How can I prove this statement about subsets?
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Let $A$, $B$, $C$ be sets. Prove that if $A subseteq C$ and $B subseteq C$ then $A cup B subseteq C$.
This is an exercise in mathematical logic.
My attempt to progress forward: This statement can be written as$$
(A subseteq C) land (B subseteq C) â A cup B subseteq C\
(x in A â x in C) land (x in B â x in C) â A cup B subseteq C
$$
But I am not even sure that is how I am supposed to do it so I am a bit stuck. Can anyone explain to me how to get through this proof? Thanks in advance.
elementary-set-theory logic
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up vote
3
down vote
favorite
Let $A$, $B$, $C$ be sets. Prove that if $A subseteq C$ and $B subseteq C$ then $A cup B subseteq C$.
This is an exercise in mathematical logic.
My attempt to progress forward: This statement can be written as$$
(A subseteq C) land (B subseteq C) â A cup B subseteq C\
(x in A â x in C) land (x in B â x in C) â A cup B subseteq C
$$
But I am not even sure that is how I am supposed to do it so I am a bit stuck. Can anyone explain to me how to get through this proof? Thanks in advance.
elementary-set-theory logic
New contributor
add a comment |Â
up vote
3
down vote
favorite
up vote
3
down vote
favorite
Let $A$, $B$, $C$ be sets. Prove that if $A subseteq C$ and $B subseteq C$ then $A cup B subseteq C$.
This is an exercise in mathematical logic.
My attempt to progress forward: This statement can be written as$$
(A subseteq C) land (B subseteq C) â A cup B subseteq C\
(x in A â x in C) land (x in B â x in C) â A cup B subseteq C
$$
But I am not even sure that is how I am supposed to do it so I am a bit stuck. Can anyone explain to me how to get through this proof? Thanks in advance.
elementary-set-theory logic
New contributor
Let $A$, $B$, $C$ be sets. Prove that if $A subseteq C$ and $B subseteq C$ then $A cup B subseteq C$.
This is an exercise in mathematical logic.
My attempt to progress forward: This statement can be written as$$
(A subseteq C) land (B subseteq C) â A cup B subseteq C\
(x in A â x in C) land (x in B â x in C) â A cup B subseteq C
$$
But I am not even sure that is how I am supposed to do it so I am a bit stuck. Can anyone explain to me how to get through this proof? Thanks in advance.
elementary-set-theory logic
elementary-set-theory logic
New contributor
New contributor
edited 13 mins ago
Taroccoesbrocco
4,21461535
4,21461535
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asked 1 hour ago
Victor Lotz
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161
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2 Answers
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Take any $xin Acup B$. That means either $xin A$ or $xin B$. Anyway you get $xin C$.
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If $A subset C$, and $B subset C$;
$A cap C =A$; and $B cap C = B$;
$Acup B = (A cap C)cup (B cap C) =$
$C cap (A cup B) subset C$
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
Take any $xin Acup B$. That means either $xin A$ or $xin B$. Anyway you get $xin C$.
add a comment |Â
up vote
6
down vote
Take any $xin Acup B$. That means either $xin A$ or $xin B$. Anyway you get $xin C$.
add a comment |Â
up vote
6
down vote
up vote
6
down vote
Take any $xin Acup B$. That means either $xin A$ or $xin B$. Anyway you get $xin C$.
Take any $xin Acup B$. That means either $xin A$ or $xin B$. Anyway you get $xin C$.
answered 1 hour ago
Mark
2,482111
2,482111
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up vote
2
down vote
If $A subset C$, and $B subset C$;
$A cap C =A$; and $B cap C = B$;
$Acup B = (A cap C)cup (B cap C) =$
$C cap (A cup B) subset C$
add a comment |Â
up vote
2
down vote
If $A subset C$, and $B subset C$;
$A cap C =A$; and $B cap C = B$;
$Acup B = (A cap C)cup (B cap C) =$
$C cap (A cup B) subset C$
add a comment |Â
up vote
2
down vote
up vote
2
down vote
If $A subset C$, and $B subset C$;
$A cap C =A$; and $B cap C = B$;
$Acup B = (A cap C)cup (B cap C) =$
$C cap (A cup B) subset C$
If $A subset C$, and $B subset C$;
$A cap C =A$; and $B cap C = B$;
$Acup B = (A cap C)cup (B cap C) =$
$C cap (A cup B) subset C$
edited 1 hour ago
answered 1 hour ago
Peter Szilas
8,5402617
8,5402617
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Victor Lotz is a new contributor. Be nice, and check out our Code of Conduct.
Victor Lotz is a new contributor. Be nice, and check out our Code of Conduct.
Victor Lotz is a new contributor. Be nice, and check out our Code of Conduct.
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