100 using only 5 number of digits
Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
favorite
I have a problem from Martin Gardner I canâÂÂt solve. Please help!
For each digit $1leq dleq 9$, make 100 using exactly five number of $i$s. Any operation is allowed, brackets as well.
For $i=1,2$ I have a solution:
$$100=111-11$$
$$100=(2*2*2+2)^2$$
For the rest please help.
number-theory
New contributor
add a comment |Â
up vote
1
down vote
favorite
I have a problem from Martin Gardner I canâÂÂt solve. Please help!
For each digit $1leq dleq 9$, make 100 using exactly five number of $i$s. Any operation is allowed, brackets as well.
For $i=1,2$ I have a solution:
$$100=111-11$$
$$100=(2*2*2+2)^2$$
For the rest please help.
number-theory
New contributor
In case anyone missed it, the same problem with exactly 6 /i/s is trivial: (iii - ii) / i works for any i in any base > i.
â Rupert Morrish
32 mins ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have a problem from Martin Gardner I canâÂÂt solve. Please help!
For each digit $1leq dleq 9$, make 100 using exactly five number of $i$s. Any operation is allowed, brackets as well.
For $i=1,2$ I have a solution:
$$100=111-11$$
$$100=(2*2*2+2)^2$$
For the rest please help.
number-theory
New contributor
I have a problem from Martin Gardner I canâÂÂt solve. Please help!
For each digit $1leq dleq 9$, make 100 using exactly five number of $i$s. Any operation is allowed, brackets as well.
For $i=1,2$ I have a solution:
$$100=111-11$$
$$100=(2*2*2+2)^2$$
For the rest please help.
number-theory
number-theory
New contributor
New contributor
edited 1 hour ago
jafe
7,5861885
7,5861885
New contributor
asked 1 hour ago
Pet123
61
61
New contributor
New contributor
In case anyone missed it, the same problem with exactly 6 /i/s is trivial: (iii - ii) / i works for any i in any base > i.
â Rupert Morrish
32 mins ago
add a comment |Â
In case anyone missed it, the same problem with exactly 6 /i/s is trivial: (iii - ii) / i works for any i in any base > i.
â Rupert Morrish
32 mins ago
In case anyone missed it, the same problem with exactly 6 /i/s is trivial: (iii - ii) / i works for any i in any base > i.
â Rupert Morrish
32 mins ago
In case anyone missed it, the same problem with exactly 6 /i/s is trivial: (iii - ii) / i works for any i in any base > i.
â Rupert Morrish
32 mins ago
add a comment |Â
4 Answers
4
active
oldest
votes
up vote
2
down vote
For 9:
$100 = 99 + (frac99)^9$
For 8:
$100 = 88 + 8 + sqrt8+8$
add a comment |Â
up vote
1
down vote
Four
$100 = (frac44 - 44) ^sqrt4$
add a comment |Â
up vote
1
down vote
Partial (will update as I figure more out)
For 3:
33*3+(3/3)
For 5:
(5*5*5)-(5*5)
For 7: (possibly cheating?)
ceiling(sqrt(7!)) + ceiling(sqrt(7!)) - (7*7) + 7. you did say any function was allowed.
1
5 could also be (5+5+5+5)*5
â PotatoLatte
1 hour ago
Definitely cheating to use ceiling and floor, I would think.
â Rupert Morrish
34 mins ago
add a comment |Â
up vote
0
down vote
Seven (almost)
$100 = (7 + 7) * (7 + frac7^07)$
add a comment |Â
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
For 9:
$100 = 99 + (frac99)^9$
For 8:
$100 = 88 + 8 + sqrt8+8$
add a comment |Â
up vote
2
down vote
For 9:
$100 = 99 + (frac99)^9$
For 8:
$100 = 88 + 8 + sqrt8+8$
add a comment |Â
up vote
2
down vote
up vote
2
down vote
For 9:
$100 = 99 + (frac99)^9$
For 8:
$100 = 88 + 8 + sqrt8+8$
For 9:
$100 = 99 + (frac99)^9$
For 8:
$100 = 88 + 8 + sqrt8+8$
answered 1 hour ago
jafe
7,5861885
7,5861885
add a comment |Â
add a comment |Â
up vote
1
down vote
Four
$100 = (frac44 - 44) ^sqrt4$
add a comment |Â
up vote
1
down vote
Four
$100 = (frac44 - 44) ^sqrt4$
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Four
$100 = (frac44 - 44) ^sqrt4$
Four
$100 = (frac44 - 44) ^sqrt4$
answered 58 mins ago
Rupert Morrish
2,5471725
2,5471725
add a comment |Â
add a comment |Â
up vote
1
down vote
Partial (will update as I figure more out)
For 3:
33*3+(3/3)
For 5:
(5*5*5)-(5*5)
For 7: (possibly cheating?)
ceiling(sqrt(7!)) + ceiling(sqrt(7!)) - (7*7) + 7. you did say any function was allowed.
1
5 could also be (5+5+5+5)*5
â PotatoLatte
1 hour ago
Definitely cheating to use ceiling and floor, I would think.
â Rupert Morrish
34 mins ago
add a comment |Â
up vote
1
down vote
Partial (will update as I figure more out)
For 3:
33*3+(3/3)
For 5:
(5*5*5)-(5*5)
For 7: (possibly cheating?)
ceiling(sqrt(7!)) + ceiling(sqrt(7!)) - (7*7) + 7. you did say any function was allowed.
1
5 could also be (5+5+5+5)*5
â PotatoLatte
1 hour ago
Definitely cheating to use ceiling and floor, I would think.
â Rupert Morrish
34 mins ago
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Partial (will update as I figure more out)
For 3:
33*3+(3/3)
For 5:
(5*5*5)-(5*5)
For 7: (possibly cheating?)
ceiling(sqrt(7!)) + ceiling(sqrt(7!)) - (7*7) + 7. you did say any function was allowed.
Partial (will update as I figure more out)
For 3:
33*3+(3/3)
For 5:
(5*5*5)-(5*5)
For 7: (possibly cheating?)
ceiling(sqrt(7!)) + ceiling(sqrt(7!)) - (7*7) + 7. you did say any function was allowed.
edited 35 mins ago
answered 1 hour ago
Excited Raichu
86315
86315
1
5 could also be (5+5+5+5)*5
â PotatoLatte
1 hour ago
Definitely cheating to use ceiling and floor, I would think.
â Rupert Morrish
34 mins ago
add a comment |Â
1
5 could also be (5+5+5+5)*5
â PotatoLatte
1 hour ago
Definitely cheating to use ceiling and floor, I would think.
â Rupert Morrish
34 mins ago
1
1
5 could also be (5+5+5+5)*5
â PotatoLatte
1 hour ago
5 could also be (5+5+5+5)*5
â PotatoLatte
1 hour ago
Definitely cheating to use ceiling and floor, I would think.
â Rupert Morrish
34 mins ago
Definitely cheating to use ceiling and floor, I would think.
â Rupert Morrish
34 mins ago
add a comment |Â
up vote
0
down vote
Seven (almost)
$100 = (7 + 7) * (7 + frac7^07)$
add a comment |Â
up vote
0
down vote
Seven (almost)
$100 = (7 + 7) * (7 + frac7^07)$
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Seven (almost)
$100 = (7 + 7) * (7 + frac7^07)$
Seven (almost)
$100 = (7 + 7) * (7 + frac7^07)$
edited 17 mins ago
answered 25 mins ago
Rupert Morrish
2,5471725
2,5471725
add a comment |Â
add a comment |Â
Pet123 is a new contributor. Be nice, and check out our Code of Conduct.
Pet123 is a new contributor. Be nice, and check out our Code of Conduct.
Pet123 is a new contributor. Be nice, and check out our Code of Conduct.
Pet123 is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f73628%2f100-using-only-5-number-of-digits%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
In case anyone missed it, the same problem with exactly 6 /i/s is trivial: (iii - ii) / i works for any i in any base > i.
â Rupert Morrish
32 mins ago