How to get only the version number of php?

up vote
9
down vote

favorite

I want to get only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

edited 7 mins ago

sebasth

6,41321644

asked 9 hours ago

The One

1,08661528

1

... | head -1 or there might be better ways
â€“Â Vlastimil
9 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
9 hours ago

add a commentÂ |Â

up vote
9
down vote

favorite

I want to get only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

edited 7 mins ago

sebasth

6,41321644

asked 9 hours ago

The One

1,08661528

1

... | head -1 or there might be better ways
â€“Â Vlastimil
9 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
9 hours ago

add a commentÂ |Â

up vote
9
down vote

favorite

I want to get only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

edited 7 mins ago

sebasth

6,41321644

asked 9 hours ago

The One

1,08661528

I want to get only the version of php installed on CentOS.

Output of php -v

PHP 7.1.16 (cli) (built: Mar 28 2018 13:19:29) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2018 Zend Technologies

I tried this following:

php -v | grep PHP | awk 'print $2'

But the output I got was:

7.1.16
(c)

How can I get only 7.1.16?

php version

edited 7 mins ago

sebasth

6,41321644

asked 9 hours ago

The One

1,08661528

edited 7 mins ago

sebasth

6,41321644

asked 9 hours ago

The One

1,08661528

edited 7 mins ago

sebasth

6,41321644

edited 7 mins ago

sebasth

6,41321644

edited 7 mins ago

sebasth

6,41321644

asked 9 hours ago

The One

1,08661528

asked 9 hours ago

The One

1,08661528

asked 9 hours ago

The One

1,08661528

1

... | head -1 or there might be better ways
â€“Â Vlastimil
9 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
9 hours ago

add a commentÂ |Â

1

... | head -1 or there might be better ways
â€“Â Vlastimil
9 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
9 hours ago

... | head -1 or there might be better ways
â€“Â Vlastimil
9 hours ago

Oh, head -1 is very simple and elegent. Thanks man.
â€“Â The One
9 hours ago

add a commentÂ |Â

7 Answers
7

active

oldest

votes

up vote
8
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 9 hours ago

Mr Shunz

2,60211619

add a commentÂ |Â

up vote
22
down vote

Extending Jeff Schaller's answer, skip the pipeline altogether and just ask for the internal constant representation:

$ php -r 'echo PHP_VERSION;'
7.1.15

You can extend this pattern to get more, or less, information:

$ php -r 'echo PHP_MAJOR_VERSION;'
7

See the PHP list of pre-defined constants for all available.

Benefit? More performant than pipelines and doesn't rely on a defined output format of php -v.

answered 5 hours ago

bishop

1,061619

add a commentÂ |Â

up vote
7
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 9 hours ago

Ravexina

1,137719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
9 hours ago

add a commentÂ |Â

up vote
7
down vote

If you've installed php via the package manager (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

edited 3 hours ago

answered 5 hours ago

Jeff Schaller

32.9k849110

add a commentÂ |Â

up vote
4
down vote

Since you started with awk, here's an awk solution:

$ php -v | awk '/^PHP/print $2'
7.2.10

answered 3 hours ago

terdonâ™¦

123k28233407

add a commentÂ |Â

up vote
1
down vote

If you want to do it with just a single function being piped, you can try using sed like this:

php -v | sed -e '/^PHP/!d' -e 's/.* ([0-9]+.[0-9]+.[0-9]+).*$/1/'

First it deletes any line that doesn't begin with PHP, then it clips the version from that line assuming it is the first sequence in the form of x.y.z.

Or, if you want something closer to your original script, simply put ^ in the front of your grep pattern to only look for lines that start with PHP:

php -v | grep ^PHP | awk 'print $2'

answered 1 hour ago

Christian Gibbons

291110

add a commentÂ |Â

up vote
0
down vote

php -v | awk NR==1'print $2'

answered 48 mins ago

Goro

4,61752356

add a commentÂ |Â

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7 Answers
7

active

oldest

votes

7 Answers
7

active

oldest

votes

up vote
8
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 9 hours ago

Mr Shunz

2,60211619

add a commentÂ |Â

up vote
8
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 9 hours ago

Mr Shunz

2,60211619

add a commentÂ |Â

up vote
8
down vote

accepted

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 9 hours ago

Mr Shunz

2,60211619

On my system:

$> php -v | grep ^PHP | cut -d' ' -f2
7.0.32-0ubuntu0.16.04.1

as grep PHP matches every PHP string it encounters.

The ^PHP means "match only the string 'PHP' when it is at the start of a line".

Obviously, this works if the output format of php -v is consistent across versions/builds.

For reference, the whole output was:

PHP 7.0.32-0ubuntu0.16.04.1 (cli) ( NTS )
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2017 Zend Technologies
 with Zend OPcache v7.0.32-0ubuntu0.16.04.1, Copyright (c) 1999-2017, by Zend Technologies

answered 9 hours ago

Mr Shunz

2,60211619

answered 9 hours ago

Mr Shunz

2,60211619

answered 9 hours ago

Mr Shunz

2,60211619

answered 9 hours ago

Mr Shunz

2,60211619

add a commentÂ |Â

up vote
22
down vote

Extending Jeff Schaller's answer, skip the pipeline altogether and just ask for the internal constant representation:

$ php -r 'echo PHP_VERSION;'
7.1.15

You can extend this pattern to get more, or less, information:

$ php -r 'echo PHP_MAJOR_VERSION;'
7

See the PHP list of pre-defined constants for all available.

Benefit? More performant than pipelines and doesn't rely on a defined output format of php -v.

answered 5 hours ago

bishop

1,061619

add a commentÂ |Â

up vote
22
down vote

Extending Jeff Schaller's answer, skip the pipeline altogether and just ask for the internal constant representation:

$ php -r 'echo PHP_VERSION;'
7.1.15

You can extend this pattern to get more, or less, information:

$ php -r 'echo PHP_MAJOR_VERSION;'
7

See the PHP list of pre-defined constants for all available.

Benefit? More performant than pipelines and doesn't rely on a defined output format of php -v.

answered 5 hours ago

bishop

1,061619

add a commentÂ |Â

up vote
22
down vote

Extending Jeff Schaller's answer, skip the pipeline altogether and just ask for the internal constant representation:

$ php -r 'echo PHP_VERSION;'
7.1.15

You can extend this pattern to get more, or less, information:

$ php -r 'echo PHP_MAJOR_VERSION;'
7

See the PHP list of pre-defined constants for all available.

Benefit? More performant than pipelines and doesn't rely on a defined output format of php -v.

answered 5 hours ago

bishop

1,061619

Extending Jeff Schaller's answer, skip the pipeline altogether and just ask for the internal constant representation:

$ php -r 'echo PHP_VERSION;'
7.1.15

You can extend this pattern to get more, or less, information:

$ php -r 'echo PHP_MAJOR_VERSION;'
7

See the PHP list of pre-defined constants for all available.

Benefit? More performant than pipelines and doesn't rely on a defined output format of php -v.

answered 5 hours ago

bishop

1,061619

answered 5 hours ago

bishop

1,061619

answered 5 hours ago

bishop

1,061619

answered 5 hours ago

bishop

1,061619

add a commentÂ |Â

up vote
7
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 9 hours ago

Ravexina

1,137719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
9 hours ago

add a commentÂ |Â

up vote
7
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 9 hours ago

Ravexina

1,137719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
9 hours ago

add a commentÂ |Â

up vote
7
down vote

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 9 hours ago

Ravexina

1,137719

There are different ways, I like to use look behind:

php -v | grep -Po '(?<=^PHP )[^ ]+'

php -v | grep -Po '(?<=PHP )([0-9.]+)'

answered 9 hours ago

Ravexina

1,137719

answered 9 hours ago

Ravexina

1,137719

answered 9 hours ago

Ravexina

1,137719

answered 9 hours ago

Ravexina

1,137719

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
9 hours ago

add a commentÂ |Â

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
9 hours ago

Thanks Ravexina. The above command worked like a charm.
â€“Â The One
9 hours ago

add a commentÂ |Â

up vote
7
down vote

If you've installed php via the package manager (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

edited 3 hours ago

answered 5 hours ago

Jeff Schaller

32.9k849110

add a commentÂ |Â

up vote
7
down vote

If you've installed php via the package manager (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

edited 3 hours ago

answered 5 hours ago

Jeff Schaller

32.9k849110

add a commentÂ |Â

up vote
7
down vote

If you've installed php via the package manager (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

edited 3 hours ago

answered 5 hours ago

Jeff Schaller

32.9k849110

If you've installed php via the package manager (e.g. RPM or yum), then you can query the version from there:

rpm -q --queryformat="%VERSION" php

Alternatively, you can ask php to tell you its version directly:

php -r 'echo phpversion();'

edited 3 hours ago

answered 5 hours ago

Jeff Schaller

32.9k849110

edited 3 hours ago

answered 5 hours ago

Jeff Schaller

32.9k849110

answered 5 hours ago

Jeff Schaller

32.9k849110

answered 5 hours ago

Jeff Schaller

32.9k849110

add a commentÂ |Â

up vote
4
down vote

Since you started with awk, here's an awk solution:

$ php -v | awk '/^PHP/print $2'
7.2.10

answered 3 hours ago

terdonâ™¦

123k28233407

add a commentÂ |Â

up vote
4
down vote

Since you started with awk, here's an awk solution:

$ php -v | awk '/^PHP/print $2'
7.2.10

answered 3 hours ago

terdonâ™¦

123k28233407

add a commentÂ |Â

up vote
4
down vote

Since you started with awk, here's an awk solution:

$ php -v | awk '/^PHP/print $2'
7.2.10

answered 3 hours ago

terdonâ™¦

123k28233407

Since you started with awk, here's an awk solution:

$ php -v | awk '/^PHP/print $2'
7.2.10

answered 3 hours ago

terdonâ™¦

123k28233407

answered 3 hours ago

terdonâ™¦

123k28233407

answered 3 hours ago

terdonâ™¦

123k28233407

answered 3 hours ago

terdonâ™¦

123k28233407

add a commentÂ |Â

up vote
1
down vote

If you want to do it with just a single function being piped, you can try using sed like this:

php -v | sed -e '/^PHP/!d' -e 's/.* ([0-9]+.[0-9]+.[0-9]+).*$/1/'

First it deletes any line that doesn't begin with PHP, then it clips the version from that line assuming it is the first sequence in the form of x.y.z.

Or, if you want something closer to your original script, simply put ^ in the front of your grep pattern to only look for lines that start with PHP:

php -v | grep ^PHP | awk 'print $2'

answered 1 hour ago

Christian Gibbons

291110

add a commentÂ |Â

up vote
1
down vote

If you want to do it with just a single function being piped, you can try using sed like this:

php -v | sed -e '/^PHP/!d' -e 's/.* ([0-9]+.[0-9]+.[0-9]+).*$/1/'

First it deletes any line that doesn't begin with PHP, then it clips the version from that line assuming it is the first sequence in the form of x.y.z.

Or, if you want something closer to your original script, simply put ^ in the front of your grep pattern to only look for lines that start with PHP:

php -v | grep ^PHP | awk 'print $2'

answered 1 hour ago

Christian Gibbons

291110

add a commentÂ |Â

up vote
1
down vote

If you want to do it with just a single function being piped, you can try using sed like this:

php -v | sed -e '/^PHP/!d' -e 's/.* ([0-9]+.[0-9]+.[0-9]+).*$/1/'

First it deletes any line that doesn't begin with PHP, then it clips the version from that line assuming it is the first sequence in the form of x.y.z.

Or, if you want something closer to your original script, simply put ^ in the front of your grep pattern to only look for lines that start with PHP:

php -v | grep ^PHP | awk 'print $2'

answered 1 hour ago

Christian Gibbons

291110

If you want to do it with just a single function being piped, you can try using sed like this:

php -v | sed -e '/^PHP/!d' -e 's/.* ([0-9]+.[0-9]+.[0-9]+).*$/1/'

First it deletes any line that doesn't begin with PHP, then it clips the version from that line assuming it is the first sequence in the form of x.y.z.

Or, if you want something closer to your original script, simply put ^ in the front of your grep pattern to only look for lines that start with PHP:

php -v | grep ^PHP | awk 'print $2'

answered 1 hour ago

Christian Gibbons

291110

answered 1 hour ago

Christian Gibbons

291110

answered 1 hour ago

Christian Gibbons

291110

answered 1 hour ago

Christian Gibbons

291110

add a commentÂ |Â

up vote
0
down vote

php -v | awk NR==1'print $2'

answered 48 mins ago

Goro

4,61752356

add a commentÂ |Â

up vote
0
down vote

php -v | awk NR==1'print $2'

answered 48 mins ago

Goro

4,61752356

add a commentÂ |Â

up vote
0
down vote

php -v | awk NR==1'print $2'

answered 48 mins ago

Goro

4,61752356

php -v | awk NR==1'print $2'

answered 48 mins ago

Goro

4,61752356

answered 48 mins ago

Goro

4,61752356

answered 48 mins ago

Goro

4,61752356

answered 48 mins ago

Goro

4,61752356

add a commentÂ |Â

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