Is the person in this video explaining it wrong?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
2
down vote

favorite












Here's the link! to the video.
Watch @3:30, this person resolves the momentum vector into two components , tangential and radial. But the velocity at every point on the orbit must be tangential right? Is it not so?










share|cite|improve this question









New contributor




Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Does the statement "the velocity at every point on the orbit must be tangential" apply to elliptical orbits?
    – Arturs C.
    3 hours ago






  • 1




    Possible duplicate: physics.stackexchange.com/q/349811/2451
    – Qmechanic♦
    3 hours ago










  • @ArtursC. Yes,it does!
    – ayc
    2 hours ago














up vote
2
down vote

favorite












Here's the link! to the video.
Watch @3:30, this person resolves the momentum vector into two components , tangential and radial. But the velocity at every point on the orbit must be tangential right? Is it not so?










share|cite|improve this question









New contributor




Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Does the statement "the velocity at every point on the orbit must be tangential" apply to elliptical orbits?
    – Arturs C.
    3 hours ago






  • 1




    Possible duplicate: physics.stackexchange.com/q/349811/2451
    – Qmechanic♦
    3 hours ago










  • @ArtursC. Yes,it does!
    – ayc
    2 hours ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











Here's the link! to the video.
Watch @3:30, this person resolves the momentum vector into two components , tangential and radial. But the velocity at every point on the orbit must be tangential right? Is it not so?










share|cite|improve this question









New contributor




Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Here's the link! to the video.
Watch @3:30, this person resolves the momentum vector into two components , tangential and radial. But the velocity at every point on the orbit must be tangential right? Is it not so?







newtonian-mechanics kinematics orbital-motion vectors






share|cite|improve this question









New contributor




Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 3 hours ago









Qmechanic♦

98.5k121741074




98.5k121741074






New contributor




Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 4 hours ago









Mike Victor

193




193




New contributor




Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Mike Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • Does the statement "the velocity at every point on the orbit must be tangential" apply to elliptical orbits?
    – Arturs C.
    3 hours ago






  • 1




    Possible duplicate: physics.stackexchange.com/q/349811/2451
    – Qmechanic♦
    3 hours ago










  • @ArtursC. Yes,it does!
    – ayc
    2 hours ago
















  • Does the statement "the velocity at every point on the orbit must be tangential" apply to elliptical orbits?
    – Arturs C.
    3 hours ago






  • 1




    Possible duplicate: physics.stackexchange.com/q/349811/2451
    – Qmechanic♦
    3 hours ago










  • @ArtursC. Yes,it does!
    – ayc
    2 hours ago















Does the statement "the velocity at every point on the orbit must be tangential" apply to elliptical orbits?
– Arturs C.
3 hours ago




Does the statement "the velocity at every point on the orbit must be tangential" apply to elliptical orbits?
– Arturs C.
3 hours ago




1




1




Possible duplicate: physics.stackexchange.com/q/349811/2451
– Qmechanic♦
3 hours ago




Possible duplicate: physics.stackexchange.com/q/349811/2451
– Qmechanic♦
3 hours ago












@ArtursC. Yes,it does!
– ayc
2 hours ago




@ArtursC. Yes,it does!
– ayc
2 hours ago










1 Answer
1






active

oldest

votes

















up vote
3
down vote













I think it's just a misunderstanding!




But the velocity at every point on the orbit must be tangential right?




Yes,it is and that's why the actual momentum vector is tangential to the ellipse




this person resolves the momentum vector into two components , tangential and radial




And yes he did.But,you should notice that he called one radial and the other perpendicular i.e the resolution is done according to the line joining the object's(planet's) location and sun and the object has radial velocity because radial velocity is defined as the component of the object's velocity that points in the direction of the radius connecting the object and the point.



And if you look at what you are calling as tangential velocity you would notice that this component, i.e perpendicular to line joining planet and sun, isn't tangential to the ellipse.It's just perpendicular to the line joining the planet and the ellipse.



Conclusion: The planet always has velocity tangential to the ellipse and the velocity perpendicular to the line joining planet and object isn't tangential to the ellipse at all instants.



Note:



Although in your question you particularly ask about momentum I just used the term velocity rather than momentum because I think it is easier to understand this way.



If you need momentum at any instant just multiply total velocity with mass(p=mv)



References:



https://en.wikipedia.org/wiki/Radial_velocity



https://www.youtube.com/watch?v=Pa3Of_3vpRc






share|cite|improve this answer










New contributor




ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















    Your Answer




    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "151"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: false,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );






    Mike Victor is a new contributor. Be nice, and check out our Code of Conduct.









     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f436907%2fis-the-person-in-this-video-explaining-it-wrong%23new-answer', 'question_page');

    );

    Post as a guest






























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote













    I think it's just a misunderstanding!




    But the velocity at every point on the orbit must be tangential right?




    Yes,it is and that's why the actual momentum vector is tangential to the ellipse




    this person resolves the momentum vector into two components , tangential and radial




    And yes he did.But,you should notice that he called one radial and the other perpendicular i.e the resolution is done according to the line joining the object's(planet's) location and sun and the object has radial velocity because radial velocity is defined as the component of the object's velocity that points in the direction of the radius connecting the object and the point.



    And if you look at what you are calling as tangential velocity you would notice that this component, i.e perpendicular to line joining planet and sun, isn't tangential to the ellipse.It's just perpendicular to the line joining the planet and the ellipse.



    Conclusion: The planet always has velocity tangential to the ellipse and the velocity perpendicular to the line joining planet and object isn't tangential to the ellipse at all instants.



    Note:



    Although in your question you particularly ask about momentum I just used the term velocity rather than momentum because I think it is easier to understand this way.



    If you need momentum at any instant just multiply total velocity with mass(p=mv)



    References:



    https://en.wikipedia.org/wiki/Radial_velocity



    https://www.youtube.com/watch?v=Pa3Of_3vpRc






    share|cite|improve this answer










    New contributor




    ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      up vote
      3
      down vote













      I think it's just a misunderstanding!




      But the velocity at every point on the orbit must be tangential right?




      Yes,it is and that's why the actual momentum vector is tangential to the ellipse




      this person resolves the momentum vector into two components , tangential and radial




      And yes he did.But,you should notice that he called one radial and the other perpendicular i.e the resolution is done according to the line joining the object's(planet's) location and sun and the object has radial velocity because radial velocity is defined as the component of the object's velocity that points in the direction of the radius connecting the object and the point.



      And if you look at what you are calling as tangential velocity you would notice that this component, i.e perpendicular to line joining planet and sun, isn't tangential to the ellipse.It's just perpendicular to the line joining the planet and the ellipse.



      Conclusion: The planet always has velocity tangential to the ellipse and the velocity perpendicular to the line joining planet and object isn't tangential to the ellipse at all instants.



      Note:



      Although in your question you particularly ask about momentum I just used the term velocity rather than momentum because I think it is easier to understand this way.



      If you need momentum at any instant just multiply total velocity with mass(p=mv)



      References:



      https://en.wikipedia.org/wiki/Radial_velocity



      https://www.youtube.com/watch?v=Pa3Of_3vpRc






      share|cite|improve this answer










      New contributor




      ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.



















        up vote
        3
        down vote










        up vote
        3
        down vote









        I think it's just a misunderstanding!




        But the velocity at every point on the orbit must be tangential right?




        Yes,it is and that's why the actual momentum vector is tangential to the ellipse




        this person resolves the momentum vector into two components , tangential and radial




        And yes he did.But,you should notice that he called one radial and the other perpendicular i.e the resolution is done according to the line joining the object's(planet's) location and sun and the object has radial velocity because radial velocity is defined as the component of the object's velocity that points in the direction of the radius connecting the object and the point.



        And if you look at what you are calling as tangential velocity you would notice that this component, i.e perpendicular to line joining planet and sun, isn't tangential to the ellipse.It's just perpendicular to the line joining the planet and the ellipse.



        Conclusion: The planet always has velocity tangential to the ellipse and the velocity perpendicular to the line joining planet and object isn't tangential to the ellipse at all instants.



        Note:



        Although in your question you particularly ask about momentum I just used the term velocity rather than momentum because I think it is easier to understand this way.



        If you need momentum at any instant just multiply total velocity with mass(p=mv)



        References:



        https://en.wikipedia.org/wiki/Radial_velocity



        https://www.youtube.com/watch?v=Pa3Of_3vpRc






        share|cite|improve this answer










        New contributor




        ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        I think it's just a misunderstanding!




        But the velocity at every point on the orbit must be tangential right?




        Yes,it is and that's why the actual momentum vector is tangential to the ellipse




        this person resolves the momentum vector into two components , tangential and radial




        And yes he did.But,you should notice that he called one radial and the other perpendicular i.e the resolution is done according to the line joining the object's(planet's) location and sun and the object has radial velocity because radial velocity is defined as the component of the object's velocity that points in the direction of the radius connecting the object and the point.



        And if you look at what you are calling as tangential velocity you would notice that this component, i.e perpendicular to line joining planet and sun, isn't tangential to the ellipse.It's just perpendicular to the line joining the planet and the ellipse.



        Conclusion: The planet always has velocity tangential to the ellipse and the velocity perpendicular to the line joining planet and object isn't tangential to the ellipse at all instants.



        Note:



        Although in your question you particularly ask about momentum I just used the term velocity rather than momentum because I think it is easier to understand this way.



        If you need momentum at any instant just multiply total velocity with mass(p=mv)



        References:



        https://en.wikipedia.org/wiki/Radial_velocity



        https://www.youtube.com/watch?v=Pa3Of_3vpRc







        share|cite|improve this answer










        New contributor




        ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|cite|improve this answer



        share|cite|improve this answer








        edited 2 hours ago





















        New contributor




        ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered 3 hours ago









        ayc

        916




        916




        New contributor




        ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        ayc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.




















            Mike Victor is a new contributor. Be nice, and check out our Code of Conduct.









             

            draft saved


            draft discarded


















            Mike Victor is a new contributor. Be nice, and check out our Code of Conduct.












            Mike Victor is a new contributor. Be nice, and check out our Code of Conduct.











            Mike Victor is a new contributor. Be nice, and check out our Code of Conduct.













             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f436907%2fis-the-person-in-this-video-explaining-it-wrong%23new-answer', 'question_page');

            );

            Post as a guest













































































            Comments

            Popular posts from this blog

            What does second last employer means? [closed]

            List of Gilmore Girls characters

            Confectionery