How to control a procedural texture with an empty?
Clash Royale CLAN TAG#URR8PPP
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0;
up vote
1
down vote
favorite
I´d like to -somehow- assign an empty object to drive a procedural texture. The idea is that I can rotate, scale or move the empty and thus it transform the procedural texture (bricks, noise texture, etc..)
How can I manipulate a procedural texture using the position of an empty?
Thanks.
procedural texture-coordinates
add a comment |Â
up vote
1
down vote
favorite
I´d like to -somehow- assign an empty object to drive a procedural texture. The idea is that I can rotate, scale or move the empty and thus it transform the procedural texture (bricks, noise texture, etc..)
How can I manipulate a procedural texture using the position of an empty?
Thanks.
procedural texture-coordinates
2
try with the Object output of the Texture Coordinate, maybe you'll get what you want
– moonboots
1 hour ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I´d like to -somehow- assign an empty object to drive a procedural texture. The idea is that I can rotate, scale or move the empty and thus it transform the procedural texture (bricks, noise texture, etc..)
How can I manipulate a procedural texture using the position of an empty?
Thanks.
procedural texture-coordinates
I´d like to -somehow- assign an empty object to drive a procedural texture. The idea is that I can rotate, scale or move the empty and thus it transform the procedural texture (bricks, noise texture, etc..)
How can I manipulate a procedural texture using the position of an empty?
Thanks.
procedural texture-coordinates
procedural texture-coordinates
asked 1 hour ago
Pierre Schiller
1749
1749
2
try with the Object output of the Texture Coordinate, maybe you'll get what you want
– moonboots
1 hour ago
add a comment |Â
2
try with the Object output of the Texture Coordinate, maybe you'll get what you want
– moonboots
1 hour ago
2
2
try with the Object output of the Texture Coordinate, maybe you'll get what you want
– moonboots
1 hour ago
try with the Object output of the Texture Coordinate, maybe you'll get what you want
– moonboots
1 hour ago
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
3
down vote
As @moonboots has commented, you've already got it.. and just done a bit too much?
This setup puts the texture into the Empty's object space, so transforms on the Empty will transform the texture.
add a comment |Â
up vote
1
down vote
It is often helpful to debug the procedural node coordinates with a setup like
As x,y,z get mapped into rgb. Here you can visualize the difference between all the different coordinate outputs, as well as check the correct transformation. As moonboots pointed out, the "Object" output works best for what you are trying to achieve.
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
As @moonboots has commented, you've already got it.. and just done a bit too much?
This setup puts the texture into the Empty's object space, so transforms on the Empty will transform the texture.
add a comment |Â
up vote
3
down vote
As @moonboots has commented, you've already got it.. and just done a bit too much?
This setup puts the texture into the Empty's object space, so transforms on the Empty will transform the texture.
add a comment |Â
up vote
3
down vote
up vote
3
down vote
As @moonboots has commented, you've already got it.. and just done a bit too much?
This setup puts the texture into the Empty's object space, so transforms on the Empty will transform the texture.
As @moonboots has commented, you've already got it.. and just done a bit too much?
This setup puts the texture into the Empty's object space, so transforms on the Empty will transform the texture.
answered 1 hour ago


Robin Betts
3,7831623
3,7831623
add a comment |Â
add a comment |Â
up vote
1
down vote
It is often helpful to debug the procedural node coordinates with a setup like
As x,y,z get mapped into rgb. Here you can visualize the difference between all the different coordinate outputs, as well as check the correct transformation. As moonboots pointed out, the "Object" output works best for what you are trying to achieve.
add a comment |Â
up vote
1
down vote
It is often helpful to debug the procedural node coordinates with a setup like
As x,y,z get mapped into rgb. Here you can visualize the difference between all the different coordinate outputs, as well as check the correct transformation. As moonboots pointed out, the "Object" output works best for what you are trying to achieve.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
It is often helpful to debug the procedural node coordinates with a setup like
As x,y,z get mapped into rgb. Here you can visualize the difference between all the different coordinate outputs, as well as check the correct transformation. As moonboots pointed out, the "Object" output works best for what you are trying to achieve.
It is often helpful to debug the procedural node coordinates with a setup like
As x,y,z get mapped into rgb. Here you can visualize the difference between all the different coordinate outputs, as well as check the correct transformation. As moonboots pointed out, the "Object" output works best for what you are trying to achieve.
edited 47 mins ago
answered 1 hour ago
miceterminator
1,57321123
1,57321123
add a comment |Â
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fblender.stackexchange.com%2fquestions%2f119626%2fhow-to-control-a-procedural-texture-with-an-empty%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
2
try with the Object output of the Texture Coordinate, maybe you'll get what you want
– moonboots
1 hour ago