Creating a number pyramid with tabularx

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up vote
1
down vote

favorite

I am trying to create a simple number pyramid like this one using a tabularx table with six columns and `multicolumn' commands.

I tried

begintabularx0.5linewidthXXXXXX
 cline3-4
 multicolumn2c&multicolumn2c&multicolumn2c\
 cline2-5
 multicolumn1c&multicolumn2c&multicolumn2c&multicolumn1c\
 hline
 multicolumn2c$frac32$&multicolumn2c$frac13$&multicolumn2c$frac12$\
 hline
 endtabularx

.. which gives me a very distorted table.

However if I add a simple empty line to the table with

&&&&&&

everything looks perfect. My only issue now is that the table is too long, because of that extra empty line.

Is there a way to get a pretty pyramid without adding that extra line?

tables tabularx

share|improve this question

asked 1 hour ago

user1583209

25516

add a comment | 

up vote
1
down vote

favorite

I am trying to create a simple number pyramid like this one using a tabularx table with six columns and `multicolumn' commands.

I tried

begintabularx0.5linewidthXXXXXX
 cline3-4
 multicolumn2c&multicolumn2c&multicolumn2c\
 cline2-5
 multicolumn1c&multicolumn2c&multicolumn2c&multicolumn1c\
 hline
 multicolumn2c$frac32$&multicolumn2c$frac13$&multicolumn2c$frac12$\
 hline
 endtabularx

.. which gives me a very distorted table.

However if I add a simple empty line to the table with

&&&&&&

everything looks perfect. My only issue now is that the table is too long, because of that extra empty line.

Is there a way to get a pretty pyramid without adding that extra line?

tables tabularx

share|improve this question

asked 1 hour ago

user1583209

25516

add a comment | 

up vote
1
down vote

favorite

up vote
1
down vote

favorite

I am trying to create a simple number pyramid like this one using a tabularx table with six columns and `multicolumn' commands.

I tried

begintabularx0.5linewidthXXXXXX
 cline3-4
 multicolumn2c&multicolumn2c&multicolumn2c\
 cline2-5
 multicolumn1c&multicolumn2c&multicolumn2c&multicolumn1c\
 hline
 multicolumn2c$frac32$&multicolumn2c$frac13$&multicolumn2c$frac12$\
 hline
 endtabularx

.. which gives me a very distorted table.

However if I add a simple empty line to the table with

&&&&&&

everything looks perfect. My only issue now is that the table is too long, because of that extra empty line.

Is there a way to get a pretty pyramid without adding that extra line?

tables tabularx

share|improve this question

asked 1 hour ago

user1583209

25516

I am trying to create a simple number pyramid like this one using a tabularx table with six columns and `multicolumn' commands.

I tried

begintabularx0.5linewidthXXXXXX
 cline3-4
 multicolumn2c&multicolumn2c&multicolumn2c\
 cline2-5
 multicolumn1c&multicolumn2c&multicolumn2c&multicolumn1c\
 hline
 multicolumn2c$frac32$&multicolumn2c$frac13$&multicolumn2c$frac12$\
 hline
 endtabularx

.. which gives me a very distorted table.

However if I add a simple empty line to the table with

&&&&&&

everything looks perfect. My only issue now is that the table is too long, because of that extra empty line.

Is there a way to get a pretty pyramid without adding that extra line?

tables tabularx

tables tabularx

share|improve this question

asked 1 hour ago

user1583209

25516

share|improve this question

asked 1 hour ago

user1583209

25516

share|improve this question

share|improve this question

asked 1 hour ago

user1583209

25516

asked 1 hour ago

user1583209

25516

asked 1 hour ago

user1583209

25516

25516

add a comment | 

add a comment | 

2 Answers
2

active

oldest

votes

up vote
3
down vote

drawing this number pyramid is much simpler than write it as table. especially if you like to use tabularx table environment. by use of the tikz package you can obtain:

documentclass[tikz, border=3mm]standalone
usetikzlibrarypositioning

begindocument
 begintikzpicture[
 node distance = 0pt,
every node/.style = draw, minimum size=7mm, inner sep=0pt, outer sep=0pt
 ]
node (n1) ;
%
node (n11) [below left=of n1.south] ;
node (n12) [right=of n11] ;
%
node (n21) [below left=of n11.south] $frac13$;
node (n22) [right=of n21] $frac13$;
node (n23) [right=of n22] $frac12$;
 endtikzpicture
enddocument

share|improve this answer

answered 43 mins ago

Zarko

113k861150

add a comment | 

up vote
2
down vote

With some low level programming:

documentclassarticle
usepackageamsmath
usepackagevarwidth

newcommandblock[1]%
 begingroup
 setlengthfboxsep0pt%
 vrule width0pt height blockdim
 ooalign%
 framebox[blockdim]rule0ptblockdimcr
 hidewidthraisebox0.5dimexprblockdim-heightraiseboxdepth#1hidewidthcr
 %
 endgroup

newcommandjoinblocksunskipkern-fboxruleignorespaces
newenvironmentblocks[1][1cm]
 beginvarwidthtextwidthsetlengthblockdim#1makeblocks
 endvarwidth
newcommandmakeblocks%
 begingrouplccode`~=`&lowercaseendgrouplet~joinblocks
 catcode`&=active
 baselineskip=0pt
 lineskiplimit=maxdimen
 lineskip=0pt
 centering

newlengthblockdim

begindocument

A pyramid
beginblocks
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

bigskip

A pyramid
beginblocks[1.5cm]
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

enddocument

share|improve this answer

answered 19 mins ago

egreg

683k8418183064

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
3
down vote

drawing this number pyramid is much simpler than write it as table. especially if you like to use tabularx table environment. by use of the tikz package you can obtain:

documentclass[tikz, border=3mm]standalone
usetikzlibrarypositioning

begindocument
 begintikzpicture[
 node distance = 0pt,
every node/.style = draw, minimum size=7mm, inner sep=0pt, outer sep=0pt
 ]
node (n1) ;
%
node (n11) [below left=of n1.south] ;
node (n12) [right=of n11] ;
%
node (n21) [below left=of n11.south] $frac13$;
node (n22) [right=of n21] $frac13$;
node (n23) [right=of n22] $frac12$;
 endtikzpicture
enddocument

share|improve this answer

answered 43 mins ago

Zarko

113k861150

add a comment | 

up vote
3
down vote

drawing this number pyramid is much simpler than write it as table. especially if you like to use tabularx table environment. by use of the tikz package you can obtain:

documentclass[tikz, border=3mm]standalone
usetikzlibrarypositioning

begindocument
 begintikzpicture[
 node distance = 0pt,
every node/.style = draw, minimum size=7mm, inner sep=0pt, outer sep=0pt
 ]
node (n1) ;
%
node (n11) [below left=of n1.south] ;
node (n12) [right=of n11] ;
%
node (n21) [below left=of n11.south] $frac13$;
node (n22) [right=of n21] $frac13$;
node (n23) [right=of n22] $frac12$;
 endtikzpicture
enddocument

share|improve this answer

answered 43 mins ago

Zarko

113k861150

add a comment | 

up vote
3
down vote

up vote
3
down vote

drawing this number pyramid is much simpler than write it as table. especially if you like to use tabularx table environment. by use of the tikz package you can obtain:

documentclass[tikz, border=3mm]standalone
usetikzlibrarypositioning

begindocument
 begintikzpicture[
 node distance = 0pt,
every node/.style = draw, minimum size=7mm, inner sep=0pt, outer sep=0pt
 ]
node (n1) ;
%
node (n11) [below left=of n1.south] ;
node (n12) [right=of n11] ;
%
node (n21) [below left=of n11.south] $frac13$;
node (n22) [right=of n21] $frac13$;
node (n23) [right=of n22] $frac12$;
 endtikzpicture
enddocument

share|improve this answer

answered 43 mins ago

Zarko

113k861150

drawing this number pyramid is much simpler than write it as table. especially if you like to use tabularx table environment. by use of the tikz package you can obtain:

documentclass[tikz, border=3mm]standalone
usetikzlibrarypositioning

begindocument
 begintikzpicture[
 node distance = 0pt,
every node/.style = draw, minimum size=7mm, inner sep=0pt, outer sep=0pt
 ]
node (n1) ;
%
node (n11) [below left=of n1.south] ;
node (n12) [right=of n11] ;
%
node (n21) [below left=of n11.south] $frac13$;
node (n22) [right=of n21] $frac13$;
node (n23) [right=of n22] $frac12$;
 endtikzpicture
enddocument

share|improve this answer

answered 43 mins ago

Zarko

113k861150

share|improve this answer

share|improve this answer

answered 43 mins ago

Zarko

113k861150

answered 43 mins ago

Zarko

113k861150

answered 43 mins ago

Zarko

113k861150

113k861150

add a comment | 

add a comment | 

up vote
2
down vote

With some low level programming:

documentclassarticle
usepackageamsmath
usepackagevarwidth

newcommandblock[1]%
 begingroup
 setlengthfboxsep0pt%
 vrule width0pt height blockdim
 ooalign%
 framebox[blockdim]rule0ptblockdimcr
 hidewidthraisebox0.5dimexprblockdim-heightraiseboxdepth#1hidewidthcr
 %
 endgroup

newcommandjoinblocksunskipkern-fboxruleignorespaces
newenvironmentblocks[1][1cm]
 beginvarwidthtextwidthsetlengthblockdim#1makeblocks
 endvarwidth
newcommandmakeblocks%
 begingrouplccode`~=`&lowercaseendgrouplet~joinblocks
 catcode`&=active
 baselineskip=0pt
 lineskiplimit=maxdimen
 lineskip=0pt
 centering

newlengthblockdim

begindocument

A pyramid
beginblocks
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

bigskip

A pyramid
beginblocks[1.5cm]
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

enddocument

share|improve this answer

answered 19 mins ago

egreg

683k8418183064

add a comment | 

up vote
2
down vote

With some low level programming:

documentclassarticle
usepackageamsmath
usepackagevarwidth

newcommandblock[1]%
 begingroup
 setlengthfboxsep0pt%
 vrule width0pt height blockdim
 ooalign%
 framebox[blockdim]rule0ptblockdimcr
 hidewidthraisebox0.5dimexprblockdim-heightraiseboxdepth#1hidewidthcr
 %
 endgroup

newcommandjoinblocksunskipkern-fboxruleignorespaces
newenvironmentblocks[1][1cm]
 beginvarwidthtextwidthsetlengthblockdim#1makeblocks
 endvarwidth
newcommandmakeblocks%
 begingrouplccode`~=`&lowercaseendgrouplet~joinblocks
 catcode`&=active
 baselineskip=0pt
 lineskiplimit=maxdimen
 lineskip=0pt
 centering

newlengthblockdim

begindocument

A pyramid
beginblocks
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

bigskip

A pyramid
beginblocks[1.5cm]
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

enddocument

share|improve this answer

answered 19 mins ago

egreg

683k8418183064

add a comment | 

up vote
2
down vote

up vote
2
down vote

With some low level programming:

documentclassarticle
usepackageamsmath
usepackagevarwidth

newcommandblock[1]%
 begingroup
 setlengthfboxsep0pt%
 vrule width0pt height blockdim
 ooalign%
 framebox[blockdim]rule0ptblockdimcr
 hidewidthraisebox0.5dimexprblockdim-heightraiseboxdepth#1hidewidthcr
 %
 endgroup

newcommandjoinblocksunskipkern-fboxruleignorespaces
newenvironmentblocks[1][1cm]
 beginvarwidthtextwidthsetlengthblockdim#1makeblocks
 endvarwidth
newcommandmakeblocks%
 begingrouplccode`~=`&lowercaseendgrouplet~joinblocks
 catcode`&=active
 baselineskip=0pt
 lineskiplimit=maxdimen
 lineskip=0pt
 centering

newlengthblockdim

begindocument

A pyramid
beginblocks
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

bigskip

A pyramid
beginblocks[1.5cm]
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

enddocument

share|improve this answer

answered 19 mins ago

egreg

683k8418183064

With some low level programming:

documentclassarticle
usepackageamsmath
usepackagevarwidth

newcommandblock[1]%
 begingroup
 setlengthfboxsep0pt%
 vrule width0pt height blockdim
 ooalign%
 framebox[blockdim]rule0ptblockdimcr
 hidewidthraisebox0.5dimexprblockdim-heightraiseboxdepth#1hidewidthcr
 %
 endgroup

newcommandjoinblocksunskipkern-fboxruleignorespaces
newenvironmentblocks[1][1cm]
 beginvarwidthtextwidthsetlengthblockdim#1makeblocks
 endvarwidth
newcommandmakeblocks%
 begingrouplccode`~=`&lowercaseendgrouplet~joinblocks
 catcode`&=active
 baselineskip=0pt
 lineskiplimit=maxdimen
 lineskip=0pt
 centering

newlengthblockdim

begindocument

A pyramid
beginblocks
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

bigskip

A pyramid
beginblocks[1.5cm]
 block1\
 block2 & block3 \
 block4 & block5 & block$dfrac366$
endblocks
in context

enddocument

share|improve this answer

answered 19 mins ago

egreg

683k8418183064

share|improve this answer

share|improve this answer

answered 19 mins ago

egreg

683k8418183064

answered 19 mins ago

egreg

683k8418183064

answered 19 mins ago

egreg

683k8418183064

683k8418183064

add a comment | 

add a comment | 

 

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