Filling circular segment using Tkz-Euclide

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up vote
2
down vote

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I tried to fill a circular segment but I'm having trouble doing it. Here's my MWE:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (90:-90:1.5cm) -- cycle;
endscope
endtikzpicture

enddocument

I'll rotate the picture by 143 degrees.

tikz-pgf draw tkz-euclide

share|improve this question

edited 1 hour ago

marmot

59.9k463128

asked 1 hour ago

Mark Fantini

153127

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I added usetkzobjall to make your code compile.
  – marmot
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Oops, forgot. Thanks!
  – Mark Fantini
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

favorite

I tried to fill a circular segment but I'm having trouble doing it. Here's my MWE:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (90:-90:1.5cm) -- cycle;
endscope
endtikzpicture

enddocument

I'll rotate the picture by 143 degrees.

tikz-pgf draw tkz-euclide

share|improve this question

edited 1 hour ago

marmot

59.9k463128

asked 1 hour ago

Mark Fantini

153127

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I added usetkzobjall to make your code compile.
  – marmot
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Oops, forgot. Thanks!
  – Mark Fantini
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

favorite

up vote
2
down vote

favorite

I tried to fill a circular segment but I'm having trouble doing it. Here's my MWE:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (90:-90:1.5cm) -- cycle;
endscope
endtikzpicture

enddocument

I'll rotate the picture by 143 degrees.

tikz-pgf draw tkz-euclide

share|improve this question

edited 1 hour ago

marmot

59.9k463128

asked 1 hour ago

Mark Fantini

153127

I tried to fill a circular segment but I'm having trouble doing it. Here's my MWE:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (90:-90:1.5cm) -- cycle;
endscope
endtikzpicture

enddocument

I'll rotate the picture by 143 degrees.

tikz-pgf draw tkz-euclide

tikz-pgf draw tkz-euclide

share|improve this question

edited 1 hour ago

marmot

59.9k463128

asked 1 hour ago

Mark Fantini

153127

share|improve this question

edited 1 hour ago

marmot

59.9k463128

asked 1 hour ago

Mark Fantini

153127

share|improve this question

share|improve this question

edited 1 hour ago

marmot

59.9k463128

edited 1 hour ago

marmot

59.9k463128

edited 1 hour ago

marmot

59.9k463128

59.9k463128

asked 1 hour ago

Mark Fantini

153127

asked 1 hour ago

Mark Fantini

153127

asked 1 hour ago

Mark Fantini

153127

153127

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I added usetkzobjall to make your code compile.
  – marmot
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Oops, forgot. Thanks!
  – Mark Fantini
  1 hour ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I added usetkzobjall to make your code compile.
  – marmot
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Oops, forgot. Thanks!
  – Mark Fantini
  1 hour ago
  

  
  
  
  

I added usetkzobjall to make your code compile.
– marmot
1 hour ago

I added usetkzobjall to make your code compile.
– marmot
1 hour ago

Oops, forgot. Thanks!
– Mark Fantini
1 hour ago

Oops, forgot. Thanks!
– Mark Fantini
1 hour ago

add a comment | 

2 Answers
2

active

oldest

votes

up vote
2
down vote

Really easy with the calc library. Perhaps even easier with tkz-euclide if you speak French, which I don't.

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill let p1=($(A)-(O)$),p2=($(B)-(O)$),
n1=atan2(y1,x1),n2=atan2(y2,x2),n3=veclen(x1,y1) in 
(B) -- (A) arc (n1:n2:n3) -- cycle;
endscope
endtikzpicture
enddocument

Explanation: p1=($(A)-(O)$) means that the coordinates of p1, x1 and y1 will be the x- and y-coordinates of the vector O-A, likewise for p2 and B. Correspondingly, n1 and n2 will be the angles of A and B, respectively, and n3 the radius of the circle. These are the quantities needed to draw the arc.

share|improve this answer

edited 48 mins ago

answered 58 mins ago

marmot

59.9k463128

add a comment | 

up vote
2
down vote

It is simply a calculation error of half the angle AOB which measures arcsin(3/5) or about 36.8699 degrees with a radius of 2.5 cm.

This give:

fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;

Full code:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;
endscope
endtikzpicture

enddocument

share|improve this answer

answered 43 mins ago

AndréC

3,211729

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
2
down vote

Really easy with the calc library. Perhaps even easier with tkz-euclide if you speak French, which I don't.

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill let p1=($(A)-(O)$),p2=($(B)-(O)$),
n1=atan2(y1,x1),n2=atan2(y2,x2),n3=veclen(x1,y1) in 
(B) -- (A) arc (n1:n2:n3) -- cycle;
endscope
endtikzpicture
enddocument

Explanation: p1=($(A)-(O)$) means that the coordinates of p1, x1 and y1 will be the x- and y-coordinates of the vector O-A, likewise for p2 and B. Correspondingly, n1 and n2 will be the angles of A and B, respectively, and n3 the radius of the circle. These are the quantities needed to draw the arc.

share|improve this answer

edited 48 mins ago

answered 58 mins ago

marmot

59.9k463128

add a comment | 

up vote
2
down vote

Really easy with the calc library. Perhaps even easier with tkz-euclide if you speak French, which I don't.

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill let p1=($(A)-(O)$),p2=($(B)-(O)$),
n1=atan2(y1,x1),n2=atan2(y2,x2),n3=veclen(x1,y1) in 
(B) -- (A) arc (n1:n2:n3) -- cycle;
endscope
endtikzpicture
enddocument

Explanation: p1=($(A)-(O)$) means that the coordinates of p1, x1 and y1 will be the x- and y-coordinates of the vector O-A, likewise for p2 and B. Correspondingly, n1 and n2 will be the angles of A and B, respectively, and n3 the radius of the circle. These are the quantities needed to draw the arc.

share|improve this answer

edited 48 mins ago

answered 58 mins ago

marmot

59.9k463128

add a comment | 

up vote
2
down vote

up vote
2
down vote

Really easy with the calc library. Perhaps even easier with tkz-euclide if you speak French, which I don't.

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill let p1=($(A)-(O)$),p2=($(B)-(O)$),
n1=atan2(y1,x1),n2=atan2(y2,x2),n3=veclen(x1,y1) in 
(B) -- (A) arc (n1:n2:n3) -- cycle;
endscope
endtikzpicture
enddocument

Explanation: p1=($(A)-(O)$) means that the coordinates of p1, x1 and y1 will be the x- and y-coordinates of the vector O-A, likewise for p2 and B. Correspondingly, n1 and n2 will be the angles of A and B, respectively, and n3 the radius of the circle. These are the quantities needed to draw the arc.

share|improve this answer

edited 48 mins ago

answered 58 mins ago

marmot

59.9k463128

Really easy with the calc library. Perhaps even easier with tkz-euclide if you speak French, which I don't.

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill let p1=($(A)-(O)$),p2=($(B)-(O)$),
n1=atan2(y1,x1),n2=atan2(y2,x2),n3=veclen(x1,y1) in 
(B) -- (A) arc (n1:n2:n3) -- cycle;
endscope
endtikzpicture
enddocument

Explanation: p1=($(A)-(O)$) means that the coordinates of p1, x1 and y1 will be the x- and y-coordinates of the vector O-A, likewise for p2 and B. Correspondingly, n1 and n2 will be the angles of A and B, respectively, and n3 the radius of the circle. These are the quantities needed to draw the arc.

share|improve this answer

edited 48 mins ago

answered 58 mins ago

marmot

59.9k463128

share|improve this answer

share|improve this answer

edited 48 mins ago

edited 48 mins ago

edited 48 mins ago

answered 58 mins ago

marmot

59.9k463128

answered 58 mins ago

marmot

59.9k463128

answered 58 mins ago

marmot

59.9k463128

59.9k463128

add a comment | 

add a comment | 

up vote
2
down vote

It is simply a calculation error of half the angle AOB which measures arcsin(3/5) or about 36.8699 degrees with a radius of 2.5 cm.

This give:

fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;

Full code:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;
endscope
endtikzpicture

enddocument

share|improve this answer

answered 43 mins ago

AndréC

3,211729

add a comment | 

up vote
2
down vote

It is simply a calculation error of half the angle AOB which measures arcsin(3/5) or about 36.8699 degrees with a radius of 2.5 cm.

This give:

fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;

Full code:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;
endscope
endtikzpicture

enddocument

share|improve this answer

answered 43 mins ago

AndréC

3,211729

add a comment | 

up vote
2
down vote

up vote
2
down vote

It is simply a calculation error of half the angle AOB which measures arcsin(3/5) or about 36.8699 degrees with a radius of 2.5 cm.

This give:

fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;

Full code:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;
endscope
endtikzpicture

enddocument

share|improve this answer

answered 43 mins ago

AndréC

3,211729

It is simply a calculation error of half the angle AOB which measures arcsin(3/5) or about 36.8699 degrees with a radius of 2.5 cm.

This give:

fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;

Full code:

documentclass[10pt]scrartcl
usepackagetikz
usepackagetkz-euclide
usetikzlibrarycalc,backgrounds
usetkzobjall
begindocument

begintikzpicture
tkzDefPoints0/0/C, 4/0/B
tkzDrawTriangle[pythagore](C,B)
tkzGetPointA
tkzDefCircle[circum](A,B,C)
tkzGetPointO
tkzGetLengthcr
tkzDrawCircle[R](O,cr pt)
tkzDrawPoints(O)
tkzLabelPoints[left](A)
tkzLabelPoints[right](C)
tkzLabelPoints[above left](B)
tkzLabelPoints[below](O)
tkzLabelSegment[above left](A,B)Large 6 cm
tkzLabelSegment[above right](B,C)Large 8 cm
beginscope[fill=gray, opacity=0.5]
fill[clip] (B) -- (A) arc (36.8699:-36.8699:2.5cm) -- cycle;
endscope
endtikzpicture

enddocument

share|improve this answer

answered 43 mins ago

AndréC

3,211729

share|improve this answer

share|improve this answer

answered 43 mins ago

AndréC

3,211729

answered 43 mins ago

AndréC

3,211729

answered 43 mins ago

AndréC

3,211729

3,211729

add a comment | 

add a comment | 

 

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