caps in series, equivalent capacitance to reduce voltage rating

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For example, I need 100uF 60V capacitor for filtering in power supply. DC source is about 40V.



But I have 400uF 20V caps.



If I arrange four of them in series I got in total 100 uF and each cap has voltage drop 10 volts according DC source.



Thus, can I replace 100uF 60V capacitor with four 400uF 20V caps in series? 20V caps are OK?



How to design symmetrizing resistors for it?










share|improve this question



















  • 2




    What's the highest DC leakage value for the 20 volt capacitors. If you don't know then read the data sheet. If you can't find a data sheet buy one capacitor rated for the correct voltage.
    – Andy aka
    3 hours ago










  • Yes, you are right if it is available why not to buy cap that I need. However, recently I read research paper about high voltage power supplies, to filter out rectified voltage they use capacitor bank with value 1.2 mF, voltage in circuit was 800V. So, how to design such kind capacitor bank is purpose of my question. Yes, there are some specific terms in this question, but I need at least some general vision how to design such a capacitor bank.
    – Max Rock
    3 hours ago











  • This isn't really a discussion site.
    – Andy aka
    2 hours ago










  • Recently I asked this question another way, I closed it as answered. But this issue emerges again electronics.stackexchange.com/questions/396887/…
    – Max Rock
    2 hours ago







  • 1




    OVP Protection and BMS battery balancing on high voltage strings of DC are similar issues often performed by Active voltage limiters for the mismatched voltage and expected current flow and mismatched tolerances after aging. In your case 4 MOV’s may work but depends on startup current surge. Wouldn’t you rather get the right parts?
    – Tony EE rocketscientist
    43 mins ago














up vote
2
down vote

favorite












For example, I need 100uF 60V capacitor for filtering in power supply. DC source is about 40V.



But I have 400uF 20V caps.



If I arrange four of them in series I got in total 100 uF and each cap has voltage drop 10 volts according DC source.



Thus, can I replace 100uF 60V capacitor with four 400uF 20V caps in series? 20V caps are OK?



How to design symmetrizing resistors for it?










share|improve this question



















  • 2




    What's the highest DC leakage value for the 20 volt capacitors. If you don't know then read the data sheet. If you can't find a data sheet buy one capacitor rated for the correct voltage.
    – Andy aka
    3 hours ago










  • Yes, you are right if it is available why not to buy cap that I need. However, recently I read research paper about high voltage power supplies, to filter out rectified voltage they use capacitor bank with value 1.2 mF, voltage in circuit was 800V. So, how to design such kind capacitor bank is purpose of my question. Yes, there are some specific terms in this question, but I need at least some general vision how to design such a capacitor bank.
    – Max Rock
    3 hours ago











  • This isn't really a discussion site.
    – Andy aka
    2 hours ago










  • Recently I asked this question another way, I closed it as answered. But this issue emerges again electronics.stackexchange.com/questions/396887/…
    – Max Rock
    2 hours ago







  • 1




    OVP Protection and BMS battery balancing on high voltage strings of DC are similar issues often performed by Active voltage limiters for the mismatched voltage and expected current flow and mismatched tolerances after aging. In your case 4 MOV’s may work but depends on startup current surge. Wouldn’t you rather get the right parts?
    – Tony EE rocketscientist
    43 mins ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











For example, I need 100uF 60V capacitor for filtering in power supply. DC source is about 40V.



But I have 400uF 20V caps.



If I arrange four of them in series I got in total 100 uF and each cap has voltage drop 10 volts according DC source.



Thus, can I replace 100uF 60V capacitor with four 400uF 20V caps in series? 20V caps are OK?



How to design symmetrizing resistors for it?










share|improve this question















For example, I need 100uF 60V capacitor for filtering in power supply. DC source is about 40V.



But I have 400uF 20V caps.



If I arrange four of them in series I got in total 100 uF and each cap has voltage drop 10 volts according DC source.



Thus, can I replace 100uF 60V capacitor with four 400uF 20V caps in series? 20V caps are OK?



How to design symmetrizing resistors for it?







capacitor switch-mode-power-supply






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 4 hours ago

























asked 4 hours ago









Max Rock

256




256







  • 2




    What's the highest DC leakage value for the 20 volt capacitors. If you don't know then read the data sheet. If you can't find a data sheet buy one capacitor rated for the correct voltage.
    – Andy aka
    3 hours ago










  • Yes, you are right if it is available why not to buy cap that I need. However, recently I read research paper about high voltage power supplies, to filter out rectified voltage they use capacitor bank with value 1.2 mF, voltage in circuit was 800V. So, how to design such kind capacitor bank is purpose of my question. Yes, there are some specific terms in this question, but I need at least some general vision how to design such a capacitor bank.
    – Max Rock
    3 hours ago











  • This isn't really a discussion site.
    – Andy aka
    2 hours ago










  • Recently I asked this question another way, I closed it as answered. But this issue emerges again electronics.stackexchange.com/questions/396887/…
    – Max Rock
    2 hours ago







  • 1




    OVP Protection and BMS battery balancing on high voltage strings of DC are similar issues often performed by Active voltage limiters for the mismatched voltage and expected current flow and mismatched tolerances after aging. In your case 4 MOV’s may work but depends on startup current surge. Wouldn’t you rather get the right parts?
    – Tony EE rocketscientist
    43 mins ago












  • 2




    What's the highest DC leakage value for the 20 volt capacitors. If you don't know then read the data sheet. If you can't find a data sheet buy one capacitor rated for the correct voltage.
    – Andy aka
    3 hours ago










  • Yes, you are right if it is available why not to buy cap that I need. However, recently I read research paper about high voltage power supplies, to filter out rectified voltage they use capacitor bank with value 1.2 mF, voltage in circuit was 800V. So, how to design such kind capacitor bank is purpose of my question. Yes, there are some specific terms in this question, but I need at least some general vision how to design such a capacitor bank.
    – Max Rock
    3 hours ago











  • This isn't really a discussion site.
    – Andy aka
    2 hours ago










  • Recently I asked this question another way, I closed it as answered. But this issue emerges again electronics.stackexchange.com/questions/396887/…
    – Max Rock
    2 hours ago







  • 1




    OVP Protection and BMS battery balancing on high voltage strings of DC are similar issues often performed by Active voltage limiters for the mismatched voltage and expected current flow and mismatched tolerances after aging. In your case 4 MOV’s may work but depends on startup current surge. Wouldn’t you rather get the right parts?
    – Tony EE rocketscientist
    43 mins ago







2




2




What's the highest DC leakage value for the 20 volt capacitors. If you don't know then read the data sheet. If you can't find a data sheet buy one capacitor rated for the correct voltage.
– Andy aka
3 hours ago




What's the highest DC leakage value for the 20 volt capacitors. If you don't know then read the data sheet. If you can't find a data sheet buy one capacitor rated for the correct voltage.
– Andy aka
3 hours ago












Yes, you are right if it is available why not to buy cap that I need. However, recently I read research paper about high voltage power supplies, to filter out rectified voltage they use capacitor bank with value 1.2 mF, voltage in circuit was 800V. So, how to design such kind capacitor bank is purpose of my question. Yes, there are some specific terms in this question, but I need at least some general vision how to design such a capacitor bank.
– Max Rock
3 hours ago





Yes, you are right if it is available why not to buy cap that I need. However, recently I read research paper about high voltage power supplies, to filter out rectified voltage they use capacitor bank with value 1.2 mF, voltage in circuit was 800V. So, how to design such kind capacitor bank is purpose of my question. Yes, there are some specific terms in this question, but I need at least some general vision how to design such a capacitor bank.
– Max Rock
3 hours ago













This isn't really a discussion site.
– Andy aka
2 hours ago




This isn't really a discussion site.
– Andy aka
2 hours ago












Recently I asked this question another way, I closed it as answered. But this issue emerges again electronics.stackexchange.com/questions/396887/…
– Max Rock
2 hours ago





Recently I asked this question another way, I closed it as answered. But this issue emerges again electronics.stackexchange.com/questions/396887/…
– Max Rock
2 hours ago





1




1




OVP Protection and BMS battery balancing on high voltage strings of DC are similar issues often performed by Active voltage limiters for the mismatched voltage and expected current flow and mismatched tolerances after aging. In your case 4 MOV’s may work but depends on startup current surge. Wouldn’t you rather get the right parts?
– Tony EE rocketscientist
43 mins ago




OVP Protection and BMS battery balancing on high voltage strings of DC are similar issues often performed by Active voltage limiters for the mismatched voltage and expected current flow and mismatched tolerances after aging. In your case 4 MOV’s may work but depends on startup current surge. Wouldn’t you rather get the right parts?
– Tony EE rocketscientist
43 mins ago










3 Answers
3






active

oldest

votes

















up vote
3
down vote













You will have to include a parallel resistor-ladder to stabilize the node voltages. The resistor values must be high enough for the low-pass to be effective
$$f_c = frac12pi RC $$
and low enough to ensure a save operating point (smaller than the capacitors leakage).
This will cost you some additional power.






share|improve this answer




















  • Could you join discussion under question? Please, read my comment. Is this approach (arranging in series) applicable in higher values also?
    – Max Rock
    2 hours ago










  • @MaxRock yes sure you can do that with high voltages. I don't expect the reaistors to cause any trouble, however, you have to check the capacitors AC-behaviour for switched applications. Electrolytic caps (you said you'd use those?) are pretty bad for stabilising fast transients.
    – michi7x7
    1 hour ago











  • What kind caps are more applicable for this issue?
    – Max Rock
    1 hour ago










  • @MaxRock there are quite some options: ti.com/jp/lit/pdf/slyt639
    – michi7x7
    1 hour ago

















up vote
1
down vote













Well, you have 4 400uF/20V capacitor. to make a 100uF capacitance, you could make a series circuit from them and for symmetrizing you have to make one 1Mohm resistor parallel with each 400uF capacitor.
With this combination, you have made a circuit that is some how equivalent with a 100uF/80V capacitor that could tolerate 80V at most. For reliability issues, you can just use 80% of this therefore your circuit must not be under more than 0.8 * 80 == 64V.
Due to your need that is a 100uF/60V capacitor it seems OK but be careful that reducing the number of component will increase the reliability and production costs and this solution is just good when you have strong reasons. For example, the 100uF/60V capacitor is too big for the system case or big for tolerating g-shocks.
Moreover the capacitance and tolerated voltage of the capacitors have direct relation with ambient temperature and you have to support it in your design.



In the desktop PC switching power supplies, you can see two series 220uF~680uF/200V capacitors at its high voltage region (input == 220V AC). These capacitors are also symmetrized with two 1 Mega Ohm resistors and manufactured in very high volume with enough reliability.
Desktop SPSS has used this combination because for reducing the 100Hz ripple of the DC output, it needs biggest capacitor that is able to be fitted in the case and tolerate 400V. Regulated value of the 220V AC input line voltage is around 308V DC and caps must work under it properly therefore the combination of caps in the desktop SPSS must be able to tolerate 400V (80% of it is 320V that is near enough to 308V DC)






share|improve this answer








New contributor




Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
























    up vote
    -1
    down vote













    Yes, as you say 4x 400uF caps in series gives 100uF and if they are rated at 20V each then total rating will be 80V, which is above your spec so it should be fine.






    share|improve this answer
















    • 1




      Wrong because you haven't accounted for the different leakage resistances on each. Three might have ten times more leakage than the remaining one and this will mean two thirds of the voltage will appear across just one capacitor. Did you not read the bit in the question about symmetrizing resistors?
      – Andy aka
      3 hours ago











    • Nope that wasn't present in the question when I posted my answer. Do you know a method for calculating where exactly the voltage will be seen?
      – FeraTaTa
      3 hours ago










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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote













    You will have to include a parallel resistor-ladder to stabilize the node voltages. The resistor values must be high enough for the low-pass to be effective
    $$f_c = frac12pi RC $$
    and low enough to ensure a save operating point (smaller than the capacitors leakage).
    This will cost you some additional power.






    share|improve this answer




















    • Could you join discussion under question? Please, read my comment. Is this approach (arranging in series) applicable in higher values also?
      – Max Rock
      2 hours ago










    • @MaxRock yes sure you can do that with high voltages. I don't expect the reaistors to cause any trouble, however, you have to check the capacitors AC-behaviour for switched applications. Electrolytic caps (you said you'd use those?) are pretty bad for stabilising fast transients.
      – michi7x7
      1 hour ago











    • What kind caps are more applicable for this issue?
      – Max Rock
      1 hour ago










    • @MaxRock there are quite some options: ti.com/jp/lit/pdf/slyt639
      – michi7x7
      1 hour ago














    up vote
    3
    down vote













    You will have to include a parallel resistor-ladder to stabilize the node voltages. The resistor values must be high enough for the low-pass to be effective
    $$f_c = frac12pi RC $$
    and low enough to ensure a save operating point (smaller than the capacitors leakage).
    This will cost you some additional power.






    share|improve this answer




















    • Could you join discussion under question? Please, read my comment. Is this approach (arranging in series) applicable in higher values also?
      – Max Rock
      2 hours ago










    • @MaxRock yes sure you can do that with high voltages. I don't expect the reaistors to cause any trouble, however, you have to check the capacitors AC-behaviour for switched applications. Electrolytic caps (you said you'd use those?) are pretty bad for stabilising fast transients.
      – michi7x7
      1 hour ago











    • What kind caps are more applicable for this issue?
      – Max Rock
      1 hour ago










    • @MaxRock there are quite some options: ti.com/jp/lit/pdf/slyt639
      – michi7x7
      1 hour ago












    up vote
    3
    down vote










    up vote
    3
    down vote









    You will have to include a parallel resistor-ladder to stabilize the node voltages. The resistor values must be high enough for the low-pass to be effective
    $$f_c = frac12pi RC $$
    and low enough to ensure a save operating point (smaller than the capacitors leakage).
    This will cost you some additional power.






    share|improve this answer












    You will have to include a parallel resistor-ladder to stabilize the node voltages. The resistor values must be high enough for the low-pass to be effective
    $$f_c = frac12pi RC $$
    and low enough to ensure a save operating point (smaller than the capacitors leakage).
    This will cost you some additional power.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 3 hours ago









    michi7x7

    24716




    24716











    • Could you join discussion under question? Please, read my comment. Is this approach (arranging in series) applicable in higher values also?
      – Max Rock
      2 hours ago










    • @MaxRock yes sure you can do that with high voltages. I don't expect the reaistors to cause any trouble, however, you have to check the capacitors AC-behaviour for switched applications. Electrolytic caps (you said you'd use those?) are pretty bad for stabilising fast transients.
      – michi7x7
      1 hour ago











    • What kind caps are more applicable for this issue?
      – Max Rock
      1 hour ago










    • @MaxRock there are quite some options: ti.com/jp/lit/pdf/slyt639
      – michi7x7
      1 hour ago
















    • Could you join discussion under question? Please, read my comment. Is this approach (arranging in series) applicable in higher values also?
      – Max Rock
      2 hours ago










    • @MaxRock yes sure you can do that with high voltages. I don't expect the reaistors to cause any trouble, however, you have to check the capacitors AC-behaviour for switched applications. Electrolytic caps (you said you'd use those?) are pretty bad for stabilising fast transients.
      – michi7x7
      1 hour ago











    • What kind caps are more applicable for this issue?
      – Max Rock
      1 hour ago










    • @MaxRock there are quite some options: ti.com/jp/lit/pdf/slyt639
      – michi7x7
      1 hour ago















    Could you join discussion under question? Please, read my comment. Is this approach (arranging in series) applicable in higher values also?
    – Max Rock
    2 hours ago




    Could you join discussion under question? Please, read my comment. Is this approach (arranging in series) applicable in higher values also?
    – Max Rock
    2 hours ago












    @MaxRock yes sure you can do that with high voltages. I don't expect the reaistors to cause any trouble, however, you have to check the capacitors AC-behaviour for switched applications. Electrolytic caps (you said you'd use those?) are pretty bad for stabilising fast transients.
    – michi7x7
    1 hour ago





    @MaxRock yes sure you can do that with high voltages. I don't expect the reaistors to cause any trouble, however, you have to check the capacitors AC-behaviour for switched applications. Electrolytic caps (you said you'd use those?) are pretty bad for stabilising fast transients.
    – michi7x7
    1 hour ago













    What kind caps are more applicable for this issue?
    – Max Rock
    1 hour ago




    What kind caps are more applicable for this issue?
    – Max Rock
    1 hour ago












    @MaxRock there are quite some options: ti.com/jp/lit/pdf/slyt639
    – michi7x7
    1 hour ago




    @MaxRock there are quite some options: ti.com/jp/lit/pdf/slyt639
    – michi7x7
    1 hour ago












    up vote
    1
    down vote













    Well, you have 4 400uF/20V capacitor. to make a 100uF capacitance, you could make a series circuit from them and for symmetrizing you have to make one 1Mohm resistor parallel with each 400uF capacitor.
    With this combination, you have made a circuit that is some how equivalent with a 100uF/80V capacitor that could tolerate 80V at most. For reliability issues, you can just use 80% of this therefore your circuit must not be under more than 0.8 * 80 == 64V.
    Due to your need that is a 100uF/60V capacitor it seems OK but be careful that reducing the number of component will increase the reliability and production costs and this solution is just good when you have strong reasons. For example, the 100uF/60V capacitor is too big for the system case or big for tolerating g-shocks.
    Moreover the capacitance and tolerated voltage of the capacitors have direct relation with ambient temperature and you have to support it in your design.



    In the desktop PC switching power supplies, you can see two series 220uF~680uF/200V capacitors at its high voltage region (input == 220V AC). These capacitors are also symmetrized with two 1 Mega Ohm resistors and manufactured in very high volume with enough reliability.
    Desktop SPSS has used this combination because for reducing the 100Hz ripple of the DC output, it needs biggest capacitor that is able to be fitted in the case and tolerate 400V. Regulated value of the 220V AC input line voltage is around 308V DC and caps must work under it properly therefore the combination of caps in the desktop SPSS must be able to tolerate 400V (80% of it is 320V that is near enough to 308V DC)






    share|improve this answer








    New contributor




    Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      up vote
      1
      down vote













      Well, you have 4 400uF/20V capacitor. to make a 100uF capacitance, you could make a series circuit from them and for symmetrizing you have to make one 1Mohm resistor parallel with each 400uF capacitor.
      With this combination, you have made a circuit that is some how equivalent with a 100uF/80V capacitor that could tolerate 80V at most. For reliability issues, you can just use 80% of this therefore your circuit must not be under more than 0.8 * 80 == 64V.
      Due to your need that is a 100uF/60V capacitor it seems OK but be careful that reducing the number of component will increase the reliability and production costs and this solution is just good when you have strong reasons. For example, the 100uF/60V capacitor is too big for the system case or big for tolerating g-shocks.
      Moreover the capacitance and tolerated voltage of the capacitors have direct relation with ambient temperature and you have to support it in your design.



      In the desktop PC switching power supplies, you can see two series 220uF~680uF/200V capacitors at its high voltage region (input == 220V AC). These capacitors are also symmetrized with two 1 Mega Ohm resistors and manufactured in very high volume with enough reliability.
      Desktop SPSS has used this combination because for reducing the 100Hz ripple of the DC output, it needs biggest capacitor that is able to be fitted in the case and tolerate 400V. Regulated value of the 220V AC input line voltage is around 308V DC and caps must work under it properly therefore the combination of caps in the desktop SPSS must be able to tolerate 400V (80% of it is 320V that is near enough to 308V DC)






      share|improve this answer








      New contributor




      Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.



















        up vote
        1
        down vote










        up vote
        1
        down vote









        Well, you have 4 400uF/20V capacitor. to make a 100uF capacitance, you could make a series circuit from them and for symmetrizing you have to make one 1Mohm resistor parallel with each 400uF capacitor.
        With this combination, you have made a circuit that is some how equivalent with a 100uF/80V capacitor that could tolerate 80V at most. For reliability issues, you can just use 80% of this therefore your circuit must not be under more than 0.8 * 80 == 64V.
        Due to your need that is a 100uF/60V capacitor it seems OK but be careful that reducing the number of component will increase the reliability and production costs and this solution is just good when you have strong reasons. For example, the 100uF/60V capacitor is too big for the system case or big for tolerating g-shocks.
        Moreover the capacitance and tolerated voltage of the capacitors have direct relation with ambient temperature and you have to support it in your design.



        In the desktop PC switching power supplies, you can see two series 220uF~680uF/200V capacitors at its high voltage region (input == 220V AC). These capacitors are also symmetrized with two 1 Mega Ohm resistors and manufactured in very high volume with enough reliability.
        Desktop SPSS has used this combination because for reducing the 100Hz ripple of the DC output, it needs biggest capacitor that is able to be fitted in the case and tolerate 400V. Regulated value of the 220V AC input line voltage is around 308V DC and caps must work under it properly therefore the combination of caps in the desktop SPSS must be able to tolerate 400V (80% of it is 320V that is near enough to 308V DC)






        share|improve this answer








        New contributor




        Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        Well, you have 4 400uF/20V capacitor. to make a 100uF capacitance, you could make a series circuit from them and for symmetrizing you have to make one 1Mohm resistor parallel with each 400uF capacitor.
        With this combination, you have made a circuit that is some how equivalent with a 100uF/80V capacitor that could tolerate 80V at most. For reliability issues, you can just use 80% of this therefore your circuit must not be under more than 0.8 * 80 == 64V.
        Due to your need that is a 100uF/60V capacitor it seems OK but be careful that reducing the number of component will increase the reliability and production costs and this solution is just good when you have strong reasons. For example, the 100uF/60V capacitor is too big for the system case or big for tolerating g-shocks.
        Moreover the capacitance and tolerated voltage of the capacitors have direct relation with ambient temperature and you have to support it in your design.



        In the desktop PC switching power supplies, you can see two series 220uF~680uF/200V capacitors at its high voltage region (input == 220V AC). These capacitors are also symmetrized with two 1 Mega Ohm resistors and manufactured in very high volume with enough reliability.
        Desktop SPSS has used this combination because for reducing the 100Hz ripple of the DC output, it needs biggest capacitor that is able to be fitted in the case and tolerate 400V. Regulated value of the 220V AC input line voltage is around 308V DC and caps must work under it properly therefore the combination of caps in the desktop SPSS must be able to tolerate 400V (80% of it is 320V that is near enough to 308V DC)







        share|improve this answer








        New contributor




        Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|improve this answer



        share|improve this answer






        New contributor




        Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered 45 mins ago









        Behzad Daemi

        311




        311




        New contributor




        Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        Behzad Daemi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.




















            up vote
            -1
            down vote













            Yes, as you say 4x 400uF caps in series gives 100uF and if they are rated at 20V each then total rating will be 80V, which is above your spec so it should be fine.






            share|improve this answer
















            • 1




              Wrong because you haven't accounted for the different leakage resistances on each. Three might have ten times more leakage than the remaining one and this will mean two thirds of the voltage will appear across just one capacitor. Did you not read the bit in the question about symmetrizing resistors?
              – Andy aka
              3 hours ago











            • Nope that wasn't present in the question when I posted my answer. Do you know a method for calculating where exactly the voltage will be seen?
              – FeraTaTa
              3 hours ago














            up vote
            -1
            down vote













            Yes, as you say 4x 400uF caps in series gives 100uF and if they are rated at 20V each then total rating will be 80V, which is above your spec so it should be fine.






            share|improve this answer
















            • 1




              Wrong because you haven't accounted for the different leakage resistances on each. Three might have ten times more leakage than the remaining one and this will mean two thirds of the voltage will appear across just one capacitor. Did you not read the bit in the question about symmetrizing resistors?
              – Andy aka
              3 hours ago











            • Nope that wasn't present in the question when I posted my answer. Do you know a method for calculating where exactly the voltage will be seen?
              – FeraTaTa
              3 hours ago












            up vote
            -1
            down vote










            up vote
            -1
            down vote









            Yes, as you say 4x 400uF caps in series gives 100uF and if they are rated at 20V each then total rating will be 80V, which is above your spec so it should be fine.






            share|improve this answer












            Yes, as you say 4x 400uF caps in series gives 100uF and if they are rated at 20V each then total rating will be 80V, which is above your spec so it should be fine.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 4 hours ago









            FeraTaTa

            554




            554







            • 1




              Wrong because you haven't accounted for the different leakage resistances on each. Three might have ten times more leakage than the remaining one and this will mean two thirds of the voltage will appear across just one capacitor. Did you not read the bit in the question about symmetrizing resistors?
              – Andy aka
              3 hours ago











            • Nope that wasn't present in the question when I posted my answer. Do you know a method for calculating where exactly the voltage will be seen?
              – FeraTaTa
              3 hours ago












            • 1




              Wrong because you haven't accounted for the different leakage resistances on each. Three might have ten times more leakage than the remaining one and this will mean two thirds of the voltage will appear across just one capacitor. Did you not read the bit in the question about symmetrizing resistors?
              – Andy aka
              3 hours ago











            • Nope that wasn't present in the question when I posted my answer. Do you know a method for calculating where exactly the voltage will be seen?
              – FeraTaTa
              3 hours ago







            1




            1




            Wrong because you haven't accounted for the different leakage resistances on each. Three might have ten times more leakage than the remaining one and this will mean two thirds of the voltage will appear across just one capacitor. Did you not read the bit in the question about symmetrizing resistors?
            – Andy aka
            3 hours ago





            Wrong because you haven't accounted for the different leakage resistances on each. Three might have ten times more leakage than the remaining one and this will mean two thirds of the voltage will appear across just one capacitor. Did you not read the bit in the question about symmetrizing resistors?
            – Andy aka
            3 hours ago













            Nope that wasn't present in the question when I posted my answer. Do you know a method for calculating where exactly the voltage will be seen?
            – FeraTaTa
            3 hours ago




            Nope that wasn't present in the question when I posted my answer. Do you know a method for calculating where exactly the voltage will be seen?
            – FeraTaTa
            3 hours ago

















             

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