How to move files from subdirectories that have the same directory name to its relative upper/parent directory?

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up vote
1
down vote

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So, I have a directory structure like this:

parent/
├── sub1
│   └── source
│   └── file1
│ └── file2
├── sub2
│   └── sub2.1
│   └── source
│   └── something1
│ └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

I want to move all files (with different filename) from all directories named source to its relative upper/parent directory. So, the result should be something like this:

parent2/
├── sub1
│   ├── file1
│ ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│ ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

Is there an easy way (one liner) to accomplish this, maybe using the find command?
Preferably one that's not too complex for me to understand. :D I'm quite new to Linux.

command-line bash 18.04 directory

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edited 3 hours ago

asked 4 hours ago

Lukman Hakim

62

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add a comment | 

up vote
1
down vote

favorite

So, I have a directory structure like this:

parent/
├── sub1
│   └── source
│   └── file1
│ └── file2
├── sub2
│   └── sub2.1
│   └── source
│   └── something1
│ └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

I want to move all files (with different filename) from all directories named source to its relative upper/parent directory. So, the result should be something like this:

parent2/
├── sub1
│   ├── file1
│ ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│ ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

Is there an easy way (one liner) to accomplish this, maybe using the find command?
Preferably one that's not too complex for me to understand. :D I'm quite new to Linux.

command-line bash 18.04 directory

share|improve this question

edited 3 hours ago

asked 4 hours ago

Lukman Hakim

62

New contributor

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

up vote
1
down vote

favorite

up vote
1
down vote

favorite

So, I have a directory structure like this:

parent/
├── sub1
│   └── source
│   └── file1
│ └── file2
├── sub2
│   └── sub2.1
│   └── source
│   └── something1
│ └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

I want to move all files (with different filename) from all directories named source to its relative upper/parent directory. So, the result should be something like this:

parent2/
├── sub1
│   ├── file1
│ ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│ ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

Is there an easy way (one liner) to accomplish this, maybe using the find command?
Preferably one that's not too complex for me to understand. :D I'm quite new to Linux.

command-line bash 18.04 directory

share|improve this question

edited 3 hours ago

asked 4 hours ago

Lukman Hakim

62

New contributor

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

So, I have a directory structure like this:

parent/
├── sub1
│   └── source
│   └── file1
│ └── file2
├── sub2
│   └── sub2.1
│   └── source
│   └── something1
│ └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

I want to move all files (with different filename) from all directories named source to its relative upper/parent directory. So, the result should be something like this:

parent2/
├── sub1
│   ├── file1
│ ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│ ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

Is there an easy way (one liner) to accomplish this, maybe using the find command?
Preferably one that's not too complex for me to understand. :D I'm quite new to Linux.

command-line bash 18.04 directory

command-line bash 18.04 directory

share|improve this question

edited 3 hours ago

asked 4 hours ago

Lukman Hakim

62

New contributor

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 3 hours ago

asked 4 hours ago

Lukman Hakim

62

New contributor

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

share|improve this question

edited 3 hours ago

edited 3 hours ago

edited 3 hours ago

asked 4 hours ago

Lukman Hakim

62

New contributor

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 4 hours ago

Lukman Hakim

62

asked 4 hours ago

Lukman Hakim

62

62

New contributor

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

New contributor

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Lukman Hakim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

add a comment | 

3 Answers
3

active

oldest

votes

up vote
3
down vote

A simple for loop with the globstar option enabled (run shopt -s globstar to do that) will do the job:

for i in ./**/source/; do
 mv "$i"* "$i%source/"
done

The GNU parallel equivalent for this loop is:

parallel mv * /// ::: ./**/source/

Explanation

globstar

If set, the pattern ** used in a pathname expansion context will match all files and zero or more directories
and subdirectories. If the pattern is followed by a /, only directories and subdirectories match.

./**/source/ matches every directory named source in and under the current directory, the mv command moves every file from inside the directory to its parent directory – $i%source/ is a parameter expansion which removes the string source/ from the end of the (path) string.

Example run

$ tree
.
├── sub1
│   └── source
│   ├── file1
│   └── file2
├── sub2
│   └── sub2.1
│   └── source
│   ├── something1
│   └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

$ for i in ./**/source/; do mv "$i"* "$i%source/"; done
$ tree
.
├── sub1
│   ├── file1
│   ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│   ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

share|improve this answer

edited 1 hour ago

answered 3 hours ago

dessert

20.4k55896

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I tried. works only in one dir `$ for i in ./**/source/; do echo "$i" ; done ./sub1/source/'
  – Vijay
  1 hour ago
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @dessert globstar option was not enabled. Thanks.
  – Vijay
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
0
down vote

You can use the below code to get what you want:

dir=$(find . -name 'source' | sed s:source::)
echo $dir
for path in $dir; do
 mv "$path"source/* "$path"
done

The find command returns the directory path from parent to source directory. In this find . -name 'source' '.' represents the parent directory and 'source' represents the subdirectory you want to find.

The sed command removes source from the result of find command.

And the rest is just iteration (for) and move command (mv)

share|improve this answer

edited 13 mins ago

wjandrea

7,52642257

answered 21 mins ago

Sathish Kanna

616

add a comment | 

up vote
0
down vote

If you want a find solution, you could use this:

find parent -name "source" -type d -exec bash -c 'cd "$1"; mv * ..' bash ;

Explanation:

• 
  find parent -name "source" -type d - For each directory named source in parent...


• 
  -exec bash -c '...' bash ; - Call Bash with bash as $0 and the directory path as $1
  


• 
  cd "$1"; mv * .. - cd into the directory; move all its contents up one level.
  
  
  • Alternative: mv "$1"/* "$1/.."
    
  
  

This is more or less based on dessert's answer.

share|improve this answer

edited 3 mins ago

answered 15 mins ago

wjandrea

7,52642257

add a comment | 

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
3
down vote

A simple for loop with the globstar option enabled (run shopt -s globstar to do that) will do the job:

for i in ./**/source/; do
 mv "$i"* "$i%source/"
done

The GNU parallel equivalent for this loop is:

parallel mv * /// ::: ./**/source/

Explanation

globstar

If set, the pattern ** used in a pathname expansion context will match all files and zero or more directories
and subdirectories. If the pattern is followed by a /, only directories and subdirectories match.

./**/source/ matches every directory named source in and under the current directory, the mv command moves every file from inside the directory to its parent directory – $i%source/ is a parameter expansion which removes the string source/ from the end of the (path) string.

Example run

$ tree
.
├── sub1
│   └── source
│   ├── file1
│   └── file2
├── sub2
│   └── sub2.1
│   └── source
│   ├── something1
│   └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

$ for i in ./**/source/; do mv "$i"* "$i%source/"; done
$ tree
.
├── sub1
│   ├── file1
│   ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│   ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

share|improve this answer

edited 1 hour ago

answered 3 hours ago

dessert

20.4k55896

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I tried. works only in one dir `$ for i in ./**/source/; do echo "$i" ; done ./sub1/source/'
  – Vijay
  1 hour ago
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @dessert globstar option was not enabled. Thanks.
  – Vijay
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

A simple for loop with the globstar option enabled (run shopt -s globstar to do that) will do the job:

for i in ./**/source/; do
 mv "$i"* "$i%source/"
done

The GNU parallel equivalent for this loop is:

parallel mv * /// ::: ./**/source/

Explanation

globstar

If set, the pattern ** used in a pathname expansion context will match all files and zero or more directories
and subdirectories. If the pattern is followed by a /, only directories and subdirectories match.

./**/source/ matches every directory named source in and under the current directory, the mv command moves every file from inside the directory to its parent directory – $i%source/ is a parameter expansion which removes the string source/ from the end of the (path) string.

Example run

$ tree
.
├── sub1
│   └── source
│   ├── file1
│   └── file2
├── sub2
│   └── sub2.1
│   └── source
│   ├── something1
│   └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

$ for i in ./**/source/; do mv "$i"* "$i%source/"; done
$ tree
.
├── sub1
│   ├── file1
│   ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│   ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

share|improve this answer

edited 1 hour ago

answered 3 hours ago

dessert

20.4k55896

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I tried. works only in one dir `$ for i in ./**/source/; do echo "$i" ; done ./sub1/source/'
  – Vijay
  1 hour ago
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @dessert globstar option was not enabled. Thanks.
  – Vijay
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

up vote
3
down vote

A simple for loop with the globstar option enabled (run shopt -s globstar to do that) will do the job:

for i in ./**/source/; do
 mv "$i"* "$i%source/"
done

The GNU parallel equivalent for this loop is:

parallel mv * /// ::: ./**/source/

Explanation

globstar

If set, the pattern ** used in a pathname expansion context will match all files and zero or more directories
and subdirectories. If the pattern is followed by a /, only directories and subdirectories match.

./**/source/ matches every directory named source in and under the current directory, the mv command moves every file from inside the directory to its parent directory – $i%source/ is a parameter expansion which removes the string source/ from the end of the (path) string.

Example run

$ tree
.
├── sub1
│   └── source
│   ├── file1
│   └── file2
├── sub2
│   └── sub2.1
│   └── source
│   ├── something1
│   └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

$ for i in ./**/source/; do mv "$i"* "$i%source/"; done
$ tree
.
├── sub1
│   ├── file1
│   ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│   ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

share|improve this answer

edited 1 hour ago

answered 3 hours ago

dessert

20.4k55896

A simple for loop with the globstar option enabled (run shopt -s globstar to do that) will do the job:

for i in ./**/source/; do
 mv "$i"* "$i%source/"
done

The GNU parallel equivalent for this loop is:

parallel mv * /// ::: ./**/source/

Explanation

globstar

If set, the pattern ** used in a pathname expansion context will match all files and zero or more directories
and subdirectories. If the pattern is followed by a /, only directories and subdirectories match.

./**/source/ matches every directory named source in and under the current directory, the mv command moves every file from inside the directory to its parent directory – $i%source/ is a parameter expansion which removes the string source/ from the end of the (path) string.

Example run

$ tree
.
├── sub1
│   └── source
│   ├── file1
│   └── file2
├── sub2
│   └── sub2.1
│   └── source
│   ├── something1
│   └── something2
└── sub3
 └── sub3.1
 └── sub3.1.1
 └── source
 └── other.zip

$ for i in ./**/source/; do mv "$i"* "$i%source/"; done
$ tree
.
├── sub1
│   ├── file1
│   ├── file2
│   └── source
├── sub2
│   └── sub2.1
│   ├── something1
│   ├── something2
│   └── source
└── sub3
 └── sub3.1
 └── sub3.1.1
 ├── other.zip
 └── source

share|improve this answer

edited 1 hour ago

answered 3 hours ago

dessert

20.4k55896

share|improve this answer

share|improve this answer

edited 1 hour ago

edited 1 hour ago

edited 1 hour ago

answered 3 hours ago

dessert

20.4k55896

answered 3 hours ago

dessert

20.4k55896

answered 3 hours ago

dessert

20.4k55896

20.4k55896

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I tried. works only in one dir `$ for i in ./**/source/; do echo "$i" ; done ./sub1/source/'
  – Vijay
  1 hour ago
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @dessert globstar option was not enabled. Thanks.
  – Vijay
  1 hour ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  I tried. works only in one dir `$ for i in ./**/source/; do echo "$i" ; done ./sub1/source/'
  – Vijay
  1 hour ago
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @dessert globstar option was not enabled. Thanks.
  – Vijay
  1 hour ago
  

  
  
  
  

I tried. works only in one dir `$ for i in ./**/source/; do echo "$i" ; done ./sub1/source/'
– Vijay
1 hour ago

I tried. works only in one dir `$ for i in ./**/source/; do echo "$i" ; done ./sub1/source/'
– Vijay
1 hour ago

1

1

@dessert globstar option was not enabled. Thanks.
– Vijay
1 hour ago

@dessert globstar option was not enabled. Thanks.
– Vijay
1 hour ago

add a comment | 

up vote
0
down vote

You can use the below code to get what you want:

dir=$(find . -name 'source' | sed s:source::)
echo $dir
for path in $dir; do
 mv "$path"source/* "$path"
done

The find command returns the directory path from parent to source directory. In this find . -name 'source' '.' represents the parent directory and 'source' represents the subdirectory you want to find.

The sed command removes source from the result of find command.

And the rest is just iteration (for) and move command (mv)

share|improve this answer

edited 13 mins ago

wjandrea

7,52642257

answered 21 mins ago

Sathish Kanna

616

add a comment | 

up vote
0
down vote

You can use the below code to get what you want:

dir=$(find . -name 'source' | sed s:source::)
echo $dir
for path in $dir; do
 mv "$path"source/* "$path"
done

The find command returns the directory path from parent to source directory. In this find . -name 'source' '.' represents the parent directory and 'source' represents the subdirectory you want to find.

The sed command removes source from the result of find command.

And the rest is just iteration (for) and move command (mv)

share|improve this answer

edited 13 mins ago

wjandrea

7,52642257

answered 21 mins ago

Sathish Kanna

616

add a comment | 

up vote
0
down vote

up vote
0
down vote

You can use the below code to get what you want:

dir=$(find . -name 'source' | sed s:source::)
echo $dir
for path in $dir; do
 mv "$path"source/* "$path"
done

The find command returns the directory path from parent to source directory. In this find . -name 'source' '.' represents the parent directory and 'source' represents the subdirectory you want to find.

The sed command removes source from the result of find command.

And the rest is just iteration (for) and move command (mv)

share|improve this answer

edited 13 mins ago

wjandrea

7,52642257

answered 21 mins ago

Sathish Kanna

616

You can use the below code to get what you want:

dir=$(find . -name 'source' | sed s:source::)
echo $dir
for path in $dir; do
 mv "$path"source/* "$path"
done

The find command returns the directory path from parent to source directory. In this find . -name 'source' '.' represents the parent directory and 'source' represents the subdirectory you want to find.

The sed command removes source from the result of find command.

And the rest is just iteration (for) and move command (mv)

share|improve this answer

edited 13 mins ago

wjandrea

7,52642257

answered 21 mins ago

Sathish Kanna

616

share|improve this answer

share|improve this answer

edited 13 mins ago

wjandrea

7,52642257

edited 13 mins ago

wjandrea

7,52642257

edited 13 mins ago

wjandrea

7,52642257

7,52642257

answered 21 mins ago

Sathish Kanna

616

answered 21 mins ago

Sathish Kanna

616

answered 21 mins ago

Sathish Kanna

616

616

add a comment | 

add a comment | 

up vote
0
down vote

If you want a find solution, you could use this:

find parent -name "source" -type d -exec bash -c 'cd "$1"; mv * ..' bash ;

Explanation:

• 
  find parent -name "source" -type d - For each directory named source in parent...


• 
  -exec bash -c '...' bash ; - Call Bash with bash as $0 and the directory path as $1
  


• 
  cd "$1"; mv * .. - cd into the directory; move all its contents up one level.
  
  
  • Alternative: mv "$1"/* "$1/.."
    
  
  

This is more or less based on dessert's answer.

share|improve this answer

edited 3 mins ago

answered 15 mins ago

wjandrea

7,52642257

add a comment | 

up vote
0
down vote

If you want a find solution, you could use this:

find parent -name "source" -type d -exec bash -c 'cd "$1"; mv * ..' bash ;

Explanation:

• 
  find parent -name "source" -type d - For each directory named source in parent...


• 
  -exec bash -c '...' bash ; - Call Bash with bash as $0 and the directory path as $1
  


• 
  cd "$1"; mv * .. - cd into the directory; move all its contents up one level.
  
  
  • Alternative: mv "$1"/* "$1/.."
    
  
  

This is more or less based on dessert's answer.

share|improve this answer

edited 3 mins ago

answered 15 mins ago

wjandrea

7,52642257

add a comment | 

up vote
0
down vote

up vote
0
down vote

If you want a find solution, you could use this:

find parent -name "source" -type d -exec bash -c 'cd "$1"; mv * ..' bash ;

Explanation:

• 
  find parent -name "source" -type d - For each directory named source in parent...


• 
  -exec bash -c '...' bash ; - Call Bash with bash as $0 and the directory path as $1
  


• 
  cd "$1"; mv * .. - cd into the directory; move all its contents up one level.
  
  
  • Alternative: mv "$1"/* "$1/.."
    
  
  

This is more or less based on dessert's answer.

share|improve this answer

edited 3 mins ago

answered 15 mins ago

wjandrea

7,52642257

If you want a find solution, you could use this:

find parent -name "source" -type d -exec bash -c 'cd "$1"; mv * ..' bash ;

Explanation:

• 
  find parent -name "source" -type d - For each directory named source in parent...


• 
  -exec bash -c '...' bash ; - Call Bash with bash as $0 and the directory path as $1
  


• 
  cd "$1"; mv * .. - cd into the directory; move all its contents up one level.
  
  
  • Alternative: mv "$1"/* "$1/.."
    
  
  

This is more or less based on dessert's answer.

share|improve this answer

edited 3 mins ago

answered 15 mins ago

wjandrea

7,52642257

share|improve this answer

share|improve this answer

edited 3 mins ago

edited 3 mins ago

edited 3 mins ago

answered 15 mins ago

wjandrea

7,52642257

answered 15 mins ago

wjandrea

7,52642257

answered 15 mins ago

wjandrea

7,52642257

7,52642257

add a comment | 

add a comment | 

Lukman Hakim is a new contributor. Be nice, and check out our Code of Conduct.

 

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Lukman Hakim is a new contributor. Be nice, and check out our Code of Conduct.

Lukman Hakim is a new contributor. Be nice, and check out our Code of Conduct.

Lukman Hakim is a new contributor. Be nice, and check out our Code of Conduct.

 

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