Display numbers lacking 2's

Clash Royale CLAN TAG#URR8PPP

up vote
3
down vote

favorite

Display numbers from one to one-hundred (in increasing order), but number 2 shouldn’t appear anywhere in the sequence. So, for example, the numbers two (2) or twenty-three (23) shouldn't be in the sequence.

Here is an example output, with newlines separating the numbers:

1
3
4
5
6
7
8
9
10
11
13
14
15
16
17
18
19
30
31
33
34
35
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85
86
87
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90
91
93
94
95
96
97
98
99
100

code-golf sequence kolmogorov-complexity

share|improve this question

edited 16 mins ago

xnor

87.1k17181431

asked 11 hours ago

Monolica

483

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Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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• 
  
  
  

  
  6
  

  
  
  
  
  
  

  
  I assume the winning criteria is code-golf right?
  – Luis felipe De jesus Munoz
  11 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Does the order matter? ('Sequence' seems to imply that it does.)
  – Arnauld
  11 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Our site does not work the same way as other sites from the Stack Exchange network. Regarding accepted answers, please take this comment from Jonathan Allan into account. And please add a winning criterion.
  – Arnauld
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Might I suggest using the Sandbox in the future to get feedback on your challenges before posting?
  – Jo King
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Monolica If the shortest answer wins, you'll need the tag [code-golf]. Here is a list for all available winning criteria tags for future reference.
  – Kevin Cruijssen
  10 hours ago
  
  

  
  
  
  

 | 
show 7 more comments

up vote
3
down vote

favorite

Display numbers from one to one-hundred (in increasing order), but number 2 shouldn’t appear anywhere in the sequence. So, for example, the numbers two (2) or twenty-three (23) shouldn't be in the sequence.

Here is an example output, with newlines separating the numbers:

1
3
4
5
6
7
8
9
10
11
13
14
15
16
17
18
19
30
31
33
34
35
36
37
38
39
40
41
43
44
45
46
47
48
49
50
51
53
54
55
56
57
58
59
60
61
63
64
65
66
67
68
69
70
71
73
74
75
76
77
78
79
80
81
83
84
85
86
87
88
89
90
91
93
94
95
96
97
98
99
100

code-golf sequence kolmogorov-complexity

share|improve this question

edited 16 mins ago

xnor

87.1k17181431

asked 11 hours ago

Monolica

483

New contributor

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  6
  

  
  
  
  
  
  

  
  I assume the winning criteria is code-golf right?
  – Luis felipe De jesus Munoz
  11 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Does the order matter? ('Sequence' seems to imply that it does.)
  – Arnauld
  11 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Our site does not work the same way as other sites from the Stack Exchange network. Regarding accepted answers, please take this comment from Jonathan Allan into account. And please add a winning criterion.
  – Arnauld
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Might I suggest using the Sandbox in the future to get feedback on your challenges before posting?
  – Jo King
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Monolica If the shortest answer wins, you'll need the tag [code-golf]. Here is a list for all available winning criteria tags for future reference.
  – Kevin Cruijssen
  10 hours ago
  
  

  
  
  
  

 | 
show 7 more comments

up vote
3
down vote

favorite

up vote
3
down vote

favorite

Display numbers from one to one-hundred (in increasing order), but number 2 shouldn’t appear anywhere in the sequence. So, for example, the numbers two (2) or twenty-three (23) shouldn't be in the sequence.

Here is an example output, with newlines separating the numbers:

1
3
4
5
6
7
8
9
10
11
13
14
15
16
17
18
19
30
31
33
34
35
36
37
38
39
40
41
43
44
45
46
47
48
49
50
51
53
54
55
56
57
58
59
60
61
63
64
65
66
67
68
69
70
71
73
74
75
76
77
78
79
80
81
83
84
85
86
87
88
89
90
91
93
94
95
96
97
98
99
100

code-golf sequence kolmogorov-complexity

share|improve this question

edited 16 mins ago

xnor

87.1k17181431

asked 11 hours ago

Monolica

483

New contributor

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Display numbers from one to one-hundred (in increasing order), but number 2 shouldn’t appear anywhere in the sequence. So, for example, the numbers two (2) or twenty-three (23) shouldn't be in the sequence.

Here is an example output, with newlines separating the numbers:

1
3
4
5
6
7
8
9
10
11
13
14
15
16
17
18
19
30
31
33
34
35
36
37
38
39
40
41
43
44
45
46
47
48
49
50
51
53
54
55
56
57
58
59
60
61
63
64
65
66
67
68
69
70
71
73
74
75
76
77
78
79
80
81
83
84
85
86
87
88
89
90
91
93
94
95
96
97
98
99
100

code-golf sequence kolmogorov-complexity

code-golf sequence kolmogorov-complexity

share|improve this question

edited 16 mins ago

xnor

87.1k17181431

asked 11 hours ago

Monolica

483

New contributor

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 16 mins ago

xnor

87.1k17181431

asked 11 hours ago

Monolica

483

New contributor

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

share|improve this question

edited 16 mins ago

xnor

87.1k17181431

edited 16 mins ago

xnor

87.1k17181431

edited 16 mins ago

xnor

87.1k17181431

87.1k17181431

asked 11 hours ago

Monolica

483

New contributor

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 11 hours ago

Monolica

483

asked 11 hours ago

Monolica

483

483

New contributor

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

New contributor

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Monolica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  6
  

  
  
  
  
  
  

  
  I assume the winning criteria is code-golf right?
  – Luis felipe De jesus Munoz
  11 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Does the order matter? ('Sequence' seems to imply that it does.)
  – Arnauld
  11 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Our site does not work the same way as other sites from the Stack Exchange network. Regarding accepted answers, please take this comment from Jonathan Allan into account. And please add a winning criterion.
  – Arnauld
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Might I suggest using the Sandbox in the future to get feedback on your challenges before posting?
  – Jo King
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Monolica If the shortest answer wins, you'll need the tag [code-golf]. Here is a list for all available winning criteria tags for future reference.
  – Kevin Cruijssen
  10 hours ago
  
  

  
  
  
  

 | 
show 7 more comments

• 
  
  
  

  
  6
  

  
  
  
  
  
  

  
  I assume the winning criteria is code-golf right?
  – Luis felipe De jesus Munoz
  11 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Does the order matter? ('Sequence' seems to imply that it does.)
  – Arnauld
  11 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Our site does not work the same way as other sites from the Stack Exchange network. Regarding accepted answers, please take this comment from Jonathan Allan into account. And please add a winning criterion.
  – Arnauld
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Might I suggest using the Sandbox in the future to get feedback on your challenges before posting?
  – Jo King
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Monolica If the shortest answer wins, you'll need the tag [code-golf]. Here is a list for all available winning criteria tags for future reference.
  – Kevin Cruijssen
  10 hours ago
  
  

  
  
  
  

6

6

I assume the winning criteria is code-golf right?
– Luis felipe De jesus Munoz
11 hours ago

I assume the winning criteria is code-golf right?
– Luis felipe De jesus Munoz
11 hours ago

Does the order matter? ('Sequence' seems to imply that it does.)
– Arnauld
11 hours ago

Does the order matter? ('Sequence' seems to imply that it does.)
– Arnauld
11 hours ago

2

2

Our site does not work the same way as other sites from the Stack Exchange network. Regarding accepted answers, please take this comment from Jonathan Allan into account. And please add a winning criterion.
– Arnauld
10 hours ago

Our site does not work the same way as other sites from the Stack Exchange network. Regarding accepted answers, please take this comment from Jonathan Allan into account. And please add a winning criterion.
– Arnauld
10 hours ago

1

1

Might I suggest using the Sandbox in the future to get feedback on your challenges before posting?
– Jo King
10 hours ago

Might I suggest using the Sandbox in the future to get feedback on your challenges before posting?
– Jo King
10 hours ago

1

1

@Monolica If the shortest answer wins, you'll need the tag [code-golf]. Here is a list for all available winning criteria tags for future reference.
– Kevin Cruijssen
10 hours ago

@Monolica If the shortest answer wins, you'll need the tag [code-golf]. Here is a list for all available winning criteria tags for future reference.
– Kevin Cruijssen
10 hours ago

 | 
show 7 more comments

13 Answers
13

active

oldest

votes

up vote
5
down vote



accepted

05AB1E, 6 bytes

тLʒ2å_

Try it online!

Explanation

тL # push [1 ... 100]
 ʒ # filter, keep only elements that
 2Ã¥_ # does not contain 2

share|improve this answer

answered 11 hours ago

Emigna

43.5k431131

add a comment | 

up vote
6
down vote

R, 19 bytes

grep(2,1:100,inv=T)

Try it online!

share|improve this answer

edited 5 hours ago

answered 10 hours ago

ngm

2,47920

• 
  
  
  

  
  

  
  
  
  
  
  

  
  grep(2,1:100,inv=T) for 19.
  – J.Doe
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Ha - this was what I tried at first but with v=F as well because obviously, I thought to myself, I want the values and not the indices...duh!
  – ngm
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Inverting the regex itself is a byte shorter (in this case).
  – ngm
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Doesn't work, still lets 2s past. You'd need ^[^2]*$ which is, um, not shorter.
  – J.Doe
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  What, are we supposed to check our answers now?
  – ngm
  5 hours ago
  

  
  
  
  

add a comment | 

up vote
4
down vote

Python 2, 44 bytes

print[n for n in range(1,101)if'2'not in`n`]

Try it online!

share|improve this answer

answered 11 hours ago

TFeld

12k2833

add a comment | 

up vote
3
down vote

Java 10, 67 bytes

v->for(int i=0;++i<101;)if(i%10!=2&i/10!=2)System.out.println(i);

Try it online.

Explanation:

v-> // Method with empty unused parameter and no return-type
 for(int i=0;++i<101;) // Loop `i` in the range (0, 101)
 if(i%10!=2 // If `i` modulo-10 is not 2
 &i/10!=2) // And `i` integer-divided by 10 is not 2 either
 System.out.println(i); // Print `i` with a trailing newline

share|improve this answer

answered 10 hours ago

Kevin Cruijssen

30.9k553168

add a comment | 

up vote
3
down vote

Perl 6, 22 bytes

put grep !/2/,1..100

Try it online!

There's probably a better way to do the code block, but I couldn't find a regex adverb to invert the match

share|improve this answer

edited 10 hours ago

answered 11 hours ago

Jo King

16.6k24190

• 
  
  
  

  
  

  
  
  
  
  
  

  
  remove the brackets around the numbers. Otherwise it is fine.
  – Monolica
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Monolica Fixed
  – Jo King
  10 hours ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

JavaScript (ES6), 43 bytes

Returns the sequence as a comma-separated string.

f=(n=98)=>n?f(n-=n-27?n%10?1:2:11)+[,n+3]:1

Try it online!

Why doing it this way?

We could iterate from $1$ to $100$ and test each number with /2/.test(n), which is a rather concise statement. But in this scenario, we'd have to handle empty entries with something like (/2/.test(n)?'':...), which adds a couple more bytes.

For example, this would work for 45 bytes:

f=(n=1)=>n>99?n:(/2/.test(n)?'':[n,,])+f(n+1)

Or this would work for 44 bytes, if a leading comma is acceptable:

f=(n=100)=>n?f(n-1)+(/2/.test(n)?'':[,n]):''

All in all (and until proven otherwise), it turns out to be shorter to skip right away all values of $n$ that contain a $2$.

Commented

f = // f is a recursive function taking:
(n = 98) => // n = counter, initialized to 98
 n ? // if n is not equal to 0:
 f( // prepend the result of a recursive call:
 n -= // update n:
 n - 27 ? // if n is not equal to 27:
 n % 10 ? // if n is not a multiple of 10:
 1 // subtract 1 from n
 : // else:
 2 // subtract 2 from n
 : // else (n = 27):
 11 // subtract 11 from n (--> 16)
 ) + // end of recursive call
 [, n + 3] // append a comma, followed by n + 3; notice that this is the value
 // of n *after* it was updated for the recursive call; at the first
 // iteration, we have: n = 98 -> updated to 97 -> n + 3 = 100
 : // else (n = 0):
 1 // output the first term '1' and stop recursion

share|improve this answer

edited 8 hours ago

answered 10 hours ago

Arnauld

65.6k583277

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This is so cool!
  – Emigna
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

Japt, 7 bytes

Lõs kø2

Try it online!

share|improve this answer

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

add a comment | 

up vote
2
down vote

Tcl, 47 bytes

time if [incr i]%10!=2&$i/10!=2 puts $i 100

Try it online!

---

Tcl, 50 bytes

time if 2 ni [split [incr i] ""] puts $i 100

Try it online!

share|improve this answer

edited 10 hours ago

answered 10 hours ago

sergiol

2,1771825

add a comment | 

up vote
2
down vote

Red, 44 bytes

repeat n 100[unless find form n"2"[print n]]

Try it online!

Uses unless instead of if not, because why not? :)

share|improve this answer

edited 10 hours ago

answered 10 hours ago

Galen Ivanov

4,9671929

add a comment | 

up vote
2
down vote

PowerShell, 22 bytes

1..100|?$_-notmatch2

Try it online!

Generates the range 1 to 100, then pulls out those objects where |?... they do -notmatch the number 2. Each item is left on the pipeline, and output is implicit.

share|improve this answer

answered 3 hours ago

AdmBorkBork

24.7k360215

add a comment | 

up vote
1
down vote

Retina, 19 bytes

100*
L$`.
$.>`
A`2

Try it online! Explanation:

100*

Insert 100 characters.

L$`.
$.>`

For each character, list the number of characters up to and including that character.

A`2

Remove all entries that contain a 2.

share|improve this answer

answered 11 hours ago

Neil

75.8k744171

add a comment | 

up vote
1
down vote

Stax, 6 bytes

Ç░τ╒╜h

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

AJ 10 squared
f output each value in [1 .. n] satisfying the following filter
 E get array of decimal digits in number
 2# count the number of 2s
 ! logical not

Run this one

share|improve this answer

answered 3 hours ago

recursive

4,4561220

add a comment | 

up vote
0
down vote

Python 2, 39 bytes

k=7
exec"k+=10;print(k>177)*10+k/9;"*81

Try it online!

Uses arithmetic operations only to generate numbers without 2's.

The value k follows the arithmetic progression 17, 27, 37, 47, ..., which when floor-divided by 9 gives 1,3,4,5,6,7,8,9,10,11,13,14,... which counts up numbers not ending in 2. To skip 20 through 29, outputs are increased by 10 past a certain threshold.

share|improve this answer

answered 43 mins ago

xnor

87.1k17181431

add a comment | 

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13 Answers
13

active

oldest

votes

13 Answers
13

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
5
down vote



accepted

05AB1E, 6 bytes

тLʒ2å_

Try it online!

Explanation

тL # push [1 ... 100]
 ʒ # filter, keep only elements that
 2Ã¥_ # does not contain 2

share|improve this answer

answered 11 hours ago

Emigna

43.5k431131

add a comment | 

up vote
5
down vote



accepted

05AB1E, 6 bytes

тLʒ2å_

Try it online!

Explanation

тL # push [1 ... 100]
 ʒ # filter, keep only elements that
 2Ã¥_ # does not contain 2

share|improve this answer

answered 11 hours ago

Emigna

43.5k431131

add a comment | 

up vote
5
down vote



accepted

up vote
5
down vote



accepted

05AB1E, 6 bytes

тLʒ2å_

Try it online!

Explanation

тL # push [1 ... 100]
 ʒ # filter, keep only elements that
 2Ã¥_ # does not contain 2

share|improve this answer

answered 11 hours ago

Emigna

43.5k431131

05AB1E, 6 bytes

тLʒ2å_

Try it online!

Explanation

тL # push [1 ... 100]
 ʒ # filter, keep only elements that
 2Ã¥_ # does not contain 2

share|improve this answer

answered 11 hours ago

Emigna

43.5k431131

share|improve this answer

share|improve this answer

answered 11 hours ago

Emigna

43.5k431131

answered 11 hours ago

Emigna

43.5k431131

answered 11 hours ago

Emigna

43.5k431131

43.5k431131

add a comment | 

add a comment | 

up vote
6
down vote

R, 19 bytes

grep(2,1:100,inv=T)

Try it online!

share|improve this answer

edited 5 hours ago

answered 10 hours ago

ngm

2,47920

• 
  
  
  

  
  

  
  
  
  
  
  

  
  grep(2,1:100,inv=T) for 19.
  – J.Doe
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Ha - this was what I tried at first but with v=F as well because obviously, I thought to myself, I want the values and not the indices...duh!
  – ngm
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Inverting the regex itself is a byte shorter (in this case).
  – ngm
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Doesn't work, still lets 2s past. You'd need ^[^2]*$ which is, um, not shorter.
  – J.Doe
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  What, are we supposed to check our answers now?
  – ngm
  5 hours ago
  

  
  
  
  

add a comment | 

up vote
6
down vote

R, 19 bytes

grep(2,1:100,inv=T)

Try it online!

share|improve this answer

edited 5 hours ago

answered 10 hours ago

ngm

2,47920

• 
  
  
  

  
  

  
  
  
  
  
  

  
  grep(2,1:100,inv=T) for 19.
  – J.Doe
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Ha - this was what I tried at first but with v=F as well because obviously, I thought to myself, I want the values and not the indices...duh!
  – ngm
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Inverting the regex itself is a byte shorter (in this case).
  – ngm
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Doesn't work, still lets 2s past. You'd need ^[^2]*$ which is, um, not shorter.
  – J.Doe
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  What, are we supposed to check our answers now?
  – ngm
  5 hours ago
  

  
  
  
  

add a comment | 

up vote
6
down vote

up vote
6
down vote

R, 19 bytes

grep(2,1:100,inv=T)

Try it online!

share|improve this answer

edited 5 hours ago

answered 10 hours ago

ngm

2,47920

R, 19 bytes

grep(2,1:100,inv=T)

Try it online!

share|improve this answer

edited 5 hours ago

answered 10 hours ago

ngm

2,47920

share|improve this answer

share|improve this answer

edited 5 hours ago

edited 5 hours ago

edited 5 hours ago

answered 10 hours ago

ngm

2,47920

answered 10 hours ago

ngm

2,47920

answered 10 hours ago

ngm

2,47920

2,47920

• 
  
  
  

  
  

  
  
  
  
  
  

  
  grep(2,1:100,inv=T) for 19.
  – J.Doe
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Ha - this was what I tried at first but with v=F as well because obviously, I thought to myself, I want the values and not the indices...duh!
  – ngm
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Inverting the regex itself is a byte shorter (in this case).
  – ngm
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Doesn't work, still lets 2s past. You'd need ^[^2]*$ which is, um, not shorter.
  – J.Doe
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  What, are we supposed to check our answers now?
  – ngm
  5 hours ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  grep(2,1:100,inv=T) for 19.
  – J.Doe
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Ha - this was what I tried at first but with v=F as well because obviously, I thought to myself, I want the values and not the indices...duh!
  – ngm
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Inverting the regex itself is a byte shorter (in this case).
  – ngm
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Doesn't work, still lets 2s past. You'd need ^[^2]*$ which is, um, not shorter.
  – J.Doe
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  What, are we supposed to check our answers now?
  – ngm
  5 hours ago
  

  
  
  
  

grep(2,1:100,inv=T) for 19.
– J.Doe
6 hours ago

grep(2,1:100,inv=T) for 19.
– J.Doe
6 hours ago

1

1

Ha - this was what I tried at first but with v=F as well because obviously, I thought to myself, I want the values and not the indices...duh!
– ngm
5 hours ago

Ha - this was what I tried at first but with v=F as well because obviously, I thought to myself, I want the values and not the indices...duh!
– ngm
5 hours ago

Inverting the regex itself is a byte shorter (in this case).
– ngm
5 hours ago

Inverting the regex itself is a byte shorter (in this case).
– ngm
5 hours ago

Doesn't work, still lets 2s past. You'd need ^[^2]*$ which is, um, not shorter.
– J.Doe
5 hours ago

Doesn't work, still lets 2s past. You'd need ^[^2]*$ which is, um, not shorter.
– J.Doe
5 hours ago

1

1

What, are we supposed to check our answers now?
– ngm
5 hours ago

What, are we supposed to check our answers now?
– ngm
5 hours ago

add a comment | 

up vote
4
down vote

Python 2, 44 bytes

print[n for n in range(1,101)if'2'not in`n`]

Try it online!

share|improve this answer

answered 11 hours ago

TFeld

12k2833

add a comment | 

up vote
4
down vote

Python 2, 44 bytes

print[n for n in range(1,101)if'2'not in`n`]

Try it online!

share|improve this answer

answered 11 hours ago

TFeld

12k2833

add a comment | 

up vote
4
down vote

up vote
4
down vote

Python 2, 44 bytes

print[n for n in range(1,101)if'2'not in`n`]

Try it online!

share|improve this answer

answered 11 hours ago

TFeld

12k2833

Python 2, 44 bytes

print[n for n in range(1,101)if'2'not in`n`]

Try it online!

share|improve this answer

answered 11 hours ago

TFeld

12k2833

share|improve this answer

share|improve this answer

answered 11 hours ago

TFeld

12k2833

answered 11 hours ago

TFeld

12k2833

answered 11 hours ago

TFeld

12k2833

12k2833

add a comment | 

add a comment | 

up vote
3
down vote

Java 10, 67 bytes

v->for(int i=0;++i<101;)if(i%10!=2&i/10!=2)System.out.println(i);

Try it online.

Explanation:

v-> // Method with empty unused parameter and no return-type
 for(int i=0;++i<101;) // Loop `i` in the range (0, 101)
 if(i%10!=2 // If `i` modulo-10 is not 2
 &i/10!=2) // And `i` integer-divided by 10 is not 2 either
 System.out.println(i); // Print `i` with a trailing newline

share|improve this answer

answered 10 hours ago

Kevin Cruijssen

30.9k553168

add a comment | 

up vote
3
down vote

Java 10, 67 bytes

v->for(int i=0;++i<101;)if(i%10!=2&i/10!=2)System.out.println(i);

Try it online.

Explanation:

v-> // Method with empty unused parameter and no return-type
 for(int i=0;++i<101;) // Loop `i` in the range (0, 101)
 if(i%10!=2 // If `i` modulo-10 is not 2
 &i/10!=2) // And `i` integer-divided by 10 is not 2 either
 System.out.println(i); // Print `i` with a trailing newline

share|improve this answer

answered 10 hours ago

Kevin Cruijssen

30.9k553168

add a comment | 

up vote
3
down vote

up vote
3
down vote

Java 10, 67 bytes

v->for(int i=0;++i<101;)if(i%10!=2&i/10!=2)System.out.println(i);

Try it online.

Explanation:

v-> // Method with empty unused parameter and no return-type
 for(int i=0;++i<101;) // Loop `i` in the range (0, 101)
 if(i%10!=2 // If `i` modulo-10 is not 2
 &i/10!=2) // And `i` integer-divided by 10 is not 2 either
 System.out.println(i); // Print `i` with a trailing newline

share|improve this answer

answered 10 hours ago

Kevin Cruijssen

30.9k553168

Java 10, 67 bytes

v->for(int i=0;++i<101;)if(i%10!=2&i/10!=2)System.out.println(i);

Try it online.

Explanation:

v-> // Method with empty unused parameter and no return-type
 for(int i=0;++i<101;) // Loop `i` in the range (0, 101)
 if(i%10!=2 // If `i` modulo-10 is not 2
 &i/10!=2) // And `i` integer-divided by 10 is not 2 either
 System.out.println(i); // Print `i` with a trailing newline

share|improve this answer

answered 10 hours ago

Kevin Cruijssen

30.9k553168

share|improve this answer

share|improve this answer

answered 10 hours ago

Kevin Cruijssen

30.9k553168

answered 10 hours ago

Kevin Cruijssen

30.9k553168

answered 10 hours ago

Kevin Cruijssen

30.9k553168

30.9k553168

add a comment | 

add a comment | 

up vote
3
down vote

Perl 6, 22 bytes

put grep !/2/,1..100

Try it online!

There's probably a better way to do the code block, but I couldn't find a regex adverb to invert the match

share|improve this answer

edited 10 hours ago

answered 11 hours ago

Jo King

16.6k24190

• 
  
  
  

  
  

  
  
  
  
  
  

  
  remove the brackets around the numbers. Otherwise it is fine.
  – Monolica
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Monolica Fixed
  – Jo King
  10 hours ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

Perl 6, 22 bytes

put grep !/2/,1..100

Try it online!

There's probably a better way to do the code block, but I couldn't find a regex adverb to invert the match

share|improve this answer

edited 10 hours ago

answered 11 hours ago

Jo King

16.6k24190

• 
  
  
  

  
  

  
  
  
  
  
  

  
  remove the brackets around the numbers. Otherwise it is fine.
  – Monolica
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Monolica Fixed
  – Jo King
  10 hours ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

up vote
3
down vote

Perl 6, 22 bytes

put grep !/2/,1..100

Try it online!

There's probably a better way to do the code block, but I couldn't find a regex adverb to invert the match

share|improve this answer

edited 10 hours ago

answered 11 hours ago

Jo King

16.6k24190

Perl 6, 22 bytes

put grep !/2/,1..100

Try it online!

There's probably a better way to do the code block, but I couldn't find a regex adverb to invert the match

share|improve this answer

edited 10 hours ago

answered 11 hours ago

Jo King

16.6k24190

share|improve this answer

share|improve this answer

edited 10 hours ago

edited 10 hours ago

edited 10 hours ago

answered 11 hours ago

Jo King

16.6k24190

answered 11 hours ago

Jo King

16.6k24190

answered 11 hours ago

Jo King

16.6k24190

16.6k24190

• 
  
  
  

  
  

  
  
  
  
  
  

  
  remove the brackets around the numbers. Otherwise it is fine.
  – Monolica
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Monolica Fixed
  – Jo King
  10 hours ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  remove the brackets around the numbers. Otherwise it is fine.
  – Monolica
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Monolica Fixed
  – Jo King
  10 hours ago
  

  
  
  
  

remove the brackets around the numbers. Otherwise it is fine.
– Monolica
10 hours ago

remove the brackets around the numbers. Otherwise it is fine.
– Monolica
10 hours ago

@Monolica Fixed
– Jo King
10 hours ago

@Monolica Fixed
– Jo King
10 hours ago

add a comment | 

up vote
3
down vote

JavaScript (ES6), 43 bytes

Returns the sequence as a comma-separated string.

f=(n=98)=>n?f(n-=n-27?n%10?1:2:11)+[,n+3]:1

Try it online!

Why doing it this way?

We could iterate from $1$ to $100$ and test each number with /2/.test(n), which is a rather concise statement. But in this scenario, we'd have to handle empty entries with something like (/2/.test(n)?'':...), which adds a couple more bytes.

For example, this would work for 45 bytes:

f=(n=1)=>n>99?n:(/2/.test(n)?'':[n,,])+f(n+1)

Or this would work for 44 bytes, if a leading comma is acceptable:

f=(n=100)=>n?f(n-1)+(/2/.test(n)?'':[,n]):''

All in all (and until proven otherwise), it turns out to be shorter to skip right away all values of $n$ that contain a $2$.

Commented

f = // f is a recursive function taking:
(n = 98) => // n = counter, initialized to 98
 n ? // if n is not equal to 0:
 f( // prepend the result of a recursive call:
 n -= // update n:
 n - 27 ? // if n is not equal to 27:
 n % 10 ? // if n is not a multiple of 10:
 1 // subtract 1 from n
 : // else:
 2 // subtract 2 from n
 : // else (n = 27):
 11 // subtract 11 from n (--> 16)
 ) + // end of recursive call
 [, n + 3] // append a comma, followed by n + 3; notice that this is the value
 // of n *after* it was updated for the recursive call; at the first
 // iteration, we have: n = 98 -> updated to 97 -> n + 3 = 100
 : // else (n = 0):
 1 // output the first term '1' and stop recursion

share|improve this answer

edited 8 hours ago

answered 10 hours ago

Arnauld

65.6k583277

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This is so cool!
  – Emigna
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

JavaScript (ES6), 43 bytes

Returns the sequence as a comma-separated string.

f=(n=98)=>n?f(n-=n-27?n%10?1:2:11)+[,n+3]:1

Try it online!

Why doing it this way?

We could iterate from $1$ to $100$ and test each number with /2/.test(n), which is a rather concise statement. But in this scenario, we'd have to handle empty entries with something like (/2/.test(n)?'':...), which adds a couple more bytes.

For example, this would work for 45 bytes:

f=(n=1)=>n>99?n:(/2/.test(n)?'':[n,,])+f(n+1)

Or this would work for 44 bytes, if a leading comma is acceptable:

f=(n=100)=>n?f(n-1)+(/2/.test(n)?'':[,n]):''

All in all (and until proven otherwise), it turns out to be shorter to skip right away all values of $n$ that contain a $2$.

Commented

f = // f is a recursive function taking:
(n = 98) => // n = counter, initialized to 98
 n ? // if n is not equal to 0:
 f( // prepend the result of a recursive call:
 n -= // update n:
 n - 27 ? // if n is not equal to 27:
 n % 10 ? // if n is not a multiple of 10:
 1 // subtract 1 from n
 : // else:
 2 // subtract 2 from n
 : // else (n = 27):
 11 // subtract 11 from n (--> 16)
 ) + // end of recursive call
 [, n + 3] // append a comma, followed by n + 3; notice that this is the value
 // of n *after* it was updated for the recursive call; at the first
 // iteration, we have: n = 98 -> updated to 97 -> n + 3 = 100
 : // else (n = 0):
 1 // output the first term '1' and stop recursion

share|improve this answer

edited 8 hours ago

answered 10 hours ago

Arnauld

65.6k583277

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This is so cool!
  – Emigna
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

up vote
3
down vote

JavaScript (ES6), 43 bytes

Returns the sequence as a comma-separated string.

f=(n=98)=>n?f(n-=n-27?n%10?1:2:11)+[,n+3]:1

Try it online!

Why doing it this way?

We could iterate from $1$ to $100$ and test each number with /2/.test(n), which is a rather concise statement. But in this scenario, we'd have to handle empty entries with something like (/2/.test(n)?'':...), which adds a couple more bytes.

For example, this would work for 45 bytes:

f=(n=1)=>n>99?n:(/2/.test(n)?'':[n,,])+f(n+1)

Or this would work for 44 bytes, if a leading comma is acceptable:

f=(n=100)=>n?f(n-1)+(/2/.test(n)?'':[,n]):''

All in all (and until proven otherwise), it turns out to be shorter to skip right away all values of $n$ that contain a $2$.

Commented

f = // f is a recursive function taking:
(n = 98) => // n = counter, initialized to 98
 n ? // if n is not equal to 0:
 f( // prepend the result of a recursive call:
 n -= // update n:
 n - 27 ? // if n is not equal to 27:
 n % 10 ? // if n is not a multiple of 10:
 1 // subtract 1 from n
 : // else:
 2 // subtract 2 from n
 : // else (n = 27):
 11 // subtract 11 from n (--> 16)
 ) + // end of recursive call
 [, n + 3] // append a comma, followed by n + 3; notice that this is the value
 // of n *after* it was updated for the recursive call; at the first
 // iteration, we have: n = 98 -> updated to 97 -> n + 3 = 100
 : // else (n = 0):
 1 // output the first term '1' and stop recursion

share|improve this answer

edited 8 hours ago

answered 10 hours ago

Arnauld

65.6k583277

JavaScript (ES6), 43 bytes

Returns the sequence as a comma-separated string.

f=(n=98)=>n?f(n-=n-27?n%10?1:2:11)+[,n+3]:1

Try it online!

Why doing it this way?

We could iterate from $1$ to $100$ and test each number with /2/.test(n), which is a rather concise statement. But in this scenario, we'd have to handle empty entries with something like (/2/.test(n)?'':...), which adds a couple more bytes.

For example, this would work for 45 bytes:

f=(n=1)=>n>99?n:(/2/.test(n)?'':[n,,])+f(n+1)

Or this would work for 44 bytes, if a leading comma is acceptable:

f=(n=100)=>n?f(n-1)+(/2/.test(n)?'':[,n]):''

All in all (and until proven otherwise), it turns out to be shorter to skip right away all values of $n$ that contain a $2$.

Commented

f = // f is a recursive function taking:
(n = 98) => // n = counter, initialized to 98
 n ? // if n is not equal to 0:
 f( // prepend the result of a recursive call:
 n -= // update n:
 n - 27 ? // if n is not equal to 27:
 n % 10 ? // if n is not a multiple of 10:
 1 // subtract 1 from n
 : // else:
 2 // subtract 2 from n
 : // else (n = 27):
 11 // subtract 11 from n (--> 16)
 ) + // end of recursive call
 [, n + 3] // append a comma, followed by n + 3; notice that this is the value
 // of n *after* it was updated for the recursive call; at the first
 // iteration, we have: n = 98 -> updated to 97 -> n + 3 = 100
 : // else (n = 0):
 1 // output the first term '1' and stop recursion

share|improve this answer

edited 8 hours ago

answered 10 hours ago

Arnauld

65.6k583277

share|improve this answer

share|improve this answer

edited 8 hours ago

edited 8 hours ago

edited 8 hours ago

answered 10 hours ago

Arnauld

65.6k583277

answered 10 hours ago

Arnauld

65.6k583277

answered 10 hours ago

Arnauld

65.6k583277

65.6k583277

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This is so cool!
  – Emigna
  4 hours ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This is so cool!
  – Emigna
  4 hours ago
  

  
  
  
  

This is so cool!
– Emigna
4 hours ago

This is so cool!
– Emigna
4 hours ago

add a comment | 

up vote
2
down vote

Japt, 7 bytes

Lõs kø2

Try it online!

share|improve this answer

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

add a comment | 

up vote
2
down vote

Japt, 7 bytes

Lõs kø2

Try it online!

share|improve this answer

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

add a comment | 

up vote
2
down vote

up vote
2
down vote

Japt, 7 bytes

Lõs kø2

Try it online!

share|improve this answer

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

Japt, 7 bytes

Lõs kø2

Try it online!

share|improve this answer

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

share|improve this answer

share|improve this answer

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

answered 11 hours ago

Luis felipe De jesus Munoz

3,0561046

3,0561046

add a comment | 

add a comment | 

up vote
2
down vote

Tcl, 47 bytes

time if [incr i]%10!=2&$i/10!=2 puts $i 100

Try it online!

---

Tcl, 50 bytes

time if 2 ni [split [incr i] ""] puts $i 100

Try it online!

share|improve this answer

edited 10 hours ago

answered 10 hours ago

sergiol

2,1771825

add a comment | 

up vote
2
down vote

Tcl, 47 bytes

time if [incr i]%10!=2&$i/10!=2 puts $i 100

Try it online!

---

Tcl, 50 bytes

time if 2 ni [split [incr i] ""] puts $i 100

Try it online!

share|improve this answer

edited 10 hours ago

answered 10 hours ago

sergiol

2,1771825

add a comment | 

up vote
2
down vote

up vote
2
down vote

Tcl, 47 bytes

time if [incr i]%10!=2&$i/10!=2 puts $i 100

Try it online!

---

Tcl, 50 bytes

time if 2 ni [split [incr i] ""] puts $i 100

Try it online!

share|improve this answer

edited 10 hours ago

answered 10 hours ago

sergiol

2,1771825

Tcl, 47 bytes

time if [incr i]%10!=2&$i/10!=2 puts $i 100

Try it online!

---

Tcl, 50 bytes

time if 2 ni [split [incr i] ""] puts $i 100

Try it online!

share|improve this answer

edited 10 hours ago

answered 10 hours ago

sergiol

2,1771825

share|improve this answer

share|improve this answer

edited 10 hours ago

edited 10 hours ago

edited 10 hours ago

answered 10 hours ago

sergiol

2,1771825

answered 10 hours ago

sergiol

2,1771825

answered 10 hours ago

sergiol

2,1771825

2,1771825

add a comment | 

add a comment | 

up vote
2
down vote

Red, 44 bytes

repeat n 100[unless find form n"2"[print n]]

Try it online!

Uses unless instead of if not, because why not? :)

share|improve this answer

edited 10 hours ago

answered 10 hours ago

Galen Ivanov

4,9671929

add a comment | 

up vote
2
down vote

Red, 44 bytes

repeat n 100[unless find form n"2"[print n]]

Try it online!

Uses unless instead of if not, because why not? :)

share|improve this answer

edited 10 hours ago

answered 10 hours ago

Galen Ivanov

4,9671929

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up vote
2
down vote

up vote
2
down vote

Red, 44 bytes

repeat n 100[unless find form n"2"[print n]]

Try it online!

Uses unless instead of if not, because why not? :)

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edited 10 hours ago

answered 10 hours ago

Galen Ivanov

4,9671929

Red, 44 bytes

repeat n 100[unless find form n"2"[print n]]

Try it online!

Uses unless instead of if not, because why not? :)

share|improve this answer

edited 10 hours ago

answered 10 hours ago

Galen Ivanov

4,9671929

share|improve this answer

share|improve this answer

edited 10 hours ago

edited 10 hours ago

edited 10 hours ago

answered 10 hours ago

Galen Ivanov

4,9671929

answered 10 hours ago

Galen Ivanov

4,9671929

answered 10 hours ago

Galen Ivanov

4,9671929

4,9671929

add a comment | 

add a comment | 

up vote
2
down vote

PowerShell, 22 bytes

1..100|?$_-notmatch2

Try it online!

Generates the range 1 to 100, then pulls out those objects where |?... they do -notmatch the number 2. Each item is left on the pipeline, and output is implicit.

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answered 3 hours ago

AdmBorkBork

24.7k360215

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up vote
2
down vote

PowerShell, 22 bytes

1..100|?$_-notmatch2

Try it online!

Generates the range 1 to 100, then pulls out those objects where |?... they do -notmatch the number 2. Each item is left on the pipeline, and output is implicit.

share|improve this answer

answered 3 hours ago

AdmBorkBork

24.7k360215

add a comment | 

up vote
2
down vote

up vote
2
down vote

PowerShell, 22 bytes

1..100|?$_-notmatch2

Try it online!

Generates the range 1 to 100, then pulls out those objects where |?... they do -notmatch the number 2. Each item is left on the pipeline, and output is implicit.

share|improve this answer

answered 3 hours ago

AdmBorkBork

24.7k360215

PowerShell, 22 bytes

1..100|?$_-notmatch2

Try it online!

Generates the range 1 to 100, then pulls out those objects where |?... they do -notmatch the number 2. Each item is left on the pipeline, and output is implicit.

share|improve this answer

answered 3 hours ago

AdmBorkBork

24.7k360215

share|improve this answer

share|improve this answer

answered 3 hours ago

AdmBorkBork

24.7k360215

answered 3 hours ago

AdmBorkBork

24.7k360215

answered 3 hours ago

AdmBorkBork

24.7k360215

24.7k360215

add a comment | 

add a comment | 

up vote
1
down vote

Retina, 19 bytes

100*
L$`.
$.>`
A`2

Try it online! Explanation:

100*

Insert 100 characters.

L$`.
$.>`

For each character, list the number of characters up to and including that character.

A`2

Remove all entries that contain a 2.

share|improve this answer

answered 11 hours ago

Neil

75.8k744171

add a comment | 

up vote
1
down vote

Retina, 19 bytes

100*
L$`.
$.>`
A`2

Try it online! Explanation:

100*

Insert 100 characters.

L$`.
$.>`

For each character, list the number of characters up to and including that character.

A`2

Remove all entries that contain a 2.

share|improve this answer

answered 11 hours ago

Neil

75.8k744171

add a comment | 

up vote
1
down vote

up vote
1
down vote

Retina, 19 bytes

100*
L$`.
$.>`
A`2

Try it online! Explanation:

100*

Insert 100 characters.

L$`.
$.>`

For each character, list the number of characters up to and including that character.

A`2

Remove all entries that contain a 2.

share|improve this answer

answered 11 hours ago

Neil

75.8k744171

Retina, 19 bytes

100*
L$`.
$.>`
A`2

Try it online! Explanation:

100*

Insert 100 characters.

L$`.
$.>`

For each character, list the number of characters up to and including that character.

A`2

Remove all entries that contain a 2.

share|improve this answer

answered 11 hours ago

Neil

75.8k744171

share|improve this answer

share|improve this answer

answered 11 hours ago

Neil

75.8k744171

answered 11 hours ago

Neil

75.8k744171

answered 11 hours ago

Neil

75.8k744171

75.8k744171

add a comment | 

add a comment | 

up vote
1
down vote

Stax, 6 bytes

Ç░τ╒╜h

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

AJ 10 squared
f output each value in [1 .. n] satisfying the following filter
 E get array of decimal digits in number
 2# count the number of 2s
 ! logical not

Run this one

share|improve this answer

answered 3 hours ago

recursive

4,4561220

add a comment | 

up vote
1
down vote

Stax, 6 bytes

Ç░τ╒╜h

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

AJ 10 squared
f output each value in [1 .. n] satisfying the following filter
 E get array of decimal digits in number
 2# count the number of 2s
 ! logical not

Run this one

share|improve this answer

answered 3 hours ago

recursive

4,4561220

add a comment | 

up vote
1
down vote

up vote
1
down vote

Stax, 6 bytes

Ç░τ╒╜h

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

AJ 10 squared
f output each value in [1 .. n] satisfying the following filter
 E get array of decimal digits in number
 2# count the number of 2s
 ! logical not

Run this one

share|improve this answer

answered 3 hours ago

recursive

4,4561220

Stax, 6 bytes

Ç░τ╒╜h

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

AJ 10 squared
f output each value in [1 .. n] satisfying the following filter
 E get array of decimal digits in number
 2# count the number of 2s
 ! logical not

Run this one

share|improve this answer

answered 3 hours ago

recursive

4,4561220

share|improve this answer

share|improve this answer

answered 3 hours ago

recursive

4,4561220

answered 3 hours ago

recursive

4,4561220

answered 3 hours ago

recursive

4,4561220

4,4561220

add a comment | 

add a comment | 

up vote
0
down vote

Python 2, 39 bytes

k=7
exec"k+=10;print(k>177)*10+k/9;"*81

Try it online!

Uses arithmetic operations only to generate numbers without 2's.

The value k follows the arithmetic progression 17, 27, 37, 47, ..., which when floor-divided by 9 gives 1,3,4,5,6,7,8,9,10,11,13,14,... which counts up numbers not ending in 2. To skip 20 through 29, outputs are increased by 10 past a certain threshold.

share|improve this answer

answered 43 mins ago

xnor

87.1k17181431

add a comment | 

up vote
0
down vote

Python 2, 39 bytes

k=7
exec"k+=10;print(k>177)*10+k/9;"*81

Try it online!

Uses arithmetic operations only to generate numbers without 2's.

The value k follows the arithmetic progression 17, 27, 37, 47, ..., which when floor-divided by 9 gives 1,3,4,5,6,7,8,9,10,11,13,14,... which counts up numbers not ending in 2. To skip 20 through 29, outputs are increased by 10 past a certain threshold.

share|improve this answer

answered 43 mins ago

xnor

87.1k17181431

add a comment | 

up vote
0
down vote

up vote
0
down vote

Python 2, 39 bytes

k=7
exec"k+=10;print(k>177)*10+k/9;"*81

Try it online!

Uses arithmetic operations only to generate numbers without 2's.

The value k follows the arithmetic progression 17, 27, 37, 47, ..., which when floor-divided by 9 gives 1,3,4,5,6,7,8,9,10,11,13,14,... which counts up numbers not ending in 2. To skip 20 through 29, outputs are increased by 10 past a certain threshold.

share|improve this answer

answered 43 mins ago

xnor

87.1k17181431

Python 2, 39 bytes

k=7
exec"k+=10;print(k>177)*10+k/9;"*81

Try it online!

Uses arithmetic operations only to generate numbers without 2's.

The value k follows the arithmetic progression 17, 27, 37, 47, ..., which when floor-divided by 9 gives 1,3,4,5,6,7,8,9,10,11,13,14,... which counts up numbers not ending in 2. To skip 20 through 29, outputs are increased by 10 past a certain threshold.

share|improve this answer

answered 43 mins ago

xnor

87.1k17181431

share|improve this answer

share|improve this answer

answered 43 mins ago

xnor

87.1k17181431

answered 43 mins ago

xnor

87.1k17181431

answered 43 mins ago

xnor

87.1k17181431

87.1k17181431

add a comment | 

add a comment | 

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Monolica is a new contributor. Be nice, and check out our Code of Conduct.

Monolica is a new contributor. Be nice, and check out our Code of Conduct.

 

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