Is it possible to draw a hollow circle using polygon?

Clash Royale CLAN TAG#URR8PPP

up vote
1
down vote

favorite

The question is simple. I have the following commands

r = 0.24;
R = 0.25; 

unitcircle = 
 Table[Sin[[Theta]], Cos[[Theta]], [Theta], 2 [Pi], 0, -[Pi]/
 40] // N;
 incircle = r*unitcircle;
 outcircle = R*unitcircle;

which define the outer points and inner points of a hollow circle. Is it possible to draw such a hollow circle using the polygon command?

graphics graphics3d polygons drawing

share|improve this question

asked 5 hours ago

Msen Rezaee

39228

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  Kind of yes, but should you? No. See Annulus and if it should be a polygon take a look at FilledCurve.
  – Kuba♦
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  But, with the command polygon no. right? something like playing with the points that you input to Polygon?
  – Msen Rezaee
  5 hours ago
  
  

  
  
  
  

add a comment | 

up vote
1
down vote

favorite

The question is simple. I have the following commands

r = 0.24;
R = 0.25; 

unitcircle = 
 Table[Sin[[Theta]], Cos[[Theta]], [Theta], 2 [Pi], 0, -[Pi]/
 40] // N;
 incircle = r*unitcircle;
 outcircle = R*unitcircle;

which define the outer points and inner points of a hollow circle. Is it possible to draw such a hollow circle using the polygon command?

graphics graphics3d polygons drawing

share|improve this question

asked 5 hours ago

Msen Rezaee

39228

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  Kind of yes, but should you? No. See Annulus and if it should be a polygon take a look at FilledCurve.
  – Kuba♦
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  But, with the command polygon no. right? something like playing with the points that you input to Polygon?
  – Msen Rezaee
  5 hours ago
  
  

  
  
  
  

add a comment | 

up vote
1
down vote

favorite

up vote
1
down vote

favorite

The question is simple. I have the following commands

r = 0.24;
R = 0.25; 

unitcircle = 
 Table[Sin[[Theta]], Cos[[Theta]], [Theta], 2 [Pi], 0, -[Pi]/
 40] // N;
 incircle = r*unitcircle;
 outcircle = R*unitcircle;

which define the outer points and inner points of a hollow circle. Is it possible to draw such a hollow circle using the polygon command?

graphics graphics3d polygons drawing

share|improve this question

asked 5 hours ago

Msen Rezaee

39228

The question is simple. I have the following commands

r = 0.24;
R = 0.25; 

unitcircle = 
 Table[Sin[[Theta]], Cos[[Theta]], [Theta], 2 [Pi], 0, -[Pi]/
 40] // N;
 incircle = r*unitcircle;
 outcircle = R*unitcircle;

which define the outer points and inner points of a hollow circle. Is it possible to draw such a hollow circle using the polygon command?

graphics graphics3d polygons drawing

graphics graphics3d polygons drawing

share|improve this question

asked 5 hours ago

Msen Rezaee

39228

share|improve this question

asked 5 hours ago

Msen Rezaee

39228

share|improve this question

share|improve this question

asked 5 hours ago

Msen Rezaee

39228

asked 5 hours ago

Msen Rezaee

39228

asked 5 hours ago

Msen Rezaee

39228

39228

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  Kind of yes, but should you? No. See Annulus and if it should be a polygon take a look at FilledCurve.
  – Kuba♦
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  But, with the command polygon no. right? something like playing with the points that you input to Polygon?
  – Msen Rezaee
  5 hours ago
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  Kind of yes, but should you? No. See Annulus and if it should be a polygon take a look at FilledCurve.
  – Kuba♦
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  But, with the command polygon no. right? something like playing with the points that you input to Polygon?
  – Msen Rezaee
  5 hours ago
  
  

  
  
  
  

3

3

Kind of yes, but should you? No. See Annulus and if it should be a polygon take a look at FilledCurve.
– Kuba♦
5 hours ago

Kind of yes, but should you? No. See Annulus and if it should be a polygon take a look at FilledCurve.
– Kuba♦
5 hours ago

But, with the command polygon no. right? something like playing with the points that you input to Polygon?
– Msen Rezaee
5 hours ago

But, with the command polygon no. right? something like playing with the points that you input to Polygon?
– Msen Rezaee
5 hours ago

add a comment | 

3 Answers
3

active

oldest

votes

up vote
4
down vote



accepted

Polygon is always filled (it can be filled with white). Use Circle for a "hollow" circle.

r = 0.24; R = 0.25;

Graphics[Circle[0, 0, #] & /@ r, R]

Graphics[EdgeForm[Black], White, Polygon[CirclePoints[#, 50]] & /@ R, r]

Note that since the polygons are filled, the smaller circle must be drawn on top (last) to be seen.

EDIT: For a red background, either

Graphics[White, Annulus[0, 0, r, R], Background -> Red]

Or,

Graphics[White, Polygon[CirclePoints[R, 50]], Red, 
 Polygon[CirclePoints[r, 50]], Background -> Red]

You could also use EdgeForm to make the borders more distinct.

share|improve this answer

edited 3 hours ago

answered 5 hours ago

Bob Hanlon

55.6k23589

• 
  
  
  

  
  

  
  
  
  
  
  

  
  thanks a lot for the answer
  – Msen Rezaee
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee the question is, what do you expect to see if there is e.g. a red background.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba I expect to see red everywhere except on the thin surface of my circle
  – Msen Rezaee
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee that is unclear for me. What should be between those black edges, and what should be inside the inner edge.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba in the case of a red background, I expect to see red outside the outer edge and inside the inner edge. But not on the thin surface of the circle.
  – Msen Rezaee
  4 hours ago
  

  
  
  
  

 | 
show 1 more comment

up vote
1
down vote

FilledCurve can be used to achieve polygons (but also Bezier curves and B-splines) with holes (here formed by a two very circle-like polygons). It's a bit convoluted in this case. Red line on background for illustrative purposes:

Graphics[Thick, Red, Line[.25 -1, -1, 1, 1],
 FaceForm@White, EdgeForm@Black, 
 FilledCurve[
 List@*Line /@ 
 Table[r Sin[a], Cos[a], r, .24, .25, a, 0, 2 Pi, Pi/50]]]

share|improve this answer

edited 1 hour ago

answered 1 hour ago

kirma

9,45112756

add a comment | 

up vote
1
down vote

Here's one way:

outer = CirclePoints[2, 100];
AppendTo[outer, First[outer]];
inner = CirclePoints[1, 100];
AppendTo[inner, First[inner]];
Graphics@Polygon[Join[inner, Reverse[outer]]]

A hollow annulus is trickier:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Polygon[Join[inner, Reverse[outer]]],
 White, Thickness[0.01],
 Line[1.03 First[inner], 0.985 First[outer]]
 ]

I couldn't get away with just a polygon for this one, I had to cover up the line from where the inner circle connects to the outer. Had I done this with a polygon it would still be two polygons and not one. We can also draw another polygon like the first one here above in white to make the first one appear hollow.

As an aside, I see that Annulus has been mentioned but no one has shown how to make it hollow as far as I can tell:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Annulus
 ]

share|improve this answer

edited 23 mins ago

answered 55 mins ago

C. E.

47.7k391193

add a comment | 

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
4
down vote



accepted

Polygon is always filled (it can be filled with white). Use Circle for a "hollow" circle.

r = 0.24; R = 0.25;

Graphics[Circle[0, 0, #] & /@ r, R]

Graphics[EdgeForm[Black], White, Polygon[CirclePoints[#, 50]] & /@ R, r]

Note that since the polygons are filled, the smaller circle must be drawn on top (last) to be seen.

EDIT: For a red background, either

Graphics[White, Annulus[0, 0, r, R], Background -> Red]

Or,

Graphics[White, Polygon[CirclePoints[R, 50]], Red, 
 Polygon[CirclePoints[r, 50]], Background -> Red]

You could also use EdgeForm to make the borders more distinct.

share|improve this answer

edited 3 hours ago

answered 5 hours ago

Bob Hanlon

55.6k23589

• 
  
  
  

  
  

  
  
  
  
  
  

  
  thanks a lot for the answer
  – Msen Rezaee
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee the question is, what do you expect to see if there is e.g. a red background.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba I expect to see red everywhere except on the thin surface of my circle
  – Msen Rezaee
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee that is unclear for me. What should be between those black edges, and what should be inside the inner edge.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba in the case of a red background, I expect to see red outside the outer edge and inside the inner edge. But not on the thin surface of the circle.
  – Msen Rezaee
  4 hours ago
  

  
  
  
  

 | 
show 1 more comment

up vote
4
down vote



accepted

Polygon is always filled (it can be filled with white). Use Circle for a "hollow" circle.

r = 0.24; R = 0.25;

Graphics[Circle[0, 0, #] & /@ r, R]

Graphics[EdgeForm[Black], White, Polygon[CirclePoints[#, 50]] & /@ R, r]

Note that since the polygons are filled, the smaller circle must be drawn on top (last) to be seen.

EDIT: For a red background, either

Graphics[White, Annulus[0, 0, r, R], Background -> Red]

Or,

Graphics[White, Polygon[CirclePoints[R, 50]], Red, 
 Polygon[CirclePoints[r, 50]], Background -> Red]

You could also use EdgeForm to make the borders more distinct.

share|improve this answer

edited 3 hours ago

answered 5 hours ago

Bob Hanlon

55.6k23589

• 
  
  
  

  
  

  
  
  
  
  
  

  
  thanks a lot for the answer
  – Msen Rezaee
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee the question is, what do you expect to see if there is e.g. a red background.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba I expect to see red everywhere except on the thin surface of my circle
  – Msen Rezaee
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee that is unclear for me. What should be between those black edges, and what should be inside the inner edge.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba in the case of a red background, I expect to see red outside the outer edge and inside the inner edge. But not on the thin surface of the circle.
  – Msen Rezaee
  4 hours ago
  

  
  
  
  

 | 
show 1 more comment

up vote
4
down vote



accepted

up vote
4
down vote



accepted

Polygon is always filled (it can be filled with white). Use Circle for a "hollow" circle.

r = 0.24; R = 0.25;

Graphics[Circle[0, 0, #] & /@ r, R]

Graphics[EdgeForm[Black], White, Polygon[CirclePoints[#, 50]] & /@ R, r]

Note that since the polygons are filled, the smaller circle must be drawn on top (last) to be seen.

EDIT: For a red background, either

Graphics[White, Annulus[0, 0, r, R], Background -> Red]

Or,

Graphics[White, Polygon[CirclePoints[R, 50]], Red, 
 Polygon[CirclePoints[r, 50]], Background -> Red]

You could also use EdgeForm to make the borders more distinct.

share|improve this answer

edited 3 hours ago

answered 5 hours ago

Bob Hanlon

55.6k23589

Polygon is always filled (it can be filled with white). Use Circle for a "hollow" circle.

r = 0.24; R = 0.25;

Graphics[Circle[0, 0, #] & /@ r, R]

Graphics[EdgeForm[Black], White, Polygon[CirclePoints[#, 50]] & /@ R, r]

Note that since the polygons are filled, the smaller circle must be drawn on top (last) to be seen.

EDIT: For a red background, either

Graphics[White, Annulus[0, 0, r, R], Background -> Red]

Or,

Graphics[White, Polygon[CirclePoints[R, 50]], Red, 
 Polygon[CirclePoints[r, 50]], Background -> Red]

You could also use EdgeForm to make the borders more distinct.

share|improve this answer

edited 3 hours ago

answered 5 hours ago

Bob Hanlon

55.6k23589

share|improve this answer

share|improve this answer

edited 3 hours ago

edited 3 hours ago

edited 3 hours ago

answered 5 hours ago

Bob Hanlon

55.6k23589

answered 5 hours ago

Bob Hanlon

55.6k23589

answered 5 hours ago

Bob Hanlon

55.6k23589

55.6k23589

• 
  
  
  

  
  

  
  
  
  
  
  

  
  thanks a lot for the answer
  – Msen Rezaee
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee the question is, what do you expect to see if there is e.g. a red background.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba I expect to see red everywhere except on the thin surface of my circle
  – Msen Rezaee
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee that is unclear for me. What should be between those black edges, and what should be inside the inner edge.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba in the case of a red background, I expect to see red outside the outer edge and inside the inner edge. But not on the thin surface of the circle.
  – Msen Rezaee
  4 hours ago
  

  
  
  
  

 | 
show 1 more comment

• 
  
  
  

  
  

  
  
  
  
  
  

  
  thanks a lot for the answer
  – Msen Rezaee
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee the question is, what do you expect to see if there is e.g. a red background.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba I expect to see red everywhere except on the thin surface of my circle
  – Msen Rezaee
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @MsenRezaee that is unclear for me. What should be between those black edges, and what should be inside the inner edge.
  – Kuba♦
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba in the case of a red background, I expect to see red outside the outer edge and inside the inner edge. But not on the thin surface of the circle.
  – Msen Rezaee
  4 hours ago
  

  
  
  
  

thanks a lot for the answer
– Msen Rezaee
5 hours ago

thanks a lot for the answer
– Msen Rezaee
5 hours ago

@MsenRezaee the question is, what do you expect to see if there is e.g. a red background.
– Kuba♦
4 hours ago

@MsenRezaee the question is, what do you expect to see if there is e.g. a red background.
– Kuba♦
4 hours ago

@Kuba I expect to see red everywhere except on the thin surface of my circle
– Msen Rezaee
4 hours ago

@Kuba I expect to see red everywhere except on the thin surface of my circle
– Msen Rezaee
4 hours ago

@MsenRezaee that is unclear for me. What should be between those black edges, and what should be inside the inner edge.
– Kuba♦
4 hours ago

@MsenRezaee that is unclear for me. What should be between those black edges, and what should be inside the inner edge.
– Kuba♦
4 hours ago

@Kuba in the case of a red background, I expect to see red outside the outer edge and inside the inner edge. But not on the thin surface of the circle.
– Msen Rezaee
4 hours ago

@Kuba in the case of a red background, I expect to see red outside the outer edge and inside the inner edge. But not on the thin surface of the circle.
– Msen Rezaee
4 hours ago

 | 
show 1 more comment

up vote
1
down vote

FilledCurve can be used to achieve polygons (but also Bezier curves and B-splines) with holes (here formed by a two very circle-like polygons). It's a bit convoluted in this case. Red line on background for illustrative purposes:

Graphics[Thick, Red, Line[.25 -1, -1, 1, 1],
 FaceForm@White, EdgeForm@Black, 
 FilledCurve[
 List@*Line /@ 
 Table[r Sin[a], Cos[a], r, .24, .25, a, 0, 2 Pi, Pi/50]]]

share|improve this answer

edited 1 hour ago

answered 1 hour ago

kirma

9,45112756

add a comment | 

up vote
1
down vote

FilledCurve can be used to achieve polygons (but also Bezier curves and B-splines) with holes (here formed by a two very circle-like polygons). It's a bit convoluted in this case. Red line on background for illustrative purposes:

Graphics[Thick, Red, Line[.25 -1, -1, 1, 1],
 FaceForm@White, EdgeForm@Black, 
 FilledCurve[
 List@*Line /@ 
 Table[r Sin[a], Cos[a], r, .24, .25, a, 0, 2 Pi, Pi/50]]]

share|improve this answer

edited 1 hour ago

answered 1 hour ago

kirma

9,45112756

add a comment | 

up vote
1
down vote

up vote
1
down vote

FilledCurve can be used to achieve polygons (but also Bezier curves and B-splines) with holes (here formed by a two very circle-like polygons). It's a bit convoluted in this case. Red line on background for illustrative purposes:

Graphics[Thick, Red, Line[.25 -1, -1, 1, 1],
 FaceForm@White, EdgeForm@Black, 
 FilledCurve[
 List@*Line /@ 
 Table[r Sin[a], Cos[a], r, .24, .25, a, 0, 2 Pi, Pi/50]]]

share|improve this answer

edited 1 hour ago

answered 1 hour ago

kirma

9,45112756

FilledCurve can be used to achieve polygons (but also Bezier curves and B-splines) with holes (here formed by a two very circle-like polygons). It's a bit convoluted in this case. Red line on background for illustrative purposes:

Graphics[Thick, Red, Line[.25 -1, -1, 1, 1],
 FaceForm@White, EdgeForm@Black, 
 FilledCurve[
 List@*Line /@ 
 Table[r Sin[a], Cos[a], r, .24, .25, a, 0, 2 Pi, Pi/50]]]

share|improve this answer

edited 1 hour ago

answered 1 hour ago

kirma

9,45112756

share|improve this answer

share|improve this answer

edited 1 hour ago

edited 1 hour ago

edited 1 hour ago

answered 1 hour ago

kirma

9,45112756

answered 1 hour ago

kirma

9,45112756

answered 1 hour ago

kirma

9,45112756

9,45112756

add a comment | 

add a comment | 

up vote
1
down vote

Here's one way:

outer = CirclePoints[2, 100];
AppendTo[outer, First[outer]];
inner = CirclePoints[1, 100];
AppendTo[inner, First[inner]];
Graphics@Polygon[Join[inner, Reverse[outer]]]

A hollow annulus is trickier:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Polygon[Join[inner, Reverse[outer]]],
 White, Thickness[0.01],
 Line[1.03 First[inner], 0.985 First[outer]]
 ]

I couldn't get away with just a polygon for this one, I had to cover up the line from where the inner circle connects to the outer. Had I done this with a polygon it would still be two polygons and not one. We can also draw another polygon like the first one here above in white to make the first one appear hollow.

As an aside, I see that Annulus has been mentioned but no one has shown how to make it hollow as far as I can tell:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Annulus
 ]

share|improve this answer

edited 23 mins ago

answered 55 mins ago

C. E.

47.7k391193

add a comment | 

up vote
1
down vote

Here's one way:

outer = CirclePoints[2, 100];
AppendTo[outer, First[outer]];
inner = CirclePoints[1, 100];
AppendTo[inner, First[inner]];
Graphics@Polygon[Join[inner, Reverse[outer]]]

A hollow annulus is trickier:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Polygon[Join[inner, Reverse[outer]]],
 White, Thickness[0.01],
 Line[1.03 First[inner], 0.985 First[outer]]
 ]

I couldn't get away with just a polygon for this one, I had to cover up the line from where the inner circle connects to the outer. Had I done this with a polygon it would still be two polygons and not one. We can also draw another polygon like the first one here above in white to make the first one appear hollow.

As an aside, I see that Annulus has been mentioned but no one has shown how to make it hollow as far as I can tell:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Annulus
 ]

share|improve this answer

edited 23 mins ago

answered 55 mins ago

C. E.

47.7k391193

add a comment | 

up vote
1
down vote

up vote
1
down vote

Here's one way:

outer = CirclePoints[2, 100];
AppendTo[outer, First[outer]];
inner = CirclePoints[1, 100];
AppendTo[inner, First[inner]];
Graphics@Polygon[Join[inner, Reverse[outer]]]

A hollow annulus is trickier:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Polygon[Join[inner, Reverse[outer]]],
 White, Thickness[0.01],
 Line[1.03 First[inner], 0.985 First[outer]]
 ]

I couldn't get away with just a polygon for this one, I had to cover up the line from where the inner circle connects to the outer. Had I done this with a polygon it would still be two polygons and not one. We can also draw another polygon like the first one here above in white to make the first one appear hollow.

As an aside, I see that Annulus has been mentioned but no one has shown how to make it hollow as far as I can tell:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Annulus
 ]

share|improve this answer

edited 23 mins ago

answered 55 mins ago

C. E.

47.7k391193

Here's one way:

outer = CirclePoints[2, 100];
AppendTo[outer, First[outer]];
inner = CirclePoints[1, 100];
AppendTo[inner, First[inner]];
Graphics@Polygon[Join[inner, Reverse[outer]]]

A hollow annulus is trickier:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Polygon[Join[inner, Reverse[outer]]],
 White, Thickness[0.01],
 Line[1.03 First[inner], 0.985 First[outer]]
 ]

I couldn't get away with just a polygon for this one, I had to cover up the line from where the inner circle connects to the outer. Had I done this with a polygon it would still be two polygons and not one. We can also draw another polygon like the first one here above in white to make the first one appear hollow.

As an aside, I see that Annulus has been mentioned but no one has shown how to make it hollow as far as I can tell:

Graphics[
 FaceForm,
 EdgeForm[Black],
 Annulus
 ]

share|improve this answer

edited 23 mins ago

answered 55 mins ago

C. E.

47.7k391193

share|improve this answer

share|improve this answer

edited 23 mins ago

edited 23 mins ago

edited 23 mins ago

answered 55 mins ago

C. E.

47.7k391193

answered 55 mins ago

C. E.

47.7k391193

answered 55 mins ago

C. E.

47.7k391193

47.7k391193

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