How to grep only php version from php -v?

up vote
1
down vote

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I want to grep only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

edited 3 hours ago

Jeff Schaller

32.8k849110

asked 4 hours ago

The One

1,04661528

1

... | head -1 or there might be better ways
â€“Â Vlastimil
4 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
1
down vote

favorite

I want to grep only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

edited 3 hours ago

Jeff Schaller

32.8k849110

asked 4 hours ago

The One

1,04661528

1

... | head -1 or there might be better ways
â€“Â Vlastimil
4 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
1
down vote

favorite

I want to grep only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

edited 3 hours ago

Jeff Schaller

32.8k849110

asked 4 hours ago

The One

1,04661528

I want to grep only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

centos awk php version

edited 3 hours ago

Jeff Schaller

32.8k849110

asked 4 hours ago

The One

1,04661528

edited 3 hours ago

Jeff Schaller

32.8k849110

asked 4 hours ago

The One

1,04661528

edited 3 hours ago

Jeff Schaller

32.8k849110

edited 3 hours ago

Jeff Schaller

32.8k849110

edited 3 hours ago

Jeff Schaller

32.8k849110

asked 4 hours ago

The One

1,04661528

asked 4 hours ago

The One

1,04661528

asked 4 hours ago

The One

1,04661528

1

... | head -1 or there might be better ways
â€“Â Vlastimil
4 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
3 hours ago

add a commentÂ |Â

1

... | head -1 or there might be better ways
â€“Â Vlastimil
4 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
3 hours ago

... | head -1 or there might be better ways
â€“Â Vlastimil
4 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
3 hours ago

add a commentÂ |Â

3 Answers
3

active

oldest

votes

up vote
2
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 3 hours ago

Mr Shunz

2,54111619

Thanks man. It worked.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
2
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 3 hours ago

Ravexina

997719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
1
down vote

If you've install php via the package manage (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

answered 17 mins ago

Jeff Schaller

32.8k849110

add a commentÂ |Â

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
2
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 3 hours ago

Mr Shunz

2,54111619

Thanks man. It worked.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
2
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 3 hours ago

Mr Shunz

2,54111619

Thanks man. It worked.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
2
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 3 hours ago

Mr Shunz

2,54111619

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 3 hours ago

Mr Shunz

2,54111619

answered 3 hours ago

Mr Shunz

2,54111619

answered 3 hours ago

Mr Shunz

2,54111619

answered 3 hours ago

Mr Shunz

2,54111619

Thanks man. It worked.
â€“Â The One
3 hours ago

add a commentÂ |Â

Thanks man. It worked.
â€“Â The One
3 hours ago

Thanks man. It worked.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
2
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 3 hours ago

Ravexina

997719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
2
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 3 hours ago

Ravexina

997719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
2
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 3 hours ago

Ravexina

997719

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 3 hours ago

Ravexina

997719

answered 3 hours ago

Ravexina

997719

answered 3 hours ago

Ravexina

997719

answered 3 hours ago

Ravexina

997719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
3 hours ago

add a commentÂ |Â

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
3 hours ago

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
3 hours ago

add a commentÂ |Â

up vote
1
down vote

If you've install php via the package manage (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

answered 17 mins ago

Jeff Schaller

32.8k849110

add a commentÂ |Â

up vote
1
down vote

If you've install php via the package manage (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

answered 17 mins ago

Jeff Schaller

32.8k849110

add a commentÂ |Â

up vote
1
down vote

If you've install php via the package manage (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

answered 17 mins ago

Jeff Schaller

32.8k849110

If you've install php via the package manage (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

answered 17 mins ago

Jeff Schaller

32.8k849110

answered 17 mins ago

Jeff Schaller

32.8k849110

answered 17 mins ago

Jeff Schaller

32.8k849110

answered 17 mins ago

Jeff Schaller

32.8k849110

add a commentÂ |Â

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