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What is a term for an operator/function in which the order of parameters makes no difference?
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I'm trying to recall the term for an operator/function where f(a, b) = f(b, a). For example, a + b = b + a for all values of a and b. However a - b != b - a unless a = b.
terminology mathematics computing
asked 4 hours ago
JohnLBevan
355213
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I'm trying to recall the term for an operator/function where f(a, b) = f(b, a). For example, a + b = b + a for all values of a and b. However a - b != b - a unless a = b.
terminology mathematics computing
asked 4 hours ago
JohnLBevan
355213
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I'm trying to recall the term for an operator/function where f(a, b) = f(b, a). For example, a + b = b + a for all values of a and b. However a - b != b - a unless a = b.
terminology mathematics computing
asked 4 hours ago
JohnLBevan
355213
I'm trying to recall the term for an operator/function where f(a, b) = f(b, a). For example, a + b = b + a for all values of a and b. However a - b != b - a unless a = b.
terminology mathematics computing
terminology mathematics computing
asked 4 hours ago
JohnLBevan
355213
asked 4 hours ago
JohnLBevan
355213
asked 4 hours ago
JohnLBevan
355213
asked 4 hours ago
JohnLBevan
355213
asked 4 hours ago
JohnLBevan
355213
355213
add a comment |Â
add a comment |Â
3 Answers
3
active
oldest
votes
up vote
5
down vote
accepted
I think the word you are looking for is commutative:
(mathematics, of a binary operation) Such that the order in which the operands are taken does not affect their image under the operation.
Addition on the real numbers is commutative because for any real
numbers s , t, it is true that
s + t = t + s.
Addition and multiplication are commutative operations but subtraction and division are not.
answered 4 hours ago
Toby Speight
639412
1
That's the term for operators, but not for functions. Mathematicians say symmetric functions.
– Peter Shor
1 hour ago
Thanks @Peter - if you have a suitable reference, consider adding an answer, or editing mine to extend it.
– Toby Speight
1 hour ago
add a comment |Â
up vote
3
down vote
Commutative Operation
Any operation ⊕ for which a⊕b = b⊕a for all values of a and b.
Addition and multiplication are both commutative. Subtraction,
division, and composition of functions are not. For example, 5 + 6 = 6
+ 5 but 5 – 6 ≠6 – 5.
answered 4 hours ago
michael.hor257k
9,05121534
add a comment |Â
up vote
1
down vote
You ask for the word for operators or functions. The word mathematicians generally use is different in the two cases.
A function which does not depend on the order of the arguments is usually called a symmetric function. So f(a,b,c) = f(b,a,c) = f(b,c,a), although the word commutative is occasionally used.
And as the other answers say, an operator which does not depend on the order of the operands is called a commutative operator. So a·b=b·a.
answered 1 hour ago
Peter Shor
60.1k5115212
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
I think the word you are looking for is commutative:
(mathematics, of a binary operation) Such that the order in which the operands are taken does not affect their image under the operation.
Addition on the real numbers is commutative because for any real
numbers s , t, it is true that
s + t = t + s.
Addition and multiplication are commutative operations but subtraction and division are not.
answered 4 hours ago
Toby Speight
639412
1
That's the term for operators, but not for functions. Mathematicians say symmetric functions.
– Peter Shor
1 hour ago
Thanks @Peter - if you have a suitable reference, consider adding an answer, or editing mine to extend it.
– Toby Speight
1 hour ago
add a comment |Â
up vote
5
down vote
accepted
I think the word you are looking for is commutative:
(mathematics, of a binary operation) Such that the order in which the operands are taken does not affect their image under the operation.
Addition on the real numbers is commutative because for any real
numbers s , t, it is true that
s + t = t + s.
Addition and multiplication are commutative operations but subtraction and division are not.
answered 4 hours ago
Toby Speight
639412
1
That's the term for operators, but not for functions. Mathematicians say symmetric functions.
– Peter Shor
1 hour ago
Thanks @Peter - if you have a suitable reference, consider adding an answer, or editing mine to extend it.
– Toby Speight
1 hour ago
add a comment |Â
up vote
5
down vote
accepted
up vote
5
down vote
accepted
I think the word you are looking for is commutative:
(mathematics, of a binary operation) Such that the order in which the operands are taken does not affect their image under the operation.
Addition on the real numbers is commutative because for any real
numbers s , t, it is true that
s + t = t + s.
Addition and multiplication are commutative operations but subtraction and division are not.
answered 4 hours ago
Toby Speight
639412
I think the word you are looking for is commutative:
(mathematics, of a binary operation) Such that the order in which the operands are taken does not affect their image under the operation.
Addition on the real numbers is commutative because for any real
numbers s , t, it is true that
s + t = t + s.
Addition and multiplication are commutative operations but subtraction and division are not.
answered 4 hours ago
Toby Speight
639412
answered 4 hours ago
Toby Speight
639412
answered 4 hours ago
Toby Speight
639412
answered 4 hours ago
Toby Speight
639412
639412
1
That's the term for operators, but not for functions. Mathematicians say symmetric functions.
– Peter Shor
1 hour ago
Thanks @Peter - if you have a suitable reference, consider adding an answer, or editing mine to extend it.
– Toby Speight
1 hour ago
add a comment |Â
1
That's the term for operators, but not for functions. Mathematicians say symmetric functions.
– Peter Shor
1 hour ago
Thanks @Peter - if you have a suitable reference, consider adding an answer, or editing mine to extend it.
– Toby Speight
1 hour ago
1
1
That's the term for operators, but not for functions. Mathematicians say symmetric functions.
– Peter Shor
1 hour ago
That's the term for operators, but not for functions. Mathematicians say symmetric functions.
– Peter Shor
1 hour ago
Thanks @Peter - if you have a suitable reference, consider adding an answer, or editing mine to extend it.
– Toby Speight
1 hour ago
Thanks @Peter - if you have a suitable reference, consider adding an answer, or editing mine to extend it.
– Toby Speight
1 hour ago
add a comment |Â
up vote
3
down vote
Commutative Operation
Any operation ⊕ for which a⊕b = b⊕a for all values of a and b.
Addition and multiplication are both commutative. Subtraction,
division, and composition of functions are not. For example, 5 + 6 = 6
+ 5 but 5 – 6 ≠6 – 5.
answered 4 hours ago
michael.hor257k
9,05121534
add a comment |Â
up vote
3
down vote
Commutative Operation
Any operation ⊕ for which a⊕b = b⊕a for all values of a and b.
Addition and multiplication are both commutative. Subtraction,
division, and composition of functions are not. For example, 5 + 6 = 6
+ 5 but 5 – 6 ≠6 – 5.
answered 4 hours ago
michael.hor257k
9,05121534
add a comment |Â
up vote
3
down vote
up vote
3
down vote
Commutative Operation
Any operation ⊕ for which a⊕b = b⊕a for all values of a and b.
Addition and multiplication are both commutative. Subtraction,
division, and composition of functions are not. For example, 5 + 6 = 6
+ 5 but 5 – 6 ≠6 – 5.
answered 4 hours ago
michael.hor257k
9,05121534
Commutative Operation
Any operation ⊕ for which a⊕b = b⊕a for all values of a and b.
Addition and multiplication are both commutative. Subtraction,
division, and composition of functions are not. For example, 5 + 6 = 6
+ 5 but 5 – 6 ≠6 – 5.
answered 4 hours ago
michael.hor257k
9,05121534
answered 4 hours ago
michael.hor257k
9,05121534
answered 4 hours ago
michael.hor257k
9,05121534
answered 4 hours ago
michael.hor257k
9,05121534
9,05121534
add a comment |Â
add a comment |Â
up vote
1
down vote
You ask for the word for operators or functions. The word mathematicians generally use is different in the two cases.
A function which does not depend on the order of the arguments is usually called a symmetric function. So f(a,b,c) = f(b,a,c) = f(b,c,a), although the word commutative is occasionally used.
And as the other answers say, an operator which does not depend on the order of the operands is called a commutative operator. So a·b=b·a.
answered 1 hour ago
Peter Shor
60.1k5115212
add a comment |Â
up vote
1
down vote
You ask for the word for operators or functions. The word mathematicians generally use is different in the two cases.
A function which does not depend on the order of the arguments is usually called a symmetric function. So f(a,b,c) = f(b,a,c) = f(b,c,a), although the word commutative is occasionally used.
And as the other answers say, an operator which does not depend on the order of the operands is called a commutative operator. So a·b=b·a.
answered 1 hour ago
Peter Shor
60.1k5115212
add a comment |Â
up vote
1
down vote
up vote
1
down vote
You ask for the word for operators or functions. The word mathematicians generally use is different in the two cases.
A function which does not depend on the order of the arguments is usually called a symmetric function. So f(a,b,c) = f(b,a,c) = f(b,c,a), although the word commutative is occasionally used.
And as the other answers say, an operator which does not depend on the order of the operands is called a commutative operator. So a·b=b·a.
answered 1 hour ago
Peter Shor
60.1k5115212
You ask for the word for operators or functions. The word mathematicians generally use is different in the two cases.
A function which does not depend on the order of the arguments is usually called a symmetric function. So f(a,b,c) = f(b,a,c) = f(b,c,a), although the word commutative is occasionally used.
And as the other answers say, an operator which does not depend on the order of the operands is called a commutative operator. So a·b=b·a.
answered 1 hour ago
Peter Shor
60.1k5115212
answered 1 hour ago
Peter Shor
60.1k5115212
answered 1 hour ago
Peter Shor
60.1k5115212
answered 1 hour ago
Peter Shor
60.1k5115212
60.1k5115212
add a comment |Â
add a comment |Â
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