Extract first column value for line with specific second column value from three-columns file with awk

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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I need to Write an awk command that will return the identification number from the following table for only the lines where the title is Turtle. This table is stored in turtle.txt



Id Num. Title CatchDate
433417 RedTurtle 2001-06-29
493303 BlueTurtle 1998-09-20
259497 Turtle 1985-05-08
229505 RedTurtle 1994-07-13
473076 OrangeTurtle 2002-03-08
221907 Blueturtle 1999-07-02
457032 Turtle 1993-04-09
490359 RedTurtle 1996-11-12
494595 SnappingTurtle 1985-05-20
402421 BlueTurtle 1999-08-16









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  • 1




    I'm amazed that this simple question could attract 6 answers so far.
    – simlev
    1 hour ago










  • @simlev, the Hot Network Questions algorithm is a mystery; it's contributing to the views & votes here
    – Jeff Schaller
    1 hour ago










  • Hi Kamat. I generalized the title of your question. The answer would be the same if this was about, say, a part number / description / price table, so the fact that it's about animals in this case seems inconsequential to answering the question.
    – Michael Kjörling
    19 secs ago














up vote
5
down vote

favorite












I need to Write an awk command that will return the identification number from the following table for only the lines where the title is Turtle. This table is stored in turtle.txt



Id Num. Title CatchDate
433417 RedTurtle 2001-06-29
493303 BlueTurtle 1998-09-20
259497 Turtle 1985-05-08
229505 RedTurtle 1994-07-13
473076 OrangeTurtle 2002-03-08
221907 Blueturtle 1999-07-02
457032 Turtle 1993-04-09
490359 RedTurtle 1996-11-12
494595 SnappingTurtle 1985-05-20
402421 BlueTurtle 1999-08-16









share|improve this question









New contributor




Kamat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 1




    I'm amazed that this simple question could attract 6 answers so far.
    – simlev
    1 hour ago










  • @simlev, the Hot Network Questions algorithm is a mystery; it's contributing to the views & votes here
    – Jeff Schaller
    1 hour ago










  • Hi Kamat. I generalized the title of your question. The answer would be the same if this was about, say, a part number / description / price table, so the fact that it's about animals in this case seems inconsequential to answering the question.
    – Michael Kjörling
    19 secs ago












up vote
5
down vote

favorite









up vote
5
down vote

favorite











I need to Write an awk command that will return the identification number from the following table for only the lines where the title is Turtle. This table is stored in turtle.txt



Id Num. Title CatchDate
433417 RedTurtle 2001-06-29
493303 BlueTurtle 1998-09-20
259497 Turtle 1985-05-08
229505 RedTurtle 1994-07-13
473076 OrangeTurtle 2002-03-08
221907 Blueturtle 1999-07-02
457032 Turtle 1993-04-09
490359 RedTurtle 1996-11-12
494595 SnappingTurtle 1985-05-20
402421 BlueTurtle 1999-08-16









share|improve this question









New contributor




Kamat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I need to Write an awk command that will return the identification number from the following table for only the lines where the title is Turtle. This table is stored in turtle.txt



Id Num. Title CatchDate
433417 RedTurtle 2001-06-29
493303 BlueTurtle 1998-09-20
259497 Turtle 1985-05-08
229505 RedTurtle 1994-07-13
473076 OrangeTurtle 2002-03-08
221907 Blueturtle 1999-07-02
457032 Turtle 1993-04-09
490359 RedTurtle 1996-11-12
494595 SnappingTurtle 1985-05-20
402421 BlueTurtle 1999-08-16






text-processing awk






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share|improve this question









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Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 1 min ago









Michael Kjörling

16.2k84799




16.2k84799






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asked 4 hours ago









Kamat

333




333




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Kamat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






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Check out our Code of Conduct.







  • 1




    I'm amazed that this simple question could attract 6 answers so far.
    – simlev
    1 hour ago










  • @simlev, the Hot Network Questions algorithm is a mystery; it's contributing to the views & votes here
    – Jeff Schaller
    1 hour ago










  • Hi Kamat. I generalized the title of your question. The answer would be the same if this was about, say, a part number / description / price table, so the fact that it's about animals in this case seems inconsequential to answering the question.
    – Michael Kjörling
    19 secs ago












  • 1




    I'm amazed that this simple question could attract 6 answers so far.
    – simlev
    1 hour ago










  • @simlev, the Hot Network Questions algorithm is a mystery; it's contributing to the views & votes here
    – Jeff Schaller
    1 hour ago










  • Hi Kamat. I generalized the title of your question. The answer would be the same if this was about, say, a part number / description / price table, so the fact that it's about animals in this case seems inconsequential to answering the question.
    – Michael Kjörling
    19 secs ago







1




1




I'm amazed that this simple question could attract 6 answers so far.
– simlev
1 hour ago




I'm amazed that this simple question could attract 6 answers so far.
– simlev
1 hour ago












@simlev, the Hot Network Questions algorithm is a mystery; it's contributing to the views & votes here
– Jeff Schaller
1 hour ago




@simlev, the Hot Network Questions algorithm is a mystery; it's contributing to the views & votes here
– Jeff Schaller
1 hour ago












Hi Kamat. I generalized the title of your question. The answer would be the same if this was about, say, a part number / description / price table, so the fact that it's about animals in this case seems inconsequential to answering the question.
– Michael Kjörling
19 secs ago




Hi Kamat. I generalized the title of your question. The answer would be the same if this was about, say, a part number / description / price table, so the fact that it's about animals in this case seems inconsequential to answering the question.
– Michael Kjörling
19 secs ago










6 Answers
6






active

oldest

votes

















up vote
5
down vote













You can use:



awk '$2 == "Turtle" print $1' file
259497
457032





share|improve this answer





























    up vote
    5
    down vote













    awk '$2 == "Turtle" print $1' turtle.txt
    259497
    457032


    $2 is the field to select

    Turtle is the text to match

    print $1 is to print the first field.

    turtle.txt is the name of the source file.






    share|improve this answer





























      up vote
      4
      down vote













      Golfing it:



      $ awk '$2=="Turtle"&&$0=$1' <file
      259497
      457032


      Or, expanded in stages until we reach Isaac's and Goro's answers



      awk '$2 == "Turtle" && $0 = $1' <file

      awk '$2 == "Turtle" $0 = $1; print ' <file

      awk '$2 == "Turtle" print $1 ' <file


      The three are not exactly equivalent as my golfed code would not print the number if it was zero (the result of $0=$1 is used as a conditional).




      Here's a proper sed solution to make up for the golfing above:



      $ sed -n '/<Turtle>/s/[[:blank:]].*//p' <file
      259497
      457032


      It finds all lines containing the word Turtle and then remowes the first space or tab character and everything after it on those lines before printing them (printing of other lines is inhibited by -n).



      The < and > matches word start and end boundaries so that <Turtle> matches only the string Turtle and not e.g. RedTurtle.






      share|improve this answer






















      • The first one won't work properly when the id is zero
        – user000001
        1 hour ago










      • @user000001 This was already made clear in the answer.
        – Kusalananda
        1 hour ago






      • 1




        But it adds nothing useful IMO. That's more of an example of things not to do (use assignments as conditions in awk).
        – Stéphane Chazelas
        1 hour ago











      • Note that <Turtle> is not portable and would match on Red-Turtle. You would need something like sed -n 's/^[[:blank:]]*([^[:blank:]]1,)[[:blank:]]1,Turtle([[:blank:]].*)0,1$/1/p' for a real equivalent.
        – Stéphane Chazelas
        1 hour ago

















      up vote
      3
      down vote













      non-awk alternative:



      grep -w "Turtle" turtle.txt | cut -d " " -f 1






      share|improve this answer



























        up vote
        3
        down vote













        Using sed:



        sed -n '/sTurtles/s/^([0-9]+)s.*/1/p' file





        share|improve this answer



























          up vote
          1
          down vote













          You may employ grep in this:



           grep -oP '^d+(?=h+Turtleh)'





          share|improve this answer




















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            6 Answers
            6






            active

            oldest

            votes








            6 Answers
            6






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            5
            down vote













            You can use:



            awk '$2 == "Turtle" print $1' file
            259497
            457032





            share|improve this answer


























              up vote
              5
              down vote













              You can use:



              awk '$2 == "Turtle" print $1' file
              259497
              457032





              share|improve this answer
























                up vote
                5
                down vote










                up vote
                5
                down vote









                You can use:



                awk '$2 == "Turtle" print $1' file
                259497
                457032





                share|improve this answer














                You can use:



                awk '$2 == "Turtle" print $1' file
                259497
                457032






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 4 hours ago

























                answered 4 hours ago









                Goro

                7,54253270




                7,54253270






















                    up vote
                    5
                    down vote













                    awk '$2 == "Turtle" print $1' turtle.txt
                    259497
                    457032


                    $2 is the field to select

                    Turtle is the text to match

                    print $1 is to print the first field.

                    turtle.txt is the name of the source file.






                    share|improve this answer


























                      up vote
                      5
                      down vote













                      awk '$2 == "Turtle" print $1' turtle.txt
                      259497
                      457032


                      $2 is the field to select

                      Turtle is the text to match

                      print $1 is to print the first field.

                      turtle.txt is the name of the source file.






                      share|improve this answer
























                        up vote
                        5
                        down vote










                        up vote
                        5
                        down vote









                        awk '$2 == "Turtle" print $1' turtle.txt
                        259497
                        457032


                        $2 is the field to select

                        Turtle is the text to match

                        print $1 is to print the first field.

                        turtle.txt is the name of the source file.






                        share|improve this answer














                        awk '$2 == "Turtle" print $1' turtle.txt
                        259497
                        457032


                        $2 is the field to select

                        Turtle is the text to match

                        print $1 is to print the first field.

                        turtle.txt is the name of the source file.







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited 4 hours ago

























                        answered 4 hours ago









                        Isaac

                        7,81711137




                        7,81711137




















                            up vote
                            4
                            down vote













                            Golfing it:



                            $ awk '$2=="Turtle"&&$0=$1' <file
                            259497
                            457032


                            Or, expanded in stages until we reach Isaac's and Goro's answers



                            awk '$2 == "Turtle" && $0 = $1' <file

                            awk '$2 == "Turtle" $0 = $1; print ' <file

                            awk '$2 == "Turtle" print $1 ' <file


                            The three are not exactly equivalent as my golfed code would not print the number if it was zero (the result of $0=$1 is used as a conditional).




                            Here's a proper sed solution to make up for the golfing above:



                            $ sed -n '/<Turtle>/s/[[:blank:]].*//p' <file
                            259497
                            457032


                            It finds all lines containing the word Turtle and then remowes the first space or tab character and everything after it on those lines before printing them (printing of other lines is inhibited by -n).



                            The < and > matches word start and end boundaries so that <Turtle> matches only the string Turtle and not e.g. RedTurtle.






                            share|improve this answer






















                            • The first one won't work properly when the id is zero
                              – user000001
                              1 hour ago










                            • @user000001 This was already made clear in the answer.
                              – Kusalananda
                              1 hour ago






                            • 1




                              But it adds nothing useful IMO. That's more of an example of things not to do (use assignments as conditions in awk).
                              – Stéphane Chazelas
                              1 hour ago











                            • Note that <Turtle> is not portable and would match on Red-Turtle. You would need something like sed -n 's/^[[:blank:]]*([^[:blank:]]1,)[[:blank:]]1,Turtle([[:blank:]].*)0,1$/1/p' for a real equivalent.
                              – Stéphane Chazelas
                              1 hour ago














                            up vote
                            4
                            down vote













                            Golfing it:



                            $ awk '$2=="Turtle"&&$0=$1' <file
                            259497
                            457032


                            Or, expanded in stages until we reach Isaac's and Goro's answers



                            awk '$2 == "Turtle" && $0 = $1' <file

                            awk '$2 == "Turtle" $0 = $1; print ' <file

                            awk '$2 == "Turtle" print $1 ' <file


                            The three are not exactly equivalent as my golfed code would not print the number if it was zero (the result of $0=$1 is used as a conditional).




                            Here's a proper sed solution to make up for the golfing above:



                            $ sed -n '/<Turtle>/s/[[:blank:]].*//p' <file
                            259497
                            457032


                            It finds all lines containing the word Turtle and then remowes the first space or tab character and everything after it on those lines before printing them (printing of other lines is inhibited by -n).



                            The < and > matches word start and end boundaries so that <Turtle> matches only the string Turtle and not e.g. RedTurtle.






                            share|improve this answer






















                            • The first one won't work properly when the id is zero
                              – user000001
                              1 hour ago










                            • @user000001 This was already made clear in the answer.
                              – Kusalananda
                              1 hour ago






                            • 1




                              But it adds nothing useful IMO. That's more of an example of things not to do (use assignments as conditions in awk).
                              – Stéphane Chazelas
                              1 hour ago











                            • Note that <Turtle> is not portable and would match on Red-Turtle. You would need something like sed -n 's/^[[:blank:]]*([^[:blank:]]1,)[[:blank:]]1,Turtle([[:blank:]].*)0,1$/1/p' for a real equivalent.
                              – Stéphane Chazelas
                              1 hour ago












                            up vote
                            4
                            down vote










                            up vote
                            4
                            down vote









                            Golfing it:



                            $ awk '$2=="Turtle"&&$0=$1' <file
                            259497
                            457032


                            Or, expanded in stages until we reach Isaac's and Goro's answers



                            awk '$2 == "Turtle" && $0 = $1' <file

                            awk '$2 == "Turtle" $0 = $1; print ' <file

                            awk '$2 == "Turtle" print $1 ' <file


                            The three are not exactly equivalent as my golfed code would not print the number if it was zero (the result of $0=$1 is used as a conditional).




                            Here's a proper sed solution to make up for the golfing above:



                            $ sed -n '/<Turtle>/s/[[:blank:]].*//p' <file
                            259497
                            457032


                            It finds all lines containing the word Turtle and then remowes the first space or tab character and everything after it on those lines before printing them (printing of other lines is inhibited by -n).



                            The < and > matches word start and end boundaries so that <Turtle> matches only the string Turtle and not e.g. RedTurtle.






                            share|improve this answer














                            Golfing it:



                            $ awk '$2=="Turtle"&&$0=$1' <file
                            259497
                            457032


                            Or, expanded in stages until we reach Isaac's and Goro's answers



                            awk '$2 == "Turtle" && $0 = $1' <file

                            awk '$2 == "Turtle" $0 = $1; print ' <file

                            awk '$2 == "Turtle" print $1 ' <file


                            The three are not exactly equivalent as my golfed code would not print the number if it was zero (the result of $0=$1 is used as a conditional).




                            Here's a proper sed solution to make up for the golfing above:



                            $ sed -n '/<Turtle>/s/[[:blank:]].*//p' <file
                            259497
                            457032


                            It finds all lines containing the word Turtle and then remowes the first space or tab character and everything after it on those lines before printing them (printing of other lines is inhibited by -n).



                            The < and > matches word start and end boundaries so that <Turtle> matches only the string Turtle and not e.g. RedTurtle.







                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited 3 hours ago

























                            answered 4 hours ago









                            Kusalananda

                            109k14210333




                            109k14210333











                            • The first one won't work properly when the id is zero
                              – user000001
                              1 hour ago










                            • @user000001 This was already made clear in the answer.
                              – Kusalananda
                              1 hour ago






                            • 1




                              But it adds nothing useful IMO. That's more of an example of things not to do (use assignments as conditions in awk).
                              – Stéphane Chazelas
                              1 hour ago











                            • Note that <Turtle> is not portable and would match on Red-Turtle. You would need something like sed -n 's/^[[:blank:]]*([^[:blank:]]1,)[[:blank:]]1,Turtle([[:blank:]].*)0,1$/1/p' for a real equivalent.
                              – Stéphane Chazelas
                              1 hour ago
















                            • The first one won't work properly when the id is zero
                              – user000001
                              1 hour ago










                            • @user000001 This was already made clear in the answer.
                              – Kusalananda
                              1 hour ago






                            • 1




                              But it adds nothing useful IMO. That's more of an example of things not to do (use assignments as conditions in awk).
                              – Stéphane Chazelas
                              1 hour ago











                            • Note that <Turtle> is not portable and would match on Red-Turtle. You would need something like sed -n 's/^[[:blank:]]*([^[:blank:]]1,)[[:blank:]]1,Turtle([[:blank:]].*)0,1$/1/p' for a real equivalent.
                              – Stéphane Chazelas
                              1 hour ago















                            The first one won't work properly when the id is zero
                            – user000001
                            1 hour ago




                            The first one won't work properly when the id is zero
                            – user000001
                            1 hour ago












                            @user000001 This was already made clear in the answer.
                            – Kusalananda
                            1 hour ago




                            @user000001 This was already made clear in the answer.
                            – Kusalananda
                            1 hour ago




                            1




                            1




                            But it adds nothing useful IMO. That's more of an example of things not to do (use assignments as conditions in awk).
                            – Stéphane Chazelas
                            1 hour ago





                            But it adds nothing useful IMO. That's more of an example of things not to do (use assignments as conditions in awk).
                            – Stéphane Chazelas
                            1 hour ago













                            Note that <Turtle> is not portable and would match on Red-Turtle. You would need something like sed -n 's/^[[:blank:]]*([^[:blank:]]1,)[[:blank:]]1,Turtle([[:blank:]].*)0,1$/1/p' for a real equivalent.
                            – Stéphane Chazelas
                            1 hour ago




                            Note that <Turtle> is not portable and would match on Red-Turtle. You would need something like sed -n 's/^[[:blank:]]*([^[:blank:]]1,)[[:blank:]]1,Turtle([[:blank:]].*)0,1$/1/p' for a real equivalent.
                            – Stéphane Chazelas
                            1 hour ago










                            up vote
                            3
                            down vote













                            non-awk alternative:



                            grep -w "Turtle" turtle.txt | cut -d " " -f 1






                            share|improve this answer
























                              up vote
                              3
                              down vote













                              non-awk alternative:



                              grep -w "Turtle" turtle.txt | cut -d " " -f 1






                              share|improve this answer






















                                up vote
                                3
                                down vote










                                up vote
                                3
                                down vote









                                non-awk alternative:



                                grep -w "Turtle" turtle.txt | cut -d " " -f 1






                                share|improve this answer












                                non-awk alternative:



                                grep -w "Turtle" turtle.txt | cut -d " " -f 1







                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered 4 hours ago









                                RobotJohnny

                                740216




                                740216




















                                    up vote
                                    3
                                    down vote













                                    Using sed:



                                    sed -n '/sTurtles/s/^([0-9]+)s.*/1/p' file





                                    share|improve this answer
























                                      up vote
                                      3
                                      down vote













                                      Using sed:



                                      sed -n '/sTurtles/s/^([0-9]+)s.*/1/p' file





                                      share|improve this answer






















                                        up vote
                                        3
                                        down vote










                                        up vote
                                        3
                                        down vote









                                        Using sed:



                                        sed -n '/sTurtles/s/^([0-9]+)s.*/1/p' file





                                        share|improve this answer












                                        Using sed:



                                        sed -n '/sTurtles/s/^([0-9]+)s.*/1/p' file






                                        share|improve this answer












                                        share|improve this answer



                                        share|improve this answer










                                        answered 4 hours ago









                                        oliv

                                        1,121210




                                        1,121210




















                                            up vote
                                            1
                                            down vote













                                            You may employ grep in this:



                                             grep -oP '^d+(?=h+Turtleh)'





                                            share|improve this answer
























                                              up vote
                                              1
                                              down vote













                                              You may employ grep in this:



                                               grep -oP '^d+(?=h+Turtleh)'





                                              share|improve this answer






















                                                up vote
                                                1
                                                down vote










                                                up vote
                                                1
                                                down vote









                                                You may employ grep in this:



                                                 grep -oP '^d+(?=h+Turtleh)'





                                                share|improve this answer












                                                You may employ grep in this:



                                                 grep -oP '^d+(?=h+Turtleh)'






                                                share|improve this answer












                                                share|improve this answer



                                                share|improve this answer










                                                answered 1 hour ago









                                                Rakesh Sharma

                                                207113




                                                207113




















                                                    Kamat is a new contributor. Be nice, and check out our Code of Conduct.









                                                     

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