Mixing
Different object size of True and False in Python 3
Clash Royale CLAN TAG#URR8PPP
up vote
16
down vote
favorite
Experimenting with magic methods (__sizeof__ in particular) on different Python objects I stumbled over the following behaviour:
Python 2.7
>>> False.__sizeof__()
24
>>> True.__sizeof__()
24
Python 3.x
>>> False.__sizeof__()
24
>>> True.__sizeof__()
28
What changed in Python 3 that makes the size of True greater than the size of False?
python python-3.x python-2.7 cpython python-internals
edited 19 mins ago
Peter Mortensen
13.2k1983111
asked 7 hours ago
Simon Fromme
1,327721
add a comment |Â
up vote
16
down vote
favorite
Experimenting with magic methods (__sizeof__ in particular) on different Python objects I stumbled over the following behaviour:
Python 2.7
>>> False.__sizeof__()
24
>>> True.__sizeof__()
24
Python 3.x
>>> False.__sizeof__()
24
>>> True.__sizeof__()
28
What changed in Python 3 that makes the size of True greater than the size of False?
python python-3.x python-2.7 cpython python-internals
edited 19 mins ago
Peter Mortensen
13.2k1983111
asked 7 hours ago
Simon Fromme
1,327721
2
diris totally irrelevant.
– juanpa.arrivillaga
7 hours ago
3
Related, the same behavior appears for0vs1
– user3483203
7 hours ago
@juanpa.arrivillaga can you qualify that? Ifdiris irrelevant in understanding this, what is?
– roganjosh
7 hours ago
2
Becausedirreturns a lot of things that have nothing to do with whatsys.sizeofreturns. Note,dir([1,2,3,4,5]) == dir()butsys.getsizeof([1,2,3,4,5,]) != sys.getsizeof()
– juanpa.arrivillaga
6 hours ago
1
@roganjosh and just in general,dirwill give you every attribute accessible from an object, but you don't care about that, so for example, when you ask about the size of an object you generally don't want to include all the methods that belong to various classes that it has access to, do you?
– juanpa.arrivillaga
6 hours ago
add a comment |Â
up vote
16
down vote
favorite
up vote
16
down vote
favorite
Experimenting with magic methods (__sizeof__ in particular) on different Python objects I stumbled over the following behaviour:
Python 2.7
>>> False.__sizeof__()
24
>>> True.__sizeof__()
24
Python 3.x
>>> False.__sizeof__()
24
>>> True.__sizeof__()
28
What changed in Python 3 that makes the size of True greater than the size of False?
python python-3.x python-2.7 cpython python-internals
edited 19 mins ago
Peter Mortensen
13.2k1983111
asked 7 hours ago
Simon Fromme
1,327721
Experimenting with magic methods (__sizeof__ in particular) on different Python objects I stumbled over the following behaviour:
Python 2.7
>>> False.__sizeof__()
24
>>> True.__sizeof__()
24
Python 3.x
>>> False.__sizeof__()
24
>>> True.__sizeof__()
28
What changed in Python 3 that makes the size of True greater than the size of False?
python python-3.x python-2.7 cpython python-internals
python python-3.x python-2.7 cpython python-internals
edited 19 mins ago
Peter Mortensen
13.2k1983111
asked 7 hours ago
Simon Fromme
1,327721
edited 19 mins ago
Peter Mortensen
13.2k1983111
asked 7 hours ago
Simon Fromme
1,327721
edited 19 mins ago
Peter Mortensen
13.2k1983111
edited 19 mins ago
Peter Mortensen
13.2k1983111
edited 19 mins ago
Peter Mortensen
13.2k1983111
13.2k1983111
asked 7 hours ago
Simon Fromme
1,327721
asked 7 hours ago
Simon Fromme
1,327721
asked 7 hours ago
Simon Fromme
1,327721
1,327721
2
diris totally irrelevant.
– juanpa.arrivillaga
7 hours ago
3
Related, the same behavior appears for0vs1
– user3483203
7 hours ago
@juanpa.arrivillaga can you qualify that? Ifdiris irrelevant in understanding this, what is?
– roganjosh
7 hours ago
2
Becausedirreturns a lot of things that have nothing to do with whatsys.sizeofreturns. Note,dir([1,2,3,4,5]) == dir()butsys.getsizeof([1,2,3,4,5,]) != sys.getsizeof()
– juanpa.arrivillaga
6 hours ago
1
@roganjosh and just in general,dirwill give you every attribute accessible from an object, but you don't care about that, so for example, when you ask about the size of an object you generally don't want to include all the methods that belong to various classes that it has access to, do you?
– juanpa.arrivillaga
6 hours ago
add a comment |Â
2
diris totally irrelevant.
– juanpa.arrivillaga
7 hours ago
3
Related, the same behavior appears for0vs1
– user3483203
7 hours ago
@juanpa.arrivillaga can you qualify that? Ifdiris irrelevant in understanding this, what is?
– roganjosh
7 hours ago
2
Becausedirreturns a lot of things that have nothing to do with whatsys.sizeofreturns. Note,dir([1,2,3,4,5]) == dir()butsys.getsizeof([1,2,3,4,5,]) != sys.getsizeof()
– juanpa.arrivillaga
6 hours ago
1
@roganjosh and just in general,dirwill give you every attribute accessible from an object, but you don't care about that, so for example, when you ask about the size of an object you generally don't want to include all the methods that belong to various classes that it has access to, do you?
– juanpa.arrivillaga
6 hours ago
2
2
dir is totally irrelevant.– juanpa.arrivillaga
7 hours ago
dir is totally irrelevant.– juanpa.arrivillaga
7 hours ago
3
3
Related, the same behavior appears for
0 vs 1– user3483203
7 hours ago
Related, the same behavior appears for
0 vs 1– user3483203
7 hours ago
@juanpa.arrivillaga can you qualify that? If
dir is irrelevant in understanding this, what is?– roganjosh
7 hours ago
@juanpa.arrivillaga can you qualify that? If
dir is irrelevant in understanding this, what is?– roganjosh
7 hours ago
2
2
Because
dir returns a lot of things that have nothing to do with what sys.sizeof returns. Note, dir([1,2,3,4,5]) == dir() but sys.getsizeof([1,2,3,4,5,]) != sys.getsizeof()– juanpa.arrivillaga
6 hours ago
Because
dir returns a lot of things that have nothing to do with what sys.sizeof returns. Note, dir([1,2,3,4,5]) == dir() but sys.getsizeof([1,2,3,4,5,]) != sys.getsizeof()– juanpa.arrivillaga
6 hours ago
1
1
@roganjosh and just in general,
dir will give you every attribute accessible from an object, but you don't care about that, so for example, when you ask about the size of an object you generally don't want to include all the methods that belong to various classes that it has access to, do you?– juanpa.arrivillaga
6 hours ago
@roganjosh and just in general,
dir will give you every attribute accessible from an object, but you don't care about that, so for example, when you ask about the size of an object you generally don't want to include all the methods that belong to various classes that it has access to, do you?– juanpa.arrivillaga
6 hours ago
add a comment |Â
4 Answers
4
active
oldest
votes
up vote
16
down vote
It is because bool is a subclass of int in both Python 2 and 3.
>>> issubclass(bool, int)
True
But the int implementation has changed.
In Python 2, int was the one that was 32 or 64 bits, depending on the system, as opposed to arbitrary-length long.
In Python 3, int is arbitrary-length - the long of Python 2 was renamed to int and the original Python 2 int dropped altogether.
In Python 2 you get the exactly same behaviour for long objects 1L and 0L:
Python 2.7.15rc1 (default, Apr 15 2018, 21:51:34)
[GCC 7.3.0] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.getsizeof(1L)
28
>>> sys.getsizeof(0L)
24
The long/Python 3 int is a variable-length object, just like a tuple - when it is allocated, enough memory is allocated to hold all the binary digits required to represent it. The length of the variable part is stored in the object head. 0 requires no binary digits (its variable length is 0), but even 1 spills over, and requires extra digits.
I.e. 0 is represented as binary string of length 0:
<>
and 1 is represented as a 30-bit binary string:
<000000000000000000000000000001>
The default configuration in Python uses 30 bits in a uint32_t; so 2**30 - 1 still fits in 28 bytes on x86-64, and 2**30 will require 32;
2**30 - 1 will be presented as
<111111111111111111111111111111>
i.e. all 30 value bits set to 1; 2**30 will need more, and it will have internal representation
<000000000000000000000000000001000000000000000000000000000000>
As for True using 28 bytes instead of 24 - you need not worry. True is a singleton and therefore only 4 bytes are lost in total in any Python program, not 4 for every usage of True.
answered 7 hours ago
Antti Haapala
76.5k16143189
Yep, and long objects just use no extra pointer to represent 0
– juanpa.arrivillaga
6 hours ago
2
@roganjosh they are the same type. That doesn't mean they have the same size.sys.getsizeof([1,2,3,4,5])andsys.getsizeof()are not the same...
– juanpa.arrivillaga
6 hours ago
@roganjoshintobjects in Python 2 were always the same size.longobjects were arbitrarily-sized (like Python 3intobjects, indeed, Python 3intobjects are just Python 2 long objects)
– juanpa.arrivillaga
6 hours ago
@juanpa.arrivillaga now it makes sense to me :)
– roganjosh
6 hours ago
add a comment |Â
up vote
6
down vote
Both True and False are longobjects in CPython:
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1
;
You thus can say that a Boolean is a subclass of a python-3.x int where True takes as value 1, and False takes as value 0. We thus make a call to PyVarObject_HEAD_INIT with as type parameter a reference to PyBool_Type and with ob_size as value 0 and 1 respectively.
Now since python-3.x, there is no long anymore: these have been merged, and the int object will, depending on the size of the number, take a different value.
If we inspect the source code of the longlobject type, we see:
/* Long integer representation.
The absolute value of a number is equal to
SUM(for i=0 through abs(ob_size)-1) ob_digit[i] * 2**(SHIFT*i)
Negative numbers are represented with ob_size < 0;
zero is represented by ob_size == 0.
In a normalized number, ob_digit[abs(ob_size)-1] (the most significant
digit) is never zero. Also, in all cases, for all valid i,
0 <= ob_digit[i] <= MASK.
The allocation function takes care of allocating extra memory
so that ob_digit[0] ... ob_digit[abs(ob_size)-1] are actually available.
CAUTION: Generic code manipulating subtypes of PyVarObject has to
aware that ints abuse ob_size's sign bit.
*/
struct _longobject
PyObject_VAR_HEAD
digit ob_digit[1];
;
To make a long story short, an _longobject can be seen as an array of "digits", but you should here see digits not as decimal digits, but as groups of bits that thus can be added, multiplied, etc.
Now as is specified in the comment, it says that:
zero is represented by ob_size == 0.
So in case the value is zero, no digits are added, whereas for small integers (values less than 230 in CPython), it takes one digit, and so on.
edited 8 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Willem Van Onsem
134k16126214
add a comment |Â
up vote
3
down vote
I haven't seen CPython code for this, but I believe this has something to do with optimization of integers in Python 3. Probably, as long was dropped, some optimizations were unified. int in Python 3 is arbitrary-sized int – the same as long was in Python 2. As bool stores in the same way as new int, it affects both.
Interesting part:
>>> (0).__sizeof__()
24
>>> (1).__sizeof__() # Here one more "block" is allocated
28
>>> (2**30-1).__sizeof__() # This is the maximum integer size fitting into 28
28
+ bytes for object headers should complete the equation.
edited 16 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Slam
3,34511832
Actually, now in Python 3,intis just what Python 2longwas, it was reallyintthat was "dropped"
– juanpa.arrivillaga
6 hours ago
Internally – absolutely true, I'm talking about names, but thx for clarification
– Slam
6 hours ago
Indeed, in CPython 3 source code, it's still longobject
– juanpa.arrivillaga
6 hours ago
It is actually deoptimization... pessimization?
– Antti Haapala
6 hours ago
It's probably not. I may be wrong, but this overhead does not cost as much as two different types + seamless cast in runtime. The truth is, you rarely operate such a huge amount of ints in normal python program to care about this extra memory. If you do – you should use something like numpy to run with ~0 overhead and have pure int32/64 – no headers, no reallocation. But overflows from time to time )
– Slam
6 hours ago
add a comment |Â
up vote
2
down vote
Take a look at the cpython code for True and False
Internally it is represented as integer
PyTypeObject PyBool_Type =
PyVarObject_HEAD_INIT(&PyType_Type, 0)
"bool",
sizeof(struct _longobject),
0,
0, /* tp_dealloc */
0, /* tp_print */
0, /* tp_getattr */
0, /* tp_setattr */
0, /* tp_reserved */
bool_repr, /* tp_repr */
&bool_as_number, /* tp_as_number */
0, /* tp_as_sequence */
0, /* tp_as_mapping */
0, /* tp_hash */
0, /* tp_call */
bool_repr, /* tp_str */
0, /* tp_getattro */
0, /* tp_setattro */
0, /* tp_as_buffer */
Py_TPFLAGS_DEFAULT, /* tp_flags */
bool_doc, /* tp_doc */
0, /* tp_traverse */
0, /* tp_clear */
0, /* tp_richcompare */
0, /* tp_weaklistoffset */
0, /* tp_iter */
0, /* tp_iternext */
0, /* tp_methods */
0, /* tp_members */
0, /* tp_getset */
&PyLong_Type, /* tp_base */
0, /* tp_dict */
0, /* tp_descr_get */
0, /* tp_descr_set */
0, /* tp_dictoffset */
0, /* tp_init */
0, /* tp_alloc */
bool_new, /* tp_new */
;
/* The objects representing bool values False and True */
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct = {
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1 answered 6 hours ago
Kamil Niski
1,950111
I don't know why this was downvoted
– Antti Haapala
6 hours ago
I think i just was not as quick to answer properly as others :)
– Kamil Niski
6 hours ago
The answer only gets halfway there. It's represented as an integer.. yeah? And so what?
– wim
6 hours ago
@wim I don't see the need to explain it further since guys above already did great job at this. I don't want to duplicate content. Please refer to their answers.
– Kamil Niski
6 hours ago
2
I think so, but it's up to you. Should you wait for it to maybe get +3 and then delete you may earn a disciplined badge... :)
– wim
5 hours ago
 |Â
show 2 more comments
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
16
down vote
It is because bool is a subclass of int in both Python 2 and 3.
>>> issubclass(bool, int)
True
But the int implementation has changed.
In Python 2, int was the one that was 32 or 64 bits, depending on the system, as opposed to arbitrary-length long.
In Python 3, int is arbitrary-length - the long of Python 2 was renamed to int and the original Python 2 int dropped altogether.
In Python 2 you get the exactly same behaviour for long objects 1L and 0L:
Python 2.7.15rc1 (default, Apr 15 2018, 21:51:34)
[GCC 7.3.0] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.getsizeof(1L)
28
>>> sys.getsizeof(0L)
24
The long/Python 3 int is a variable-length object, just like a tuple - when it is allocated, enough memory is allocated to hold all the binary digits required to represent it. The length of the variable part is stored in the object head. 0 requires no binary digits (its variable length is 0), but even 1 spills over, and requires extra digits.
I.e. 0 is represented as binary string of length 0:
<>
and 1 is represented as a 30-bit binary string:
<000000000000000000000000000001>
The default configuration in Python uses 30 bits in a uint32_t; so 2**30 - 1 still fits in 28 bytes on x86-64, and 2**30 will require 32;
2**30 - 1 will be presented as
<111111111111111111111111111111>
i.e. all 30 value bits set to 1; 2**30 will need more, and it will have internal representation
<000000000000000000000000000001000000000000000000000000000000>
As for True using 28 bytes instead of 24 - you need not worry. True is a singleton and therefore only 4 bytes are lost in total in any Python program, not 4 for every usage of True.
answered 7 hours ago
Antti Haapala
76.5k16143189
Yep, and long objects just use no extra pointer to represent 0
– juanpa.arrivillaga
6 hours ago
2
@roganjosh they are the same type. That doesn't mean they have the same size.sys.getsizeof([1,2,3,4,5])andsys.getsizeof()are not the same...
– juanpa.arrivillaga
6 hours ago
@roganjoshintobjects in Python 2 were always the same size.longobjects were arbitrarily-sized (like Python 3intobjects, indeed, Python 3intobjects are just Python 2 long objects)
– juanpa.arrivillaga
6 hours ago
@juanpa.arrivillaga now it makes sense to me :)
– roganjosh
6 hours ago
add a comment |Â
up vote
16
down vote
It is because bool is a subclass of int in both Python 2 and 3.
>>> issubclass(bool, int)
True
But the int implementation has changed.
In Python 2, int was the one that was 32 or 64 bits, depending on the system, as opposed to arbitrary-length long.
In Python 3, int is arbitrary-length - the long of Python 2 was renamed to int and the original Python 2 int dropped altogether.
In Python 2 you get the exactly same behaviour for long objects 1L and 0L:
Python 2.7.15rc1 (default, Apr 15 2018, 21:51:34)
[GCC 7.3.0] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.getsizeof(1L)
28
>>> sys.getsizeof(0L)
24
The long/Python 3 int is a variable-length object, just like a tuple - when it is allocated, enough memory is allocated to hold all the binary digits required to represent it. The length of the variable part is stored in the object head. 0 requires no binary digits (its variable length is 0), but even 1 spills over, and requires extra digits.
I.e. 0 is represented as binary string of length 0:
<>
and 1 is represented as a 30-bit binary string:
<000000000000000000000000000001>
The default configuration in Python uses 30 bits in a uint32_t; so 2**30 - 1 still fits in 28 bytes on x86-64, and 2**30 will require 32;
2**30 - 1 will be presented as
<111111111111111111111111111111>
i.e. all 30 value bits set to 1; 2**30 will need more, and it will have internal representation
<000000000000000000000000000001000000000000000000000000000000>
As for True using 28 bytes instead of 24 - you need not worry. True is a singleton and therefore only 4 bytes are lost in total in any Python program, not 4 for every usage of True.
answered 7 hours ago
Antti Haapala
76.5k16143189
Yep, and long objects just use no extra pointer to represent 0
– juanpa.arrivillaga
6 hours ago
2
@roganjosh they are the same type. That doesn't mean they have the same size.sys.getsizeof([1,2,3,4,5])andsys.getsizeof()are not the same...
– juanpa.arrivillaga
6 hours ago
@roganjoshintobjects in Python 2 were always the same size.longobjects were arbitrarily-sized (like Python 3intobjects, indeed, Python 3intobjects are just Python 2 long objects)
– juanpa.arrivillaga
6 hours ago
@juanpa.arrivillaga now it makes sense to me :)
– roganjosh
6 hours ago
add a comment |Â
up vote
16
down vote
up vote
16
down vote
It is because bool is a subclass of int in both Python 2 and 3.
>>> issubclass(bool, int)
True
But the int implementation has changed.
In Python 2, int was the one that was 32 or 64 bits, depending on the system, as opposed to arbitrary-length long.
In Python 3, int is arbitrary-length - the long of Python 2 was renamed to int and the original Python 2 int dropped altogether.
In Python 2 you get the exactly same behaviour for long objects 1L and 0L:
Python 2.7.15rc1 (default, Apr 15 2018, 21:51:34)
[GCC 7.3.0] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.getsizeof(1L)
28
>>> sys.getsizeof(0L)
24
The long/Python 3 int is a variable-length object, just like a tuple - when it is allocated, enough memory is allocated to hold all the binary digits required to represent it. The length of the variable part is stored in the object head. 0 requires no binary digits (its variable length is 0), but even 1 spills over, and requires extra digits.
I.e. 0 is represented as binary string of length 0:
<>
and 1 is represented as a 30-bit binary string:
<000000000000000000000000000001>
The default configuration in Python uses 30 bits in a uint32_t; so 2**30 - 1 still fits in 28 bytes on x86-64, and 2**30 will require 32;
2**30 - 1 will be presented as
<111111111111111111111111111111>
i.e. all 30 value bits set to 1; 2**30 will need more, and it will have internal representation
<000000000000000000000000000001000000000000000000000000000000>
As for True using 28 bytes instead of 24 - you need not worry. True is a singleton and therefore only 4 bytes are lost in total in any Python program, not 4 for every usage of True.
answered 7 hours ago
Antti Haapala
76.5k16143189
It is because bool is a subclass of int in both Python 2 and 3.
>>> issubclass(bool, int)
True
But the int implementation has changed.
In Python 2, int was the one that was 32 or 64 bits, depending on the system, as opposed to arbitrary-length long.
In Python 3, int is arbitrary-length - the long of Python 2 was renamed to int and the original Python 2 int dropped altogether.
In Python 2 you get the exactly same behaviour for long objects 1L and 0L:
Python 2.7.15rc1 (default, Apr 15 2018, 21:51:34)
[GCC 7.3.0] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> sys.getsizeof(1L)
28
>>> sys.getsizeof(0L)
24
The long/Python 3 int is a variable-length object, just like a tuple - when it is allocated, enough memory is allocated to hold all the binary digits required to represent it. The length of the variable part is stored in the object head. 0 requires no binary digits (its variable length is 0), but even 1 spills over, and requires extra digits.
I.e. 0 is represented as binary string of length 0:
<>
and 1 is represented as a 30-bit binary string:
<000000000000000000000000000001>
The default configuration in Python uses 30 bits in a uint32_t; so 2**30 - 1 still fits in 28 bytes on x86-64, and 2**30 will require 32;
2**30 - 1 will be presented as
<111111111111111111111111111111>
i.e. all 30 value bits set to 1; 2**30 will need more, and it will have internal representation
<000000000000000000000000000001000000000000000000000000000000>
As for True using 28 bytes instead of 24 - you need not worry. True is a singleton and therefore only 4 bytes are lost in total in any Python program, not 4 for every usage of True.
answered 7 hours ago
Antti Haapala
76.5k16143189
edited 5 hours ago
answered 7 hours ago
Antti Haapala
76.5k16143189
answered 7 hours ago
Antti Haapala
76.5k16143189
answered 7 hours ago
Antti Haapala
76.5k16143189
76.5k16143189
Yep, and long objects just use no extra pointer to represent 0
– juanpa.arrivillaga
6 hours ago
2
@roganjosh they are the same type. That doesn't mean they have the same size.sys.getsizeof([1,2,3,4,5])andsys.getsizeof()are not the same...
– juanpa.arrivillaga
6 hours ago
@roganjoshintobjects in Python 2 were always the same size.longobjects were arbitrarily-sized (like Python 3intobjects, indeed, Python 3intobjects are just Python 2 long objects)
– juanpa.arrivillaga
6 hours ago
@juanpa.arrivillaga now it makes sense to me :)
– roganjosh
6 hours ago
add a comment |Â
Yep, and long objects just use no extra pointer to represent 0
– juanpa.arrivillaga
6 hours ago
2
@roganjosh they are the same type. That doesn't mean they have the same size.sys.getsizeof([1,2,3,4,5])andsys.getsizeof()are not the same...
– juanpa.arrivillaga
6 hours ago
@roganjoshintobjects in Python 2 were always the same size.longobjects were arbitrarily-sized (like Python 3intobjects, indeed, Python 3intobjects are just Python 2 long objects)
– juanpa.arrivillaga
6 hours ago
@juanpa.arrivillaga now it makes sense to me :)
– roganjosh
6 hours ago
Yep, and long objects just use no extra pointer to represent 0
– juanpa.arrivillaga
6 hours ago
Yep, and long objects just use no extra pointer to represent 0
– juanpa.arrivillaga
6 hours ago
2
2
@roganjosh they are the same type. That doesn't mean they have the same size.
sys.getsizeof([1,2,3,4,5]) and sys.getsizeof() are not the same...– juanpa.arrivillaga
6 hours ago
@roganjosh they are the same type. That doesn't mean they have the same size.
sys.getsizeof([1,2,3,4,5]) and sys.getsizeof() are not the same...– juanpa.arrivillaga
6 hours ago
@roganjosh
int objects in Python 2 were always the same size. long objects were arbitrarily-sized (like Python 3 int objects, indeed, Python 3 int objects are just Python 2 long objects)– juanpa.arrivillaga
6 hours ago
@roganjosh
int objects in Python 2 were always the same size. long objects were arbitrarily-sized (like Python 3 int objects, indeed, Python 3 int objects are just Python 2 long objects)– juanpa.arrivillaga
6 hours ago
@juanpa.arrivillaga now it makes sense to me :)
– roganjosh
6 hours ago
@juanpa.arrivillaga now it makes sense to me :)
– roganjosh
6 hours ago
add a comment |Â
up vote
6
down vote
Both True and False are longobjects in CPython:
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1
;
You thus can say that a Boolean is a subclass of a python-3.x int where True takes as value 1, and False takes as value 0. We thus make a call to PyVarObject_HEAD_INIT with as type parameter a reference to PyBool_Type and with ob_size as value 0 and 1 respectively.
Now since python-3.x, there is no long anymore: these have been merged, and the int object will, depending on the size of the number, take a different value.
If we inspect the source code of the longlobject type, we see:
/* Long integer representation.
The absolute value of a number is equal to
SUM(for i=0 through abs(ob_size)-1) ob_digit[i] * 2**(SHIFT*i)
Negative numbers are represented with ob_size < 0;
zero is represented by ob_size == 0.
In a normalized number, ob_digit[abs(ob_size)-1] (the most significant
digit) is never zero. Also, in all cases, for all valid i,
0 <= ob_digit[i] <= MASK.
The allocation function takes care of allocating extra memory
so that ob_digit[0] ... ob_digit[abs(ob_size)-1] are actually available.
CAUTION: Generic code manipulating subtypes of PyVarObject has to
aware that ints abuse ob_size's sign bit.
*/
struct _longobject
PyObject_VAR_HEAD
digit ob_digit[1];
;
To make a long story short, an _longobject can be seen as an array of "digits", but you should here see digits not as decimal digits, but as groups of bits that thus can be added, multiplied, etc.
Now as is specified in the comment, it says that:
zero is represented by ob_size == 0.
So in case the value is zero, no digits are added, whereas for small integers (values less than 230 in CPython), it takes one digit, and so on.
edited 8 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Willem Van Onsem
134k16126214
add a comment |Â
up vote
6
down vote
Both True and False are longobjects in CPython:
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1
;
You thus can say that a Boolean is a subclass of a python-3.x int where True takes as value 1, and False takes as value 0. We thus make a call to PyVarObject_HEAD_INIT with as type parameter a reference to PyBool_Type and with ob_size as value 0 and 1 respectively.
Now since python-3.x, there is no long anymore: these have been merged, and the int object will, depending on the size of the number, take a different value.
If we inspect the source code of the longlobject type, we see:
/* Long integer representation.
The absolute value of a number is equal to
SUM(for i=0 through abs(ob_size)-1) ob_digit[i] * 2**(SHIFT*i)
Negative numbers are represented with ob_size < 0;
zero is represented by ob_size == 0.
In a normalized number, ob_digit[abs(ob_size)-1] (the most significant
digit) is never zero. Also, in all cases, for all valid i,
0 <= ob_digit[i] <= MASK.
The allocation function takes care of allocating extra memory
so that ob_digit[0] ... ob_digit[abs(ob_size)-1] are actually available.
CAUTION: Generic code manipulating subtypes of PyVarObject has to
aware that ints abuse ob_size's sign bit.
*/
struct _longobject
PyObject_VAR_HEAD
digit ob_digit[1];
;
To make a long story short, an _longobject can be seen as an array of "digits", but you should here see digits not as decimal digits, but as groups of bits that thus can be added, multiplied, etc.
Now as is specified in the comment, it says that:
zero is represented by ob_size == 0.
So in case the value is zero, no digits are added, whereas for small integers (values less than 230 in CPython), it takes one digit, and so on.
edited 8 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Willem Van Onsem
134k16126214
add a comment |Â
up vote
6
down vote
up vote
6
down vote
Both True and False are longobjects in CPython:
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1
;
You thus can say that a Boolean is a subclass of a python-3.x int where True takes as value 1, and False takes as value 0. We thus make a call to PyVarObject_HEAD_INIT with as type parameter a reference to PyBool_Type and with ob_size as value 0 and 1 respectively.
Now since python-3.x, there is no long anymore: these have been merged, and the int object will, depending on the size of the number, take a different value.
If we inspect the source code of the longlobject type, we see:
/* Long integer representation.
The absolute value of a number is equal to
SUM(for i=0 through abs(ob_size)-1) ob_digit[i] * 2**(SHIFT*i)
Negative numbers are represented with ob_size < 0;
zero is represented by ob_size == 0.
In a normalized number, ob_digit[abs(ob_size)-1] (the most significant
digit) is never zero. Also, in all cases, for all valid i,
0 <= ob_digit[i] <= MASK.
The allocation function takes care of allocating extra memory
so that ob_digit[0] ... ob_digit[abs(ob_size)-1] are actually available.
CAUTION: Generic code manipulating subtypes of PyVarObject has to
aware that ints abuse ob_size's sign bit.
*/
struct _longobject
PyObject_VAR_HEAD
digit ob_digit[1];
;
To make a long story short, an _longobject can be seen as an array of "digits", but you should here see digits not as decimal digits, but as groups of bits that thus can be added, multiplied, etc.
Now as is specified in the comment, it says that:
zero is represented by ob_size == 0.
So in case the value is zero, no digits are added, whereas for small integers (values less than 230 in CPython), it takes one digit, and so on.
edited 8 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Willem Van Onsem
134k16126214
Both True and False are longobjects in CPython:
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1
;
You thus can say that a Boolean is a subclass of a python-3.x int where True takes as value 1, and False takes as value 0. We thus make a call to PyVarObject_HEAD_INIT with as type parameter a reference to PyBool_Type and with ob_size as value 0 and 1 respectively.
Now since python-3.x, there is no long anymore: these have been merged, and the int object will, depending on the size of the number, take a different value.
If we inspect the source code of the longlobject type, we see:
/* Long integer representation.
The absolute value of a number is equal to
SUM(for i=0 through abs(ob_size)-1) ob_digit[i] * 2**(SHIFT*i)
Negative numbers are represented with ob_size < 0;
zero is represented by ob_size == 0.
In a normalized number, ob_digit[abs(ob_size)-1] (the most significant
digit) is never zero. Also, in all cases, for all valid i,
0 <= ob_digit[i] <= MASK.
The allocation function takes care of allocating extra memory
so that ob_digit[0] ... ob_digit[abs(ob_size)-1] are actually available.
CAUTION: Generic code manipulating subtypes of PyVarObject has to
aware that ints abuse ob_size's sign bit.
*/
struct _longobject
PyObject_VAR_HEAD
digit ob_digit[1];
;
To make a long story short, an _longobject can be seen as an array of "digits", but you should here see digits not as decimal digits, but as groups of bits that thus can be added, multiplied, etc.
Now as is specified in the comment, it says that:
zero is represented by ob_size == 0.
So in case the value is zero, no digits are added, whereas for small integers (values less than 230 in CPython), it takes one digit, and so on.
edited 8 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Willem Van Onsem
134k16126214
edited 8 mins ago
Peter Mortensen
13.2k1983111
edited 8 mins ago
Peter Mortensen
13.2k1983111
edited 8 mins ago
Peter Mortensen
13.2k1983111
13.2k1983111
answered 6 hours ago
Willem Van Onsem
134k16126214
answered 6 hours ago
Willem Van Onsem
134k16126214
answered 6 hours ago
Willem Van Onsem
134k16126214
134k16126214
add a comment |Â
add a comment |Â
up vote
3
down vote
I haven't seen CPython code for this, but I believe this has something to do with optimization of integers in Python 3. Probably, as long was dropped, some optimizations were unified. int in Python 3 is arbitrary-sized int – the same as long was in Python 2. As bool stores in the same way as new int, it affects both.
Interesting part:
>>> (0).__sizeof__()
24
>>> (1).__sizeof__() # Here one more "block" is allocated
28
>>> (2**30-1).__sizeof__() # This is the maximum integer size fitting into 28
28
+ bytes for object headers should complete the equation.
edited 16 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Slam
3,34511832
Actually, now in Python 3,intis just what Python 2longwas, it was reallyintthat was "dropped"
– juanpa.arrivillaga
6 hours ago
Internally – absolutely true, I'm talking about names, but thx for clarification
– Slam
6 hours ago
Indeed, in CPython 3 source code, it's still longobject
– juanpa.arrivillaga
6 hours ago
It is actually deoptimization... pessimization?
– Antti Haapala
6 hours ago
It's probably not. I may be wrong, but this overhead does not cost as much as two different types + seamless cast in runtime. The truth is, you rarely operate such a huge amount of ints in normal python program to care about this extra memory. If you do – you should use something like numpy to run with ~0 overhead and have pure int32/64 – no headers, no reallocation. But overflows from time to time )
– Slam
6 hours ago
add a comment |Â
up vote
3
down vote
I haven't seen CPython code for this, but I believe this has something to do with optimization of integers in Python 3. Probably, as long was dropped, some optimizations were unified. int in Python 3 is arbitrary-sized int – the same as long was in Python 2. As bool stores in the same way as new int, it affects both.
Interesting part:
>>> (0).__sizeof__()
24
>>> (1).__sizeof__() # Here one more "block" is allocated
28
>>> (2**30-1).__sizeof__() # This is the maximum integer size fitting into 28
28
+ bytes for object headers should complete the equation.
edited 16 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Slam
3,34511832
Actually, now in Python 3,intis just what Python 2longwas, it was reallyintthat was "dropped"
– juanpa.arrivillaga
6 hours ago
Internally – absolutely true, I'm talking about names, but thx for clarification
– Slam
6 hours ago
Indeed, in CPython 3 source code, it's still longobject
– juanpa.arrivillaga
6 hours ago
It is actually deoptimization... pessimization?
– Antti Haapala
6 hours ago
It's probably not. I may be wrong, but this overhead does not cost as much as two different types + seamless cast in runtime. The truth is, you rarely operate such a huge amount of ints in normal python program to care about this extra memory. If you do – you should use something like numpy to run with ~0 overhead and have pure int32/64 – no headers, no reallocation. But overflows from time to time )
– Slam
6 hours ago
add a comment |Â
up vote
3
down vote
up vote
3
down vote
I haven't seen CPython code for this, but I believe this has something to do with optimization of integers in Python 3. Probably, as long was dropped, some optimizations were unified. int in Python 3 is arbitrary-sized int – the same as long was in Python 2. As bool stores in the same way as new int, it affects both.
Interesting part:
>>> (0).__sizeof__()
24
>>> (1).__sizeof__() # Here one more "block" is allocated
28
>>> (2**30-1).__sizeof__() # This is the maximum integer size fitting into 28
28
+ bytes for object headers should complete the equation.
edited 16 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Slam
3,34511832
I haven't seen CPython code for this, but I believe this has something to do with optimization of integers in Python 3. Probably, as long was dropped, some optimizations were unified. int in Python 3 is arbitrary-sized int – the same as long was in Python 2. As bool stores in the same way as new int, it affects both.
Interesting part:
>>> (0).__sizeof__()
24
>>> (1).__sizeof__() # Here one more "block" is allocated
28
>>> (2**30-1).__sizeof__() # This is the maximum integer size fitting into 28
28
+ bytes for object headers should complete the equation.
edited 16 mins ago
Peter Mortensen
13.2k1983111
answered 6 hours ago
Slam
3,34511832
edited 16 mins ago
Peter Mortensen
13.2k1983111
edited 16 mins ago
Peter Mortensen
13.2k1983111
edited 16 mins ago
Peter Mortensen
13.2k1983111
13.2k1983111
answered 6 hours ago
Slam
3,34511832
answered 6 hours ago
Slam
3,34511832
answered 6 hours ago
Slam
3,34511832
3,34511832
Actually, now in Python 3,intis just what Python 2longwas, it was reallyintthat was "dropped"
– juanpa.arrivillaga
6 hours ago
Internally – absolutely true, I'm talking about names, but thx for clarification
– Slam
6 hours ago
Indeed, in CPython 3 source code, it's still longobject
– juanpa.arrivillaga
6 hours ago
It is actually deoptimization... pessimization?
– Antti Haapala
6 hours ago
It's probably not. I may be wrong, but this overhead does not cost as much as two different types + seamless cast in runtime. The truth is, you rarely operate such a huge amount of ints in normal python program to care about this extra memory. If you do – you should use something like numpy to run with ~0 overhead and have pure int32/64 – no headers, no reallocation. But overflows from time to time )
– Slam
6 hours ago
add a comment |Â
Actually, now in Python 3,intis just what Python 2longwas, it was reallyintthat was "dropped"
– juanpa.arrivillaga
6 hours ago
Internally – absolutely true, I'm talking about names, but thx for clarification
– Slam
6 hours ago
Indeed, in CPython 3 source code, it's still longobject
– juanpa.arrivillaga
6 hours ago
It is actually deoptimization... pessimization?
– Antti Haapala
6 hours ago
It's probably not. I may be wrong, but this overhead does not cost as much as two different types + seamless cast in runtime. The truth is, you rarely operate such a huge amount of ints in normal python program to care about this extra memory. If you do – you should use something like numpy to run with ~0 overhead and have pure int32/64 – no headers, no reallocation. But overflows from time to time )
– Slam
6 hours ago
Actually, now in Python 3,
int is just what Python 2 long was, it was really int that was "dropped"– juanpa.arrivillaga
6 hours ago
Actually, now in Python 3,
int is just what Python 2 long was, it was really int that was "dropped"– juanpa.arrivillaga
6 hours ago
Internally – absolutely true, I'm talking about names, but thx for clarification
– Slam
6 hours ago
Internally – absolutely true, I'm talking about names, but thx for clarification
– Slam
6 hours ago
Indeed, in CPython 3 source code, it's still longobject
– juanpa.arrivillaga
6 hours ago
Indeed, in CPython 3 source code, it's still longobject
– juanpa.arrivillaga
6 hours ago
It is actually deoptimization... pessimization?
– Antti Haapala
6 hours ago
It is actually deoptimization... pessimization?
– Antti Haapala
6 hours ago
It's probably not. I may be wrong, but this overhead does not cost as much as two different types + seamless cast in runtime. The truth is, you rarely operate such a huge amount of ints in normal python program to care about this extra memory. If you do – you should use something like numpy to run with ~0 overhead and have pure int32/64 – no headers, no reallocation. But overflows from time to time )
– Slam
6 hours ago
It's probably not. I may be wrong, but this overhead does not cost as much as two different types + seamless cast in runtime. The truth is, you rarely operate such a huge amount of ints in normal python program to care about this extra memory. If you do – you should use something like numpy to run with ~0 overhead and have pure int32/64 – no headers, no reallocation. But overflows from time to time )
– Slam
6 hours ago
add a comment |Â
up vote
2
down vote
Take a look at the cpython code for True and False
Internally it is represented as integer
PyTypeObject PyBool_Type =
PyVarObject_HEAD_INIT(&PyType_Type, 0)
"bool",
sizeof(struct _longobject),
0,
0, /* tp_dealloc */
0, /* tp_print */
0, /* tp_getattr */
0, /* tp_setattr */
0, /* tp_reserved */
bool_repr, /* tp_repr */
&bool_as_number, /* tp_as_number */
0, /* tp_as_sequence */
0, /* tp_as_mapping */
0, /* tp_hash */
0, /* tp_call */
bool_repr, /* tp_str */
0, /* tp_getattro */
0, /* tp_setattro */
0, /* tp_as_buffer */
Py_TPFLAGS_DEFAULT, /* tp_flags */
bool_doc, /* tp_doc */
0, /* tp_traverse */
0, /* tp_clear */
0, /* tp_richcompare */
0, /* tp_weaklistoffset */
0, /* tp_iter */
0, /* tp_iternext */
0, /* tp_methods */
0, /* tp_members */
0, /* tp_getset */
&PyLong_Type, /* tp_base */
0, /* tp_dict */
0, /* tp_descr_get */
0, /* tp_descr_set */
0, /* tp_dictoffset */
0, /* tp_init */
0, /* tp_alloc */
bool_new, /* tp_new */
;
/* The objects representing bool values False and True */
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct = {
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1 answered 6 hours ago
Kamil Niski
1,950111
I don't know why this was downvoted
– Antti Haapala
6 hours ago
I think i just was not as quick to answer properly as others :)
– Kamil Niski
6 hours ago
The answer only gets halfway there. It's represented as an integer.. yeah? And so what?
– wim
6 hours ago
@wim I don't see the need to explain it further since guys above already did great job at this. I don't want to duplicate content. Please refer to their answers.
– Kamil Niski
6 hours ago
2
I think so, but it's up to you. Should you wait for it to maybe get +3 and then delete you may earn a disciplined badge... :)
– wim
5 hours ago
 |Â
show 2 more comments
up vote
2
down vote
Take a look at the cpython code for True and False
Internally it is represented as integer
PyTypeObject PyBool_Type =
PyVarObject_HEAD_INIT(&PyType_Type, 0)
"bool",
sizeof(struct _longobject),
0,
0, /* tp_dealloc */
0, /* tp_print */
0, /* tp_getattr */
0, /* tp_setattr */
0, /* tp_reserved */
bool_repr, /* tp_repr */
&bool_as_number, /* tp_as_number */
0, /* tp_as_sequence */
0, /* tp_as_mapping */
0, /* tp_hash */
0, /* tp_call */
bool_repr, /* tp_str */
0, /* tp_getattro */
0, /* tp_setattro */
0, /* tp_as_buffer */
Py_TPFLAGS_DEFAULT, /* tp_flags */
bool_doc, /* tp_doc */
0, /* tp_traverse */
0, /* tp_clear */
0, /* tp_richcompare */
0, /* tp_weaklistoffset */
0, /* tp_iter */
0, /* tp_iternext */
0, /* tp_methods */
0, /* tp_members */
0, /* tp_getset */
&PyLong_Type, /* tp_base */
0, /* tp_dict */
0, /* tp_descr_get */
0, /* tp_descr_set */
0, /* tp_dictoffset */
0, /* tp_init */
0, /* tp_alloc */
bool_new, /* tp_new */
;
/* The objects representing bool values False and True */
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct = {
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1 answered 6 hours ago
Kamil Niski
1,950111
I don't know why this was downvoted
– Antti Haapala
6 hours ago
I think i just was not as quick to answer properly as others :)
– Kamil Niski
6 hours ago
The answer only gets halfway there. It's represented as an integer.. yeah? And so what?
– wim
6 hours ago
@wim I don't see the need to explain it further since guys above already did great job at this. I don't want to duplicate content. Please refer to their answers.
– Kamil Niski
6 hours ago
2
I think so, but it's up to you. Should you wait for it to maybe get +3 and then delete you may earn a disciplined badge... :)
– wim
5 hours ago
 |Â
show 2 more comments
up vote
2
down vote
up vote
2
down vote
Take a look at the cpython code for True and False
Internally it is represented as integer
PyTypeObject PyBool_Type =
PyVarObject_HEAD_INIT(&PyType_Type, 0)
"bool",
sizeof(struct _longobject),
0,
0, /* tp_dealloc */
0, /* tp_print */
0, /* tp_getattr */
0, /* tp_setattr */
0, /* tp_reserved */
bool_repr, /* tp_repr */
&bool_as_number, /* tp_as_number */
0, /* tp_as_sequence */
0, /* tp_as_mapping */
0, /* tp_hash */
0, /* tp_call */
bool_repr, /* tp_str */
0, /* tp_getattro */
0, /* tp_setattro */
0, /* tp_as_buffer */
Py_TPFLAGS_DEFAULT, /* tp_flags */
bool_doc, /* tp_doc */
0, /* tp_traverse */
0, /* tp_clear */
0, /* tp_richcompare */
0, /* tp_weaklistoffset */
0, /* tp_iter */
0, /* tp_iternext */
0, /* tp_methods */
0, /* tp_members */
0, /* tp_getset */
&PyLong_Type, /* tp_base */
0, /* tp_dict */
0, /* tp_descr_get */
0, /* tp_descr_set */
0, /* tp_dictoffset */
0, /* tp_init */
0, /* tp_alloc */
bool_new, /* tp_new */
;
/* The objects representing bool values False and True */
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct = {
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1 answered 6 hours ago
Kamil Niski
1,950111
Take a look at the cpython code for True and False
Internally it is represented as integer
PyTypeObject PyBool_Type =
PyVarObject_HEAD_INIT(&PyType_Type, 0)
"bool",
sizeof(struct _longobject),
0,
0, /* tp_dealloc */
0, /* tp_print */
0, /* tp_getattr */
0, /* tp_setattr */
0, /* tp_reserved */
bool_repr, /* tp_repr */
&bool_as_number, /* tp_as_number */
0, /* tp_as_sequence */
0, /* tp_as_mapping */
0, /* tp_hash */
0, /* tp_call */
bool_repr, /* tp_str */
0, /* tp_getattro */
0, /* tp_setattro */
0, /* tp_as_buffer */
Py_TPFLAGS_DEFAULT, /* tp_flags */
bool_doc, /* tp_doc */
0, /* tp_traverse */
0, /* tp_clear */
0, /* tp_richcompare */
0, /* tp_weaklistoffset */
0, /* tp_iter */
0, /* tp_iternext */
0, /* tp_methods */
0, /* tp_members */
0, /* tp_getset */
&PyLong_Type, /* tp_base */
0, /* tp_dict */
0, /* tp_descr_get */
0, /* tp_descr_set */
0, /* tp_dictoffset */
0, /* tp_init */
0, /* tp_alloc */
bool_new, /* tp_new */
;
/* The objects representing bool values False and True */
struct _longobject _Py_FalseStruct =
PyVarObject_HEAD_INIT(&PyBool_Type, 0)
0
;
struct _longobject _Py_TrueStruct = {
PyVarObject_HEAD_INIT(&PyBool_Type, 1)
1 answered 6 hours ago
Kamil Niski
1,950111
edited 6 hours ago
answered 6 hours ago
Kamil Niski
1,950111
answered 6 hours ago
Kamil Niski
1,950111
answered 6 hours ago
Kamil Niski
1,950111
1,950111
I don't know why this was downvoted
– Antti Haapala
6 hours ago
I think i just was not as quick to answer properly as others :)
– Kamil Niski
6 hours ago
The answer only gets halfway there. It's represented as an integer.. yeah? And so what?
– wim
6 hours ago
@wim I don't see the need to explain it further since guys above already did great job at this. I don't want to duplicate content. Please refer to their answers.
– Kamil Niski
6 hours ago
2
I think so, but it's up to you. Should you wait for it to maybe get +3 and then delete you may earn a disciplined badge... :)
– wim
5 hours ago
 |Â
show 2 more comments
I don't know why this was downvoted
– Antti Haapala
6 hours ago
I think i just was not as quick to answer properly as others :)
– Kamil Niski
6 hours ago
The answer only gets halfway there. It's represented as an integer.. yeah? And so what?
– wim
6 hours ago
@wim I don't see the need to explain it further since guys above already did great job at this. I don't want to duplicate content. Please refer to their answers.
– Kamil Niski
6 hours ago
2
I think so, but it's up to you. Should you wait for it to maybe get +3 and then delete you may earn a disciplined badge... :)
– wim
5 hours ago
I don't know why this was downvoted
– Antti Haapala
6 hours ago
I don't know why this was downvoted
– Antti Haapala
6 hours ago
I think i just was not as quick to answer properly as others :)
– Kamil Niski
6 hours ago
I think i just was not as quick to answer properly as others :)
– Kamil Niski
6 hours ago
The answer only gets halfway there. It's represented as an integer.. yeah? And so what?
– wim
6 hours ago
The answer only gets halfway there. It's represented as an integer.. yeah? And so what?
– wim
6 hours ago
@wim I don't see the need to explain it further since guys above already did great job at this. I don't want to duplicate content. Please refer to their answers.
– Kamil Niski
6 hours ago
@wim I don't see the need to explain it further since guys above already did great job at this. I don't want to duplicate content. Please refer to their answers.
– Kamil Niski
6 hours ago
2
2
I think so, but it's up to you. Should you wait for it to maybe get +3 and then delete you may earn a disciplined badge... :)
– wim
5 hours ago
I think so, but it's up to you. Should you wait for it to maybe get +3 and then delete you may earn a disciplined badge... :)
– wim
5 hours ago
 |Â
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2
diris totally irrelevant.– juanpa.arrivillaga
7 hours ago
3
Related, the same behavior appears for
0vs1– user3483203
7 hours ago
@juanpa.arrivillaga can you qualify that? If
diris irrelevant in understanding this, what is?– roganjosh
7 hours ago
2
Because
dirreturns a lot of things that have nothing to do with whatsys.sizeofreturns. Note,dir([1,2,3,4,5]) == dir()butsys.getsizeof([1,2,3,4,5,]) != sys.getsizeof()– juanpa.arrivillaga
6 hours ago
1
@roganjosh and just in general,
dirwill give you every attribute accessible from an object, but you don't care about that, so for example, when you ask about the size of an object you generally don't want to include all the methods that belong to various classes that it has access to, do you?– juanpa.arrivillaga
6 hours ago