Column space and null space
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Let $Ain M_5,7(mathbbR)$ be a matrix such that $Ax=b$ has solution for every $b$.
I have to say what this information tells me about column- and null-space and rows of a matrix. The only thing I can think of is that column-space can have dimension $1$ to $5$ and null-space dimension can be deduced using rank-nullity theorem.
Is there something more to see here?
linear-algebra matrices systems-of-equations
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up vote
4
down vote
favorite
Let $Ain M_5,7(mathbbR)$ be a matrix such that $Ax=b$ has solution for every $b$.
I have to say what this information tells me about column- and null-space and rows of a matrix. The only thing I can think of is that column-space can have dimension $1$ to $5$ and null-space dimension can be deduced using rank-nullity theorem.
Is there something more to see here?
linear-algebra matrices systems-of-equations
add a comment |Â
up vote
4
down vote
favorite
up vote
4
down vote
favorite
Let $Ain M_5,7(mathbbR)$ be a matrix such that $Ax=b$ has solution for every $b$.
I have to say what this information tells me about column- and null-space and rows of a matrix. The only thing I can think of is that column-space can have dimension $1$ to $5$ and null-space dimension can be deduced using rank-nullity theorem.
Is there something more to see here?
linear-algebra matrices systems-of-equations
Let $Ain M_5,7(mathbbR)$ be a matrix such that $Ax=b$ has solution for every $b$.
I have to say what this information tells me about column- and null-space and rows of a matrix. The only thing I can think of is that column-space can have dimension $1$ to $5$ and null-space dimension can be deduced using rank-nullity theorem.
Is there something more to see here?
linear-algebra matrices systems-of-equations
linear-algebra matrices systems-of-equations
asked 3 hours ago
smiljanic997
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1 Answer
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Column space is all of $mathbbR^5$ since any $bin mathbbR^5$ appears in the range of $A$. Thus rank is 5, and so the rank-nullity theorem says $5+mathrmnullity=7$, thus $mathrmnullity=2$.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
Column space is all of $mathbbR^5$ since any $bin mathbbR^5$ appears in the range of $A$. Thus rank is 5, and so the rank-nullity theorem says $5+mathrmnullity=7$, thus $mathrmnullity=2$.
add a comment |Â
up vote
5
down vote
Column space is all of $mathbbR^5$ since any $bin mathbbR^5$ appears in the range of $A$. Thus rank is 5, and so the rank-nullity theorem says $5+mathrmnullity=7$, thus $mathrmnullity=2$.
add a comment |Â
up vote
5
down vote
up vote
5
down vote
Column space is all of $mathbbR^5$ since any $bin mathbbR^5$ appears in the range of $A$. Thus rank is 5, and so the rank-nullity theorem says $5+mathrmnullity=7$, thus $mathrmnullity=2$.
Column space is all of $mathbbR^5$ since any $bin mathbbR^5$ appears in the range of $A$. Thus rank is 5, and so the rank-nullity theorem says $5+mathrmnullity=7$, thus $mathrmnullity=2$.
answered 3 hours ago
Ben Mares
1212
1212
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