How fast am I vrooooming?

Clash Royale CLAN TAG#URR8PPP

up vote
4
down vote

favorite

1

Introduction

My car speedometer was hacked! Instead of showing me how fast i'm driving, it just shows: "Vroooom!" Please help me know how fast i'm going.

Challenge

Take a string as input, and check if it matches the regex /^[Vv]ro*m!$/m. In English that means any line of the string must start with a capital or lowercase v, then a lowercase r, then any amount (including zero) of the lowercase letter o, then the exact string m!. There may be other lines, but the Vroom string must be on it's own line.

If you find a match, then you must count the amount of o's in the Vroom string and output it. If you don't find a match however, you should output any default value that can't be outputted otherwise (like -1 or an empty string)

Reminders

• I/O is in any reasonable format
  


• 
  Standard loopholes are banned


• Submission may be a full program or function


• Input is guaranteed to only have 1 Vroom string

Scoring

This is code-golf, so the shortest code in bytes wins. However, I will not mark any answer as accepted.

Test cases

Input

Vrom!

Output 1

Input

vrooooooom!

Output 7

Input

Hello, Vroom!

Output (none)

Input

Foo bar boo baz
Vrooom!
hi

Output 3

Input

Vrm!ooo

Output (none)

Input

PPCG puzzlers pie

Output (none)

Input

hallo
vROOOm!

Output (none)

code-golf string decision-problem counting

share|improve this question

edited 42 mins ago

asked 1 hour ago

FireCubez

3139

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is raising an error on no Vroom acceptable? Alternatively, can I return a list with the speed and use the empty list for no Vroom?
  – Mnemonic
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Mnemonic Sure.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suggest adding a testcase with uppercase r, o and/or m.
  – Shaggy
  43 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  What's the correct output for Vrm!?
  – Neil
  22 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Usually, I'd complain about requiring input validation, but, in this challenge, it's exactly what separates it from a normal "find the length" challenge.
  – Erik the Outgolfer
  22 mins ago
  

  
  
  
  

 | 
show 1 more comment

up vote
4
down vote

favorite

1

Introduction

My car speedometer was hacked! Instead of showing me how fast i'm driving, it just shows: "Vroooom!" Please help me know how fast i'm going.

Challenge

Take a string as input, and check if it matches the regex /^[Vv]ro*m!$/m. In English that means any line of the string must start with a capital or lowercase v, then a lowercase r, then any amount (including zero) of the lowercase letter o, then the exact string m!. There may be other lines, but the Vroom string must be on it's own line.

If you find a match, then you must count the amount of o's in the Vroom string and output it. If you don't find a match however, you should output any default value that can't be outputted otherwise (like -1 or an empty string)

Reminders

• I/O is in any reasonable format
  


• 
  Standard loopholes are banned


• Submission may be a full program or function


• Input is guaranteed to only have 1 Vroom string

Scoring

This is code-golf, so the shortest code in bytes wins. However, I will not mark any answer as accepted.

Test cases

Input

Vrom!

Output 1

Input

vrooooooom!

Output 7

Input

Hello, Vroom!

Output (none)

Input

Foo bar boo baz
Vrooom!
hi

Output 3

Input

Vrm!ooo

Output (none)

Input

PPCG puzzlers pie

Output (none)

Input

hallo
vROOOm!

Output (none)

code-golf string decision-problem counting

share|improve this question

edited 42 mins ago

asked 1 hour ago

FireCubez

3139

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is raising an error on no Vroom acceptable? Alternatively, can I return a list with the speed and use the empty list for no Vroom?
  – Mnemonic
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Mnemonic Sure.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suggest adding a testcase with uppercase r, o and/or m.
  – Shaggy
  43 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  What's the correct output for Vrm!?
  – Neil
  22 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Usually, I'd complain about requiring input validation, but, in this challenge, it's exactly what separates it from a normal "find the length" challenge.
  – Erik the Outgolfer
  22 mins ago
  

  
  
  
  

 | 
show 1 more comment

up vote
4
down vote

favorite

1

up vote
4
down vote

favorite

1

1

Introduction

My car speedometer was hacked! Instead of showing me how fast i'm driving, it just shows: "Vroooom!" Please help me know how fast i'm going.

Challenge

Take a string as input, and check if it matches the regex /^[Vv]ro*m!$/m. In English that means any line of the string must start with a capital or lowercase v, then a lowercase r, then any amount (including zero) of the lowercase letter o, then the exact string m!. There may be other lines, but the Vroom string must be on it's own line.

If you find a match, then you must count the amount of o's in the Vroom string and output it. If you don't find a match however, you should output any default value that can't be outputted otherwise (like -1 or an empty string)

Reminders

• I/O is in any reasonable format
  


• 
  Standard loopholes are banned


• Submission may be a full program or function


• Input is guaranteed to only have 1 Vroom string

Scoring

This is code-golf, so the shortest code in bytes wins. However, I will not mark any answer as accepted.

Test cases

Input

Vrom!

Output 1

Input

vrooooooom!

Output 7

Input

Hello, Vroom!

Output (none)

Input

Foo bar boo baz
Vrooom!
hi

Output 3

Input

Vrm!ooo

Output (none)

Input

PPCG puzzlers pie

Output (none)

Input

hallo
vROOOm!

Output (none)

code-golf string decision-problem counting

share|improve this question

edited 42 mins ago

asked 1 hour ago

FireCubez

3139

Introduction

My car speedometer was hacked! Instead of showing me how fast i'm driving, it just shows: "Vroooom!" Please help me know how fast i'm going.

Challenge

Take a string as input, and check if it matches the regex /^[Vv]ro*m!$/m. In English that means any line of the string must start with a capital or lowercase v, then a lowercase r, then any amount (including zero) of the lowercase letter o, then the exact string m!. There may be other lines, but the Vroom string must be on it's own line.

If you find a match, then you must count the amount of o's in the Vroom string and output it. If you don't find a match however, you should output any default value that can't be outputted otherwise (like -1 or an empty string)

Reminders

• I/O is in any reasonable format
  


• 
  Standard loopholes are banned


• Submission may be a full program or function


• Input is guaranteed to only have 1 Vroom string

Scoring

This is code-golf, so the shortest code in bytes wins. However, I will not mark any answer as accepted.

Test cases

Input

Vrom!

Output 1

Input

vrooooooom!

Output 7

Input

Hello, Vroom!

Output (none)

Input

Foo bar boo baz
Vrooom!
hi

Output 3

Input

Vrm!ooo

Output (none)

Input

PPCG puzzlers pie

Output (none)

Input

hallo
vROOOm!

Output (none)

code-golf string decision-problem counting

code-golf string decision-problem counting

share|improve this question

edited 42 mins ago

asked 1 hour ago

FireCubez

3139

share|improve this question

edited 42 mins ago

asked 1 hour ago

FireCubez

3139

share|improve this question

share|improve this question

edited 42 mins ago

edited 42 mins ago

edited 42 mins ago

asked 1 hour ago

FireCubez

3139

asked 1 hour ago

FireCubez

3139

asked 1 hour ago

FireCubez

3139

3139

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is raising an error on no Vroom acceptable? Alternatively, can I return a list with the speed and use the empty list for no Vroom?
  – Mnemonic
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Mnemonic Sure.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suggest adding a testcase with uppercase r, o and/or m.
  – Shaggy
  43 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  What's the correct output for Vrm!?
  – Neil
  22 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Usually, I'd complain about requiring input validation, but, in this challenge, it's exactly what separates it from a normal "find the length" challenge.
  – Erik the Outgolfer
  22 mins ago
  

  
  
  
  

 | 
show 1 more comment

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is raising an error on no Vroom acceptable? Alternatively, can I return a list with the speed and use the empty list for no Vroom?
  – Mnemonic
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Mnemonic Sure.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suggest adding a testcase with uppercase r, o and/or m.
  – Shaggy
  43 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  What's the correct output for Vrm!?
  – Neil
  22 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Usually, I'd complain about requiring input validation, but, in this challenge, it's exactly what separates it from a normal "find the length" challenge.
  – Erik the Outgolfer
  22 mins ago
  

  
  
  
  

Is raising an error on no Vroom acceptable? Alternatively, can I return a list with the speed and use the empty list for no Vroom?
– Mnemonic
1 hour ago

Is raising an error on no Vroom acceptable? Alternatively, can I return a list with the speed and use the empty list for no Vroom?
– Mnemonic
1 hour ago

@Mnemonic Sure.
– FireCubez
1 hour ago

@Mnemonic Sure.
– FireCubez
1 hour ago

Suggest adding a testcase with uppercase r, o and/or m.
– Shaggy
43 mins ago

Suggest adding a testcase with uppercase r, o and/or m.
– Shaggy
43 mins ago

What's the correct output for Vrm!?
– Neil
22 mins ago

What's the correct output for Vrm!?
– Neil
22 mins ago

Usually, I'd complain about requiring input validation, but, in this challenge, it's exactly what separates it from a normal "find the length" challenge.
– Erik the Outgolfer
22 mins ago

Usually, I'd complain about requiring input validation, but, in this challenge, it's exactly what separates it from a normal "find the length" challenge.
– Erik the Outgolfer
22 mins ago

 | 
show 1 more comment

8 Answers
8

active

oldest

votes

up vote
1
down vote

PowerShell, 83 bytes

($args-split"`n"|%if(($x=[regex]::Match($_,"^[Vv]ro*m!$")).success)$x).length-4

Try it online!

-splits the input $args on `newlines, pipes those into a for loop. Each iteration, we check whether our [regex]::Match is a .success or not. If so, we leave $x (the regex results object) on the pipeline. Outside the loop, we take the .length property -- if it's the regex results object, this is the length of the match (e.g., "Vroom!" would be 6); if it's not a regex results object, the length is zero. We then subtract 4 to remove the counts for the Vrm! and leave that on the pipeline. Output is implicit. Outputs a -4 if no match is found.

share|improve this answer

answered 1 hour ago

AdmBorkBork

25.2k361220

• 
  
  
  

  
  

  
  
  
  
  
  

  
  sls "^[Vv]ro*m!$"?
  – mazzy
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy How would that work for multiline input? Your only input is one string, and so sls will give back ('','Vroom!','') for example.
  – AdmBorkBork
  57 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  it's not completed solution. I mean, you can try sls instead [regex]::Match
  – mazzy
  54 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy Maybe you should post it as a separate solution.
  – AdmBorkBork
  50 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

SNOBOL4 (CSNOBOL4), 99 bytes

I	I =INPUT	:F(END)
	I POS(0) ('V' | 'v') 'r' ARBNO('o') . X 'm!' RPOS(0)	:F(I)
	OUTPUT =SIZE(X)
END

Try it online!

Pretty direct SNOBOL translation of the spec, reads each line until it finds one that matches ^[Vv]ro*m!$, then outputs the length of the o* bit.

Outputs nothing if no Vroom! can bound found.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Giuseppe

15.7k31051

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is all that whitespace necessary? Wow.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @FireCubez yep, that's what you get with a 50+ year-old language: weird whitespace requirements. It uses space/tab as concatenation and you must surround operators with whitespace as well.
  – Giuseppe
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

sed 4.2.2, 20 bytes

-nr options required at the command-line.

s/^[Vv]r(o*)m!$/1/p

This outputs the speed in unary as the number of os.

Try it online!

share|improve this answer

answered 44 mins ago

Digital Trauma

58.1k786220

add a comment | 

up vote
1
down vote

JavaScript (Node.js), 41 bytes

a=>(l=/[Vv]r(o*)m!/.exec(a))&&l[1].length

Try it online!

share|improve this answer

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

add a comment | 

up vote
1
down vote

Powershell, 62 bytes

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length

Explanation:

• 
  -cmatch means case-sensitive match;


• 
  (?ms) inside regexp means:
  
  
  • Use multiline mode. ^ and $ match the beginning and end of a line, instead of the beginning and end of a string.
  
  
  • Use single-line mode, where the period . matches every character (instead of every character except n)
  
  


• 
  $Matches[1] gives a group of o-sequence.

Test script:

$f = 

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length



@(
,('Vrom!',1)
,('vrooooooom!',7)
,('Hello, Vroom!',$null)
,('Foo bar boo baz
Vrooom!
hi',3)
,('Vrm!ooo',$null)
,('PPCG puzzlers pie',$null)
,('hallo
vROOOm!',$null)
,('
Vrooom!
Vrooooom!
',5) # undefined behavior. By default regexp is greedy, therefore last Vroom displayed.
,('vrm!',0) # :)
) | % 
 $n,$expected = $_
 $result = &$f $n
 "$($result-eq$expected): $result"

Output:

True: 1
True: 7
True:
True: 3
True:
True:
True:
True: 5
True: 0

share|improve this answer

edited 18 mins ago

answered 25 mins ago

mazzy

1,455312

add a comment | 

up vote
0
down vote

Stax, 16 bytes

ü%.÷¶▌é⌂ü╥╪╛╪àG⌐

Run and debug it

share|improve this answer

answered 59 mins ago

recursive

4,7991221

add a comment | 

up vote
0
down vote

Retina, 21 bytes

L$m`^[Vv]r(o*)m!$
$.1

Try it online! Explanation: L lists matches, so if the regex fails to match then output is empty. $ causes the result to be the substitution rather than the match. m makes it a multiline match (the equivalent to the trailing m in the question). The . in the substitution makes it output the length of the capture in decimal.

share|improve this answer

answered 17 mins ago

Neil

77.2k744174

add a comment | 

up vote
0
down vote

Japt, 21 bytes

f"^[Vv]ro*m!$"'m mè'o

Try it online!

Explanation:

f Get the substrings that match
 "^[Vv]ro*m!$" The provided RegEx
 'm in multiline mode
 mè'o Count the number of "o"

share|improve this answer

answered 15 mins ago

Kamil Drakari

2,401416

add a comment | 

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8 Answers
8

active

oldest

votes

8 Answers
8

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
1
down vote

PowerShell, 83 bytes

($args-split"`n"|%if(($x=[regex]::Match($_,"^[Vv]ro*m!$")).success)$x).length-4

Try it online!

-splits the input $args on `newlines, pipes those into a for loop. Each iteration, we check whether our [regex]::Match is a .success or not. If so, we leave $x (the regex results object) on the pipeline. Outside the loop, we take the .length property -- if it's the regex results object, this is the length of the match (e.g., "Vroom!" would be 6); if it's not a regex results object, the length is zero. We then subtract 4 to remove the counts for the Vrm! and leave that on the pipeline. Output is implicit. Outputs a -4 if no match is found.

share|improve this answer

answered 1 hour ago

AdmBorkBork

25.2k361220

• 
  
  
  

  
  

  
  
  
  
  
  

  
  sls "^[Vv]ro*m!$"?
  – mazzy
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy How would that work for multiline input? Your only input is one string, and so sls will give back ('','Vroom!','') for example.
  – AdmBorkBork
  57 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  it's not completed solution. I mean, you can try sls instead [regex]::Match
  – mazzy
  54 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy Maybe you should post it as a separate solution.
  – AdmBorkBork
  50 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

PowerShell, 83 bytes

($args-split"`n"|%if(($x=[regex]::Match($_,"^[Vv]ro*m!$")).success)$x).length-4

Try it online!

-splits the input $args on `newlines, pipes those into a for loop. Each iteration, we check whether our [regex]::Match is a .success or not. If so, we leave $x (the regex results object) on the pipeline. Outside the loop, we take the .length property -- if it's the regex results object, this is the length of the match (e.g., "Vroom!" would be 6); if it's not a regex results object, the length is zero. We then subtract 4 to remove the counts for the Vrm! and leave that on the pipeline. Output is implicit. Outputs a -4 if no match is found.

share|improve this answer

answered 1 hour ago

AdmBorkBork

25.2k361220

• 
  
  
  

  
  

  
  
  
  
  
  

  
  sls "^[Vv]ro*m!$"?
  – mazzy
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy How would that work for multiline input? Your only input is one string, and so sls will give back ('','Vroom!','') for example.
  – AdmBorkBork
  57 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  it's not completed solution. I mean, you can try sls instead [regex]::Match
  – mazzy
  54 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy Maybe you should post it as a separate solution.
  – AdmBorkBork
  50 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

up vote
1
down vote

PowerShell, 83 bytes

($args-split"`n"|%if(($x=[regex]::Match($_,"^[Vv]ro*m!$")).success)$x).length-4

Try it online!

-splits the input $args on `newlines, pipes those into a for loop. Each iteration, we check whether our [regex]::Match is a .success or not. If so, we leave $x (the regex results object) on the pipeline. Outside the loop, we take the .length property -- if it's the regex results object, this is the length of the match (e.g., "Vroom!" would be 6); if it's not a regex results object, the length is zero. We then subtract 4 to remove the counts for the Vrm! and leave that on the pipeline. Output is implicit. Outputs a -4 if no match is found.

share|improve this answer

answered 1 hour ago

AdmBorkBork

25.2k361220

PowerShell, 83 bytes

($args-split"`n"|%if(($x=[regex]::Match($_,"^[Vv]ro*m!$")).success)$x).length-4

Try it online!

-splits the input $args on `newlines, pipes those into a for loop. Each iteration, we check whether our [regex]::Match is a .success or not. If so, we leave $x (the regex results object) on the pipeline. Outside the loop, we take the .length property -- if it's the regex results object, this is the length of the match (e.g., "Vroom!" would be 6); if it's not a regex results object, the length is zero. We then subtract 4 to remove the counts for the Vrm! and leave that on the pipeline. Output is implicit. Outputs a -4 if no match is found.

share|improve this answer

answered 1 hour ago

AdmBorkBork

25.2k361220

share|improve this answer

share|improve this answer

answered 1 hour ago

AdmBorkBork

25.2k361220

answered 1 hour ago

AdmBorkBork

25.2k361220

answered 1 hour ago

AdmBorkBork

25.2k361220

25.2k361220

• 
  
  
  

  
  

  
  
  
  
  
  

  
  sls "^[Vv]ro*m!$"?
  – mazzy
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy How would that work for multiline input? Your only input is one string, and so sls will give back ('','Vroom!','') for example.
  – AdmBorkBork
  57 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  it's not completed solution. I mean, you can try sls instead [regex]::Match
  – mazzy
  54 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy Maybe you should post it as a separate solution.
  – AdmBorkBork
  50 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  sls "^[Vv]ro*m!$"?
  – mazzy
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy How would that work for multiline input? Your only input is one string, and so sls will give back ('','Vroom!','') for example.
  – AdmBorkBork
  57 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  it's not completed solution. I mean, you can try sls instead [regex]::Match
  – mazzy
  54 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @mazzy Maybe you should post it as a separate solution.
  – AdmBorkBork
  50 mins ago
  

  
  
  
  

sls "^[Vv]ro*m!$"?
– mazzy
1 hour ago

sls "^[Vv]ro*m!$"?
– mazzy
1 hour ago

@mazzy How would that work for multiline input? Your only input is one string, and so sls will give back ('','Vroom!','') for example.
– AdmBorkBork
57 mins ago

@mazzy How would that work for multiline input? Your only input is one string, and so sls will give back ('','Vroom!','') for example.
– AdmBorkBork
57 mins ago

it's not completed solution. I mean, you can try sls instead [regex]::Match
– mazzy
54 mins ago

it's not completed solution. I mean, you can try sls instead [regex]::Match
– mazzy
54 mins ago

@mazzy Maybe you should post it as a separate solution.
– AdmBorkBork
50 mins ago

@mazzy Maybe you should post it as a separate solution.
– AdmBorkBork
50 mins ago

add a comment | 

up vote
1
down vote

SNOBOL4 (CSNOBOL4), 99 bytes

I	I =INPUT	:F(END)
	I POS(0) ('V' | 'v') 'r' ARBNO('o') . X 'm!' RPOS(0)	:F(I)
	OUTPUT =SIZE(X)
END

Try it online!

Pretty direct SNOBOL translation of the spec, reads each line until it finds one that matches ^[Vv]ro*m!$, then outputs the length of the o* bit.

Outputs nothing if no Vroom! can bound found.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Giuseppe

15.7k31051

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is all that whitespace necessary? Wow.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @FireCubez yep, that's what you get with a 50+ year-old language: weird whitespace requirements. It uses space/tab as concatenation and you must surround operators with whitespace as well.
  – Giuseppe
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

SNOBOL4 (CSNOBOL4), 99 bytes

I	I =INPUT	:F(END)
	I POS(0) ('V' | 'v') 'r' ARBNO('o') . X 'm!' RPOS(0)	:F(I)
	OUTPUT =SIZE(X)
END

Try it online!

Pretty direct SNOBOL translation of the spec, reads each line until it finds one that matches ^[Vv]ro*m!$, then outputs the length of the o* bit.

Outputs nothing if no Vroom! can bound found.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Giuseppe

15.7k31051

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is all that whitespace necessary? Wow.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @FireCubez yep, that's what you get with a 50+ year-old language: weird whitespace requirements. It uses space/tab as concatenation and you must surround operators with whitespace as well.
  – Giuseppe
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

up vote
1
down vote

SNOBOL4 (CSNOBOL4), 99 bytes

I	I =INPUT	:F(END)
	I POS(0) ('V' | 'v') 'r' ARBNO('o') . X 'm!' RPOS(0)	:F(I)
	OUTPUT =SIZE(X)
END

Try it online!

Pretty direct SNOBOL translation of the spec, reads each line until it finds one that matches ^[Vv]ro*m!$, then outputs the length of the o* bit.

Outputs nothing if no Vroom! can bound found.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Giuseppe

15.7k31051

SNOBOL4 (CSNOBOL4), 99 bytes

I	I =INPUT	:F(END)
	I POS(0) ('V' | 'v') 'r' ARBNO('o') . X 'm!' RPOS(0)	:F(I)
	OUTPUT =SIZE(X)
END

Try it online!

Pretty direct SNOBOL translation of the spec, reads each line until it finds one that matches ^[Vv]ro*m!$, then outputs the length of the o* bit.

Outputs nothing if no Vroom! can bound found.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

Giuseppe

15.7k31051

share|improve this answer

share|improve this answer

edited 1 hour ago

edited 1 hour ago

edited 1 hour ago

answered 1 hour ago

Giuseppe

15.7k31051

answered 1 hour ago

Giuseppe

15.7k31051

answered 1 hour ago

Giuseppe

15.7k31051

15.7k31051

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is all that whitespace necessary? Wow.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @FireCubez yep, that's what you get with a 50+ year-old language: weird whitespace requirements. It uses space/tab as concatenation and you must surround operators with whitespace as well.
  – Giuseppe
  1 hour ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Is all that whitespace necessary? Wow.
  – FireCubez
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @FireCubez yep, that's what you get with a 50+ year-old language: weird whitespace requirements. It uses space/tab as concatenation and you must surround operators with whitespace as well.
  – Giuseppe
  1 hour ago
  

  
  
  
  

Is all that whitespace necessary? Wow.
– FireCubez
1 hour ago

Is all that whitespace necessary? Wow.
– FireCubez
1 hour ago

1

1

@FireCubez yep, that's what you get with a 50+ year-old language: weird whitespace requirements. It uses space/tab as concatenation and you must surround operators with whitespace as well.
– Giuseppe
1 hour ago

@FireCubez yep, that's what you get with a 50+ year-old language: weird whitespace requirements. It uses space/tab as concatenation and you must surround operators with whitespace as well.
– Giuseppe
1 hour ago

add a comment | 

up vote
1
down vote

sed 4.2.2, 20 bytes

-nr options required at the command-line.

s/^[Vv]r(o*)m!$/1/p

This outputs the speed in unary as the number of os.

Try it online!

share|improve this answer

answered 44 mins ago

Digital Trauma

58.1k786220

add a comment | 

up vote
1
down vote

sed 4.2.2, 20 bytes

-nr options required at the command-line.

s/^[Vv]r(o*)m!$/1/p

This outputs the speed in unary as the number of os.

Try it online!

share|improve this answer

answered 44 mins ago

Digital Trauma

58.1k786220

add a comment | 

up vote
1
down vote

up vote
1
down vote

sed 4.2.2, 20 bytes

-nr options required at the command-line.

s/^[Vv]r(o*)m!$/1/p

This outputs the speed in unary as the number of os.

Try it online!

share|improve this answer

answered 44 mins ago

Digital Trauma

58.1k786220

sed 4.2.2, 20 bytes

-nr options required at the command-line.

s/^[Vv]r(o*)m!$/1/p

This outputs the speed in unary as the number of os.

Try it online!

share|improve this answer

answered 44 mins ago

Digital Trauma

58.1k786220

share|improve this answer

share|improve this answer

answered 44 mins ago

Digital Trauma

58.1k786220

answered 44 mins ago

Digital Trauma

58.1k786220

answered 44 mins ago

Digital Trauma

58.1k786220

58.1k786220

add a comment | 

add a comment | 

up vote
1
down vote

JavaScript (Node.js), 41 bytes

a=>(l=/[Vv]r(o*)m!/.exec(a))&&l[1].length

Try it online!

share|improve this answer

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

add a comment | 

up vote
1
down vote

JavaScript (Node.js), 41 bytes

a=>(l=/[Vv]r(o*)m!/.exec(a))&&l[1].length

Try it online!

share|improve this answer

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

add a comment | 

up vote
1
down vote

up vote
1
down vote

JavaScript (Node.js), 41 bytes

a=>(l=/[Vv]r(o*)m!/.exec(a))&&l[1].length

Try it online!

share|improve this answer

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

JavaScript (Node.js), 41 bytes

a=>(l=/[Vv]r(o*)m!/.exec(a))&&l[1].length

Try it online!

share|improve this answer

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

share|improve this answer

share|improve this answer

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

answered 28 mins ago

Luis felipe De jesus Munoz

3,51511049

3,51511049

add a comment | 

add a comment | 

up vote
1
down vote

Powershell, 62 bytes

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length

Explanation:

• 
  -cmatch means case-sensitive match;


• 
  (?ms) inside regexp means:
  
  
  • Use multiline mode. ^ and $ match the beginning and end of a line, instead of the beginning and end of a string.
  
  
  • Use single-line mode, where the period . matches every character (instead of every character except n)
  
  


• 
  $Matches[1] gives a group of o-sequence.

Test script:

$f = 

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length



@(
,('Vrom!',1)
,('vrooooooom!',7)
,('Hello, Vroom!',$null)
,('Foo bar boo baz
Vrooom!
hi',3)
,('Vrm!ooo',$null)
,('PPCG puzzlers pie',$null)
,('hallo
vROOOm!',$null)
,('
Vrooom!
Vrooooom!
',5) # undefined behavior. By default regexp is greedy, therefore last Vroom displayed.
,('vrm!',0) # :)
) | % 
 $n,$expected = $_
 $result = &$f $n
 "$($result-eq$expected): $result"

Output:

True: 1
True: 7
True:
True: 3
True:
True:
True:
True: 5
True: 0

share|improve this answer

edited 18 mins ago

answered 25 mins ago

mazzy

1,455312

add a comment | 

up vote
1
down vote

Powershell, 62 bytes

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length

Explanation:

• 
  -cmatch means case-sensitive match;


• 
  (?ms) inside regexp means:
  
  
  • Use multiline mode. ^ and $ match the beginning and end of a line, instead of the beginning and end of a string.
  
  
  • Use single-line mode, where the period . matches every character (instead of every character except n)
  
  


• 
  $Matches[1] gives a group of o-sequence.

Test script:

$f = 

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length



@(
,('Vrom!',1)
,('vrooooooom!',7)
,('Hello, Vroom!',$null)
,('Foo bar boo baz
Vrooom!
hi',3)
,('Vrm!ooo',$null)
,('PPCG puzzlers pie',$null)
,('hallo
vROOOm!',$null)
,('
Vrooom!
Vrooooom!
',5) # undefined behavior. By default regexp is greedy, therefore last Vroom displayed.
,('vrm!',0) # :)
) | % 
 $n,$expected = $_
 $result = &$f $n
 "$($result-eq$expected): $result"

Output:

True: 1
True: 7
True:
True: 3
True:
True:
True:
True: 5
True: 0

share|improve this answer

edited 18 mins ago

answered 25 mins ago

mazzy

1,455312

add a comment | 

up vote
1
down vote

up vote
1
down vote

Powershell, 62 bytes

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length

Explanation:

• 
  -cmatch means case-sensitive match;


• 
  (?ms) inside regexp means:
  
  
  • Use multiline mode. ^ and $ match the beginning and end of a line, instead of the beginning and end of a string.
  
  
  • Use single-line mode, where the period . matches every character (instead of every character except n)
  
  


• 
  $Matches[1] gives a group of o-sequence.

Test script:

$f = 

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length



@(
,('Vrom!',1)
,('vrooooooom!',7)
,('Hello, Vroom!',$null)
,('Foo bar boo baz
Vrooom!
hi',3)
,('Vrm!ooo',$null)
,('PPCG puzzlers pie',$null)
,('hallo
vROOOm!',$null)
,('
Vrooom!
Vrooooom!
',5) # undefined behavior. By default regexp is greedy, therefore last Vroom displayed.
,('vrm!',0) # :)
) | % 
 $n,$expected = $_
 $result = &$f $n
 "$($result-eq$expected): $result"

Output:

True: 1
True: 7
True:
True: 3
True:
True:
True:
True: 5
True: 0

share|improve this answer

edited 18 mins ago

answered 25 mins ago

mazzy

1,455312

Powershell, 62 bytes

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length

Explanation:

• 
  -cmatch means case-sensitive match;


• 
  (?ms) inside regexp means:
  
  
  • Use multiline mode. ^ and $ match the beginning and end of a line, instead of the beginning and end of a string.
  
  
  • Use single-line mode, where the period . matches every character (instead of every character except n)
  
  


• 
  $Matches[1] gives a group of o-sequence.

Test script:

$f = 

if("$args"-cmatch'(?ms).*^[Vv]r(o*)m!$.*')$Matches[1].Length



@(
,('Vrom!',1)
,('vrooooooom!',7)
,('Hello, Vroom!',$null)
,('Foo bar boo baz
Vrooom!
hi',3)
,('Vrm!ooo',$null)
,('PPCG puzzlers pie',$null)
,('hallo
vROOOm!',$null)
,('
Vrooom!
Vrooooom!
',5) # undefined behavior. By default regexp is greedy, therefore last Vroom displayed.
,('vrm!',0) # :)
) | % 
 $n,$expected = $_
 $result = &$f $n
 "$($result-eq$expected): $result"

Output:

True: 1
True: 7
True:
True: 3
True:
True:
True:
True: 5
True: 0

share|improve this answer

edited 18 mins ago

answered 25 mins ago

mazzy

1,455312

share|improve this answer

share|improve this answer

edited 18 mins ago

edited 18 mins ago

edited 18 mins ago

answered 25 mins ago

mazzy

1,455312

answered 25 mins ago

mazzy

1,455312

answered 25 mins ago

mazzy

1,455312

1,455312

add a comment | 

add a comment | 

up vote
0
down vote

Stax, 16 bytes

ü%.÷¶▌é⌂ü╥╪╛╪àG⌐

Run and debug it

share|improve this answer

answered 59 mins ago

recursive

4,7991221

add a comment | 

up vote
0
down vote

Stax, 16 bytes

ü%.÷¶▌é⌂ü╥╪╛╪àG⌐

Run and debug it

share|improve this answer

answered 59 mins ago

recursive

4,7991221

add a comment | 

up vote
0
down vote

up vote
0
down vote

Stax, 16 bytes

ü%.÷¶▌é⌂ü╥╪╛╪àG⌐

Run and debug it

share|improve this answer

answered 59 mins ago

recursive

4,7991221

Stax, 16 bytes

ü%.÷¶▌é⌂ü╥╪╛╪àG⌐

Run and debug it

share|improve this answer

answered 59 mins ago

recursive

4,7991221

share|improve this answer

share|improve this answer

answered 59 mins ago

recursive

4,7991221

answered 59 mins ago

recursive

4,7991221

answered 59 mins ago

recursive

4,7991221

4,7991221

add a comment | 

add a comment | 

up vote
0
down vote

Retina, 21 bytes

L$m`^[Vv]r(o*)m!$
$.1

Try it online! Explanation: L lists matches, so if the regex fails to match then output is empty. $ causes the result to be the substitution rather than the match. m makes it a multiline match (the equivalent to the trailing m in the question). The . in the substitution makes it output the length of the capture in decimal.

share|improve this answer

answered 17 mins ago

Neil

77.2k744174

add a comment | 

up vote
0
down vote

Retina, 21 bytes

L$m`^[Vv]r(o*)m!$
$.1

Try it online! Explanation: L lists matches, so if the regex fails to match then output is empty. $ causes the result to be the substitution rather than the match. m makes it a multiline match (the equivalent to the trailing m in the question). The . in the substitution makes it output the length of the capture in decimal.

share|improve this answer

answered 17 mins ago

Neil

77.2k744174

add a comment | 

up vote
0
down vote

up vote
0
down vote

Retina, 21 bytes

L$m`^[Vv]r(o*)m!$
$.1

Try it online! Explanation: L lists matches, so if the regex fails to match then output is empty. $ causes the result to be the substitution rather than the match. m makes it a multiline match (the equivalent to the trailing m in the question). The . in the substitution makes it output the length of the capture in decimal.

share|improve this answer

answered 17 mins ago

Neil

77.2k744174

Retina, 21 bytes

L$m`^[Vv]r(o*)m!$
$.1

Try it online! Explanation: L lists matches, so if the regex fails to match then output is empty. $ causes the result to be the substitution rather than the match. m makes it a multiline match (the equivalent to the trailing m in the question). The . in the substitution makes it output the length of the capture in decimal.

share|improve this answer

answered 17 mins ago

Neil

77.2k744174

share|improve this answer

share|improve this answer

answered 17 mins ago

Neil

77.2k744174

answered 17 mins ago

Neil

77.2k744174

answered 17 mins ago

Neil

77.2k744174

77.2k744174

add a comment | 

add a comment | 

up vote
0
down vote

Japt, 21 bytes

f"^[Vv]ro*m!$"'m mè'o

Try it online!

Explanation:

f Get the substrings that match
 "^[Vv]ro*m!$" The provided RegEx
 'm in multiline mode
 mè'o Count the number of "o"

share|improve this answer

answered 15 mins ago

Kamil Drakari

2,401416

add a comment | 

up vote
0
down vote

Japt, 21 bytes

f"^[Vv]ro*m!$"'m mè'o

Try it online!

Explanation:

f Get the substrings that match
 "^[Vv]ro*m!$" The provided RegEx
 'm in multiline mode
 mè'o Count the number of "o"

share|improve this answer

answered 15 mins ago

Kamil Drakari

2,401416

add a comment | 

up vote
0
down vote

up vote
0
down vote

Japt, 21 bytes

f"^[Vv]ro*m!$"'m mè'o

Try it online!

Explanation:

f Get the substrings that match
 "^[Vv]ro*m!$" The provided RegEx
 'm in multiline mode
 mè'o Count the number of "o"

share|improve this answer

answered 15 mins ago

Kamil Drakari

2,401416

Japt, 21 bytes

f"^[Vv]ro*m!$"'m mè'o

Try it online!

Explanation:

f Get the substrings that match
 "^[Vv]ro*m!$" The provided RegEx
 'm in multiline mode
 mè'o Count the number of "o"

share|improve this answer

answered 15 mins ago

Kamil Drakari

2,401416

share|improve this answer

share|improve this answer

answered 15 mins ago

Kamil Drakari

2,401416

answered 15 mins ago

Kamil Drakari

2,401416

answered 15 mins ago

Kamil Drakari

2,401416

2,401416

add a comment | 

add a comment | 

 

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