Mixing
How to draw a Taylor diagrams
Clash Royale CLAN TAG#URR8PPP
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Is there any package or a way to draw Taylor diagrams (From this paper) easily?
Any help will be appreciated.
tikz-pgf
edited 3 hours ago
Sebastiano
7,78741654
asked 3 hours ago
Mark
61
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Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |Â
up vote
1
down vote
favorite
Is there any package or a way to draw Taylor diagrams (From this paper) easily?
Any help will be appreciated.
tikz-pgf
edited 3 hours ago
Sebastiano
7,78741654
asked 3 hours ago
Mark
61
New contributor
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Welcome to TeX.Stackexchange!
– samcarter
3 hours ago
2
I'm not sure if there is a dedicated package for only these diagrams, but I think you could just do them withpolar axesthat come with pgfplots, particularly see section 5.10.6 Partial Polar Axes of the manual as well as 5.11. SMITH CHARTS.
– marmot
2 hours ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Is there any package or a way to draw Taylor diagrams (From this paper) easily?
Any help will be appreciated.
tikz-pgf
edited 3 hours ago
Sebastiano
7,78741654
asked 3 hours ago
Mark
61
New contributor
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Is there any package or a way to draw Taylor diagrams (From this paper) easily?
Any help will be appreciated.
tikz-pgf
tikz-pgf
edited 3 hours ago
Sebastiano
7,78741654
asked 3 hours ago
Mark
61
New contributor
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 hours ago
Sebastiano
7,78741654
asked 3 hours ago
Mark
61
New contributor
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 hours ago
Sebastiano
7,78741654
edited 3 hours ago
Sebastiano
7,78741654
edited 3 hours ago
Sebastiano
7,78741654
7,78741654
asked 3 hours ago
Mark
61
New contributor
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
Mark
61
asked 3 hours ago
Mark
61
61
New contributor
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Welcome to TeX.Stackexchange!
– samcarter
3 hours ago
2
I'm not sure if there is a dedicated package for only these diagrams, but I think you could just do them withpolar axesthat come with pgfplots, particularly see section 5.10.6 Partial Polar Axes of the manual as well as 5.11. SMITH CHARTS.
– marmot
2 hours ago
add a comment |Â
Welcome to TeX.Stackexchange!
– samcarter
3 hours ago
2
I'm not sure if there is a dedicated package for only these diagrams, but I think you could just do them withpolar axesthat come with pgfplots, particularly see section 5.10.6 Partial Polar Axes of the manual as well as 5.11. SMITH CHARTS.
– marmot
2 hours ago
Welcome to TeX.Stackexchange!
– samcarter
3 hours ago
Welcome to TeX.Stackexchange!
– samcarter
3 hours ago
2
2
I'm not sure if there is a dedicated package for only these diagrams, but I think you could just do them with
polar axes that come with pgfplots, particularly see section 5.10.6 Partial Polar Axes of the manual as well as 5.11. SMITH CHARTS.– marmot
2 hours ago
I'm not sure if there is a dedicated package for only these diagrams, but I think you could just do them with
polar axes that come with pgfplots, particularly see section 5.10.6 Partial Polar Axes of the manual as well as 5.11. SMITH CHARTS.– marmot
2 hours ago
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
5
down vote
OK. So, I won't do all the work for you. But, I will do enough so that you should be able to figure out how to add everything else that remains to be done.
What I show you here is as follows:
- How to clip a portion of a picture
- How to draw concentric circles about a given center
- How to label along a curved path
- How to place a label at a point along a path
- How label at the end points of a line
- How to get different styles of dashed and dotted lines
- How to plot points
- Different approaches to scaling the text
And, I believe that should allow you to complete the rest of the picture.
Here's the code to generate the diagram:
documentclass[tikz,border=6pt]standalone
usepackageamsmath
usepackagetikz
usetikzlibrarycalc
usetikzlibrarydecorations.text
pagestyleempty
begindocument
begintikzpicture[
x=(4cm,0),
y=(0,4cm),
radius=4cm,
]
%% notation (<angle>:<radius>) gives polar coordinates
%% (<x-coor>,<y-coord>) Euclidean coordinates
%% draw semi-circles clipped by the 1st quadrant arc
%% `scope` prevents the entirety of the remainder of
%% picture from being clipped.
beginscope
draw[clip] (0,0) -- (1,0) arc (0:90:1) -- cycle;
foreach myr in 1,2,...,5
%% draw a circle centered at (5/7,0)
%% arc starts at point (myr/6,0) and proceeds through an
%% angle of 180 degrees with a radius of myr/6 units
draw[blue,densely dotted] (5/7,0) ++ (myr/6,0) arc (0:180:myr/6);
endscope
%% place a label along one of the above clipped arcs.
path (5/7,0) ++ (2/6,0) arc (0:180:2/6) node[pos=0.75,
rotate=0.75*180-90,
anchor=south,
inner sep=4pt,
scale=0.5,
blue] (A) $0.25$;
%% label the correlation coefficient values
pgfkeys/pgf/number format/precision=1
foreach myp in 0,1,2,...,11
%% calculate the angle myangle from the integer myp
pgfmathsetmacromyangle90*(12-myp)/12
pgfmathparsemyp/10
pgfmathroundtozerofillpgfmathresult
pgfmathsetmacromylabelpgfmathresult
%% handle labels that don't follow the previous pattern
ifdimmylabel pt=1.0pt%%
defmylabel0.95
fi
ifdimmylabel pt=1.1pt%%
defmylabel0.99%%
fi
%% draw the dashed lines from orgin to arc with labels outside arc
draw[gray!50,
dash pattern=on 1.25pt off 0.5pt,
line width=0.1pt] (myangle:1) node[black,
anchor=180+myangle]
$scriptscriptstylemylabel$ -- (0,0);
%% labeling along a curve
%% a fancy approach that's necessary for labels conforming to
%% a curved path. Not necessary for labels along straight lines.
path[postaction=decoration=text along path,
text align=center,
text=Correlation Coefficient,
decorate]
(0,1.15) arc (90:0:1.15);
%% some data points
node[blue] at (35:4/7+1/2*1/7) $diamond$;
node[red,scale=0.5] at (32:5/7) $pmbtriangle$;
%% draw the quarter circle in the first quadrant
draw (0,0) -- (1,0);
draw (0,0) -- (1,0) arc (0:90:1) -- cycle;
endtikzpicture
enddocument
answered 1 hour ago
A.Ellett
35.6k1064164
+1 (I guess that the angles between the segments should not coincide, but I also see why you would not want to go through the semi-clear paper linked in the question to look for the formula. ;-)
– marmot
1 hour ago
@marmot Well, I don't want to do all of the OP's work. :-) But, I did want to give the OP and idea of how to approach each detail of the picture.
– A.Ellett
1 hour ago
@marmot Actually, unless absolutely necessary, I probably would not use the same formula, but instead I'd use a logarithmic function to be place those labels.
– A.Ellett
1 hour ago
In the paper, the author stresses that he is using the cosine law to motivate the diagram, but he fails to provide the formula for the labels. I guess that they are computed from theerf, but I'm not sure of that. Analytic approximations toerfcan be found on this site. But I think that the least thing the OP should do is to specify this.
– marmot
1 hour ago
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
OK. So, I won't do all the work for you. But, I will do enough so that you should be able to figure out how to add everything else that remains to be done.
What I show you here is as follows:
- How to clip a portion of a picture
- How to draw concentric circles about a given center
- How to label along a curved path
- How to place a label at a point along a path
- How label at the end points of a line
- How to get different styles of dashed and dotted lines
- How to plot points
- Different approaches to scaling the text
And, I believe that should allow you to complete the rest of the picture.
Here's the code to generate the diagram:
documentclass[tikz,border=6pt]standalone
usepackageamsmath
usepackagetikz
usetikzlibrarycalc
usetikzlibrarydecorations.text
pagestyleempty
begindocument
begintikzpicture[
x=(4cm,0),
y=(0,4cm),
radius=4cm,
]
%% notation (<angle>:<radius>) gives polar coordinates
%% (<x-coor>,<y-coord>) Euclidean coordinates
%% draw semi-circles clipped by the 1st quadrant arc
%% `scope` prevents the entirety of the remainder of
%% picture from being clipped.
beginscope
draw[clip] (0,0) -- (1,0) arc (0:90:1) -- cycle;
foreach myr in 1,2,...,5
%% draw a circle centered at (5/7,0)
%% arc starts at point (myr/6,0) and proceeds through an
%% angle of 180 degrees with a radius of myr/6 units
draw[blue,densely dotted] (5/7,0) ++ (myr/6,0) arc (0:180:myr/6);
endscope
%% place a label along one of the above clipped arcs.
path (5/7,0) ++ (2/6,0) arc (0:180:2/6) node[pos=0.75,
rotate=0.75*180-90,
anchor=south,
inner sep=4pt,
scale=0.5,
blue] (A) $0.25$;
%% label the correlation coefficient values
pgfkeys/pgf/number format/precision=1
foreach myp in 0,1,2,...,11
%% calculate the angle myangle from the integer myp
pgfmathsetmacromyangle90*(12-myp)/12
pgfmathparsemyp/10
pgfmathroundtozerofillpgfmathresult
pgfmathsetmacromylabelpgfmathresult
%% handle labels that don't follow the previous pattern
ifdimmylabel pt=1.0pt%%
defmylabel0.95
fi
ifdimmylabel pt=1.1pt%%
defmylabel0.99%%
fi
%% draw the dashed lines from orgin to arc with labels outside arc
draw[gray!50,
dash pattern=on 1.25pt off 0.5pt,
line width=0.1pt] (myangle:1) node[black,
anchor=180+myangle]
$scriptscriptstylemylabel$ -- (0,0);
%% labeling along a curve
%% a fancy approach that's necessary for labels conforming to
%% a curved path. Not necessary for labels along straight lines.
path[postaction=decoration=text along path,
text align=center,
text=Correlation Coefficient,
decorate]
(0,1.15) arc (90:0:1.15);
%% some data points
node[blue] at (35:4/7+1/2*1/7) $diamond$;
node[red,scale=0.5] at (32:5/7) $pmbtriangle$;
%% draw the quarter circle in the first quadrant
draw (0,0) -- (1,0);
draw (0,0) -- (1,0) arc (0:90:1) -- cycle;
endtikzpicture
enddocument
answered 1 hour ago
A.Ellett
35.6k1064164
+1 (I guess that the angles between the segments should not coincide, but I also see why you would not want to go through the semi-clear paper linked in the question to look for the formula. ;-)
– marmot
1 hour ago
@marmot Well, I don't want to do all of the OP's work. :-) But, I did want to give the OP and idea of how to approach each detail of the picture.
– A.Ellett
1 hour ago
@marmot Actually, unless absolutely necessary, I probably would not use the same formula, but instead I'd use a logarithmic function to be place those labels.
– A.Ellett
1 hour ago
In the paper, the author stresses that he is using the cosine law to motivate the diagram, but he fails to provide the formula for the labels. I guess that they are computed from theerf, but I'm not sure of that. Analytic approximations toerfcan be found on this site. But I think that the least thing the OP should do is to specify this.
– marmot
1 hour ago
add a comment |Â
up vote
5
down vote
OK. So, I won't do all the work for you. But, I will do enough so that you should be able to figure out how to add everything else that remains to be done.
What I show you here is as follows:
- How to clip a portion of a picture
- How to draw concentric circles about a given center
- How to label along a curved path
- How to place a label at a point along a path
- How label at the end points of a line
- How to get different styles of dashed and dotted lines
- How to plot points
- Different approaches to scaling the text
And, I believe that should allow you to complete the rest of the picture.
Here's the code to generate the diagram:
documentclass[tikz,border=6pt]standalone
usepackageamsmath
usepackagetikz
usetikzlibrarycalc
usetikzlibrarydecorations.text
pagestyleempty
begindocument
begintikzpicture[
x=(4cm,0),
y=(0,4cm),
radius=4cm,
]
%% notation (<angle>:<radius>) gives polar coordinates
%% (<x-coor>,<y-coord>) Euclidean coordinates
%% draw semi-circles clipped by the 1st quadrant arc
%% `scope` prevents the entirety of the remainder of
%% picture from being clipped.
beginscope
draw[clip] (0,0) -- (1,0) arc (0:90:1) -- cycle;
foreach myr in 1,2,...,5
%% draw a circle centered at (5/7,0)
%% arc starts at point (myr/6,0) and proceeds through an
%% angle of 180 degrees with a radius of myr/6 units
draw[blue,densely dotted] (5/7,0) ++ (myr/6,0) arc (0:180:myr/6);
endscope
%% place a label along one of the above clipped arcs.
path (5/7,0) ++ (2/6,0) arc (0:180:2/6) node[pos=0.75,
rotate=0.75*180-90,
anchor=south,
inner sep=4pt,
scale=0.5,
blue] (A) $0.25$;
%% label the correlation coefficient values
pgfkeys/pgf/number format/precision=1
foreach myp in 0,1,2,...,11
%% calculate the angle myangle from the integer myp
pgfmathsetmacromyangle90*(12-myp)/12
pgfmathparsemyp/10
pgfmathroundtozerofillpgfmathresult
pgfmathsetmacromylabelpgfmathresult
%% handle labels that don't follow the previous pattern
ifdimmylabel pt=1.0pt%%
defmylabel0.95
fi
ifdimmylabel pt=1.1pt%%
defmylabel0.99%%
fi
%% draw the dashed lines from orgin to arc with labels outside arc
draw[gray!50,
dash pattern=on 1.25pt off 0.5pt,
line width=0.1pt] (myangle:1) node[black,
anchor=180+myangle]
$scriptscriptstylemylabel$ -- (0,0);
%% labeling along a curve
%% a fancy approach that's necessary for labels conforming to
%% a curved path. Not necessary for labels along straight lines.
path[postaction=decoration=text along path,
text align=center,
text=Correlation Coefficient,
decorate]
(0,1.15) arc (90:0:1.15);
%% some data points
node[blue] at (35:4/7+1/2*1/7) $diamond$;
node[red,scale=0.5] at (32:5/7) $pmbtriangle$;
%% draw the quarter circle in the first quadrant
draw (0,0) -- (1,0);
draw (0,0) -- (1,0) arc (0:90:1) -- cycle;
endtikzpicture
enddocument
answered 1 hour ago
A.Ellett
35.6k1064164
+1 (I guess that the angles between the segments should not coincide, but I also see why you would not want to go through the semi-clear paper linked in the question to look for the formula. ;-)
– marmot
1 hour ago
@marmot Well, I don't want to do all of the OP's work. :-) But, I did want to give the OP and idea of how to approach each detail of the picture.
– A.Ellett
1 hour ago
@marmot Actually, unless absolutely necessary, I probably would not use the same formula, but instead I'd use a logarithmic function to be place those labels.
– A.Ellett
1 hour ago
In the paper, the author stresses that he is using the cosine law to motivate the diagram, but he fails to provide the formula for the labels. I guess that they are computed from theerf, but I'm not sure of that. Analytic approximations toerfcan be found on this site. But I think that the least thing the OP should do is to specify this.
– marmot
1 hour ago
add a comment |Â
up vote
5
down vote
up vote
5
down vote
OK. So, I won't do all the work for you. But, I will do enough so that you should be able to figure out how to add everything else that remains to be done.
What I show you here is as follows:
- How to clip a portion of a picture
- How to draw concentric circles about a given center
- How to label along a curved path
- How to place a label at a point along a path
- How label at the end points of a line
- How to get different styles of dashed and dotted lines
- How to plot points
- Different approaches to scaling the text
And, I believe that should allow you to complete the rest of the picture.
Here's the code to generate the diagram:
documentclass[tikz,border=6pt]standalone
usepackageamsmath
usepackagetikz
usetikzlibrarycalc
usetikzlibrarydecorations.text
pagestyleempty
begindocument
begintikzpicture[
x=(4cm,0),
y=(0,4cm),
radius=4cm,
]
%% notation (<angle>:<radius>) gives polar coordinates
%% (<x-coor>,<y-coord>) Euclidean coordinates
%% draw semi-circles clipped by the 1st quadrant arc
%% `scope` prevents the entirety of the remainder of
%% picture from being clipped.
beginscope
draw[clip] (0,0) -- (1,0) arc (0:90:1) -- cycle;
foreach myr in 1,2,...,5
%% draw a circle centered at (5/7,0)
%% arc starts at point (myr/6,0) and proceeds through an
%% angle of 180 degrees with a radius of myr/6 units
draw[blue,densely dotted] (5/7,0) ++ (myr/6,0) arc (0:180:myr/6);
endscope
%% place a label along one of the above clipped arcs.
path (5/7,0) ++ (2/6,0) arc (0:180:2/6) node[pos=0.75,
rotate=0.75*180-90,
anchor=south,
inner sep=4pt,
scale=0.5,
blue] (A) $0.25$;
%% label the correlation coefficient values
pgfkeys/pgf/number format/precision=1
foreach myp in 0,1,2,...,11
%% calculate the angle myangle from the integer myp
pgfmathsetmacromyangle90*(12-myp)/12
pgfmathparsemyp/10
pgfmathroundtozerofillpgfmathresult
pgfmathsetmacromylabelpgfmathresult
%% handle labels that don't follow the previous pattern
ifdimmylabel pt=1.0pt%%
defmylabel0.95
fi
ifdimmylabel pt=1.1pt%%
defmylabel0.99%%
fi
%% draw the dashed lines from orgin to arc with labels outside arc
draw[gray!50,
dash pattern=on 1.25pt off 0.5pt,
line width=0.1pt] (myangle:1) node[black,
anchor=180+myangle]
$scriptscriptstylemylabel$ -- (0,0);
%% labeling along a curve
%% a fancy approach that's necessary for labels conforming to
%% a curved path. Not necessary for labels along straight lines.
path[postaction=decoration=text along path,
text align=center,
text=Correlation Coefficient,
decorate]
(0,1.15) arc (90:0:1.15);
%% some data points
node[blue] at (35:4/7+1/2*1/7) $diamond$;
node[red,scale=0.5] at (32:5/7) $pmbtriangle$;
%% draw the quarter circle in the first quadrant
draw (0,0) -- (1,0);
draw (0,0) -- (1,0) arc (0:90:1) -- cycle;
endtikzpicture
enddocument
answered 1 hour ago
A.Ellett
35.6k1064164
OK. So, I won't do all the work for you. But, I will do enough so that you should be able to figure out how to add everything else that remains to be done.
What I show you here is as follows:
- How to clip a portion of a picture
- How to draw concentric circles about a given center
- How to label along a curved path
- How to place a label at a point along a path
- How label at the end points of a line
- How to get different styles of dashed and dotted lines
- How to plot points
- Different approaches to scaling the text
And, I believe that should allow you to complete the rest of the picture.
Here's the code to generate the diagram:
documentclass[tikz,border=6pt]standalone
usepackageamsmath
usepackagetikz
usetikzlibrarycalc
usetikzlibrarydecorations.text
pagestyleempty
begindocument
begintikzpicture[
x=(4cm,0),
y=(0,4cm),
radius=4cm,
]
%% notation (<angle>:<radius>) gives polar coordinates
%% (<x-coor>,<y-coord>) Euclidean coordinates
%% draw semi-circles clipped by the 1st quadrant arc
%% `scope` prevents the entirety of the remainder of
%% picture from being clipped.
beginscope
draw[clip] (0,0) -- (1,0) arc (0:90:1) -- cycle;
foreach myr in 1,2,...,5
%% draw a circle centered at (5/7,0)
%% arc starts at point (myr/6,0) and proceeds through an
%% angle of 180 degrees with a radius of myr/6 units
draw[blue,densely dotted] (5/7,0) ++ (myr/6,0) arc (0:180:myr/6);
endscope
%% place a label along one of the above clipped arcs.
path (5/7,0) ++ (2/6,0) arc (0:180:2/6) node[pos=0.75,
rotate=0.75*180-90,
anchor=south,
inner sep=4pt,
scale=0.5,
blue] (A) $0.25$;
%% label the correlation coefficient values
pgfkeys/pgf/number format/precision=1
foreach myp in 0,1,2,...,11
%% calculate the angle myangle from the integer myp
pgfmathsetmacromyangle90*(12-myp)/12
pgfmathparsemyp/10
pgfmathroundtozerofillpgfmathresult
pgfmathsetmacromylabelpgfmathresult
%% handle labels that don't follow the previous pattern
ifdimmylabel pt=1.0pt%%
defmylabel0.95
fi
ifdimmylabel pt=1.1pt%%
defmylabel0.99%%
fi
%% draw the dashed lines from orgin to arc with labels outside arc
draw[gray!50,
dash pattern=on 1.25pt off 0.5pt,
line width=0.1pt] (myangle:1) node[black,
anchor=180+myangle]
$scriptscriptstylemylabel$ -- (0,0);
%% labeling along a curve
%% a fancy approach that's necessary for labels conforming to
%% a curved path. Not necessary for labels along straight lines.
path[postaction=decoration=text along path,
text align=center,
text=Correlation Coefficient,
decorate]
(0,1.15) arc (90:0:1.15);
%% some data points
node[blue] at (35:4/7+1/2*1/7) $diamond$;
node[red,scale=0.5] at (32:5/7) $pmbtriangle$;
%% draw the quarter circle in the first quadrant
draw (0,0) -- (1,0);
draw (0,0) -- (1,0) arc (0:90:1) -- cycle;
endtikzpicture
enddocument
answered 1 hour ago
A.Ellett
35.6k1064164
edited 14 mins ago
answered 1 hour ago
A.Ellett
35.6k1064164
answered 1 hour ago
A.Ellett
35.6k1064164
answered 1 hour ago
A.Ellett
35.6k1064164
35.6k1064164
+1 (I guess that the angles between the segments should not coincide, but I also see why you would not want to go through the semi-clear paper linked in the question to look for the formula. ;-)
– marmot
1 hour ago
@marmot Well, I don't want to do all of the OP's work. :-) But, I did want to give the OP and idea of how to approach each detail of the picture.
– A.Ellett
1 hour ago
@marmot Actually, unless absolutely necessary, I probably would not use the same formula, but instead I'd use a logarithmic function to be place those labels.
– A.Ellett
1 hour ago
In the paper, the author stresses that he is using the cosine law to motivate the diagram, but he fails to provide the formula for the labels. I guess that they are computed from theerf, but I'm not sure of that. Analytic approximations toerfcan be found on this site. But I think that the least thing the OP should do is to specify this.
– marmot
1 hour ago
add a comment |Â
+1 (I guess that the angles between the segments should not coincide, but I also see why you would not want to go through the semi-clear paper linked in the question to look for the formula. ;-)
– marmot
1 hour ago
@marmot Well, I don't want to do all of the OP's work. :-) But, I did want to give the OP and idea of how to approach each detail of the picture.
– A.Ellett
1 hour ago
@marmot Actually, unless absolutely necessary, I probably would not use the same formula, but instead I'd use a logarithmic function to be place those labels.
– A.Ellett
1 hour ago
In the paper, the author stresses that he is using the cosine law to motivate the diagram, but he fails to provide the formula for the labels. I guess that they are computed from theerf, but I'm not sure of that. Analytic approximations toerfcan be found on this site. But I think that the least thing the OP should do is to specify this.
– marmot
1 hour ago
+1 (I guess that the angles between the segments should not coincide, but I also see why you would not want to go through the semi-clear paper linked in the question to look for the formula. ;-)
– marmot
1 hour ago
+1 (I guess that the angles between the segments should not coincide, but I also see why you would not want to go through the semi-clear paper linked in the question to look for the formula. ;-)
– marmot
1 hour ago
@marmot Well, I don't want to do all of the OP's work. :-) But, I did want to give the OP and idea of how to approach each detail of the picture.
– A.Ellett
1 hour ago
@marmot Well, I don't want to do all of the OP's work. :-) But, I did want to give the OP and idea of how to approach each detail of the picture.
– A.Ellett
1 hour ago
@marmot Actually, unless absolutely necessary, I probably would not use the same formula, but instead I'd use a logarithmic function to be place those labels.
– A.Ellett
1 hour ago
@marmot Actually, unless absolutely necessary, I probably would not use the same formula, but instead I'd use a logarithmic function to be place those labels.
– A.Ellett
1 hour ago
In the paper, the author stresses that he is using the cosine law to motivate the diagram, but he fails to provide the formula for the labels. I guess that they are computed from the
erf, but I'm not sure of that. Analytic approximations to erf can be found on this site. But I think that the least thing the OP should do is to specify this.– marmot
1 hour ago
In the paper, the author stresses that he is using the cosine law to motivate the diagram, but he fails to provide the formula for the labels. I guess that they are computed from the
erf, but I'm not sure of that. Analytic approximations to erf can be found on this site. But I think that the least thing the OP should do is to specify this.– marmot
1 hour ago
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– samcarter
3 hours ago
2
I'm not sure if there is a dedicated package for only these diagrams, but I think you could just do them with
polar axesthat come with pgfplots, particularly see section 5.10.6 Partial Polar Axes of the manual as well as 5.11. SMITH CHARTS.– marmot
2 hours ago