for those lines.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,color=red] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,color=black] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

edited 1 hour ago

answered 2 hours ago

marmot

57.5k462124

That's exactly what I want, but from the left-most point at (v_1=0,v_2=20,z=0) to the rightmost (v_1=10,v_2=0, z approx 1). Will change it myself :)
â€“Â pafnuti
2 hours ago

@pafnuti I add that one. There is one potential piftfall: you need to use mesh since otherwise there will be a closed cycle.
â€“Â marmot
2 hours ago

Does this mean I can't choose an arbitrary colour for the line? Because of the point meta colour map?
â€“Â pafnuti
2 hours ago

@pafnuti You can choose whatever color you like, I added an update.
â€“Â marmot
1 hour ago

add a commentÂ |Â

up vote
8
down vote

accepted

I hope I guess correctly.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,point meta=0] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,point meta=0.5] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

Of course, you can choose whatever color you like for those lines.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,color=red] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,color=black] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

edited 1 hour ago

answered 2 hours ago

marmot

57.5k462124

That's exactly what I want, but from the left-most point at (v_1=0,v_2=20,z=0) to the rightmost (v_1=10,v_2=0, z approx 1). Will change it myself :)
â€“Â pafnuti
2 hours ago

@pafnuti I add that one. There is one potential piftfall: you need to use mesh since otherwise there will be a closed cycle.
â€“Â marmot
2 hours ago

Does this mean I can't choose an arbitrary colour for the line? Because of the point meta colour map?
â€“Â pafnuti
2 hours ago

@pafnuti You can choose whatever color you like, I added an update.
â€“Â marmot
1 hour ago

add a commentÂ |Â

up vote
8
down vote

accepted

I hope I guess correctly.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,point meta=0] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,point meta=0.5] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

Of course, you can choose whatever color you like for those lines.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,color=red] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,color=black] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

edited 1 hour ago

answered 2 hours ago

marmot

57.5k462124

I hope I guess correctly.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,point meta=0] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,point meta=0.5] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

Of course, you can choose whatever color you like for those lines.

documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[scale=2,declare function=f(x,y)=((y*y/(0.5*(x+y))/20);]
beginaxis[
 title=secret research, 
 xlabel=$v_2$, ylabel=$v_1$,
 small,
 x dir=reverse
]
addplot3[
 surf,
 domain=0:20,
 domain y=0:10,
] 
 (f(x,y);
addplot3[mesh,domain=0:10,color=red] (2*x,x, (f(2*x,x));
addplot3[mesh,domain=0:10,color=black] (2*(10-x),x, (f(2*(10-x),x));
endaxis
endtikzpicture
enddocument

enter image description here

edited 1 hour ago

answered 2 hours ago

marmot

57.5k462124

edited 1 hour ago

answered 2 hours ago

marmot

57.5k462124

answered 2 hours ago

marmot

57.5k462124

answered 2 hours ago

marmot

57.5k462124

That's exactly what I want, but from the left-most point at (v_1=0,v_2=20,z=0) to the rightmost (v_1=10,v_2=0, z approx 1). Will change it myself :)
â€“Â pafnuti
2 hours ago

@pafnuti I add that one. There is one potential piftfall: you need to use mesh since otherwise there will be a closed cycle.
â€“Â marmot
2 hours ago

Does this mean I can't choose an arbitrary colour for the line? Because of the point meta colour map?
â€“Â pafnuti
2 hours ago

@pafnuti You can choose whatever color you like, I added an update.
â€“Â marmot
1 hour ago

add a commentÂ |Â

That's exactly what I want, but from the left-most point at (v_1=0,v_2=20,z=0) to the rightmost (v_1=10,v_2=0, z approx 1). Will change it myself :)
â€“Â pafnuti
2 hours ago

@pafnuti I add that one. There is one potential piftfall: you need to use mesh since otherwise there will be a closed cycle.
â€“Â marmot
2 hours ago

Does this mean I can't choose an arbitrary colour for the line? Because of the point meta colour map?
â€“Â pafnuti
2 hours ago

@pafnuti You can choose whatever color you like, I added an update.
â€“Â marmot
1 hour ago

That's exactly what I want, but from the left-most point at (v_1=0,v_2=20,z=0) to the rightmost (v_1=10,v_2=0, z approx 1). Will change it myself :)
â€“Â pafnuti
2 hours ago

@pafnuti I add that one. There is one potential piftfall: you need to use mesh since otherwise there will be a closed cycle.
â€“Â marmot
2 hours ago

Does this mean I can't choose an arbitrary colour for the line? Because of the point meta colour map?
â€“Â pafnuti
2 hours ago

@pafnuti You can choose whatever color you like, I added an update.
â€“Â marmot
1 hour ago

add a commentÂ |Â

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