True color code

Clash Royale CLAN TAG#URR8PPP

up vote
2
down vote

favorite

True color (24-bit) at Wikipedia is described in pertinent part as

24 bits almost always uses 8 bits of each of R, G, B. As of 2018
24-bit color depth is used by virtually every computer and phone
display and the vast majority of image storage formats. Almost all
cases where there are 32 bits per pixel mean that 24 are used for the
color, and the remaining 8 are the alpha channel or unused.

2²⁴ gives 16,777,216 color variations. The human eye can discriminate up to ten million colors^[10] and since the gamut of a display is smaller than the range of human vision, this means this should cover that range with more detail than can be perceived. ...

...

Macintosh systems refer to 24-bit color as "millions of colors". The term "True color" is sometime used to mean what this article is calling "Direct color".^[13] It is also often used to refer to all color depths greater or equal to 24.

All 16,777,216 colors

Task

Write a program which generates and returns all 16,777,216 color variations within an array as strings in the CSS rgb() function or RGB hexadecimal notation #RRGGBB format.

Winning criteria

Least bytes used to write the program.

code-golf string kolmogorov-complexity color

share|improve this question

edited 3 hours ago

Sanchises

5,66512251

asked 5 hours ago

guest271314

1317

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Aren't both rgb and #RRGGBB limited to the 8-bits format in their default 1 byte per pixel output? 24-bit colors are saved with 3 bytes per pixel (one for each R, G, and B). Does this mean we'll have to output the same rgb code three times each, or how do we make the differences between the three? Do you perhaps have a text-file dump of all the 16,777,216 colors we should output?
  – Kevin Cruijssen
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen If Wikipedia is inaccurate, which is entirely possible, it must be possible to prove that by way of code. Do not have a text file dump of all the colors that should be output. File:16777216colors.png is 4096 x 4096 pixels, 4096*4096 // 16777216; if the description of the image is correct, it should technically be possible to request that image, then parse the image data of each pixel to check if there are duplicates.
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen As you said, 24-bit colors are made of 1 byte per RGB component, which is exactly what #RRGGBB describes. (Not to be confused with the shorthand form #RGB which only encodes 4096 distinct colors.) Or am I misunderstanding what you mean?
  – Arnauld
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Arnauld Ah wait. 16,777,216 is just 256³, so we basically output all #RRGGBB hexadecimals. Was indeed overthinking it..
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

favorite

True color (24-bit) at Wikipedia is described in pertinent part as

24 bits almost always uses 8 bits of each of R, G, B. As of 2018
24-bit color depth is used by virtually every computer and phone
display and the vast majority of image storage formats. Almost all
cases where there are 32 bits per pixel mean that 24 are used for the
color, and the remaining 8 are the alpha channel or unused.

2²⁴ gives 16,777,216 color variations. The human eye can discriminate up to ten million colors^[10] and since the gamut of a display is smaller than the range of human vision, this means this should cover that range with more detail than can be perceived. ...

...

Macintosh systems refer to 24-bit color as "millions of colors". The term "True color" is sometime used to mean what this article is calling "Direct color".^[13] It is also often used to refer to all color depths greater or equal to 24.

All 16,777,216 colors

Task

Write a program which generates and returns all 16,777,216 color variations within an array as strings in the CSS rgb() function or RGB hexadecimal notation #RRGGBB format.

Winning criteria

Least bytes used to write the program.

code-golf string kolmogorov-complexity color

share|improve this question

edited 3 hours ago

Sanchises

5,66512251

asked 5 hours ago

guest271314

1317

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Aren't both rgb and #RRGGBB limited to the 8-bits format in their default 1 byte per pixel output? 24-bit colors are saved with 3 bytes per pixel (one for each R, G, and B). Does this mean we'll have to output the same rgb code three times each, or how do we make the differences between the three? Do you perhaps have a text-file dump of all the 16,777,216 colors we should output?
  – Kevin Cruijssen
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen If Wikipedia is inaccurate, which is entirely possible, it must be possible to prove that by way of code. Do not have a text file dump of all the colors that should be output. File:16777216colors.png is 4096 x 4096 pixels, 4096*4096 // 16777216; if the description of the image is correct, it should technically be possible to request that image, then parse the image data of each pixel to check if there are duplicates.
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen As you said, 24-bit colors are made of 1 byte per RGB component, which is exactly what #RRGGBB describes. (Not to be confused with the shorthand form #RGB which only encodes 4096 distinct colors.) Or am I misunderstanding what you mean?
  – Arnauld
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Arnauld Ah wait. 16,777,216 is just 256³, so we basically output all #RRGGBB hexadecimals. Was indeed overthinking it..
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

favorite

up vote
2
down vote

favorite

True color (24-bit) at Wikipedia is described in pertinent part as

24 bits almost always uses 8 bits of each of R, G, B. As of 2018
24-bit color depth is used by virtually every computer and phone
display and the vast majority of image storage formats. Almost all
cases where there are 32 bits per pixel mean that 24 are used for the
color, and the remaining 8 are the alpha channel or unused.

2²⁴ gives 16,777,216 color variations. The human eye can discriminate up to ten million colors^[10] and since the gamut of a display is smaller than the range of human vision, this means this should cover that range with more detail than can be perceived. ...

...

Macintosh systems refer to 24-bit color as "millions of colors". The term "True color" is sometime used to mean what this article is calling "Direct color".^[13] It is also often used to refer to all color depths greater or equal to 24.

All 16,777,216 colors

Task

Write a program which generates and returns all 16,777,216 color variations within an array as strings in the CSS rgb() function or RGB hexadecimal notation #RRGGBB format.

Winning criteria

Least bytes used to write the program.

code-golf string kolmogorov-complexity color

share|improve this question

edited 3 hours ago

Sanchises

5,66512251

asked 5 hours ago

guest271314

1317

True color (24-bit) at Wikipedia is described in pertinent part as

24 bits almost always uses 8 bits of each of R, G, B. As of 2018
24-bit color depth is used by virtually every computer and phone
display and the vast majority of image storage formats. Almost all
cases where there are 32 bits per pixel mean that 24 are used for the
color, and the remaining 8 are the alpha channel or unused.

2²⁴ gives 16,777,216 color variations. The human eye can discriminate up to ten million colors^[10] and since the gamut of a display is smaller than the range of human vision, this means this should cover that range with more detail than can be perceived. ...

...

Macintosh systems refer to 24-bit color as "millions of colors". The term "True color" is sometime used to mean what this article is calling "Direct color".^[13] It is also often used to refer to all color depths greater or equal to 24.

All 16,777,216 colors

Task

Write a program which generates and returns all 16,777,216 color variations within an array as strings in the CSS rgb() function or RGB hexadecimal notation #RRGGBB format.

Winning criteria

Least bytes used to write the program.

code-golf string kolmogorov-complexity color

code-golf string kolmogorov-complexity color

share|improve this question

edited 3 hours ago

Sanchises

5,66512251

asked 5 hours ago

guest271314

1317

share|improve this question

edited 3 hours ago

Sanchises

5,66512251

asked 5 hours ago

guest271314

1317

share|improve this question

share|improve this question

edited 3 hours ago

Sanchises

5,66512251

edited 3 hours ago

Sanchises

5,66512251

edited 3 hours ago

Sanchises

5,66512251

5,66512251

asked 5 hours ago

guest271314

1317

asked 5 hours ago

guest271314

1317

asked 5 hours ago

guest271314

1317

1317

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Aren't both rgb and #RRGGBB limited to the 8-bits format in their default 1 byte per pixel output? 24-bit colors are saved with 3 bytes per pixel (one for each R, G, and B). Does this mean we'll have to output the same rgb code three times each, or how do we make the differences between the three? Do you perhaps have a text-file dump of all the 16,777,216 colors we should output?
  – Kevin Cruijssen
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen If Wikipedia is inaccurate, which is entirely possible, it must be possible to prove that by way of code. Do not have a text file dump of all the colors that should be output. File:16777216colors.png is 4096 x 4096 pixels, 4096*4096 // 16777216; if the description of the image is correct, it should technically be possible to request that image, then parse the image data of each pixel to check if there are duplicates.
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen As you said, 24-bit colors are made of 1 byte per RGB component, which is exactly what #RRGGBB describes. (Not to be confused with the shorthand form #RGB which only encodes 4096 distinct colors.) Or am I misunderstanding what you mean?
  – Arnauld
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Arnauld Ah wait. 16,777,216 is just 256³, so we basically output all #RRGGBB hexadecimals. Was indeed overthinking it..
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Aren't both rgb and #RRGGBB limited to the 8-bits format in their default 1 byte per pixel output? 24-bit colors are saved with 3 bytes per pixel (one for each R, G, and B). Does this mean we'll have to output the same rgb code three times each, or how do we make the differences between the three? Do you perhaps have a text-file dump of all the 16,777,216 colors we should output?
  – Kevin Cruijssen
  5 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen If Wikipedia is inaccurate, which is entirely possible, it must be possible to prove that by way of code. Do not have a text file dump of all the colors that should be output. File:16777216colors.png is 4096 x 4096 pixels, 4096*4096 // 16777216; if the description of the image is correct, it should technically be possible to request that image, then parse the image data of each pixel to check if there are duplicates.
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @KevinCruijssen As you said, 24-bit colors are made of 1 byte per RGB component, which is exactly what #RRGGBB describes. (Not to be confused with the shorthand form #RGB which only encodes 4096 distinct colors.) Or am I misunderstanding what you mean?
  – Arnauld
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Arnauld Ah wait. 16,777,216 is just 256³, so we basically output all #RRGGBB hexadecimals. Was indeed overthinking it..
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

Aren't both rgb and #RRGGBB limited to the 8-bits format in their default 1 byte per pixel output? 24-bit colors are saved with 3 bytes per pixel (one for each R, G, and B). Does this mean we'll have to output the same rgb code three times each, or how do we make the differences between the three? Do you perhaps have a text-file dump of all the 16,777,216 colors we should output?
– Kevin Cruijssen
5 hours ago

Aren't both rgb and #RRGGBB limited to the 8-bits format in their default 1 byte per pixel output? 24-bit colors are saved with 3 bytes per pixel (one for each R, G, and B). Does this mean we'll have to output the same rgb code three times each, or how do we make the differences between the three? Do you perhaps have a text-file dump of all the 16,777,216 colors we should output?
– Kevin Cruijssen
5 hours ago

@KevinCruijssen If Wikipedia is inaccurate, which is entirely possible, it must be possible to prove that by way of code. Do not have a text file dump of all the colors that should be output. File:16777216colors.png is 4096 x 4096 pixels, 4096*4096 // 16777216; if the description of the image is correct, it should technically be possible to request that image, then parse the image data of each pixel to check if there are duplicates.
– guest271314
4 hours ago

@KevinCruijssen If Wikipedia is inaccurate, which is entirely possible, it must be possible to prove that by way of code. Do not have a text file dump of all the colors that should be output. File:16777216colors.png is 4096 x 4096 pixels, 4096*4096 // 16777216; if the description of the image is correct, it should technically be possible to request that image, then parse the image data of each pixel to check if there are duplicates.
– guest271314
4 hours ago

@KevinCruijssen As you said, 24-bit colors are made of 1 byte per RGB component, which is exactly what #RRGGBB describes. (Not to be confused with the shorthand form #RGB which only encodes 4096 distinct colors.) Or am I misunderstanding what you mean?
– Arnauld
4 hours ago

@KevinCruijssen As you said, 24-bit colors are made of 1 byte per RGB component, which is exactly what #RRGGBB describes. (Not to be confused with the shorthand form #RGB which only encodes 4096 distinct colors.) Or am I misunderstanding what you mean?
– Arnauld
4 hours ago

@Arnauld Ah wait. 16,777,216 is just 256³, so we basically output all #RRGGBB hexadecimals. Was indeed overthinking it..
– Kevin Cruijssen
4 hours ago

@Arnauld Ah wait. 16,777,216 is just 256³, so we basically output all #RRGGBB hexadecimals. Was indeed overthinking it..
– Kevin Cruijssen
4 hours ago

add a comment | 

10 Answers
10

active

oldest

votes

up vote
4
down vote

Python 2, 77 40 bytes

lambda:['#%06X'%c for c in range(1<<24)]

Try it online!

share|improve this answer

edited 4 hours ago

answered 4 hours ago

TFeld

11.8k2833

• 
  
  
  

  
  

  
  
  
  
  
  

  
  How can we output the entire result of F[0:16777216] at TIO The output exceeded 128KiB?
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @guest271314 TIO's output size is limited. That's why TFeld added the F[:10] to see the first 10 items of the list, and F[-10:] to see the last ten items of the list. And he also proved it contained all 16,777,216 items by outputting the length of the result-list.
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

JavaScript (ES8), 65 bytes

Returns an array of #RRGGBB strings.

_=>[...Array(1<<24)].map((_,n)=>'#'+n.toString(16).padStart(6,0))

Try it online!
(limited to the first 4096 ones, so that it can actually run)

share|improve this answer

answered 4 hours ago

Arnauld

64.8k581274

add a comment | 

up vote
3
down vote

05AB1E, 15 14 10 bytes

15Ýh6ãJ'#ì

Try it online.

Explanation:

15Ý # Create a list in the range [0, 15]
 h # Convert each to a hexadecimal value
 6ã # Create each possible sextuple combination of the list
 J # Join them together to a single string
 '#ì # And prepend a "#" before each of them

share|improve this answer

edited 3 hours ago

answered 4 hours ago

Kevin Cruijssen

30.4k553167

add a comment | 

up vote
2
down vote

R, 25 bytes

sprintf("#%06X",1:2^24-1)

Try it online!

share|improve this answer

edited 2 hours ago

answered 3 hours ago

J.Doe

8619

add a comment | 

up vote
1
down vote

Batch, 87 bytes

@set s= in (0,1,255)do @
@for /l %%r%s%for /l %%g%s%for /l %%b%s%echo rgb(%%r,%%g,%%b)

Outputs in CSS format. The variable substitution happens before the for statement is parsed so the the actual code is as follows:

@for /l %%r in (0,1,255)do @for /l %%g in (0,1,255)do @for /l %%b in (0,1,255)do @echo rgb(%%r,%%g,%%b)

share|improve this answer

answered 2 hours ago

Neil

75.6k744170

add a comment | 

up vote
0
down vote

MATL, 17 16 bytes

24W:q'#%06Xn'YD

Try it online!

The TIO version displays the first 2^10 only as not to time out. I included the final iteration in the footer to show that it indeed terminates at #FFFFFF. Saved one byte by changing to fprintf instead of manually assembling the string.

Explanation

24W:q % Range from 0 to 2^24-1
 '#%06Xn' % fprintf format spec (# followed by hexadecimal, zero-padded, fixed-width, followed by newline)
 YD % Call fprintf. Internally loops over range.

share|improve this answer

edited 2 hours ago

answered 3 hours ago

Sanchises

5,66512251

add a comment | 

up vote
0
down vote

Ruby, 31 bytes

$><<("#%06xn"*d=2**24)%[*0..d]

Try it online!

share|improve this answer

answered 1 hour ago

G B

6,5571324

add a comment | 

up vote
0
down vote

Japt, 14 bytes

Outputs as #rrggbb.

G²³ÇsG ùT6 i'#

Try it (Limited to the first 4096 elements)

---

Explanation

G :16
 ² :Squared
 ³ :Cubed
 Ç :Map the range [0,result)
 sG : Convert to base-16 string
 ù : Left pad
 T : With 0
 6 : To length 6
 i'# : Prepend "#"

share|improve this answer

edited 1 hour ago

answered 2 hours ago

Shaggy

16.8k21661

add a comment | 

up vote
0
down vote

Groovy, 53 bytes

c=a=;(1<<24).timesa.add "".format("#%06x",it);a

Function definition. c() returns an ArrayList (I assume that's fine, even through the question asks for an array).

Ungolfed, with implicit types:

ArrayList<String> c = 
 ArrayList<String> a = 
 (1 << 24).times 
 a.add("".format("#%06x", it)) // add the hex-formatted number to the list.
 
 return a

Try it online!

share|improve this answer

answered 1 hour ago

archangel.mjj

813

add a comment | 

up vote
0
down vote

Java 10, 87 84 bytes

v->int i=1<<24;var r=new String[i];for(;i-->0;)r[i]="".format("#%06X",i);return r;

-3 bytes thanks to @archangel.mjj.

Try it online (limited to the first 4,096 items).

Explanation:

v-> // Method with empty unused parameter & String-array return-type
 int i=1<<24; // Integer `i`, starting at 16,777,216
 var r=new String[i]; // Result String-array of that size
 for(;i-->0;) // Loop `i` in the range (16777216, 0]
 r[i]= // Set the `i`'th item in the array to:
 "".format("#%06X",i);// `i` converted to a hexadecimal value (of size 6)
 return r; // Return the result-array

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Kevin Cruijssen

30.4k553167

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Ah, you posted this while I was writing my post, so we have very similar answers. You can improve by three bytes with r[i]="".format("#%06X",i);
  – archangel.mjj
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @archangel.mjj Ah, I'm an idiot. Thanks! I actually had "".format("#%06X",i) before since I saw it in the Python answer, but I dropped the answer because I couldn't get it to work fast enough for TIO. Then I saw everyone just outputting the first 4,096 items on TIO, so I wrote the answer again, forgetting about "#%06X"... >.<
  – Kevin Cruijssen
  1 hour ago
  

  
  
  
  

add a comment | 

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10 Answers
10

active

oldest

votes

10 Answers
10

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
4
down vote

Python 2, 77 40 bytes

lambda:['#%06X'%c for c in range(1<<24)]

Try it online!

share|improve this answer

edited 4 hours ago

answered 4 hours ago

TFeld

11.8k2833

• 
  
  
  

  
  

  
  
  
  
  
  

  
  How can we output the entire result of F[0:16777216] at TIO The output exceeded 128KiB?
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @guest271314 TIO's output size is limited. That's why TFeld added the F[:10] to see the first 10 items of the list, and F[-10:] to see the last ten items of the list. And he also proved it contained all 16,777,216 items by outputting the length of the result-list.
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
4
down vote

Python 2, 77 40 bytes

lambda:['#%06X'%c for c in range(1<<24)]

Try it online!

share|improve this answer

edited 4 hours ago

answered 4 hours ago

TFeld

11.8k2833

• 
  
  
  

  
  

  
  
  
  
  
  

  
  How can we output the entire result of F[0:16777216] at TIO The output exceeded 128KiB?
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @guest271314 TIO's output size is limited. That's why TFeld added the F[:10] to see the first 10 items of the list, and F[-10:] to see the last ten items of the list. And he also proved it contained all 16,777,216 items by outputting the length of the result-list.
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

add a comment | 

up vote
4
down vote

up vote
4
down vote

Python 2, 77 40 bytes

lambda:['#%06X'%c for c in range(1<<24)]

Try it online!

share|improve this answer

edited 4 hours ago

answered 4 hours ago

TFeld

11.8k2833

Python 2, 77 40 bytes

lambda:['#%06X'%c for c in range(1<<24)]

Try it online!

share|improve this answer

edited 4 hours ago

answered 4 hours ago

TFeld

11.8k2833

share|improve this answer

share|improve this answer

edited 4 hours ago

edited 4 hours ago

edited 4 hours ago

answered 4 hours ago

TFeld

11.8k2833

answered 4 hours ago

TFeld

11.8k2833

answered 4 hours ago

TFeld

11.8k2833

11.8k2833

• 
  
  
  

  
  

  
  
  
  
  
  

  
  How can we output the entire result of F[0:16777216] at TIO The output exceeded 128KiB?
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @guest271314 TIO's output size is limited. That's why TFeld added the F[:10] to see the first 10 items of the list, and F[-10:] to see the last ten items of the list. And he also proved it contained all 16,777,216 items by outputting the length of the result-list.
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  How can we output the entire result of F[0:16777216] at TIO The output exceeded 128KiB?
  – guest271314
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @guest271314 TIO's output size is limited. That's why TFeld added the F[:10] to see the first 10 items of the list, and F[-10:] to see the last ten items of the list. And he also proved it contained all 16,777,216 items by outputting the length of the result-list.
  – Kevin Cruijssen
  4 hours ago
  

  
  
  
  

How can we output the entire result of F[0:16777216] at TIO The output exceeded 128KiB?
– guest271314
4 hours ago

How can we output the entire result of F[0:16777216] at TIO The output exceeded 128KiB?
– guest271314
4 hours ago

@guest271314 TIO's output size is limited. That's why TFeld added the F[:10] to see the first 10 items of the list, and F[-10:] to see the last ten items of the list. And he also proved it contained all 16,777,216 items by outputting the length of the result-list.
– Kevin Cruijssen
4 hours ago

@guest271314 TIO's output size is limited. That's why TFeld added the F[:10] to see the first 10 items of the list, and F[-10:] to see the last ten items of the list. And he also proved it contained all 16,777,216 items by outputting the length of the result-list.
– Kevin Cruijssen
4 hours ago

add a comment | 

up vote
3
down vote

JavaScript (ES8), 65 bytes

Returns an array of #RRGGBB strings.

_=>[...Array(1<<24)].map((_,n)=>'#'+n.toString(16).padStart(6,0))

Try it online!
(limited to the first 4096 ones, so that it can actually run)

share|improve this answer

answered 4 hours ago

Arnauld

64.8k581274

add a comment | 

up vote
3
down vote

JavaScript (ES8), 65 bytes

Returns an array of #RRGGBB strings.

_=>[...Array(1<<24)].map((_,n)=>'#'+n.toString(16).padStart(6,0))

Try it online!
(limited to the first 4096 ones, so that it can actually run)

share|improve this answer

answered 4 hours ago

Arnauld

64.8k581274

add a comment | 

up vote
3
down vote

up vote
3
down vote

JavaScript (ES8), 65 bytes

Returns an array of #RRGGBB strings.

_=>[...Array(1<<24)].map((_,n)=>'#'+n.toString(16).padStart(6,0))

Try it online!
(limited to the first 4096 ones, so that it can actually run)

share|improve this answer

answered 4 hours ago

Arnauld

64.8k581274

JavaScript (ES8), 65 bytes

Returns an array of #RRGGBB strings.

_=>[...Array(1<<24)].map((_,n)=>'#'+n.toString(16).padStart(6,0))

Try it online!
(limited to the first 4096 ones, so that it can actually run)

share|improve this answer

answered 4 hours ago

Arnauld

64.8k581274

share|improve this answer

share|improve this answer

answered 4 hours ago

Arnauld

64.8k581274

answered 4 hours ago

Arnauld

64.8k581274

answered 4 hours ago

Arnauld

64.8k581274

64.8k581274

add a comment | 

add a comment | 

up vote
3
down vote

05AB1E, 15 14 10 bytes

15Ýh6ãJ'#ì

Try it online.

Explanation:

15Ý # Create a list in the range [0, 15]
 h # Convert each to a hexadecimal value
 6ã # Create each possible sextuple combination of the list
 J # Join them together to a single string
 '#ì # And prepend a "#" before each of them

share|improve this answer

edited 3 hours ago

answered 4 hours ago

Kevin Cruijssen

30.4k553167

add a comment | 

up vote
3
down vote

05AB1E, 15 14 10 bytes

15Ýh6ãJ'#ì

Try it online.

Explanation:

15Ý # Create a list in the range [0, 15]
 h # Convert each to a hexadecimal value
 6ã # Create each possible sextuple combination of the list
 J # Join them together to a single string
 '#ì # And prepend a "#" before each of them

share|improve this answer

edited 3 hours ago

answered 4 hours ago

Kevin Cruijssen

30.4k553167

add a comment | 

up vote
3
down vote

up vote
3
down vote

05AB1E, 15 14 10 bytes

15Ýh6ãJ'#ì

Try it online.

Explanation:

15Ý # Create a list in the range [0, 15]
 h # Convert each to a hexadecimal value
 6ã # Create each possible sextuple combination of the list
 J # Join them together to a single string
 '#ì # And prepend a "#" before each of them

share|improve this answer

edited 3 hours ago

answered 4 hours ago

Kevin Cruijssen

30.4k553167

05AB1E, 15 14 10 bytes

15Ýh6ãJ'#ì

Try it online.

Explanation:

15Ý # Create a list in the range [0, 15]
 h # Convert each to a hexadecimal value
 6ã # Create each possible sextuple combination of the list
 J # Join them together to a single string
 '#ì # And prepend a "#" before each of them

share|improve this answer

edited 3 hours ago

answered 4 hours ago

Kevin Cruijssen

30.4k553167

share|improve this answer

share|improve this answer

edited 3 hours ago

edited 3 hours ago

edited 3 hours ago

answered 4 hours ago

Kevin Cruijssen

30.4k553167

answered 4 hours ago

Kevin Cruijssen

30.4k553167

answered 4 hours ago

Kevin Cruijssen

30.4k553167

30.4k553167

add a comment | 

add a comment | 

up vote
2
down vote

R, 25 bytes

sprintf("#%06X",1:2^24-1)

Try it online!

share|improve this answer

edited 2 hours ago

answered 3 hours ago

J.Doe

8619

add a comment | 

up vote
2
down vote

R, 25 bytes

sprintf("#%06X",1:2^24-1)

Try it online!

share|improve this answer

edited 2 hours ago

answered 3 hours ago

J.Doe

8619

add a comment | 

up vote
2
down vote

up vote
2
down vote

R, 25 bytes

sprintf("#%06X",1:2^24-1)

Try it online!

share|improve this answer

edited 2 hours ago

answered 3 hours ago

J.Doe

8619

R, 25 bytes

sprintf("#%06X",1:2^24-1)

Try it online!

share|improve this answer

edited 2 hours ago

answered 3 hours ago

J.Doe

8619

share|improve this answer

share|improve this answer

edited 2 hours ago

edited 2 hours ago

edited 2 hours ago

answered 3 hours ago

J.Doe

8619

answered 3 hours ago

J.Doe

8619

answered 3 hours ago

J.Doe

8619

8619

add a comment | 

add a comment | 

up vote
1
down vote

Batch, 87 bytes

@set s= in (0,1,255)do @
@for /l %%r%s%for /l %%g%s%for /l %%b%s%echo rgb(%%r,%%g,%%b)

Outputs in CSS format. The variable substitution happens before the for statement is parsed so the the actual code is as follows:

@for /l %%r in (0,1,255)do @for /l %%g in (0,1,255)do @for /l %%b in (0,1,255)do @echo rgb(%%r,%%g,%%b)

share|improve this answer

answered 2 hours ago

Neil

75.6k744170

add a comment | 

up vote
1
down vote

Batch, 87 bytes

@set s= in (0,1,255)do @
@for /l %%r%s%for /l %%g%s%for /l %%b%s%echo rgb(%%r,%%g,%%b)

Outputs in CSS format. The variable substitution happens before the for statement is parsed so the the actual code is as follows:

@for /l %%r in (0,1,255)do @for /l %%g in (0,1,255)do @for /l %%b in (0,1,255)do @echo rgb(%%r,%%g,%%b)

share|improve this answer

answered 2 hours ago

Neil

75.6k744170

add a comment | 

up vote
1
down vote

up vote
1
down vote

Batch, 87 bytes

@set s= in (0,1,255)do @
@for /l %%r%s%for /l %%g%s%for /l %%b%s%echo rgb(%%r,%%g,%%b)

Outputs in CSS format. The variable substitution happens before the for statement is parsed so the the actual code is as follows:

@for /l %%r in (0,1,255)do @for /l %%g in (0,1,255)do @for /l %%b in (0,1,255)do @echo rgb(%%r,%%g,%%b)

share|improve this answer

answered 2 hours ago

Neil

75.6k744170

Batch, 87 bytes

@set s= in (0,1,255)do @
@for /l %%r%s%for /l %%g%s%for /l %%b%s%echo rgb(%%r,%%g,%%b)

Outputs in CSS format. The variable substitution happens before the for statement is parsed so the the actual code is as follows:

@for /l %%r in (0,1,255)do @for /l %%g in (0,1,255)do @for /l %%b in (0,1,255)do @echo rgb(%%r,%%g,%%b)

share|improve this answer

answered 2 hours ago

Neil

75.6k744170

share|improve this answer

share|improve this answer

answered 2 hours ago

Neil

75.6k744170

answered 2 hours ago

Neil

75.6k744170

answered 2 hours ago

Neil

75.6k744170

75.6k744170

add a comment | 

add a comment | 

up vote
0
down vote

MATL, 17 16 bytes

24W:q'#%06Xn'YD

Try it online!

The TIO version displays the first 2^10 only as not to time out. I included the final iteration in the footer to show that it indeed terminates at #FFFFFF. Saved one byte by changing to fprintf instead of manually assembling the string.

Explanation

24W:q % Range from 0 to 2^24-1
 '#%06Xn' % fprintf format spec (# followed by hexadecimal, zero-padded, fixed-width, followed by newline)
 YD % Call fprintf. Internally loops over range.

share|improve this answer

edited 2 hours ago

answered 3 hours ago

Sanchises

5,66512251

add a comment | 

up vote
0
down vote

MATL, 17 16 bytes

24W:q'#%06Xn'YD

Try it online!

The TIO version displays the first 2^10 only as not to time out. I included the final iteration in the footer to show that it indeed terminates at #FFFFFF. Saved one byte by changing to fprintf instead of manually assembling the string.

Explanation

24W:q % Range from 0 to 2^24-1
 '#%06Xn' % fprintf format spec (# followed by hexadecimal, zero-padded, fixed-width, followed by newline)
 YD % Call fprintf. Internally loops over range.

share|improve this answer

edited 2 hours ago

answered 3 hours ago

Sanchises

5,66512251

add a comment | 

up vote
0
down vote

up vote
0
down vote

MATL, 17 16 bytes

24W:q'#%06Xn'YD

Try it online!

The TIO version displays the first 2^10 only as not to time out. I included the final iteration in the footer to show that it indeed terminates at #FFFFFF. Saved one byte by changing to fprintf instead of manually assembling the string.

Explanation

24W:q % Range from 0 to 2^24-1
 '#%06Xn' % fprintf format spec (# followed by hexadecimal, zero-padded, fixed-width, followed by newline)
 YD % Call fprintf. Internally loops over range.

share|improve this answer

edited 2 hours ago

answered 3 hours ago

Sanchises

5,66512251

MATL, 17 16 bytes

24W:q'#%06Xn'YD

Try it online!

The TIO version displays the first 2^10 only as not to time out. I included the final iteration in the footer to show that it indeed terminates at #FFFFFF. Saved one byte by changing to fprintf instead of manually assembling the string.

Explanation

24W:q % Range from 0 to 2^24-1
 '#%06Xn' % fprintf format spec (# followed by hexadecimal, zero-padded, fixed-width, followed by newline)
 YD % Call fprintf. Internally loops over range.

share|improve this answer

edited 2 hours ago

answered 3 hours ago

Sanchises

5,66512251

share|improve this answer

share|improve this answer

edited 2 hours ago

edited 2 hours ago

edited 2 hours ago

answered 3 hours ago

Sanchises

5,66512251

answered 3 hours ago

Sanchises

5,66512251

answered 3 hours ago

Sanchises

5,66512251

5,66512251

add a comment | 

add a comment | 

up vote
0
down vote

Ruby, 31 bytes

$><<("#%06xn"*d=2**24)%[*0..d]

Try it online!

share|improve this answer

answered 1 hour ago

G B

6,5571324

add a comment | 

up vote
0
down vote

Ruby, 31 bytes

$><<("#%06xn"*d=2**24)%[*0..d]

Try it online!

share|improve this answer

answered 1 hour ago

G B

6,5571324

add a comment | 

up vote
0
down vote

up vote
0
down vote

Ruby, 31 bytes

$><<("#%06xn"*d=2**24)%[*0..d]

Try it online!

share|improve this answer

answered 1 hour ago

G B

6,5571324

Ruby, 31 bytes

$><<("#%06xn"*d=2**24)%[*0..d]

Try it online!

share|improve this answer

answered 1 hour ago

G B

6,5571324

share|improve this answer

share|improve this answer

answered 1 hour ago

G B

6,5571324

answered 1 hour ago

G B

6,5571324

answered 1 hour ago

G B

6,5571324

6,5571324

add a comment | 

add a comment | 

up vote
0
down vote

Japt, 14 bytes

Outputs as #rrggbb.

G²³ÇsG ùT6 i'#

Try it (Limited to the first 4096 elements)

---

Explanation

G :16
 ² :Squared
 ³ :Cubed
 Ç :Map the range [0,result)
 sG : Convert to base-16 string
 ù : Left pad
 T : With 0
 6 : To length 6
 i'# : Prepend "#"

share|improve this answer

edited 1 hour ago

answered 2 hours ago

Shaggy

16.8k21661

add a comment | 

up vote
0
down vote

Japt, 14 bytes

Outputs as #rrggbb.

G²³ÇsG ùT6 i'#

Try it (Limited to the first 4096 elements)

---

Explanation

G :16
 ² :Squared
 ³ :Cubed
 Ç :Map the range [0,result)
 sG : Convert to base-16 string
 ù : Left pad
 T : With 0
 6 : To length 6
 i'# : Prepend "#"

share|improve this answer

edited 1 hour ago

answered 2 hours ago

Shaggy

16.8k21661

add a comment | 

up vote
0
down vote

up vote
0
down vote

Japt, 14 bytes

Outputs as #rrggbb.

G²³ÇsG ùT6 i'#

Try it (Limited to the first 4096 elements)

---

Explanation

G :16
 ² :Squared
 ³ :Cubed
 Ç :Map the range [0,result)
 sG : Convert to base-16 string
 ù : Left pad
 T : With 0
 6 : To length 6
 i'# : Prepend "#"

share|improve this answer

edited 1 hour ago

answered 2 hours ago

Shaggy

16.8k21661

Japt, 14 bytes

Outputs as #rrggbb.

G²³ÇsG ùT6 i'#

Try it (Limited to the first 4096 elements)

---

Explanation

G :16
 ² :Squared
 ³ :Cubed
 Ç :Map the range [0,result)
 sG : Convert to base-16 string
 ù : Left pad
 T : With 0
 6 : To length 6
 i'# : Prepend "#"

share|improve this answer

edited 1 hour ago

answered 2 hours ago

Shaggy

16.8k21661

share|improve this answer

share|improve this answer

edited 1 hour ago

edited 1 hour ago

edited 1 hour ago

answered 2 hours ago

Shaggy

16.8k21661

answered 2 hours ago

Shaggy

16.8k21661

answered 2 hours ago

Shaggy

16.8k21661

16.8k21661

add a comment | 

add a comment | 

up vote
0
down vote

Groovy, 53 bytes

c=a=;(1<<24).timesa.add "".format("#%06x",it);a

Function definition. c() returns an ArrayList (I assume that's fine, even through the question asks for an array).

Ungolfed, with implicit types:

ArrayList<String> c = 
 ArrayList<String> a = 
 (1 << 24).times 
 a.add("".format("#%06x", it)) // add the hex-formatted number to the list.
 
 return a

Try it online!

share|improve this answer

answered 1 hour ago

archangel.mjj

813

add a comment | 

up vote
0
down vote

Groovy, 53 bytes

c=a=;(1<<24).timesa.add "".format("#%06x",it);a

Function definition. c() returns an ArrayList (I assume that's fine, even through the question asks for an array).

Ungolfed, with implicit types:

ArrayList<String> c = 
 ArrayList<String> a = 
 (1 << 24).times 
 a.add("".format("#%06x", it)) // add the hex-formatted number to the list.
 
 return a

Try it online!

share|improve this answer

answered 1 hour ago

archangel.mjj

813

add a comment | 

up vote
0
down vote

up vote
0
down vote

Groovy, 53 bytes

c=a=;(1<<24).timesa.add "".format("#%06x",it);a

Function definition. c() returns an ArrayList (I assume that's fine, even through the question asks for an array).

Ungolfed, with implicit types:

ArrayList<String> c = 
 ArrayList<String> a = 
 (1 << 24).times 
 a.add("".format("#%06x", it)) // add the hex-formatted number to the list.
 
 return a

Try it online!

share|improve this answer

answered 1 hour ago

archangel.mjj

813

Groovy, 53 bytes

c=a=;(1<<24).timesa.add "".format("#%06x",it);a

Function definition. c() returns an ArrayList (I assume that's fine, even through the question asks for an array).

Ungolfed, with implicit types:

ArrayList<String> c = 
 ArrayList<String> a = 
 (1 << 24).times 
 a.add("".format("#%06x", it)) // add the hex-formatted number to the list.
 
 return a

Try it online!

share|improve this answer

answered 1 hour ago

archangel.mjj

813

share|improve this answer

share|improve this answer

answered 1 hour ago

archangel.mjj

813

answered 1 hour ago

archangel.mjj

813

answered 1 hour ago

archangel.mjj

813

813

add a comment | 

add a comment | 

up vote
0
down vote

Java 10, 87 84 bytes

v->int i=1<<24;var r=new String[i];for(;i-->0;)r[i]="".format("#%06X",i);return r;

-3 bytes thanks to @archangel.mjj.

Try it online (limited to the first 4,096 items).

Explanation:

v-> // Method with empty unused parameter & String-array return-type
 int i=1<<24; // Integer `i`, starting at 16,777,216
 var r=new String[i]; // Result String-array of that size
 for(;i-->0;) // Loop `i` in the range (16777216, 0]
 r[i]= // Set the `i`'th item in the array to:
 "".format("#%06X",i);// `i` converted to a hexadecimal value (of size 6)
 return r; // Return the result-array

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Kevin Cruijssen

30.4k553167

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Ah, you posted this while I was writing my post, so we have very similar answers. You can improve by three bytes with r[i]="".format("#%06X",i);
  – archangel.mjj
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @archangel.mjj Ah, I'm an idiot. Thanks! I actually had "".format("#%06X",i) before since I saw it in the Python answer, but I dropped the answer because I couldn't get it to work fast enough for TIO. Then I saw everyone just outputting the first 4,096 items on TIO, so I wrote the answer again, forgetting about "#%06X"... >.<
  – Kevin Cruijssen
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
0
down vote

Java 10, 87 84 bytes

v->int i=1<<24;var r=new String[i];for(;i-->0;)r[i]="".format("#%06X",i);return r;

-3 bytes thanks to @archangel.mjj.

Try it online (limited to the first 4,096 items).

Explanation:

v-> // Method with empty unused parameter & String-array return-type
 int i=1<<24; // Integer `i`, starting at 16,777,216
 var r=new String[i]; // Result String-array of that size
 for(;i-->0;) // Loop `i` in the range (16777216, 0]
 r[i]= // Set the `i`'th item in the array to:
 "".format("#%06X",i);// `i` converted to a hexadecimal value (of size 6)
 return r; // Return the result-array

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Kevin Cruijssen

30.4k553167

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Ah, you posted this while I was writing my post, so we have very similar answers. You can improve by three bytes with r[i]="".format("#%06X",i);
  – archangel.mjj
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @archangel.mjj Ah, I'm an idiot. Thanks! I actually had "".format("#%06X",i) before since I saw it in the Python answer, but I dropped the answer because I couldn't get it to work fast enough for TIO. Then I saw everyone just outputting the first 4,096 items on TIO, so I wrote the answer again, forgetting about "#%06X"... >.<
  – Kevin Cruijssen
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
0
down vote

up vote
0
down vote

Java 10, 87 84 bytes

v->int i=1<<24;var r=new String[i];for(;i-->0;)r[i]="".format("#%06X",i);return r;

-3 bytes thanks to @archangel.mjj.

Try it online (limited to the first 4,096 items).

Explanation:

v-> // Method with empty unused parameter & String-array return-type
 int i=1<<24; // Integer `i`, starting at 16,777,216
 var r=new String[i]; // Result String-array of that size
 for(;i-->0;) // Loop `i` in the range (16777216, 0]
 r[i]= // Set the `i`'th item in the array to:
 "".format("#%06X",i);// `i` converted to a hexadecimal value (of size 6)
 return r; // Return the result-array

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Kevin Cruijssen

30.4k553167

Java 10, 87 84 bytes

v->int i=1<<24;var r=new String[i];for(;i-->0;)r[i]="".format("#%06X",i);return r;

-3 bytes thanks to @archangel.mjj.

Try it online (limited to the first 4,096 items).

Explanation:

v-> // Method with empty unused parameter & String-array return-type
 int i=1<<24; // Integer `i`, starting at 16,777,216
 var r=new String[i]; // Result String-array of that size
 for(;i-->0;) // Loop `i` in the range (16777216, 0]
 r[i]= // Set the `i`'th item in the array to:
 "".format("#%06X",i);// `i` converted to a hexadecimal value (of size 6)
 return r; // Return the result-array

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Kevin Cruijssen

30.4k553167

share|improve this answer

share|improve this answer

edited 1 hour ago

edited 1 hour ago

edited 1 hour ago

answered 1 hour ago

Kevin Cruijssen

30.4k553167

answered 1 hour ago

Kevin Cruijssen

30.4k553167

answered 1 hour ago

Kevin Cruijssen

30.4k553167

30.4k553167

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Ah, you posted this while I was writing my post, so we have very similar answers. You can improve by three bytes with r[i]="".format("#%06X",i);
  – archangel.mjj
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @archangel.mjj Ah, I'm an idiot. Thanks! I actually had "".format("#%06X",i) before since I saw it in the Python answer, but I dropped the answer because I couldn't get it to work fast enough for TIO. Then I saw everyone just outputting the first 4,096 items on TIO, so I wrote the answer again, forgetting about "#%06X"... >.<
  – Kevin Cruijssen
  1 hour ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Ah, you posted this while I was writing my post, so we have very similar answers. You can improve by three bytes with r[i]="".format("#%06X",i);
  – archangel.mjj
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @archangel.mjj Ah, I'm an idiot. Thanks! I actually had "".format("#%06X",i) before since I saw it in the Python answer, but I dropped the answer because I couldn't get it to work fast enough for TIO. Then I saw everyone just outputting the first 4,096 items on TIO, so I wrote the answer again, forgetting about "#%06X"... >.<
  – Kevin Cruijssen
  1 hour ago
  

  
  
  
  

Ah, you posted this while I was writing my post, so we have very similar answers. You can improve by three bytes with r[i]="".format("#%06X",i);
– archangel.mjj
1 hour ago

Ah, you posted this while I was writing my post, so we have very similar answers. You can improve by three bytes with r[i]="".format("#%06X",i);
– archangel.mjj
1 hour ago

@archangel.mjj Ah, I'm an idiot. Thanks! I actually had "".format("#%06X",i) before since I saw it in the Python answer, but I dropped the answer because I couldn't get it to work fast enough for TIO. Then I saw everyone just outputting the first 4,096 items on TIO, so I wrote the answer again, forgetting about "#%06X"... >.<
– Kevin Cruijssen
1 hour ago

@archangel.mjj Ah, I'm an idiot. Thanks! I actually had "".format("#%06X",i) before since I saw it in the Python answer, but I dropped the answer because I couldn't get it to work fast enough for TIO. Then I saw everyone just outputting the first 4,096 items on TIO, so I wrote the answer again, forgetting about "#%06X"... >.<
– Kevin Cruijssen
1 hour ago

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