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Why does this simple circuit oscillate? (Ekasi oscillator)
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Why does an Ekasi oscillator oscillate?
From my research, I learned that when this is first plugged in, the capacitor is charging, so the LED doesn't shine.
When the capacitor reaches 12v, then the current switches to the top loop (which is possible because the voltage of the battery equals to the breakdown voltage of the flipped transistor). Note, because we are using its breakdown voltage, the base doesn't need to be connected.
As for its oscillation, I read that when the current goes through the top loop (and the LED is shining), the capacitor begins to discharge. So, because the voltage across the capacitor goes down, the current stops flowing to the top loop and goes back to the capacitor to recharge it (so the LED stops shining). This repeats, creating an oscillation/blinking LED light.
My question is: why would the capacitor discharge after it reaches 12V? What causes it to begin to discharge? Is it because when it's fully charged, no current is flowing towards it, "preventing" it from discharging? So it's free to begin discharging, but as soon as it does, then it begins to slowly recharge once again, creating this repetition? Sorry if it's a bad question folks, I just recently got into electricity! :)
Here's the schematic:
simulate this circuit – Schematic created using CircuitLab
transistors led capacitor oscillator
asked 3 hours ago
F16Falcon
111
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F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
2
down vote
favorite
Why does an Ekasi oscillator oscillate?
From my research, I learned that when this is first plugged in, the capacitor is charging, so the LED doesn't shine.
When the capacitor reaches 12v, then the current switches to the top loop (which is possible because the voltage of the battery equals to the breakdown voltage of the flipped transistor). Note, because we are using its breakdown voltage, the base doesn't need to be connected.
As for its oscillation, I read that when the current goes through the top loop (and the LED is shining), the capacitor begins to discharge. So, because the voltage across the capacitor goes down, the current stops flowing to the top loop and goes back to the capacitor to recharge it (so the LED stops shining). This repeats, creating an oscillation/blinking LED light.
My question is: why would the capacitor discharge after it reaches 12V? What causes it to begin to discharge? Is it because when it's fully charged, no current is flowing towards it, "preventing" it from discharging? So it's free to begin discharging, but as soon as it does, then it begins to slowly recharge once again, creating this repetition? Sorry if it's a bad question folks, I just recently got into electricity! :)
Here's the schematic:
simulate this circuit – Schematic created using CircuitLab
transistors led capacitor oscillator
asked 3 hours ago
F16Falcon
111
New contributor
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
What is the internal resistance of the battery?
– analogsystemsrf
3 hours ago
Your circuit does not work, the capacitor is simply across the battery and does nothing. Read this for the correct circuit: cappels.org/dproj/simplest_LED_flasher/…
– Jack Creasey
2 hours ago
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
Why does an Ekasi oscillator oscillate?
From my research, I learned that when this is first plugged in, the capacitor is charging, so the LED doesn't shine.
When the capacitor reaches 12v, then the current switches to the top loop (which is possible because the voltage of the battery equals to the breakdown voltage of the flipped transistor). Note, because we are using its breakdown voltage, the base doesn't need to be connected.
As for its oscillation, I read that when the current goes through the top loop (and the LED is shining), the capacitor begins to discharge. So, because the voltage across the capacitor goes down, the current stops flowing to the top loop and goes back to the capacitor to recharge it (so the LED stops shining). This repeats, creating an oscillation/blinking LED light.
My question is: why would the capacitor discharge after it reaches 12V? What causes it to begin to discharge? Is it because when it's fully charged, no current is flowing towards it, "preventing" it from discharging? So it's free to begin discharging, but as soon as it does, then it begins to slowly recharge once again, creating this repetition? Sorry if it's a bad question folks, I just recently got into electricity! :)
Here's the schematic:
simulate this circuit – Schematic created using CircuitLab
transistors led capacitor oscillator
asked 3 hours ago
F16Falcon
111
New contributor
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Why does an Ekasi oscillator oscillate?
From my research, I learned that when this is first plugged in, the capacitor is charging, so the LED doesn't shine.
When the capacitor reaches 12v, then the current switches to the top loop (which is possible because the voltage of the battery equals to the breakdown voltage of the flipped transistor). Note, because we are using its breakdown voltage, the base doesn't need to be connected.
As for its oscillation, I read that when the current goes through the top loop (and the LED is shining), the capacitor begins to discharge. So, because the voltage across the capacitor goes down, the current stops flowing to the top loop and goes back to the capacitor to recharge it (so the LED stops shining). This repeats, creating an oscillation/blinking LED light.
My question is: why would the capacitor discharge after it reaches 12V? What causes it to begin to discharge? Is it because when it's fully charged, no current is flowing towards it, "preventing" it from discharging? So it's free to begin discharging, but as soon as it does, then it begins to slowly recharge once again, creating this repetition? Sorry if it's a bad question folks, I just recently got into electricity! :)
Here's the schematic:
simulate this circuit – Schematic created using CircuitLab
transistors led capacitor oscillator
transistors led capacitor oscillator
asked 3 hours ago
F16Falcon
111
New contributor
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
F16Falcon
111
New contributor
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
F16Falcon
111
New contributor
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
F16Falcon
111
asked 3 hours ago
F16Falcon
111
111
New contributor
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
F16Falcon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
What is the internal resistance of the battery?
– analogsystemsrf
3 hours ago
Your circuit does not work, the capacitor is simply across the battery and does nothing. Read this for the correct circuit: cappels.org/dproj/simplest_LED_flasher/…
– Jack Creasey
2 hours ago
add a comment |Â
What is the internal resistance of the battery?
– analogsystemsrf
3 hours ago
Your circuit does not work, the capacitor is simply across the battery and does nothing. Read this for the correct circuit: cappels.org/dproj/simplest_LED_flasher/…
– Jack Creasey
2 hours ago
What is the internal resistance of the battery?
– analogsystemsrf
3 hours ago
What is the internal resistance of the battery?
– analogsystemsrf
3 hours ago
Your circuit does not work, the capacitor is simply across the battery and does nothing. Read this for the correct circuit: cappels.org/dproj/simplest_LED_flasher/…
– Jack Creasey
2 hours ago
Your circuit does not work, the capacitor is simply across the battery and does nothing. Read this for the correct circuit: cappels.org/dproj/simplest_LED_flasher/…
– Jack Creasey
2 hours ago
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
2
down vote
First, the circuit as you present it is a bit too simple -- the resistor in series with the battery as shown on this page is necessary, and must be about the right value.
Second, the reason the capacitor will discharge (in the correct circuit) is because the LED-transistor string is consuming more current than the battery (through that resistor you left out) is supplying -- so the capacitor discharges.
answered 3 hours ago
TimWescott
3495
add a comment |Â
up vote
2
down vote
If you just got into electronics, skip this example and learn the fundamentals.
Its 2 pin reverse biased part is being over stressed to create an abrupt discharge switch to allow discharging the series R current limited Cap charge.
This mode puts the transistor into DIAC like mode but only a poor version . Which is a Vthreshold triggered negative incremental resistance until the hold current threshold reverts back to high impedance.
In other words we call it a simple Relaxation Oscillator which is far better done with a simple Schmitt Logic Inverter. With R feedback and C to gnd.
edited 2 hours ago
Neil_UK
70.8k273155
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
First, the circuit as you present it is a bit too simple -- the resistor in series with the battery as shown on this page is necessary, and must be about the right value.
Second, the reason the capacitor will discharge (in the correct circuit) is because the LED-transistor string is consuming more current than the battery (through that resistor you left out) is supplying -- so the capacitor discharges.
answered 3 hours ago
TimWescott
3495
add a comment |Â
up vote
2
down vote
First, the circuit as you present it is a bit too simple -- the resistor in series with the battery as shown on this page is necessary, and must be about the right value.
Second, the reason the capacitor will discharge (in the correct circuit) is because the LED-transistor string is consuming more current than the battery (through that resistor you left out) is supplying -- so the capacitor discharges.
answered 3 hours ago
TimWescott
3495
add a comment |Â
up vote
2
down vote
up vote
2
down vote
First, the circuit as you present it is a bit too simple -- the resistor in series with the battery as shown on this page is necessary, and must be about the right value.
Second, the reason the capacitor will discharge (in the correct circuit) is because the LED-transistor string is consuming more current than the battery (through that resistor you left out) is supplying -- so the capacitor discharges.
answered 3 hours ago
TimWescott
3495
First, the circuit as you present it is a bit too simple -- the resistor in series with the battery as shown on this page is necessary, and must be about the right value.
Second, the reason the capacitor will discharge (in the correct circuit) is because the LED-transistor string is consuming more current than the battery (through that resistor you left out) is supplying -- so the capacitor discharges.
answered 3 hours ago
TimWescott
3495
answered 3 hours ago
TimWescott
3495
answered 3 hours ago
TimWescott
3495
answered 3 hours ago
TimWescott
3495
3495
add a comment |Â
add a comment |Â
up vote
2
down vote
If you just got into electronics, skip this example and learn the fundamentals.
Its 2 pin reverse biased part is being over stressed to create an abrupt discharge switch to allow discharging the series R current limited Cap charge.
This mode puts the transistor into DIAC like mode but only a poor version . Which is a Vthreshold triggered negative incremental resistance until the hold current threshold reverts back to high impedance.
In other words we call it a simple Relaxation Oscillator which is far better done with a simple Schmitt Logic Inverter. With R feedback and C to gnd.
edited 2 hours ago
Neil_UK
70.8k273155
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
add a comment |Â
up vote
2
down vote
If you just got into electronics, skip this example and learn the fundamentals.
Its 2 pin reverse biased part is being over stressed to create an abrupt discharge switch to allow discharging the series R current limited Cap charge.
This mode puts the transistor into DIAC like mode but only a poor version . Which is a Vthreshold triggered negative incremental resistance until the hold current threshold reverts back to high impedance.
In other words we call it a simple Relaxation Oscillator which is far better done with a simple Schmitt Logic Inverter. With R feedback and C to gnd.
edited 2 hours ago
Neil_UK
70.8k273155
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
add a comment |Â
up vote
2
down vote
up vote
2
down vote
If you just got into electronics, skip this example and learn the fundamentals.
Its 2 pin reverse biased part is being over stressed to create an abrupt discharge switch to allow discharging the series R current limited Cap charge.
This mode puts the transistor into DIAC like mode but only a poor version . Which is a Vthreshold triggered negative incremental resistance until the hold current threshold reverts back to high impedance.
In other words we call it a simple Relaxation Oscillator which is far better done with a simple Schmitt Logic Inverter. With R feedback and C to gnd.
edited 2 hours ago
Neil_UK
70.8k273155
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
If you just got into electronics, skip this example and learn the fundamentals.
Its 2 pin reverse biased part is being over stressed to create an abrupt discharge switch to allow discharging the series R current limited Cap charge.
This mode puts the transistor into DIAC like mode but only a poor version . Which is a Vthreshold triggered negative incremental resistance until the hold current threshold reverts back to high impedance.
In other words we call it a simple Relaxation Oscillator which is far better done with a simple Schmitt Logic Inverter. With R feedback and C to gnd.
edited 2 hours ago
Neil_UK
70.8k273155
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
edited 2 hours ago
Neil_UK
70.8k273155
edited 2 hours ago
Neil_UK
70.8k273155
edited 2 hours ago
Neil_UK
70.8k273155
70.8k273155
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
answered 3 hours ago
Tony EE rocketscientist
59.8k22090
59.8k22090
add a comment |Â
add a comment |Â
F16Falcon is a new contributor. Be nice, and check out our Code of Conduct.
F16Falcon is a new contributor. Be nice, and check out our Code of Conduct.
F16Falcon is a new contributor. Be nice, and check out our Code of Conduct.
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What is the internal resistance of the battery?
– analogsystemsrf
3 hours ago
Your circuit does not work, the capacitor is simply across the battery and does nothing. Read this for the correct circuit: cappels.org/dproj/simplest_LED_flasher/…
– Jack Creasey
2 hours ago