Transferring DownValues

up vote
1
down vote

favorite

I have a code in which I define something like this:

cc[1, 2] = 1;
cc[2, 6] = 12;
cc[3, 7] = 3;

After some manipulation I define a sort of temporary variable related to cc:

cctemp[1, 2] = 13;
cctemp[2, 6] = 8;
cctemp[3, 7] = 4;
cctemp[1, 9] = 87;

There are new and old indices.

Now in my code i wanna replace cc with cctemp.
I can do the trivial assignment and i can use a Do for the substitution but its not the best. How could I realize the assignment ?

(Ps maybe something like Activate @ Inactive ....)

Thank you

edited 48 mins ago

Carl Woll

61.1k280157

asked 1 hour ago

siderius

365

2

(1) List is in the title, but it looks like you are assigning DownValues rather than making cc a list. Do you mean cc[[1, 2]] rather than cc[1, 2], etc.? (2) Why can't you just do cc[1, 2] = cctemp[1, 2] (or cc[[1,2]] = cctemp[[1, 2]]?
â€“Â march
1 hour ago

add a commentÂ |Â

up vote
1
down vote

favorite

I have a code in which I define something like this:

cc[1, 2] = 1;
cc[2, 6] = 12;
cc[3, 7] = 3;

After some manipulation I define a sort of temporary variable related to cc:

cctemp[1, 2] = 13;
cctemp[2, 6] = 8;
cctemp[3, 7] = 4;
cctemp[1, 9] = 87;

There are new and old indices.

Now in my code i wanna replace cc with cctemp.
I can do the trivial assignment and i can use a Do for the substitution but its not the best. How could I realize the assignment ?

(Ps maybe something like Activate @ Inactive ....)

Thank you

edited 48 mins ago

Carl Woll

61.1k280157

asked 1 hour ago

siderius

365

2

(1) List is in the title, but it looks like you are assigning DownValues rather than making cc a list. Do you mean cc[[1, 2]] rather than cc[1, 2], etc.? (2) Why can't you just do cc[1, 2] = cctemp[1, 2] (or cc[[1,2]] = cctemp[[1, 2]]?
â€“Â march
1 hour ago

add a commentÂ |Â

up vote
1
down vote

favorite

I have a code in which I define something like this:

cc[1, 2] = 1;
cc[2, 6] = 12;
cc[3, 7] = 3;

After some manipulation I define a sort of temporary variable related to cc:

cctemp[1, 2] = 13;
cctemp[2, 6] = 8;
cctemp[3, 7] = 4;
cctemp[1, 9] = 87;

There are new and old indices.

Now in my code i wanna replace cc with cctemp.
I can do the trivial assignment and i can use a Do for the substitution but its not the best. How could I realize the assignment ?

(Ps maybe something like Activate @ Inactive ....)

Thank you

edited 48 mins ago

Carl Woll

61.1k280157

asked 1 hour ago

siderius

365

I have a code in which I define something like this:

cc[1, 2] = 1;
cc[2, 6] = 12;
cc[3, 7] = 3;

After some manipulation I define a sort of temporary variable related to cc:

cctemp[1, 2] = 13;
cctemp[2, 6] = 8;
cctemp[3, 7] = 4;
cctemp[1, 9] = 87;

There are new and old indices.

Now in my code i wanna replace cc with cctemp.
I can do the trivial assignment and i can use a Do for the substitution but its not the best. How could I realize the assignment ?

(Ps maybe something like Activate @ Inactive ....)

Thank you

symbolic assignment built-in-symbols

edited 48 mins ago

Carl Woll

61.1k280157

asked 1 hour ago

siderius

365

edited 48 mins ago

Carl Woll

61.1k280157

asked 1 hour ago

siderius

365

edited 48 mins ago

Carl Woll

61.1k280157

edited 48 mins ago

Carl Woll

61.1k280157

edited 48 mins ago

Carl Woll

61.1k280157

asked 1 hour ago

siderius

365

asked 1 hour ago

siderius

365

asked 1 hour ago

siderius

365

2

(1) List is in the title, but it looks like you are assigning DownValues rather than making cc a list. Do you mean cc[[1, 2]] rather than cc[1, 2], etc.? (2) Why can't you just do cc[1, 2] = cctemp[1, 2] (or cc[[1,2]] = cctemp[[1, 2]]?
â€“Â march
1 hour ago

add a commentÂ |Â

2

(1) List is in the title, but it looks like you are assigning DownValues rather than making cc a list. Do you mean cc[[1, 2]] rather than cc[1, 2], etc.? (2) Why can't you just do cc[1, 2] = cctemp[1, 2] (or cc[[1,2]] = cctemp[[1, 2]]?
â€“Â march
1 hour ago

(1) List is in the title, but it looks like you are assigning DownValues rather than making cc a list. Do you mean cc[[1, 2]] rather than cc[1, 2], etc.? (2) Why can't you just do cc[1, 2] = cctemp[1, 2] (or cc[[1,2]] = cctemp[[1, 2]]?
â€“Â march
1 hour ago

add a commentÂ |Â

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

DownValues[cc] = DownValues[cctemp] /. cctemp -> cc;
cc[1, 9]

87

cc[1, 2]

13

If cc has some assignments that are not overridden by the assignments in cctemp you can use

DownValues[cc] = DeleteDuplicatesBy[
 Join[DownValues[cctemp], DownValues[cc]] /. cctemp -> cc, #[[1,1]]&]

edited 50 mins ago

answered 1 hour ago

kglr

166k8188388

add a commentÂ |Â

up vote
3
down vote

You can make use of the undocumented Language`ExtendedDefinition function that underlies the Wolfram Cloud. Suppose:

cctemp[1,2] = 13;
cctemp[2,6] = 8;
cctemp[3,7] = 4;
cctemp[1,9] = 87;

Then:

Language`ExtendedDefiniition[cc] = Language`ExtendedDefinition[cctemp] /. cctemp -> cc;

Finally:

DownValues[cc]

HoldPattern[cc[1, 2]] :> 13, HoldPattern[cc[1, 9]] :> 87,
HoldPattern[cc[2, 6]] :> 8, HoldPattern[cc[3, 7]] :> 4

answered 1 hour ago

Carl Woll

61.1k280157

ok thank you for the answer; just two things because i want to learn: 1) where can i find the package of this function 2) why should i prefer this way over the answer of kglr ?
â€“Â siderius
1 hour ago

@siderius There is no package, the function is built-in. Using Language`ExtendedDefinition transfers UpValues, DownValues, FormatValues, etc. If all you care about are DownValues, then using DownValues instead is better.
â€“Â Carl Woll
55 mins ago

add a commentÂ |Â

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

DownValues[cc] = DownValues[cctemp] /. cctemp -> cc;
cc[1, 9]

87

cc[1, 2]

13

If cc has some assignments that are not overridden by the assignments in cctemp you can use

DownValues[cc] = DeleteDuplicatesBy[
 Join[DownValues[cctemp], DownValues[cc]] /. cctemp -> cc, #[[1,1]]&]

edited 50 mins ago

answered 1 hour ago

kglr

166k8188388

add a commentÂ |Â

up vote
2
down vote

accepted

DownValues[cc] = DownValues[cctemp] /. cctemp -> cc;
cc[1, 9]

87

cc[1, 2]

13

If cc has some assignments that are not overridden by the assignments in cctemp you can use

DownValues[cc] = DeleteDuplicatesBy[
 Join[DownValues[cctemp], DownValues[cc]] /. cctemp -> cc, #[[1,1]]&]

edited 50 mins ago

answered 1 hour ago

kglr

166k8188388

add a commentÂ |Â

up vote
2
down vote

accepted

DownValues[cc] = DownValues[cctemp] /. cctemp -> cc;
cc[1, 9]

87

cc[1, 2]

13

If cc has some assignments that are not overridden by the assignments in cctemp you can use

DownValues[cc] = DeleteDuplicatesBy[
 Join[DownValues[cctemp], DownValues[cc]] /. cctemp -> cc, #[[1,1]]&]

edited 50 mins ago

answered 1 hour ago

kglr

166k8188388

DownValues[cc] = DownValues[cctemp] /. cctemp -> cc;
cc[1, 9]

87

cc[1, 2]

13

If cc has some assignments that are not overridden by the assignments in cctemp you can use

DownValues[cc] = DeleteDuplicatesBy[
 Join[DownValues[cctemp], DownValues[cc]] /. cctemp -> cc, #[[1,1]]&]

edited 50 mins ago

answered 1 hour ago

kglr

166k8188388

edited 50 mins ago

answered 1 hour ago

kglr

166k8188388

answered 1 hour ago

kglr

166k8188388

answered 1 hour ago

kglr

166k8188388

add a commentÂ |Â

up vote
3
down vote

You can make use of the undocumented Language`ExtendedDefinition function that underlies the Wolfram Cloud. Suppose:

cctemp[1,2] = 13;
cctemp[2,6] = 8;
cctemp[3,7] = 4;
cctemp[1,9] = 87;

Then:

Language`ExtendedDefiniition[cc] = Language`ExtendedDefinition[cctemp] /. cctemp -> cc;

Finally:

DownValues[cc]

HoldPattern[cc[1, 2]] :> 13, HoldPattern[cc[1, 9]] :> 87,
HoldPattern[cc[2, 6]] :> 8, HoldPattern[cc[3, 7]] :> 4

answered 1 hour ago

Carl Woll

61.1k280157

ok thank you for the answer; just two things because i want to learn: 1) where can i find the package of this function 2) why should i prefer this way over the answer of kglr ?
â€“Â siderius
1 hour ago

@siderius There is no package, the function is built-in. Using Language`ExtendedDefinition transfers UpValues, DownValues, FormatValues, etc. If all you care about are DownValues, then using DownValues instead is better.
â€“Â Carl Woll
55 mins ago

add a commentÂ |Â

up vote
3
down vote

You can make use of the undocumented Language`ExtendedDefinition function that underlies the Wolfram Cloud. Suppose:

cctemp[1,2] = 13;
cctemp[2,6] = 8;
cctemp[3,7] = 4;
cctemp[1,9] = 87;

Then:

Language`ExtendedDefiniition[cc] = Language`ExtendedDefinition[cctemp] /. cctemp -> cc;

Finally:

DownValues[cc]

HoldPattern[cc[1, 2]] :> 13, HoldPattern[cc[1, 9]] :> 87,
HoldPattern[cc[2, 6]] :> 8, HoldPattern[cc[3, 7]] :> 4

answered 1 hour ago

Carl Woll

61.1k280157

ok thank you for the answer; just two things because i want to learn: 1) where can i find the package of this function 2) why should i prefer this way over the answer of kglr ?
â€“Â siderius
1 hour ago

@siderius There is no package, the function is built-in. Using Language`ExtendedDefinition transfers UpValues, DownValues, FormatValues, etc. If all you care about are DownValues, then using DownValues instead is better.
â€“Â Carl Woll
55 mins ago

add a commentÂ |Â

up vote
3
down vote

You can make use of the undocumented Language`ExtendedDefinition function that underlies the Wolfram Cloud. Suppose:

cctemp[1,2] = 13;
cctemp[2,6] = 8;
cctemp[3,7] = 4;
cctemp[1,9] = 87;

Then:

Language`ExtendedDefiniition[cc] = Language`ExtendedDefinition[cctemp] /. cctemp -> cc;

Finally:

DownValues[cc]

HoldPattern[cc[1, 2]] :> 13, HoldPattern[cc[1, 9]] :> 87,
HoldPattern[cc[2, 6]] :> 8, HoldPattern[cc[3, 7]] :> 4

answered 1 hour ago

Carl Woll

61.1k280157

You can make use of the undocumented Language`ExtendedDefinition function that underlies the Wolfram Cloud. Suppose:

cctemp[1,2] = 13;
cctemp[2,6] = 8;
cctemp[3,7] = 4;
cctemp[1,9] = 87;

Then:

Language`ExtendedDefiniition[cc] = Language`ExtendedDefinition[cctemp] /. cctemp -> cc;

Finally:

DownValues[cc]

HoldPattern[cc[1, 2]] :> 13, HoldPattern[cc[1, 9]] :> 87,
HoldPattern[cc[2, 6]] :> 8, HoldPattern[cc[3, 7]] :> 4

answered 1 hour ago

Carl Woll

61.1k280157

answered 1 hour ago

Carl Woll

61.1k280157

answered 1 hour ago

Carl Woll

61.1k280157

answered 1 hour ago

Carl Woll

61.1k280157

ok thank you for the answer; just two things because i want to learn: 1) where can i find the package of this function 2) why should i prefer this way over the answer of kglr ?
â€“Â siderius
1 hour ago

@siderius There is no package, the function is built-in. Using Language`ExtendedDefinition transfers UpValues, DownValues, FormatValues, etc. If all you care about are DownValues, then using DownValues instead is better.
â€“Â Carl Woll
55 mins ago

add a commentÂ |Â

ok thank you for the answer; just two things because i want to learn: 1) where can i find the package of this function 2) why should i prefer this way over the answer of kglr ?
â€“Â siderius
1 hour ago

@siderius There is no package, the function is built-in. Using Language`ExtendedDefinition transfers UpValues, DownValues, FormatValues, etc. If all you care about are DownValues, then using DownValues instead is better.
â€“Â Carl Woll
55 mins ago

ok thank you for the answer; just two things because i want to learn: 1) where can i find the package of this function 2) why should i prefer this way over the answer of kglr ?
â€“Â siderius
1 hour ago

@siderius There is no package, the function is built-in. Using Language`ExtendedDefinition transfers UpValues, DownValues, FormatValues, etc. If all you care about are DownValues, then using DownValues instead is better.
â€“Â Carl Woll
55 mins ago

add a commentÂ |Â

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