Discriminant locus of elliptic K3 surfaces

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
3
down vote

favorite












Given a complex elliptic K3 surface $picolon Xrightarrow mathbb P^1$, its discriminant locus is the divisor $$D = sum_i = 1^s n_i P_i$$ on $mathbb P^1$ such that $n_i$ is equal to the Euler-Poincaré characteristic of the fiber $pi^-1(P_i)$, where the sum runs over the points $P_i in mathbb P^1$ such that $pi^-1(P_i)$ is singular. It is well known that $deg D = 24$.




Conversely, given an effective divisor $D$ of degree $24$ on $mathbb P^1$, when is it the discriminant locus of a complex elliptic K3 surface?




I am particularly curious about the minimal possible $s$. The maximal Euler-Poincaré characteristic of a singular fiber is $20$, so $s geq 2$. But in case, say, $n_1 = 20$, then the fibration is of type $I_14^*,I_1,I_1,I_1,I_1$ (see Schütt-Schweizer), so indeed $s = 5$. Are smaller $s$ possible?










share|cite|improve this question

















  • 3




    Since the moduli space of polarized K3 surfaces is hyperbolic, the inequality $sgeq 3$ holds. An example of an elliptic fibration with $s=3$ is provided by the Legendre elliptic curve $y^2= x(x-1)(x-lambda)$ over $mathbbC-0,1$. The total space of this fibration is not K3 though.
    – Ariyan Javanpeykar
    2 hours ago










  • Sorry, I actually miswrote something in my comment. I meant to say that the moduli "space" of elliptic curves is hyperbolic. (Although the moduli space of polarized K3 surfaces is hyperbolic as well, it is the moduli space of elliptic curves which plays a role here.) Indeed, if $D$ is the support of the discriminant divisor of the elliptic surface $f:Xto mathbbP^1$, then there is a non-constant morphism $mathbbP^1 setminus D to mathcalM$ induced by the Jacobian of $Xsetminus f^-1Dto mathbbP^1setminus D$, where $mathcalM$ is the moduli of elliptic curves.
    – Ariyan Javanpeykar
    30 mins ago















up vote
3
down vote

favorite












Given a complex elliptic K3 surface $picolon Xrightarrow mathbb P^1$, its discriminant locus is the divisor $$D = sum_i = 1^s n_i P_i$$ on $mathbb P^1$ such that $n_i$ is equal to the Euler-Poincaré characteristic of the fiber $pi^-1(P_i)$, where the sum runs over the points $P_i in mathbb P^1$ such that $pi^-1(P_i)$ is singular. It is well known that $deg D = 24$.




Conversely, given an effective divisor $D$ of degree $24$ on $mathbb P^1$, when is it the discriminant locus of a complex elliptic K3 surface?




I am particularly curious about the minimal possible $s$. The maximal Euler-Poincaré characteristic of a singular fiber is $20$, so $s geq 2$. But in case, say, $n_1 = 20$, then the fibration is of type $I_14^*,I_1,I_1,I_1,I_1$ (see Schütt-Schweizer), so indeed $s = 5$. Are smaller $s$ possible?










share|cite|improve this question

















  • 3




    Since the moduli space of polarized K3 surfaces is hyperbolic, the inequality $sgeq 3$ holds. An example of an elliptic fibration with $s=3$ is provided by the Legendre elliptic curve $y^2= x(x-1)(x-lambda)$ over $mathbbC-0,1$. The total space of this fibration is not K3 though.
    – Ariyan Javanpeykar
    2 hours ago










  • Sorry, I actually miswrote something in my comment. I meant to say that the moduli "space" of elliptic curves is hyperbolic. (Although the moduli space of polarized K3 surfaces is hyperbolic as well, it is the moduli space of elliptic curves which plays a role here.) Indeed, if $D$ is the support of the discriminant divisor of the elliptic surface $f:Xto mathbbP^1$, then there is a non-constant morphism $mathbbP^1 setminus D to mathcalM$ induced by the Jacobian of $Xsetminus f^-1Dto mathbbP^1setminus D$, where $mathcalM$ is the moduli of elliptic curves.
    – Ariyan Javanpeykar
    30 mins ago













up vote
3
down vote

favorite









up vote
3
down vote

favorite











Given a complex elliptic K3 surface $picolon Xrightarrow mathbb P^1$, its discriminant locus is the divisor $$D = sum_i = 1^s n_i P_i$$ on $mathbb P^1$ such that $n_i$ is equal to the Euler-Poincaré characteristic of the fiber $pi^-1(P_i)$, where the sum runs over the points $P_i in mathbb P^1$ such that $pi^-1(P_i)$ is singular. It is well known that $deg D = 24$.




Conversely, given an effective divisor $D$ of degree $24$ on $mathbb P^1$, when is it the discriminant locus of a complex elliptic K3 surface?




I am particularly curious about the minimal possible $s$. The maximal Euler-Poincaré characteristic of a singular fiber is $20$, so $s geq 2$. But in case, say, $n_1 = 20$, then the fibration is of type $I_14^*,I_1,I_1,I_1,I_1$ (see Schütt-Schweizer), so indeed $s = 5$. Are smaller $s$ possible?










share|cite|improve this question













Given a complex elliptic K3 surface $picolon Xrightarrow mathbb P^1$, its discriminant locus is the divisor $$D = sum_i = 1^s n_i P_i$$ on $mathbb P^1$ such that $n_i$ is equal to the Euler-Poincaré characteristic of the fiber $pi^-1(P_i)$, where the sum runs over the points $P_i in mathbb P^1$ such that $pi^-1(P_i)$ is singular. It is well known that $deg D = 24$.




Conversely, given an effective divisor $D$ of degree $24$ on $mathbb P^1$, when is it the discriminant locus of a complex elliptic K3 surface?




I am particularly curious about the minimal possible $s$. The maximal Euler-Poincaré characteristic of a singular fiber is $20$, so $s geq 2$. But in case, say, $n_1 = 20$, then the fibration is of type $I_14^*,I_1,I_1,I_1,I_1$ (see Schütt-Schweizer), so indeed $s = 5$. Are smaller $s$ possible?







k3-surfaces elliptic-surfaces






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 2 hours ago









DCV

321112




321112







  • 3




    Since the moduli space of polarized K3 surfaces is hyperbolic, the inequality $sgeq 3$ holds. An example of an elliptic fibration with $s=3$ is provided by the Legendre elliptic curve $y^2= x(x-1)(x-lambda)$ over $mathbbC-0,1$. The total space of this fibration is not K3 though.
    – Ariyan Javanpeykar
    2 hours ago










  • Sorry, I actually miswrote something in my comment. I meant to say that the moduli "space" of elliptic curves is hyperbolic. (Although the moduli space of polarized K3 surfaces is hyperbolic as well, it is the moduli space of elliptic curves which plays a role here.) Indeed, if $D$ is the support of the discriminant divisor of the elliptic surface $f:Xto mathbbP^1$, then there is a non-constant morphism $mathbbP^1 setminus D to mathcalM$ induced by the Jacobian of $Xsetminus f^-1Dto mathbbP^1setminus D$, where $mathcalM$ is the moduli of elliptic curves.
    – Ariyan Javanpeykar
    30 mins ago













  • 3




    Since the moduli space of polarized K3 surfaces is hyperbolic, the inequality $sgeq 3$ holds. An example of an elliptic fibration with $s=3$ is provided by the Legendre elliptic curve $y^2= x(x-1)(x-lambda)$ over $mathbbC-0,1$. The total space of this fibration is not K3 though.
    – Ariyan Javanpeykar
    2 hours ago










  • Sorry, I actually miswrote something in my comment. I meant to say that the moduli "space" of elliptic curves is hyperbolic. (Although the moduli space of polarized K3 surfaces is hyperbolic as well, it is the moduli space of elliptic curves which plays a role here.) Indeed, if $D$ is the support of the discriminant divisor of the elliptic surface $f:Xto mathbbP^1$, then there is a non-constant morphism $mathbbP^1 setminus D to mathcalM$ induced by the Jacobian of $Xsetminus f^-1Dto mathbbP^1setminus D$, where $mathcalM$ is the moduli of elliptic curves.
    – Ariyan Javanpeykar
    30 mins ago








3




3




Since the moduli space of polarized K3 surfaces is hyperbolic, the inequality $sgeq 3$ holds. An example of an elliptic fibration with $s=3$ is provided by the Legendre elliptic curve $y^2= x(x-1)(x-lambda)$ over $mathbbC-0,1$. The total space of this fibration is not K3 though.
– Ariyan Javanpeykar
2 hours ago




Since the moduli space of polarized K3 surfaces is hyperbolic, the inequality $sgeq 3$ holds. An example of an elliptic fibration with $s=3$ is provided by the Legendre elliptic curve $y^2= x(x-1)(x-lambda)$ over $mathbbC-0,1$. The total space of this fibration is not K3 though.
– Ariyan Javanpeykar
2 hours ago












Sorry, I actually miswrote something in my comment. I meant to say that the moduli "space" of elliptic curves is hyperbolic. (Although the moduli space of polarized K3 surfaces is hyperbolic as well, it is the moduli space of elliptic curves which plays a role here.) Indeed, if $D$ is the support of the discriminant divisor of the elliptic surface $f:Xto mathbbP^1$, then there is a non-constant morphism $mathbbP^1 setminus D to mathcalM$ induced by the Jacobian of $Xsetminus f^-1Dto mathbbP^1setminus D$, where $mathcalM$ is the moduli of elliptic curves.
– Ariyan Javanpeykar
30 mins ago





Sorry, I actually miswrote something in my comment. I meant to say that the moduli "space" of elliptic curves is hyperbolic. (Although the moduli space of polarized K3 surfaces is hyperbolic as well, it is the moduli space of elliptic curves which plays a role here.) Indeed, if $D$ is the support of the discriminant divisor of the elliptic surface $f:Xto mathbbP^1$, then there is a non-constant morphism $mathbbP^1 setminus D to mathcalM$ induced by the Jacobian of $Xsetminus f^-1Dto mathbbP^1setminus D$, where $mathcalM$ is the moduli of elliptic curves.
– Ariyan Javanpeykar
30 mins ago











1 Answer
1






active

oldest

votes

















up vote
4
down vote













The minimal $s$ is $3$.



It is attained by several elliptic K3's,
including $y^2 = x^3 + (t^2-t)^4$ which has IV* fibers at
$t = 0, 1, infty$ and no other singular fibers.



The comment by Ariyan Javanpeykar gives one argument that $s$ can be
no smaller.
(This uses characteristic zero; in positive characteristic
$s$ can be as small as $1$, e.g. in characteristic 2
the elliptic K3 surface $y^2 + y = x^3 + t^9$ has only one
reducible fiber, at $t = infty$.)






share|cite|improve this answer




















    Your Answer




    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "504"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: true,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f312293%2fdiscriminant-locus-of-elliptic-k3-surfaces%23new-answer', 'question_page');

    );

    Post as a guest






























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    4
    down vote













    The minimal $s$ is $3$.



    It is attained by several elliptic K3's,
    including $y^2 = x^3 + (t^2-t)^4$ which has IV* fibers at
    $t = 0, 1, infty$ and no other singular fibers.



    The comment by Ariyan Javanpeykar gives one argument that $s$ can be
    no smaller.
    (This uses characteristic zero; in positive characteristic
    $s$ can be as small as $1$, e.g. in characteristic 2
    the elliptic K3 surface $y^2 + y = x^3 + t^9$ has only one
    reducible fiber, at $t = infty$.)






    share|cite|improve this answer
























      up vote
      4
      down vote













      The minimal $s$ is $3$.



      It is attained by several elliptic K3's,
      including $y^2 = x^3 + (t^2-t)^4$ which has IV* fibers at
      $t = 0, 1, infty$ and no other singular fibers.



      The comment by Ariyan Javanpeykar gives one argument that $s$ can be
      no smaller.
      (This uses characteristic zero; in positive characteristic
      $s$ can be as small as $1$, e.g. in characteristic 2
      the elliptic K3 surface $y^2 + y = x^3 + t^9$ has only one
      reducible fiber, at $t = infty$.)






      share|cite|improve this answer






















        up vote
        4
        down vote










        up vote
        4
        down vote









        The minimal $s$ is $3$.



        It is attained by several elliptic K3's,
        including $y^2 = x^3 + (t^2-t)^4$ which has IV* fibers at
        $t = 0, 1, infty$ and no other singular fibers.



        The comment by Ariyan Javanpeykar gives one argument that $s$ can be
        no smaller.
        (This uses characteristic zero; in positive characteristic
        $s$ can be as small as $1$, e.g. in characteristic 2
        the elliptic K3 surface $y^2 + y = x^3 + t^9$ has only one
        reducible fiber, at $t = infty$.)






        share|cite|improve this answer












        The minimal $s$ is $3$.



        It is attained by several elliptic K3's,
        including $y^2 = x^3 + (t^2-t)^4$ which has IV* fibers at
        $t = 0, 1, infty$ and no other singular fibers.



        The comment by Ariyan Javanpeykar gives one argument that $s$ can be
        no smaller.
        (This uses characteristic zero; in positive characteristic
        $s$ can be as small as $1$, e.g. in characteristic 2
        the elliptic K3 surface $y^2 + y = x^3 + t^9$ has only one
        reducible fiber, at $t = infty$.)







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 52 mins ago









        Noam D. Elkies

        54.8k9194279




        54.8k9194279



























             

            draft saved


            draft discarded















































             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f312293%2fdiscriminant-locus-of-elliptic-k3-surfaces%23new-answer', 'question_page');

            );

            Post as a guest













































































            Comments

            Popular posts from this blog

            What does second last employer means? [closed]

            List of Gilmore Girls characters

            Confectionery