Understanding power supply requirements
Clash Royale CLAN TAG#URR8PPP
up vote
2
down vote
favorite
I have a basic question about power supply requirements for typical transceivers. I'm looking at the specs for a Kenwood TM-V71A, which is a 50W mobile transceiver.
I figured that a 50W transceiver running on a 12V(-ish) power supply would pull around 4A max, but the specs for this radio show a "maximum current drain" of around 13A. How does that work?
dc-power
add a comment |Â
up vote
2
down vote
favorite
I have a basic question about power supply requirements for typical transceivers. I'm looking at the specs for a Kenwood TM-V71A, which is a 50W mobile transceiver.
I figured that a 50W transceiver running on a 12V(-ish) power supply would pull around 4A max, but the specs for this radio show a "maximum current drain" of around 13A. How does that work?
dc-power
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have a basic question about power supply requirements for typical transceivers. I'm looking at the specs for a Kenwood TM-V71A, which is a 50W mobile transceiver.
I figured that a 50W transceiver running on a 12V(-ish) power supply would pull around 4A max, but the specs for this radio show a "maximum current drain" of around 13A. How does that work?
dc-power
I have a basic question about power supply requirements for typical transceivers. I'm looking at the specs for a Kenwood TM-V71A, which is a 50W mobile transceiver.
I figured that a 50W transceiver running on a 12V(-ish) power supply would pull around 4A max, but the specs for this radio show a "maximum current drain" of around 13A. How does that work?
dc-power
dc-power
asked 3 hours ago
larsks
2889
2889
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
3
down vote
A 50W transmitter is one that can create 50 watts of RF output. The RF amplifier is never 100% efficient, so the input power requirements will always be higher than the output power.
Furthermore, the maximum current drain accounts for startup transients and other peaks in excess of the average current drain.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
A 50W transmitter is one that can create 50 watts of RF output. The RF amplifier is never 100% efficient, so the input power requirements will always be higher than the output power.
Furthermore, the maximum current drain accounts for startup transients and other peaks in excess of the average current drain.
add a comment |Â
up vote
3
down vote
A 50W transmitter is one that can create 50 watts of RF output. The RF amplifier is never 100% efficient, so the input power requirements will always be higher than the output power.
Furthermore, the maximum current drain accounts for startup transients and other peaks in excess of the average current drain.
add a comment |Â
up vote
3
down vote
up vote
3
down vote
A 50W transmitter is one that can create 50 watts of RF output. The RF amplifier is never 100% efficient, so the input power requirements will always be higher than the output power.
Furthermore, the maximum current drain accounts for startup transients and other peaks in excess of the average current drain.
A 50W transmitter is one that can create 50 watts of RF output. The RF amplifier is never 100% efficient, so the input power requirements will always be higher than the output power.
Furthermore, the maximum current drain accounts for startup transients and other peaks in excess of the average current drain.
answered 1 hour ago
Phil Frost - W8II
25.2k140113
25.2k140113
add a comment |Â
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fham.stackexchange.com%2fquestions%2f11922%2funderstanding-power-supply-requirements%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password