Gauss - Dirichlet class number formula
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Let $p=8k+3$ be a prime. Then the class number of the imaginary quadratic field $mathbb Q(sqrt-p)$ is given by
$$h(-p)=frac 13sum_k=1^fracp-12left(frac kp right).$$ While this is certainly a very elegant and compact formula, does it have any nontrivial applications or consequences? (Note that I am not asking about the Dirichlet class number formula relating the value of the corresponding $L$-series at $1$ with the class number, but rather about its particular corollary).
nt.number-theory analytic-number-theory algebraic-number-theory
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Let $p=8k+3$ be a prime. Then the class number of the imaginary quadratic field $mathbb Q(sqrt-p)$ is given by
$$h(-p)=frac 13sum_k=1^fracp-12left(frac kp right).$$ While this is certainly a very elegant and compact formula, does it have any nontrivial applications or consequences? (Note that I am not asking about the Dirichlet class number formula relating the value of the corresponding $L$-series at $1$ with the class number, but rather about its particular corollary).
nt.number-theory analytic-number-theory algebraic-number-theory
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Let $p=8k+3$ be a prime. Then the class number of the imaginary quadratic field $mathbb Q(sqrt-p)$ is given by
$$h(-p)=frac 13sum_k=1^fracp-12left(frac kp right).$$ While this is certainly a very elegant and compact formula, does it have any nontrivial applications or consequences? (Note that I am not asking about the Dirichlet class number formula relating the value of the corresponding $L$-series at $1$ with the class number, but rather about its particular corollary).
nt.number-theory analytic-number-theory algebraic-number-theory
Let $p=8k+3$ be a prime. Then the class number of the imaginary quadratic field $mathbb Q(sqrt-p)$ is given by
$$h(-p)=frac 13sum_k=1^fracp-12left(frac kp right).$$ While this is certainly a very elegant and compact formula, does it have any nontrivial applications or consequences? (Note that I am not asking about the Dirichlet class number formula relating the value of the corresponding $L$-series at $1$ with the class number, but rather about its particular corollary).
nt.number-theory analytic-number-theory algebraic-number-theory
nt.number-theory analytic-number-theory algebraic-number-theory
asked 4 hours ago
Shimrod
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Let $p=2n+1$ be a prime with $pequiv3pmod4$. By Wilson's theorem, $ (n!)^2equiv1pmod p$ and hence $n!equivpm1pmod p$. L. J. Mordell [Amer. Math. Monthly 68(1961), 145-146] used Dirichlet's class number formula $$left(2-left(frac 2pright)right) h(-p)=sum_k=1^nleft(frac kpright)$$ to deduce in few lines that $n!equiv(-1)^(h(-p)+1)/2pmod p$ if $p>3$. This is a nice application of Dirichlet's class number formula.
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
Let $p=2n+1$ be a prime with $pequiv3pmod4$. By Wilson's theorem, $ (n!)^2equiv1pmod p$ and hence $n!equivpm1pmod p$. L. J. Mordell [Amer. Math. Monthly 68(1961), 145-146] used Dirichlet's class number formula $$left(2-left(frac 2pright)right) h(-p)=sum_k=1^nleft(frac kpright)$$ to deduce in few lines that $n!equiv(-1)^(h(-p)+1)/2pmod p$ if $p>3$. This is a nice application of Dirichlet's class number formula.
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up vote
5
down vote
Let $p=2n+1$ be a prime with $pequiv3pmod4$. By Wilson's theorem, $ (n!)^2equiv1pmod p$ and hence $n!equivpm1pmod p$. L. J. Mordell [Amer. Math. Monthly 68(1961), 145-146] used Dirichlet's class number formula $$left(2-left(frac 2pright)right) h(-p)=sum_k=1^nleft(frac kpright)$$ to deduce in few lines that $n!equiv(-1)^(h(-p)+1)/2pmod p$ if $p>3$. This is a nice application of Dirichlet's class number formula.
add a comment |Â
up vote
5
down vote
up vote
5
down vote
Let $p=2n+1$ be a prime with $pequiv3pmod4$. By Wilson's theorem, $ (n!)^2equiv1pmod p$ and hence $n!equivpm1pmod p$. L. J. Mordell [Amer. Math. Monthly 68(1961), 145-146] used Dirichlet's class number formula $$left(2-left(frac 2pright)right) h(-p)=sum_k=1^nleft(frac kpright)$$ to deduce in few lines that $n!equiv(-1)^(h(-p)+1)/2pmod p$ if $p>3$. This is a nice application of Dirichlet's class number formula.
Let $p=2n+1$ be a prime with $pequiv3pmod4$. By Wilson's theorem, $ (n!)^2equiv1pmod p$ and hence $n!equivpm1pmod p$. L. J. Mordell [Amer. Math. Monthly 68(1961), 145-146] used Dirichlet's class number formula $$left(2-left(frac 2pright)right) h(-p)=sum_k=1^nleft(frac kpright)$$ to deduce in few lines that $n!equiv(-1)^(h(-p)+1)/2pmod p$ if $p>3$. This is a nice application of Dirichlet's class number formula.
answered 3 hours ago
Zhi-Wei Sun
1,665119
1,665119
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