Function[u, g[u]] vs. Function[u, g[u]] : In which the behavior between differs?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
2
down vote

favorite












Function[u, g[u]] 
Function[u, g[u]]


The documentation lists both variants without specifying the difference.
Does the behavior differ in some circumstances?






function-construction documentation







share|improve this question

















  • 1




    No difference, just some flexibility in the syntax for single-variable functions
    – Michael E2
    25 mins ago














up vote
2
down vote

favorite












Function[u, g[u]] 
Function[u, g[u]]


The documentation lists both variants without specifying the difference.
Does the behavior differ in some circumstances?






function-construction documentation







share|improve this question

















  • 1




    No difference, just some flexibility in the syntax for single-variable functions
    – Michael E2
    25 mins ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











Function[u, g[u]] 
Function[u, g[u]]


The documentation lists both variants without specifying the difference.
Does the behavior differ in some circumstances?






function-construction documentation







share|improve this question













Function[u, g[u]] 
Function[u, g[u]]


The documentation lists both variants without specifying the difference.
Does the behavior differ in some circumstances?






function-construction documentation




function-construction documentation






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 44 mins ago









Slepecky Mamut

31818




31818







  • 1




    No difference, just some flexibility in the syntax for single-variable functions
    – Michael E2
    25 mins ago












  • 1




    No difference, just some flexibility in the syntax for single-variable functions
    – Michael E2
    25 mins ago







1




1




No difference, just some flexibility in the syntax for single-variable functions
– Michael E2
25 mins ago




No difference, just some flexibility in the syntax for single-variable functions
– Michael E2
25 mins ago










1 Answer
1






active

oldest

votes

















up vote
3
down vote













There is no functional difference between Function[u, g[u]] and
Function[u, g[u]]. The following difference in speed is small but consistent on my machine (MacBook Pro):



foo = Range[5*10^6];
foo[[1]] = 1.;

Function[x, x] /@ foo; // RepeatedTiming
Function[x, x] /@ foo; // RepeatedTiming
(*
 2.4, Null
 2.0, Null
*)


It's a small difference compared to the execution time of more complicated function bodies.






share|improve this answer




















    Your Answer




    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "387"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: false,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f184384%2ffunctionu-gu-vs-functionu-gu-in-which-the-behavior-between-differ%23new-answer', 'question_page');

    );

    Post as a guest

















    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote













    There is no functional difference between Function[u, g[u]] and
    Function[u, g[u]]. The following difference in speed is small but consistent on my machine (MacBook Pro):



    foo = Range[5*10^6];
    foo[[1]] = 1.;

    Function[x, x] /@ foo; // RepeatedTiming
    Function[x, x] /@ foo; // RepeatedTiming
    (*
     2.4, Null
     2.0, Null
    *)


    It's a small difference compared to the execution time of more complicated function bodies.






    share|improve this answer
























      up vote
      3
      down vote













      There is no functional difference between Function[u, g[u]] and
      Function[u, g[u]]. The following difference in speed is small but consistent on my machine (MacBook Pro):



      foo = Range[5*10^6];
      foo[[1]] = 1.;

      Function[x, x] /@ foo; // RepeatedTiming
      Function[x, x] /@ foo; // RepeatedTiming
      (*
       2.4, Null
       2.0, Null
      *)


      It's a small difference compared to the execution time of more complicated function bodies.






      share|improve this answer






















        up vote
        3
        down vote










        up vote
        3
        down vote









        There is no functional difference between Function[u, g[u]] and
        Function[u, g[u]]. The following difference in speed is small but consistent on my machine (MacBook Pro):



        foo = Range[5*10^6];
        foo[[1]] = 1.;

        Function[x, x] /@ foo; // RepeatedTiming
        Function[x, x] /@ foo; // RepeatedTiming
        (*
         2.4, Null
         2.0, Null
        *)


        It's a small difference compared to the execution time of more complicated function bodies.






        share|improve this answer












        There is no functional difference between Function[u, g[u]] and
        Function[u, g[u]]. The following difference in speed is small but consistent on my machine (MacBook Pro):



        foo = Range[5*10^6];
        foo[[1]] = 1.;

        Function[x, x] /@ foo; // RepeatedTiming
        Function[x, x] /@ foo; // RepeatedTiming
        (*
         2.4, Null
         2.0, Null
        *)


        It's a small difference compared to the execution time of more complicated function bodies.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 14 mins ago









        Michael E2

        142k11192458




        142k11192458



























             

            draft saved


            draft discarded















































             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f184384%2ffunctionu-gu-vs-functionu-gu-in-which-the-behavior-between-differ%23new-answer', 'question_page');

            );

            Post as a guest
































































            Comments

            Post a Comment

            Popular posts from this blog

            What does second last employer means? [closed]

            Image
            Clash Royale CLAN TAG #URR8PPP .everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0; up vote -3 down vote favorite Say, for example I have worked in the following companies, Company A => 2010 - 2011 Company B => 2011 - 2012 Company C => 2012 - Till Date Company D => Have offer Now assume Company D is asking to submit documents from my second last employer. So from the list of companies given, which company would be qualified as second last employer? software-industry employer share | improve this question asked Aug 10 '14 at 5:16 Rajaprabhu Aravindasamy 559 1 6 13 closed as off-topic by Jim G., jmort253 ♦ Aug 11 '14 at 1:58 This question appears to be off-topic. The users who voted to close gave this specific reason: "Questions seeking advice on company-specific regulations, agreements, or policies should be directed to your manager or HR department. Questions that address...
            Read more

            List of Gilmore Girls characters

            Image
            The season three cast—(Back row): Lane, Michel, Paris, Emily, Richard, Sookie, Miss Patty, Kirk; Front row: Jess, Luke, Lorelai, Rory, Dean This is a list of characters for the comedy-drama television series Gilmore Girls . Contents 1 Main characters 1.1 Lorelai Gilmore 1.2 Rory Gilmore 1.3 Sookie St. James 1.4 Lane Kim 1.5 Michel Gerard 1.6 Luke Danes 1.7 Emily Gilmore 1.8 Richard Gilmore 1.9 Paris Geller 1.10 Dean Forester 1.11 Jess Mariano 1.12 Kirk Gleason 1.13 Jason Stiles 1.14 Logan Huntzberger 2 Major recurring characters 2.1 Christopher Hayden 2.2 Jackson Belleville 2.3 Mrs. Kim 2.4 Tristin DuGray 2.5 Max Medina 2.6 Taylor Doose 2.7 Dave Rygalski 2.8 Marty 3 Recurring characters 3.1 Stars Hollow 3.2 Chilton 3.3 Yale 3.4 Other 4 Notable guest stars 5 Unseen characters 6 Notes 7 References Main characters Actor Character Appearances Season 1 Season 2 Season 3 Season 4 Season 5 Season 6 Season 7 A Year in the Life Lauren Graham Lorelai Gilmore...
            Read more

            Confectionery

            Image
            Prepared foods made with a lot of sugar or other cabohydrates "Sweetmeat" redirects here. For the racehorse, see Sweetmeat (horse). Not to be confused with Sweetbread. This Kransekake is a traditional Scandinavian baker's confection. Confectionery is the art of making confections , which are food items that are rich in sugar and carbohydrates. Exact definitions are difficult. [1] In general, though, confectionery is divided into two broad and somewhat overlapping categories, bakers' confections and sugar confections. [2] Bakers' confectionery, also called flour confections , includes principally sweet pastries, cakes, and similar baked goods. Sugar confectionery includes candies ( sweets in British English), candied nuts, chocolates, chewing gum, bubble gum, pastillage, and other confections that are made primarily of sugar. In some cases, chocolate confections (confections made of chocolate) are treated as a separate category, as are sugar-free versions of ...
            Read more