What is the “CP” operation?

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In this question on Quora: What is meant by "the photon is its own antiparticle"?, an answer is given which states




In quantum theory, we have a procedure for transforming the wave function of a particle into that of an antiparticle. It is called the "CP" operation.




Unfortunately, the author of the answer does not explain what the "CP" operation is. Are they referring to a controlled-phase? Or something else?






quantum-foundations







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    up vote
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    down vote

    favorite












    In this question on Quora: What is meant by "the photon is its own antiparticle"?, an answer is given which states




    In quantum theory, we have a procedure for transforming the wave function of a particle into that of an antiparticle. It is called the "CP" operation.




    Unfortunately, the author of the answer does not explain what the "CP" operation is. Are they referring to a controlled-phase? Or something else?






    quantum-foundations







    share|improve this question

























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      In this question on Quora: What is meant by "the photon is its own antiparticle"?, an answer is given which states




      In quantum theory, we have a procedure for transforming the wave function of a particle into that of an antiparticle. It is called the "CP" operation.




      Unfortunately, the author of the answer does not explain what the "CP" operation is. Are they referring to a controlled-phase? Or something else?






      quantum-foundations







      share|improve this question















      In this question on Quora: What is meant by "the photon is its own antiparticle"?, an answer is given which states




      In quantum theory, we have a procedure for transforming the wave function of a particle into that of an antiparticle. It is called the "CP" operation.




      Unfortunately, the author of the answer does not explain what the "CP" operation is. Are they referring to a controlled-phase? Or something else?






      quantum-foundations




      quantum-foundations






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      edited 3 hours ago









      Blue

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      5,46311148










      asked 7 hours ago









      meowzz

      1,070225




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          1 Answer
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          C = charge conjugation

          P = parity



          CP symmetry is often mentioned in the context of particle physics.






          share|improve this answer




















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            1 Answer
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            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            3
            down vote



            accepted










            C = charge conjugation

            P = parity



            CP symmetry is often mentioned in the context of particle physics.






            share|improve this answer
























              up vote
              3
              down vote



              accepted










              C = charge conjugation

              P = parity



              CP symmetry is often mentioned in the context of particle physics.






              share|improve this answer






















                up vote
                3
                down vote



                accepted







                up vote
                3
                down vote



                accepted






                C = charge conjugation

                P = parity



                CP symmetry is often mentioned in the context of particle physics.






                share|improve this answer












                C = charge conjugation

                P = parity



                CP symmetry is often mentioned in the context of particle physics.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 3 hours ago









                user1271772

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