Mixing
Does an electrical outlet radiate EM waves?
Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
favorite
Please consider all cases even with a tiny values.
If plug two separated wires to each terminal of electrical outlet, like shown, will it radiate em waves?
60 hz, 230 V electrical outlet.
Wires are not connected to each other(I mean in our ends, cause, somewhere in generator they should be connected)
If it will radiate, then will radiate both wires or only that connected to phase terminal(seems it called "hot" terminal in eng)?
antenna radiation outlet
edited 1 hour ago
JRE
19.3k43665
asked 2 hours ago
Artur
113
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
1
down vote
favorite
Please consider all cases even with a tiny values.
If plug two separated wires to each terminal of electrical outlet, like shown, will it radiate em waves?
60 hz, 230 V electrical outlet.
Wires are not connected to each other(I mean in our ends, cause, somewhere in generator they should be connected)
If it will radiate, then will radiate both wires or only that connected to phase terminal(seems it called "hot" terminal in eng)?
antenna radiation outlet
edited 1 hour ago
JRE
19.3k43665
asked 2 hours ago
Artur
113
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
What do the two separated wires add compared to the wires leading to the socket?
– Jeroen3
2 hours ago
@Jeroen3, didn't understand the question. What is the difference between conneted and unconnected wires, or what?
– Artur
2 hours ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Please consider all cases even with a tiny values.
If plug two separated wires to each terminal of electrical outlet, like shown, will it radiate em waves?
60 hz, 230 V electrical outlet.
Wires are not connected to each other(I mean in our ends, cause, somewhere in generator they should be connected)
If it will radiate, then will radiate both wires or only that connected to phase terminal(seems it called "hot" terminal in eng)?
antenna radiation outlet
edited 1 hour ago
JRE
19.3k43665
asked 2 hours ago
Artur
113
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please consider all cases even with a tiny values.
If plug two separated wires to each terminal of electrical outlet, like shown, will it radiate em waves?
60 hz, 230 V electrical outlet.
Wires are not connected to each other(I mean in our ends, cause, somewhere in generator they should be connected)
If it will radiate, then will radiate both wires or only that connected to phase terminal(seems it called "hot" terminal in eng)?
antenna radiation outlet
antenna radiation outlet
edited 1 hour ago
JRE
19.3k43665
asked 2 hours ago
Artur
113
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
JRE
19.3k43665
asked 2 hours ago
Artur
113
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
JRE
19.3k43665
edited 1 hour ago
JRE
19.3k43665
edited 1 hour ago
JRE
19.3k43665
19.3k43665
asked 2 hours ago
Artur
113
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Artur
113
asked 2 hours ago
Artur
113
113
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Artur is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
What do the two separated wires add compared to the wires leading to the socket?
– Jeroen3
2 hours ago
@Jeroen3, didn't understand the question. What is the difference between conneted and unconnected wires, or what?
– Artur
2 hours ago
add a comment |Â
1
What do the two separated wires add compared to the wires leading to the socket?
– Jeroen3
2 hours ago
@Jeroen3, didn't understand the question. What is the difference between conneted and unconnected wires, or what?
– Artur
2 hours ago
1
1
What do the two separated wires add compared to the wires leading to the socket?
– Jeroen3
2 hours ago
What do the two separated wires add compared to the wires leading to the socket?
– Jeroen3
2 hours ago
@Jeroen3, didn't understand the question. What is the difference between conneted and unconnected wires, or what?
– Artur
2 hours ago
@Jeroen3, didn't understand the question. What is the difference between conneted and unconnected wires, or what?
– Artur
2 hours ago
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
4
down vote
Adding the wires is a bit pointless as there are already wires (in the wall) leading to the socket, and they also radiate EM waves just like the wires added by you.
So that answers your question: yes EM waves are radiated. But since the mains power is at a very low frequency effective radiation of the EM waves would require an antenna that is about 1500 kilometers long (that's for a $lambda/4$ antenna). The wires in our house are much shorter and therefor do not radiate very well at 60 Hz.
So yes, EM waves are indeed radiated but they're extremely weak and that's good as we want to electrical power to be used for something useful and not be radiated into space.
answered 1 hour ago
Bimpelrekkie
43.9k23996
add a comment |Â
up vote
3
down vote
Yes, it will radiate a 60Hz (or 50Hz depending on where you live) wave. It will be weak. Very weak. So weak that there's no point in worrying about it.
The radiated power depends the wavelength of the wave and the length of the two wires. To do any good, you'd want each wire to be about 1/4 of the wavelength.
For 60Hz, the wavelength is close to 5000km. At 50Hz, that'd be nearly 6000km. So, you'd need wires of 1250 or 1500km to transmit a large amount of power.
As you can see, the wire length needed to "transmit" at the AC powerline frequency is quite long.
No wire you can practically connect inside of your house can transmit an appreciable amount of power.
The "transmitted" power will appear to come from both wires if your receiver is not grounded.
If the receiver is grounded the the power will appear to come from the "hot" wire of the socket.
Even considering the length of the wires in the house (as Jeroen3 suggests) doesn't get you any notable amount of power.
You can measure it if you try. Engineers and technicians do it accidentally all the time - then curse, and improve the shielding and grounding on the extremely sensitive circuits and measuring devices they are using.
An oscilloscope, a loop of wire, and a capacitor can be made into a device to detect the AC being "broadcast" around. This only works because modern equipment is extraordinarily sensitive. If you assemble such a device, you can calculate how much power is being intentionally received - and the (miniscule) total will surprise you. Something on the order of millionths of a watt.
answered 1 hour ago
JRE
19.3k43665
First, You didn't answer to complete question(which wire will radiate - both or hot). The second, Your statement that the em wave frequency will be 60 hz is absolutely false(it's my opinion, at least). Third, what does "weak" mean? It's blurry a lot. If You meant intensity, it doesn't depends on frequency
– Artur
59 mins ago
AC power like from an outlet is either 60Hz (USA) or 50Hz (most of the rest of the world.) Anything broadcast will be at the frequency of the power line - ignoring any garbage put on it by noisy appliances.
– JRE
54 mins ago
Intensity depends on the available power, and the antenna. The size of antenna needed depends on the frequency - which is why I referred to the line frequency in my answer.
– JRE
51 mins ago
Yes, it is a blurry answer. You have blurry specifications on what is in effect a question about concepts. A specific answer is not possible, and not really useful.
– JRE
48 mins ago
Interesting that you complain about my answer being "blurry" when it in fact contains more numbers and order of magnitude references than the other answer.
– JRE
45 mins ago
 |Â
show 2 more comments
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
Adding the wires is a bit pointless as there are already wires (in the wall) leading to the socket, and they also radiate EM waves just like the wires added by you.
So that answers your question: yes EM waves are radiated. But since the mains power is at a very low frequency effective radiation of the EM waves would require an antenna that is about 1500 kilometers long (that's for a $lambda/4$ antenna). The wires in our house are much shorter and therefor do not radiate very well at 60 Hz.
So yes, EM waves are indeed radiated but they're extremely weak and that's good as we want to electrical power to be used for something useful and not be radiated into space.
answered 1 hour ago
Bimpelrekkie
43.9k23996
add a comment |Â
up vote
4
down vote
Adding the wires is a bit pointless as there are already wires (in the wall) leading to the socket, and they also radiate EM waves just like the wires added by you.
So that answers your question: yes EM waves are radiated. But since the mains power is at a very low frequency effective radiation of the EM waves would require an antenna that is about 1500 kilometers long (that's for a $lambda/4$ antenna). The wires in our house are much shorter and therefor do not radiate very well at 60 Hz.
So yes, EM waves are indeed radiated but they're extremely weak and that's good as we want to electrical power to be used for something useful and not be radiated into space.
answered 1 hour ago
Bimpelrekkie
43.9k23996
add a comment |Â
up vote
4
down vote
up vote
4
down vote
Adding the wires is a bit pointless as there are already wires (in the wall) leading to the socket, and they also radiate EM waves just like the wires added by you.
So that answers your question: yes EM waves are radiated. But since the mains power is at a very low frequency effective radiation of the EM waves would require an antenna that is about 1500 kilometers long (that's for a $lambda/4$ antenna). The wires in our house are much shorter and therefor do not radiate very well at 60 Hz.
So yes, EM waves are indeed radiated but they're extremely weak and that's good as we want to electrical power to be used for something useful and not be radiated into space.
answered 1 hour ago
Bimpelrekkie
43.9k23996
Adding the wires is a bit pointless as there are already wires (in the wall) leading to the socket, and they also radiate EM waves just like the wires added by you.
So that answers your question: yes EM waves are radiated. But since the mains power is at a very low frequency effective radiation of the EM waves would require an antenna that is about 1500 kilometers long (that's for a $lambda/4$ antenna). The wires in our house are much shorter and therefor do not radiate very well at 60 Hz.
So yes, EM waves are indeed radiated but they're extremely weak and that's good as we want to electrical power to be used for something useful and not be radiated into space.
answered 1 hour ago
Bimpelrekkie
43.9k23996
answered 1 hour ago
Bimpelrekkie
43.9k23996
answered 1 hour ago
Bimpelrekkie
43.9k23996
answered 1 hour ago
Bimpelrekkie
43.9k23996
43.9k23996
add a comment |Â
add a comment |Â
up vote
3
down vote
Yes, it will radiate a 60Hz (or 50Hz depending on where you live) wave. It will be weak. Very weak. So weak that there's no point in worrying about it.
The radiated power depends the wavelength of the wave and the length of the two wires. To do any good, you'd want each wire to be about 1/4 of the wavelength.
For 60Hz, the wavelength is close to 5000km. At 50Hz, that'd be nearly 6000km. So, you'd need wires of 1250 or 1500km to transmit a large amount of power.
As you can see, the wire length needed to "transmit" at the AC powerline frequency is quite long.
No wire you can practically connect inside of your house can transmit an appreciable amount of power.
The "transmitted" power will appear to come from both wires if your receiver is not grounded.
If the receiver is grounded the the power will appear to come from the "hot" wire of the socket.
Even considering the length of the wires in the house (as Jeroen3 suggests) doesn't get you any notable amount of power.
You can measure it if you try. Engineers and technicians do it accidentally all the time - then curse, and improve the shielding and grounding on the extremely sensitive circuits and measuring devices they are using.
An oscilloscope, a loop of wire, and a capacitor can be made into a device to detect the AC being "broadcast" around. This only works because modern equipment is extraordinarily sensitive. If you assemble such a device, you can calculate how much power is being intentionally received - and the (miniscule) total will surprise you. Something on the order of millionths of a watt.
answered 1 hour ago
JRE
19.3k43665
First, You didn't answer to complete question(which wire will radiate - both or hot). The second, Your statement that the em wave frequency will be 60 hz is absolutely false(it's my opinion, at least). Third, what does "weak" mean? It's blurry a lot. If You meant intensity, it doesn't depends on frequency
– Artur
59 mins ago
AC power like from an outlet is either 60Hz (USA) or 50Hz (most of the rest of the world.) Anything broadcast will be at the frequency of the power line - ignoring any garbage put on it by noisy appliances.
– JRE
54 mins ago
Intensity depends on the available power, and the antenna. The size of antenna needed depends on the frequency - which is why I referred to the line frequency in my answer.
– JRE
51 mins ago
Yes, it is a blurry answer. You have blurry specifications on what is in effect a question about concepts. A specific answer is not possible, and not really useful.
– JRE
48 mins ago
Interesting that you complain about my answer being "blurry" when it in fact contains more numbers and order of magnitude references than the other answer.
– JRE
45 mins ago
 |Â
show 2 more comments
up vote
3
down vote
Yes, it will radiate a 60Hz (or 50Hz depending on where you live) wave. It will be weak. Very weak. So weak that there's no point in worrying about it.
The radiated power depends the wavelength of the wave and the length of the two wires. To do any good, you'd want each wire to be about 1/4 of the wavelength.
For 60Hz, the wavelength is close to 5000km. At 50Hz, that'd be nearly 6000km. So, you'd need wires of 1250 or 1500km to transmit a large amount of power.
As you can see, the wire length needed to "transmit" at the AC powerline frequency is quite long.
No wire you can practically connect inside of your house can transmit an appreciable amount of power.
The "transmitted" power will appear to come from both wires if your receiver is not grounded.
If the receiver is grounded the the power will appear to come from the "hot" wire of the socket.
Even considering the length of the wires in the house (as Jeroen3 suggests) doesn't get you any notable amount of power.
You can measure it if you try. Engineers and technicians do it accidentally all the time - then curse, and improve the shielding and grounding on the extremely sensitive circuits and measuring devices they are using.
An oscilloscope, a loop of wire, and a capacitor can be made into a device to detect the AC being "broadcast" around. This only works because modern equipment is extraordinarily sensitive. If you assemble such a device, you can calculate how much power is being intentionally received - and the (miniscule) total will surprise you. Something on the order of millionths of a watt.
answered 1 hour ago
JRE
19.3k43665
First, You didn't answer to complete question(which wire will radiate - both or hot). The second, Your statement that the em wave frequency will be 60 hz is absolutely false(it's my opinion, at least). Third, what does "weak" mean? It's blurry a lot. If You meant intensity, it doesn't depends on frequency
– Artur
59 mins ago
AC power like from an outlet is either 60Hz (USA) or 50Hz (most of the rest of the world.) Anything broadcast will be at the frequency of the power line - ignoring any garbage put on it by noisy appliances.
– JRE
54 mins ago
Intensity depends on the available power, and the antenna. The size of antenna needed depends on the frequency - which is why I referred to the line frequency in my answer.
– JRE
51 mins ago
Yes, it is a blurry answer. You have blurry specifications on what is in effect a question about concepts. A specific answer is not possible, and not really useful.
– JRE
48 mins ago
Interesting that you complain about my answer being "blurry" when it in fact contains more numbers and order of magnitude references than the other answer.
– JRE
45 mins ago
 |Â
show 2 more comments
up vote
3
down vote
up vote
3
down vote
Yes, it will radiate a 60Hz (or 50Hz depending on where you live) wave. It will be weak. Very weak. So weak that there's no point in worrying about it.
The radiated power depends the wavelength of the wave and the length of the two wires. To do any good, you'd want each wire to be about 1/4 of the wavelength.
For 60Hz, the wavelength is close to 5000km. At 50Hz, that'd be nearly 6000km. So, you'd need wires of 1250 or 1500km to transmit a large amount of power.
As you can see, the wire length needed to "transmit" at the AC powerline frequency is quite long.
No wire you can practically connect inside of your house can transmit an appreciable amount of power.
The "transmitted" power will appear to come from both wires if your receiver is not grounded.
If the receiver is grounded the the power will appear to come from the "hot" wire of the socket.
Even considering the length of the wires in the house (as Jeroen3 suggests) doesn't get you any notable amount of power.
You can measure it if you try. Engineers and technicians do it accidentally all the time - then curse, and improve the shielding and grounding on the extremely sensitive circuits and measuring devices they are using.
An oscilloscope, a loop of wire, and a capacitor can be made into a device to detect the AC being "broadcast" around. This only works because modern equipment is extraordinarily sensitive. If you assemble such a device, you can calculate how much power is being intentionally received - and the (miniscule) total will surprise you. Something on the order of millionths of a watt.
answered 1 hour ago
JRE
19.3k43665
Yes, it will radiate a 60Hz (or 50Hz depending on where you live) wave. It will be weak. Very weak. So weak that there's no point in worrying about it.
The radiated power depends the wavelength of the wave and the length of the two wires. To do any good, you'd want each wire to be about 1/4 of the wavelength.
For 60Hz, the wavelength is close to 5000km. At 50Hz, that'd be nearly 6000km. So, you'd need wires of 1250 or 1500km to transmit a large amount of power.
As you can see, the wire length needed to "transmit" at the AC powerline frequency is quite long.
No wire you can practically connect inside of your house can transmit an appreciable amount of power.
The "transmitted" power will appear to come from both wires if your receiver is not grounded.
If the receiver is grounded the the power will appear to come from the "hot" wire of the socket.
Even considering the length of the wires in the house (as Jeroen3 suggests) doesn't get you any notable amount of power.
You can measure it if you try. Engineers and technicians do it accidentally all the time - then curse, and improve the shielding and grounding on the extremely sensitive circuits and measuring devices they are using.
An oscilloscope, a loop of wire, and a capacitor can be made into a device to detect the AC being "broadcast" around. This only works because modern equipment is extraordinarily sensitive. If you assemble such a device, you can calculate how much power is being intentionally received - and the (miniscule) total will surprise you. Something on the order of millionths of a watt.
answered 1 hour ago
JRE
19.3k43665
edited 25 mins ago
answered 1 hour ago
JRE
19.3k43665
answered 1 hour ago
JRE
19.3k43665
answered 1 hour ago
JRE
19.3k43665
19.3k43665
First, You didn't answer to complete question(which wire will radiate - both or hot). The second, Your statement that the em wave frequency will be 60 hz is absolutely false(it's my opinion, at least). Third, what does "weak" mean? It's blurry a lot. If You meant intensity, it doesn't depends on frequency
– Artur
59 mins ago
AC power like from an outlet is either 60Hz (USA) or 50Hz (most of the rest of the world.) Anything broadcast will be at the frequency of the power line - ignoring any garbage put on it by noisy appliances.
– JRE
54 mins ago
Intensity depends on the available power, and the antenna. The size of antenna needed depends on the frequency - which is why I referred to the line frequency in my answer.
– JRE
51 mins ago
Yes, it is a blurry answer. You have blurry specifications on what is in effect a question about concepts. A specific answer is not possible, and not really useful.
– JRE
48 mins ago
Interesting that you complain about my answer being "blurry" when it in fact contains more numbers and order of magnitude references than the other answer.
– JRE
45 mins ago
 |Â
show 2 more comments
First, You didn't answer to complete question(which wire will radiate - both or hot). The second, Your statement that the em wave frequency will be 60 hz is absolutely false(it's my opinion, at least). Third, what does "weak" mean? It's blurry a lot. If You meant intensity, it doesn't depends on frequency
– Artur
59 mins ago
AC power like from an outlet is either 60Hz (USA) or 50Hz (most of the rest of the world.) Anything broadcast will be at the frequency of the power line - ignoring any garbage put on it by noisy appliances.
– JRE
54 mins ago
Intensity depends on the available power, and the antenna. The size of antenna needed depends on the frequency - which is why I referred to the line frequency in my answer.
– JRE
51 mins ago
Yes, it is a blurry answer. You have blurry specifications on what is in effect a question about concepts. A specific answer is not possible, and not really useful.
– JRE
48 mins ago
Interesting that you complain about my answer being "blurry" when it in fact contains more numbers and order of magnitude references than the other answer.
– JRE
45 mins ago
First, You didn't answer to complete question(which wire will radiate - both or hot). The second, Your statement that the em wave frequency will be 60 hz is absolutely false(it's my opinion, at least). Third, what does "weak" mean? It's blurry a lot. If You meant intensity, it doesn't depends on frequency
– Artur
59 mins ago
First, You didn't answer to complete question(which wire will radiate - both or hot). The second, Your statement that the em wave frequency will be 60 hz is absolutely false(it's my opinion, at least). Third, what does "weak" mean? It's blurry a lot. If You meant intensity, it doesn't depends on frequency
– Artur
59 mins ago
AC power like from an outlet is either 60Hz (USA) or 50Hz (most of the rest of the world.) Anything broadcast will be at the frequency of the power line - ignoring any garbage put on it by noisy appliances.
– JRE
54 mins ago
AC power like from an outlet is either 60Hz (USA) or 50Hz (most of the rest of the world.) Anything broadcast will be at the frequency of the power line - ignoring any garbage put on it by noisy appliances.
– JRE
54 mins ago
Intensity depends on the available power, and the antenna. The size of antenna needed depends on the frequency - which is why I referred to the line frequency in my answer.
– JRE
51 mins ago
Intensity depends on the available power, and the antenna. The size of antenna needed depends on the frequency - which is why I referred to the line frequency in my answer.
– JRE
51 mins ago
Yes, it is a blurry answer. You have blurry specifications on what is in effect a question about concepts. A specific answer is not possible, and not really useful.
– JRE
48 mins ago
Yes, it is a blurry answer. You have blurry specifications on what is in effect a question about concepts. A specific answer is not possible, and not really useful.
– JRE
48 mins ago
Interesting that you complain about my answer being "blurry" when it in fact contains more numbers and order of magnitude references than the other answer.
– JRE
45 mins ago
Interesting that you complain about my answer being "blurry" when it in fact contains more numbers and order of magnitude references than the other answer.
– JRE
45 mins ago
 |Â
show 2 more comments
Artur is a new contributor. Be nice, and check out our Code of Conduct.
Artur is a new contributor. Be nice, and check out our Code of Conduct.
Artur is a new contributor. Be nice, and check out our Code of Conduct.
Artur is a new contributor. Be nice, and check out our Code of Conduct.
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1
What do the two separated wires add compared to the wires leading to the socket?
– Jeroen3
2 hours ago
@Jeroen3, didn't understand the question. What is the difference between conneted and unconnected wires, or what?
– Artur
2 hours ago