Mixing
Restaurant at the End of the Universe
Clash Royale CLAN TAG#URR8PPP
up vote
4
down vote
favorite
I wrote a basic menu application for my intro to python. I'm fairly new, and python does look promising. However, I am disappointed that it won't let me use Unicode.
the_burger = 16.99;
french_fries = 5.99;
currie_sauce = 19.99;
napkins_with_chocolates = 10.50;
juice_box = 89.01;
takeout = 18.99;
total = 0.0;
DONE = False
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+
| AtThe "Big Boy" Burger | $""" + str(the_burger) + """ |
+---------------------------------+---------+
| BtFrench Fries | $""" + str(french_fries) + """ |
+---------------------------------+---------+
| CtCurrie sauce | $""" + str(currie_sauce) + """ |
+---------------------------------+---------+
| DtNapkins with Chocolates | $""" + str(napkins_with_chocolates) + str(0) + """ |
+---------------------------------+---------+
| EtJuice Box | $""" + str(juice_box) + """ |
+---------------------------------+---------+
| FtTakeout | $""" + str(takeout) + """ |
+---------------------------------+---------+
""");
while(not DONE):
print("Total:", total);
Item = input("Select a letter or 'done': ");
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
total += takeout;
elif Item is "done":
print("Final total:", total);
DONE = True
The following is NOT intended for review, and is proof that it won't let me use unicode in python 3.6.5:
>>> print("♠♞ ♜ ")
Traceback (most recent call last):
File "jdoodle.py", line 1, in <module>
print("u265d u265e u265c ")
UnicodeEncodeError: 'ascii' codec can't encode character 'u265d' in position 0: ordinal not in range(128)
Command exited with non-zero status 1
python python-3.x
asked 4 hours ago
FreezePhoenix
513323
 |Â
show 5 more comments
up vote
4
down vote
favorite
I wrote a basic menu application for my intro to python. I'm fairly new, and python does look promising. However, I am disappointed that it won't let me use Unicode.
the_burger = 16.99;
french_fries = 5.99;
currie_sauce = 19.99;
napkins_with_chocolates = 10.50;
juice_box = 89.01;
takeout = 18.99;
total = 0.0;
DONE = False
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+
| AtThe "Big Boy" Burger | $""" + str(the_burger) + """ |
+---------------------------------+---------+
| BtFrench Fries | $""" + str(french_fries) + """ |
+---------------------------------+---------+
| CtCurrie sauce | $""" + str(currie_sauce) + """ |
+---------------------------------+---------+
| DtNapkins with Chocolates | $""" + str(napkins_with_chocolates) + str(0) + """ |
+---------------------------------+---------+
| EtJuice Box | $""" + str(juice_box) + """ |
+---------------------------------+---------+
| FtTakeout | $""" + str(takeout) + """ |
+---------------------------------+---------+
""");
while(not DONE):
print("Total:", total);
Item = input("Select a letter or 'done': ");
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
total += takeout;
elif Item is "done":
print("Final total:", total);
DONE = True
The following is NOT intended for review, and is proof that it won't let me use unicode in python 3.6.5:
>>> print("♠♞ ♜ ")
Traceback (most recent call last):
File "jdoodle.py", line 1, in <module>
print("u265d u265e u265c ")
UnicodeEncodeError: 'ascii' codec can't encode character 'u265d' in position 0: ordinal not in range(128)
Command exited with non-zero status 1
python python-3.x
asked 4 hours ago
FreezePhoenix
513323
4
It will let you use Unicode - and probably much more of Unicode than you're already using...
– Toby Speight
4 hours ago
3
Did you ask nicely? (What I mean is, how did you try? And how did it refuse? I know this isn't Stack Overflow, so the non-working code wouldn't be on-topic, but I'd be interested to know).
– Toby Speight
4 hours ago
2
Unicode is supposed to be available out-of-the-box. Example here.
– Mathias Ettinger
3 hours ago
2
Time to use a better IDE then: ideone.com/uK6XJ6
– Mathias Ettinger
2 hours ago
2
I'm not quite sure what the downvote is for... I've followed all of the rules for CR that I can tell.
– FreezePhoenix
1 hour ago
 |Â
show 5 more comments
up vote
4
down vote
favorite
up vote
4
down vote
favorite
I wrote a basic menu application for my intro to python. I'm fairly new, and python does look promising. However, I am disappointed that it won't let me use Unicode.
the_burger = 16.99;
french_fries = 5.99;
currie_sauce = 19.99;
napkins_with_chocolates = 10.50;
juice_box = 89.01;
takeout = 18.99;
total = 0.0;
DONE = False
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+
| AtThe "Big Boy" Burger | $""" + str(the_burger) + """ |
+---------------------------------+---------+
| BtFrench Fries | $""" + str(french_fries) + """ |
+---------------------------------+---------+
| CtCurrie sauce | $""" + str(currie_sauce) + """ |
+---------------------------------+---------+
| DtNapkins with Chocolates | $""" + str(napkins_with_chocolates) + str(0) + """ |
+---------------------------------+---------+
| EtJuice Box | $""" + str(juice_box) + """ |
+---------------------------------+---------+
| FtTakeout | $""" + str(takeout) + """ |
+---------------------------------+---------+
""");
while(not DONE):
print("Total:", total);
Item = input("Select a letter or 'done': ");
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
total += takeout;
elif Item is "done":
print("Final total:", total);
DONE = True
The following is NOT intended for review, and is proof that it won't let me use unicode in python 3.6.5:
>>> print("♠♞ ♜ ")
Traceback (most recent call last):
File "jdoodle.py", line 1, in <module>
print("u265d u265e u265c ")
UnicodeEncodeError: 'ascii' codec can't encode character 'u265d' in position 0: ordinal not in range(128)
Command exited with non-zero status 1
python python-3.x
asked 4 hours ago
FreezePhoenix
513323
I wrote a basic menu application for my intro to python. I'm fairly new, and python does look promising. However, I am disappointed that it won't let me use Unicode.
the_burger = 16.99;
french_fries = 5.99;
currie_sauce = 19.99;
napkins_with_chocolates = 10.50;
juice_box = 89.01;
takeout = 18.99;
total = 0.0;
DONE = False
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+
| AtThe "Big Boy" Burger | $""" + str(the_burger) + """ |
+---------------------------------+---------+
| BtFrench Fries | $""" + str(french_fries) + """ |
+---------------------------------+---------+
| CtCurrie sauce | $""" + str(currie_sauce) + """ |
+---------------------------------+---------+
| DtNapkins with Chocolates | $""" + str(napkins_with_chocolates) + str(0) + """ |
+---------------------------------+---------+
| EtJuice Box | $""" + str(juice_box) + """ |
+---------------------------------+---------+
| FtTakeout | $""" + str(takeout) + """ |
+---------------------------------+---------+
""");
while(not DONE):
print("Total:", total);
Item = input("Select a letter or 'done': ");
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
total += takeout;
elif Item is "done":
print("Final total:", total);
DONE = True
The following is NOT intended for review, and is proof that it won't let me use unicode in python 3.6.5:
>>> print("♠♞ ♜ ")
Traceback (most recent call last):
File "jdoodle.py", line 1, in <module>
print("u265d u265e u265c ")
UnicodeEncodeError: 'ascii' codec can't encode character 'u265d' in position 0: ordinal not in range(128)
Command exited with non-zero status 1
python python-3.x
python python-3.x
asked 4 hours ago
FreezePhoenix
513323
asked 4 hours ago
FreezePhoenix
513323
edited 2 hours ago
asked 4 hours ago
FreezePhoenix
513323
asked 4 hours ago
FreezePhoenix
513323
asked 4 hours ago
FreezePhoenix
513323
513323
4
It will let you use Unicode - and probably much more of Unicode than you're already using...
– Toby Speight
4 hours ago
3
Did you ask nicely? (What I mean is, how did you try? And how did it refuse? I know this isn't Stack Overflow, so the non-working code wouldn't be on-topic, but I'd be interested to know).
– Toby Speight
4 hours ago
2
Unicode is supposed to be available out-of-the-box. Example here.
– Mathias Ettinger
3 hours ago
2
Time to use a better IDE then: ideone.com/uK6XJ6
– Mathias Ettinger
2 hours ago
2
I'm not quite sure what the downvote is for... I've followed all of the rules for CR that I can tell.
– FreezePhoenix
1 hour ago
 |Â
show 5 more comments
4
It will let you use Unicode - and probably much more of Unicode than you're already using...
– Toby Speight
4 hours ago
3
Did you ask nicely? (What I mean is, how did you try? And how did it refuse? I know this isn't Stack Overflow, so the non-working code wouldn't be on-topic, but I'd be interested to know).
– Toby Speight
4 hours ago
2
Unicode is supposed to be available out-of-the-box. Example here.
– Mathias Ettinger
3 hours ago
2
Time to use a better IDE then: ideone.com/uK6XJ6
– Mathias Ettinger
2 hours ago
2
I'm not quite sure what the downvote is for... I've followed all of the rules for CR that I can tell.
– FreezePhoenix
1 hour ago
4
4
It will let you use Unicode - and probably much more of Unicode than you're already using...
– Toby Speight
4 hours ago
It will let you use Unicode - and probably much more of Unicode than you're already using...
– Toby Speight
4 hours ago
3
3
Did you ask nicely? (What I mean is, how did you try? And how did it refuse? I know this isn't Stack Overflow, so the non-working code wouldn't be on-topic, but I'd be interested to know).
– Toby Speight
4 hours ago
Did you ask nicely? (What I mean is, how did you try? And how did it refuse? I know this isn't Stack Overflow, so the non-working code wouldn't be on-topic, but I'd be interested to know).
– Toby Speight
4 hours ago
2
2
Unicode is supposed to be available out-of-the-box. Example here.
– Mathias Ettinger
3 hours ago
Unicode is supposed to be available out-of-the-box. Example here.
– Mathias Ettinger
3 hours ago
2
2
Time to use a better IDE then: ideone.com/uK6XJ6
– Mathias Ettinger
2 hours ago
Time to use a better IDE then: ideone.com/uK6XJ6
– Mathias Ettinger
2 hours ago
2
2
I'm not quite sure what the downvote is for... I've followed all of the rules for CR that I can tell.
– FreezePhoenix
1 hour ago
I'm not quite sure what the downvote is for... I've followed all of the rules for CR that I can tell.
– FreezePhoenix
1 hour ago
 |Â
show 5 more comments
1 Answer
1
active
oldest
votes
up vote
2
down vote
Huge bug in 3.5.2
Entering done does nothing in Python 3.5.2, use == instead of is to fix this. In general is asks if two objects are the same object not if the contents are the same, this can give results different from what you expect for lists, so I suggest using == overall.
https://dbader.org/blog/difference-between-is-and-equals-in-python
Code repetition / Extensibility
A famous problem is code extensibility, it is quite inconvenient to add another item to the menu, also if you take a look at this list of ifs
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
you will notice that the only thing that happens is adding the cost to the total each time so there is a lot of repetition.
So let me explain a better solution.
I will use a list of tuples (pairs) of the form (food, price).
Than both the printing and the accounting of the money can be done from this data structure, you will only need to add another line inside and both printing and accounting will be generated automatically.
I left out the proper printing alignement as an exercise for the reader, resource: https://stackoverflow.com/questions/5676646/how-can-i-fill-out-a-python-string-with-spaces
Code with didactic comments: (real code would not be commented so much)
# It would be better to import this from string/ascii library
ALPHABET = "ABCDEFGHILMNOPQRSTUVZ"
FOOD_WITH_PRICES = [
("Apple", 0.5),
("Ham", 4),
("Bread", 1)
]
# for x in list: is standard syntax to iterate over a list, x becomes progressively equal to each element
# enumerate adds the index to each element
def print_stilish_menu(food_with_prices):
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+""")
for (index, (food, price)) in enumerate(food_with_prices):
print("""
| lettertThe "food" | $ price |
+---------------------------------+---------+
""".format(letter=ALPHABET[index], food=food, price=price))
# list[:n] means the first n elements of a list
# for more info look for `python list slice`
print_stilish_menu(FOOD_WITH_PRICES)
total = 0
while(True):
print("Total:", total);
x = input("Select a letter or 'done': ")
if x in ALPHABET[:len(FOOD_WITH_PRICES)]:
total += FOOD_WITH_PRICES[ALPHABET.index(x)][1]
elif x == 'done':
break
# Some kind of message if the input is invalid
# is good practice
else:
print("Invalid Input")
print("You spent ".format(total))
answered 54 mins ago
Caridorc
22.8k433113
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
Huge bug in 3.5.2
Entering done does nothing in Python 3.5.2, use == instead of is to fix this. In general is asks if two objects are the same object not if the contents are the same, this can give results different from what you expect for lists, so I suggest using == overall.
https://dbader.org/blog/difference-between-is-and-equals-in-python
Code repetition / Extensibility
A famous problem is code extensibility, it is quite inconvenient to add another item to the menu, also if you take a look at this list of ifs
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
you will notice that the only thing that happens is adding the cost to the total each time so there is a lot of repetition.
So let me explain a better solution.
I will use a list of tuples (pairs) of the form (food, price).
Than both the printing and the accounting of the money can be done from this data structure, you will only need to add another line inside and both printing and accounting will be generated automatically.
I left out the proper printing alignement as an exercise for the reader, resource: https://stackoverflow.com/questions/5676646/how-can-i-fill-out-a-python-string-with-spaces
Code with didactic comments: (real code would not be commented so much)
# It would be better to import this from string/ascii library
ALPHABET = "ABCDEFGHILMNOPQRSTUVZ"
FOOD_WITH_PRICES = [
("Apple", 0.5),
("Ham", 4),
("Bread", 1)
]
# for x in list: is standard syntax to iterate over a list, x becomes progressively equal to each element
# enumerate adds the index to each element
def print_stilish_menu(food_with_prices):
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+""")
for (index, (food, price)) in enumerate(food_with_prices):
print("""
| lettertThe "food" | $ price |
+---------------------------------+---------+
""".format(letter=ALPHABET[index], food=food, price=price))
# list[:n] means the first n elements of a list
# for more info look for `python list slice`
print_stilish_menu(FOOD_WITH_PRICES)
total = 0
while(True):
print("Total:", total);
x = input("Select a letter or 'done': ")
if x in ALPHABET[:len(FOOD_WITH_PRICES)]:
total += FOOD_WITH_PRICES[ALPHABET.index(x)][1]
elif x == 'done':
break
# Some kind of message if the input is invalid
# is good practice
else:
print("Invalid Input")
print("You spent ".format(total))
answered 54 mins ago
Caridorc
22.8k433113
add a comment |Â
up vote
2
down vote
Huge bug in 3.5.2
Entering done does nothing in Python 3.5.2, use == instead of is to fix this. In general is asks if two objects are the same object not if the contents are the same, this can give results different from what you expect for lists, so I suggest using == overall.
https://dbader.org/blog/difference-between-is-and-equals-in-python
Code repetition / Extensibility
A famous problem is code extensibility, it is quite inconvenient to add another item to the menu, also if you take a look at this list of ifs
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
you will notice that the only thing that happens is adding the cost to the total each time so there is a lot of repetition.
So let me explain a better solution.
I will use a list of tuples (pairs) of the form (food, price).
Than both the printing and the accounting of the money can be done from this data structure, you will only need to add another line inside and both printing and accounting will be generated automatically.
I left out the proper printing alignement as an exercise for the reader, resource: https://stackoverflow.com/questions/5676646/how-can-i-fill-out-a-python-string-with-spaces
Code with didactic comments: (real code would not be commented so much)
# It would be better to import this from string/ascii library
ALPHABET = "ABCDEFGHILMNOPQRSTUVZ"
FOOD_WITH_PRICES = [
("Apple", 0.5),
("Ham", 4),
("Bread", 1)
]
# for x in list: is standard syntax to iterate over a list, x becomes progressively equal to each element
# enumerate adds the index to each element
def print_stilish_menu(food_with_prices):
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+""")
for (index, (food, price)) in enumerate(food_with_prices):
print("""
| lettertThe "food" | $ price |
+---------------------------------+---------+
""".format(letter=ALPHABET[index], food=food, price=price))
# list[:n] means the first n elements of a list
# for more info look for `python list slice`
print_stilish_menu(FOOD_WITH_PRICES)
total = 0
while(True):
print("Total:", total);
x = input("Select a letter or 'done': ")
if x in ALPHABET[:len(FOOD_WITH_PRICES)]:
total += FOOD_WITH_PRICES[ALPHABET.index(x)][1]
elif x == 'done':
break
# Some kind of message if the input is invalid
# is good practice
else:
print("Invalid Input")
print("You spent ".format(total))
answered 54 mins ago
Caridorc
22.8k433113
add a comment |Â
up vote
2
down vote
up vote
2
down vote
Huge bug in 3.5.2
Entering done does nothing in Python 3.5.2, use == instead of is to fix this. In general is asks if two objects are the same object not if the contents are the same, this can give results different from what you expect for lists, so I suggest using == overall.
https://dbader.org/blog/difference-between-is-and-equals-in-python
Code repetition / Extensibility
A famous problem is code extensibility, it is quite inconvenient to add another item to the menu, also if you take a look at this list of ifs
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
you will notice that the only thing that happens is adding the cost to the total each time so there is a lot of repetition.
So let me explain a better solution.
I will use a list of tuples (pairs) of the form (food, price).
Than both the printing and the accounting of the money can be done from this data structure, you will only need to add another line inside and both printing and accounting will be generated automatically.
I left out the proper printing alignement as an exercise for the reader, resource: https://stackoverflow.com/questions/5676646/how-can-i-fill-out-a-python-string-with-spaces
Code with didactic comments: (real code would not be commented so much)
# It would be better to import this from string/ascii library
ALPHABET = "ABCDEFGHILMNOPQRSTUVZ"
FOOD_WITH_PRICES = [
("Apple", 0.5),
("Ham", 4),
("Bread", 1)
]
# for x in list: is standard syntax to iterate over a list, x becomes progressively equal to each element
# enumerate adds the index to each element
def print_stilish_menu(food_with_prices):
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+""")
for (index, (food, price)) in enumerate(food_with_prices):
print("""
| lettertThe "food" | $ price |
+---------------------------------+---------+
""".format(letter=ALPHABET[index], food=food, price=price))
# list[:n] means the first n elements of a list
# for more info look for `python list slice`
print_stilish_menu(FOOD_WITH_PRICES)
total = 0
while(True):
print("Total:", total);
x = input("Select a letter or 'done': ")
if x in ALPHABET[:len(FOOD_WITH_PRICES)]:
total += FOOD_WITH_PRICES[ALPHABET.index(x)][1]
elif x == 'done':
break
# Some kind of message if the input is invalid
# is good practice
else:
print("Invalid Input")
print("You spent ".format(total))
answered 54 mins ago
Caridorc
22.8k433113
Huge bug in 3.5.2
Entering done does nothing in Python 3.5.2, use == instead of is to fix this. In general is asks if two objects are the same object not if the contents are the same, this can give results different from what you expect for lists, so I suggest using == overall.
https://dbader.org/blog/difference-between-is-and-equals-in-python
Code repetition / Extensibility
A famous problem is code extensibility, it is quite inconvenient to add another item to the menu, also if you take a look at this list of ifs
if Item is "A":
total += the_burger;
elif Item is "B":
total += french_fries;
elif Item is "C":
total += currie_sauce;
elif Item is "D":
total += napkins_with_chocolates;
elif Item is "E":
total += juice_box;
elif Item is "F":
you will notice that the only thing that happens is adding the cost to the total each time so there is a lot of repetition.
So let me explain a better solution.
I will use a list of tuples (pairs) of the form (food, price).
Than both the printing and the accounting of the money can be done from this data structure, you will only need to add another line inside and both printing and accounting will be generated automatically.
I left out the proper printing alignement as an exercise for the reader, resource: https://stackoverflow.com/questions/5676646/how-can-i-fill-out-a-python-string-with-spaces
Code with didactic comments: (real code would not be commented so much)
# It would be better to import this from string/ascii library
ALPHABET = "ABCDEFGHILMNOPQRSTUVZ"
FOOD_WITH_PRICES = [
("Apple", 0.5),
("Ham", 4),
("Bread", 1)
]
# for x in list: is standard syntax to iterate over a list, x becomes progressively equal to each element
# enumerate adds the index to each element
def print_stilish_menu(food_with_prices):
print("""
+-------------------------------------------+
| The Restaurant at the End of the Universe |
+---------------------------------+---------+""")
for (index, (food, price)) in enumerate(food_with_prices):
print("""
| lettertThe "food" | $ price |
+---------------------------------+---------+
""".format(letter=ALPHABET[index], food=food, price=price))
# list[:n] means the first n elements of a list
# for more info look for `python list slice`
print_stilish_menu(FOOD_WITH_PRICES)
total = 0
while(True):
print("Total:", total);
x = input("Select a letter or 'done': ")
if x in ALPHABET[:len(FOOD_WITH_PRICES)]:
total += FOOD_WITH_PRICES[ALPHABET.index(x)][1]
elif x == 'done':
break
# Some kind of message if the input is invalid
# is good practice
else:
print("Invalid Input")
print("You spent ".format(total))
answered 54 mins ago
Caridorc
22.8k433113
edited 49 mins ago
answered 54 mins ago
Caridorc
22.8k433113
answered 54 mins ago
Caridorc
22.8k433113
answered 54 mins ago
Caridorc
22.8k433113
22.8k433113
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4
It will let you use Unicode - and probably much more of Unicode than you're already using...
– Toby Speight
4 hours ago
3
Did you ask nicely? (What I mean is, how did you try? And how did it refuse? I know this isn't Stack Overflow, so the non-working code wouldn't be on-topic, but I'd be interested to know).
– Toby Speight
4 hours ago
2
Unicode is supposed to be available out-of-the-box. Example here.
– Mathias Ettinger
3 hours ago
2
Time to use a better IDE then: ideone.com/uK6XJ6
– Mathias Ettinger
2 hours ago
2
I'm not quite sure what the downvote is for... I've followed all of the rules for CR that I can tell.
– FreezePhoenix
1 hour ago