How can you merge objects in array of objects?

up vote
7
down vote

favorite

I'm looking for the best solution to merge all objects in one array

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

I want to achieve: name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']

What's the best option for that (es6)? Maybe I can do something like that using lodash? Which helpers should I use?

edited 9 mins ago

Constantin Chirila

16911

asked 2 hours ago

Rafonix

476

2

is every object in arrayOfObjects guaranteed to have the same properties?
â€“Â jtate
2 hours ago

add a commentÂ |Â

up vote
7
down vote

favorite

I'm looking for the best solution to merge all objects in one array

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

I want to achieve: name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']

What's the best option for that (es6)? Maybe I can do something like that using lodash? Which helpers should I use?

edited 9 mins ago

Constantin Chirila

16911

asked 2 hours ago

Rafonix

476

2

is every object in arrayOfObjects guaranteed to have the same properties?
â€“Â jtate
2 hours ago

add a commentÂ |Â

up vote
7
down vote

favorite

I'm looking for the best solution to merge all objects in one array

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

I want to achieve: name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']

What's the best option for that (es6)? Maybe I can do something like that using lodash? Which helpers should I use?

edited 9 mins ago

Constantin Chirila

16911

asked 2 hours ago

Rafonix

476

I'm looking for the best solution to merge all objects in one array

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

I want to achieve: name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']

What's the best option for that (es6)? Maybe I can do something like that using lodash? Which helpers should I use?

javascript arrays ecmascript-6 lodash

edited 9 mins ago

Constantin Chirila

16911

asked 2 hours ago

Rafonix

476

edited 9 mins ago

Constantin Chirila

16911

asked 2 hours ago

Rafonix

476

edited 9 mins ago

Constantin Chirila

16911

edited 9 mins ago

Constantin Chirila

16911

edited 9 mins ago

Constantin Chirila

16911

asked 2 hours ago

Rafonix

476

asked 2 hours ago

Rafonix

476

asked 2 hours ago

Rafonix

476

2

is every object in arrayOfObjects guaranteed to have the same properties?
â€“Â jtate
2 hours ago

add a commentÂ |Â

2

is every object in arrayOfObjects guaranteed to have the same properties?
â€“Â jtate
2 hours ago

is every object in arrayOfObjects guaranteed to have the same properties?
â€“Â jtate
2 hours ago

add a commentÂ |Â

7 Answers
7

active

oldest

votes

up vote
5
down vote

You could do it like this:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = ;
arrayOfObjects.forEach(item => 
 Object.keys(item).forEach(key => 
 if (!result[key]) 
 result[key] = ;
 
 result[key].push(item[key]);
 );
);

console.log(result);

answered 2 hours ago

ssc-hrep3

4,67521551

add a commentÂ |Â

up vote
4
down vote

You could reduce the array by iterating the entries and collecting the values, depending of the keys.

const
 array = [ name: 'Fred', surname: 'Shultz' , name: 'Anne', surname: 'Example' ],
 result = array.reduce((r, o) => ).push(v));
 return r;
 , Object.create(null));

console.log(result);

answered 2 hours ago

Nina Scholz

163k1280141

add a commentÂ |Â

up vote
2
down vote

easy with lodash:

grouped = _.mapValues(arrayOfObjects[0], 
 (val, key) => _.map(arrayOfObjects, key))

pure es6

let grouped = ;

for (let obj of arrayOfObjects)
 for (let [key, val] of Object.entries(obj))
 grouped[key] = (grouped[key] || ).concat(val)

answered 2 hours ago

georg

140k31191287

add a commentÂ |Â

up vote
0
down vote

The following should work - uses a few ES6 helpers, but the key is Array#reduce which is in ES5.

const result = arrayOfObjects.reduce((acc, obj) => 
 for (let key in obj) 
 if (key in acc) 
 acc[key].push(obj[key]);
 
 else 
 acc[key] = [obj[key]];
 
 
 return acc;
, );

answered 2 hours ago

Robin Zigmond

88839

add a commentÂ |Â

up vote
0
down vote

Here is a lodash approach

 _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

var input = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

var res = _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

console.log(res);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

This will take care if the objects doesn't have exactly same key sets

edited 1 hour ago

answered 2 hours ago

Koushik Chatterjee

2,5173924

This results in a slightly different output structure than expected.
â€“Â ssc-hrep3
2 hours ago

Ohh, yeah, need to map the value, let me edit
â€“Â Koushik Chatterjee
2 hours ago

@ssc-hrep3 see edit, I forget to map it to the expected type of result
â€“Â Koushik Chatterjee
1 hour ago

add a commentÂ |Â

up vote
0
down vote

You can use lodash's mergeWith like so:

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

Example:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>

edited 1 hour ago

answered 1 hour ago

ibrahim mahrir

20.2k41442

add a commentÂ |Â

up vote
0
down vote

Short way with array reduce:

const arrayOfObjects = [
 name: "name1", surname: "surname1", name: 'Anne', surname: 'Example', name: 'name3', surname: 'Example3'
];
/*
name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']
*/
var result = arrayOfObjects.reduce((obj,current)=>
 (obj['name'] = obj['name'],);
console.log(result);

edited 1 hour ago

answered 1 hour ago

protoproto

47336

add a commentÂ |Â

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7 Answers
7

active

oldest

votes

7 Answers
7

active

oldest

votes

up vote
5
down vote

You could do it like this:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = ;
arrayOfObjects.forEach(item => 
 Object.keys(item).forEach(key => 
 if (!result[key]) 
 result[key] = ;
 
 result[key].push(item[key]);
 );
);

console.log(result);

answered 2 hours ago

ssc-hrep3

4,67521551

add a commentÂ |Â

up vote
5
down vote

You could do it like this:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = ;
arrayOfObjects.forEach(item => 
 Object.keys(item).forEach(key => 
 if (!result[key]) 
 result[key] = ;
 
 result[key].push(item[key]);
 );
);

console.log(result);

answered 2 hours ago

ssc-hrep3

4,67521551

add a commentÂ |Â

up vote
5
down vote

You could do it like this:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = ;
arrayOfObjects.forEach(item => 
 Object.keys(item).forEach(key => 
 if (!result[key]) 
 result[key] = ;
 
 result[key].push(item[key]);
 );
);

console.log(result);

answered 2 hours ago

ssc-hrep3

4,67521551

You could do it like this:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = ;
arrayOfObjects.forEach(item => 
 Object.keys(item).forEach(key => 
 if (!result[key]) 
 result[key] = ;
 
 result[key].push(item[key]);
 );
);

console.log(result);

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = ;
arrayOfObjects.forEach(item => 
 Object.keys(item).forEach(key => 
 if (!result[key]) 
 result[key] = ;
 
 result[key].push(item[key]);
 );
);

console.log(result);

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = ;
arrayOfObjects.forEach(item => 
 Object.keys(item).forEach(key => 
 if (!result[key]) 
 result[key] = ;
 
 result[key].push(item[key]);
 );
);

console.log(result);

answered 2 hours ago

ssc-hrep3

4,67521551

answered 2 hours ago

ssc-hrep3

4,67521551

answered 2 hours ago

ssc-hrep3

4,67521551

answered 2 hours ago

ssc-hrep3

4,67521551

add a commentÂ |Â

up vote
4
down vote

You could reduce the array by iterating the entries and collecting the values, depending of the keys.

const
 array = [ name: 'Fred', surname: 'Shultz' , name: 'Anne', surname: 'Example' ],
 result = array.reduce((r, o) => ).push(v));
 return r;
 , Object.create(null));

console.log(result);

answered 2 hours ago

Nina Scholz

163k1280141

add a commentÂ |Â

up vote
4
down vote

You could reduce the array by iterating the entries and collecting the values, depending of the keys.

const
 array = [ name: 'Fred', surname: 'Shultz' , name: 'Anne', surname: 'Example' ],
 result = array.reduce((r, o) => ).push(v));
 return r;
 , Object.create(null));

console.log(result);

answered 2 hours ago

Nina Scholz

163k1280141

add a commentÂ |Â

up vote
4
down vote

You could reduce the array by iterating the entries and collecting the values, depending of the keys.

const
 array = [ name: 'Fred', surname: 'Shultz' , name: 'Anne', surname: 'Example' ],
 result = array.reduce((r, o) => ).push(v));
 return r;
 , Object.create(null));

console.log(result);

answered 2 hours ago

Nina Scholz

163k1280141

You could reduce the array by iterating the entries and collecting the values, depending of the keys.

const
 array = [ name: 'Fred', surname: 'Shultz' , name: 'Anne', surname: 'Example' ],
 result = array.reduce((r, o) => ).push(v));
 return r;
 , Object.create(null));

console.log(result);

const
 array = [ name: 'Fred', surname: 'Shultz' , name: 'Anne', surname: 'Example' ],
 result = array.reduce((r, o) => ).push(v));
 return r;
 , Object.create(null));

console.log(result);

const
 array = [ name: 'Fred', surname: 'Shultz' , name: 'Anne', surname: 'Example' ],
 result = array.reduce((r, o) => ).push(v));
 return r;
 , Object.create(null));

console.log(result);

answered 2 hours ago

Nina Scholz

163k1280141

answered 2 hours ago

Nina Scholz

163k1280141

answered 2 hours ago

Nina Scholz

163k1280141

answered 2 hours ago

Nina Scholz

163k1280141

add a commentÂ |Â

up vote
2
down vote

easy with lodash:

grouped = _.mapValues(arrayOfObjects[0], 
 (val, key) => _.map(arrayOfObjects, key))

pure es6

let grouped = ;

for (let obj of arrayOfObjects)
 for (let [key, val] of Object.entries(obj))
 grouped[key] = (grouped[key] || ).concat(val)

answered 2 hours ago

georg

140k31191287

add a commentÂ |Â

up vote
2
down vote

easy with lodash:

grouped = _.mapValues(arrayOfObjects[0], 
 (val, key) => _.map(arrayOfObjects, key))

pure es6

let grouped = ;

for (let obj of arrayOfObjects)
 for (let [key, val] of Object.entries(obj))
 grouped[key] = (grouped[key] || ).concat(val)

answered 2 hours ago

georg

140k31191287

add a commentÂ |Â

up vote
2
down vote

easy with lodash:

grouped = _.mapValues(arrayOfObjects[0], 
 (val, key) => _.map(arrayOfObjects, key))

pure es6

let grouped = ;

for (let obj of arrayOfObjects)
 for (let [key, val] of Object.entries(obj))
 grouped[key] = (grouped[key] || ).concat(val)

answered 2 hours ago

georg

140k31191287

easy with lodash:

grouped = _.mapValues(arrayOfObjects[0], 
 (val, key) => _.map(arrayOfObjects, key))

pure es6

let grouped = ;

for (let obj of arrayOfObjects)
 for (let [key, val] of Object.entries(obj))
 grouped[key] = (grouped[key] || ).concat(val)

answered 2 hours ago

georg

140k31191287

answered 2 hours ago

georg

140k31191287

answered 2 hours ago

georg

140k31191287

answered 2 hours ago

georg

140k31191287

add a commentÂ |Â

up vote
0
down vote

The following should work - uses a few ES6 helpers, but the key is Array#reduce which is in ES5.

const result = arrayOfObjects.reduce((acc, obj) => 
 for (let key in obj) 
 if (key in acc) 
 acc[key].push(obj[key]);
 
 else 
 acc[key] = [obj[key]];
 
 
 return acc;
, );

answered 2 hours ago

Robin Zigmond

88839

add a commentÂ |Â

up vote
0
down vote

The following should work - uses a few ES6 helpers, but the key is Array#reduce which is in ES5.

const result = arrayOfObjects.reduce((acc, obj) => 
 for (let key in obj) 
 if (key in acc) 
 acc[key].push(obj[key]);
 
 else 
 acc[key] = [obj[key]];
 
 
 return acc;
, );

answered 2 hours ago

Robin Zigmond

88839

add a commentÂ |Â

up vote
0
down vote

The following should work - uses a few ES6 helpers, but the key is Array#reduce which is in ES5.

const result = arrayOfObjects.reduce((acc, obj) => 
 for (let key in obj) 
 if (key in acc) 
 acc[key].push(obj[key]);
 
 else 
 acc[key] = [obj[key]];
 
 
 return acc;
, );

answered 2 hours ago

Robin Zigmond

88839

The following should work - uses a few ES6 helpers, but the key is Array#reduce which is in ES5.

const result = arrayOfObjects.reduce((acc, obj) => 
 for (let key in obj) 
 if (key in acc) 
 acc[key].push(obj[key]);
 
 else 
 acc[key] = [obj[key]];
 
 
 return acc;
, );

answered 2 hours ago

Robin Zigmond

88839

answered 2 hours ago

Robin Zigmond

88839

answered 2 hours ago

Robin Zigmond

88839

answered 2 hours ago

Robin Zigmond

88839

add a commentÂ |Â

up vote
0
down vote

Here is a lodash approach

 _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

var input = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

var res = _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

console.log(res);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

This will take care if the objects doesn't have exactly same key sets

edited 1 hour ago

answered 2 hours ago

Koushik Chatterjee

2,5173924

This results in a slightly different output structure than expected.
â€“Â ssc-hrep3
2 hours ago

Ohh, yeah, need to map the value, let me edit
â€“Â Koushik Chatterjee
2 hours ago

@ssc-hrep3 see edit, I forget to map it to the expected type of result
â€“Â Koushik Chatterjee
1 hour ago

add a commentÂ |Â

up vote
0
down vote

Here is a lodash approach

 _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

var input = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

var res = _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

console.log(res);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

This will take care if the objects doesn't have exactly same key sets

edited 1 hour ago

answered 2 hours ago

Koushik Chatterjee

2,5173924

This results in a slightly different output structure than expected.
â€“Â ssc-hrep3
2 hours ago

Ohh, yeah, need to map the value, let me edit
â€“Â Koushik Chatterjee
2 hours ago

@ssc-hrep3 see edit, I forget to map it to the expected type of result
â€“Â Koushik Chatterjee
1 hour ago

add a commentÂ |Â

up vote
0
down vote

Here is a lodash approach

 _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

var input = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

var res = _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

console.log(res);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

This will take care if the objects doesn't have exactly same key sets

edited 1 hour ago

answered 2 hours ago

Koushik Chatterjee

2,5173924

Here is a lodash approach

 _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

var input = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

var res = _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

console.log(res);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

This will take care if the objects doesn't have exactly same key sets

var input = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

var res = _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

console.log(res);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

var input = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

var res = _(input).flatMap(_.entries).groupBy(0).mapValues(v => _.map(v, 1)).value()

console.log(res);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

edited 1 hour ago

answered 2 hours ago

Koushik Chatterjee

2,5173924

edited 1 hour ago

answered 2 hours ago

Koushik Chatterjee

2,5173924

answered 2 hours ago

Koushik Chatterjee

2,5173924

answered 2 hours ago

Koushik Chatterjee

2,5173924

This results in a slightly different output structure than expected.
â€“Â ssc-hrep3
2 hours ago

Ohh, yeah, need to map the value, let me edit
â€“Â Koushik Chatterjee
2 hours ago

@ssc-hrep3 see edit, I forget to map it to the expected type of result
â€“Â Koushik Chatterjee
1 hour ago

add a commentÂ |Â

This results in a slightly different output structure than expected.
â€“Â ssc-hrep3
2 hours ago

Ohh, yeah, need to map the value, let me edit
â€“Â Koushik Chatterjee
2 hours ago

@ssc-hrep3 see edit, I forget to map it to the expected type of result
â€“Â Koushik Chatterjee
1 hour ago

This results in a slightly different output structure than expected.
â€“Â ssc-hrep3
2 hours ago

Ohh, yeah, need to map the value, let me edit
â€“Â Koushik Chatterjee
2 hours ago

@ssc-hrep3 see edit, I forget to map it to the expected type of result
â€“Â Koushik Chatterjee
1 hour ago

add a commentÂ |Â

up vote
0
down vote

You can use lodash's mergeWith like so:

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

Example:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>

edited 1 hour ago

answered 1 hour ago

ibrahim mahrir

20.2k41442

add a commentÂ |Â

up vote
0
down vote

You can use lodash's mergeWith like so:

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

Example:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>

edited 1 hour ago

answered 1 hour ago

ibrahim mahrir

20.2k41442

add a commentÂ |Â

up vote
0
down vote

You can use lodash's mergeWith like so:

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

Example:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>

edited 1 hour ago

answered 1 hour ago

ibrahim mahrir

20.2k41442

You can use lodash's mergeWith like so:

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

Example:

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>

const arrayOfObjects = [
 name: 'Fred', surname: 'Shultz', name: 'Anne', surname: 'Example'
];

const result = _.mergeWith(, ...arrayOfObjects, (value, objValue) =>
 (value || ).concat(objValue)
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>

edited 1 hour ago

answered 1 hour ago

ibrahim mahrir

20.2k41442

edited 1 hour ago

answered 1 hour ago

ibrahim mahrir

20.2k41442

answered 1 hour ago

ibrahim mahrir

20.2k41442

answered 1 hour ago

ibrahim mahrir

20.2k41442

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Short way with array reduce:

const arrayOfObjects = [
 name: "name1", surname: "surname1", name: 'Anne', surname: 'Example', name: 'name3', surname: 'Example3'
];
/*
name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']
*/
var result = arrayOfObjects.reduce((obj,current)=>
 (obj['name'] = obj['name'],);
console.log(result);

edited 1 hour ago

answered 1 hour ago

protoproto

47336

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up vote
0
down vote

Short way with array reduce:

const arrayOfObjects = [
 name: "name1", surname: "surname1", name: 'Anne', surname: 'Example', name: 'name3', surname: 'Example3'
];
/*
name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']
*/
var result = arrayOfObjects.reduce((obj,current)=>
 (obj['name'] = obj['name'],);
console.log(result);

edited 1 hour ago

answered 1 hour ago

protoproto

47336

add a commentÂ |Â

up vote
0
down vote

Short way with array reduce:

const arrayOfObjects = [
 name: "name1", surname: "surname1", name: 'Anne', surname: 'Example', name: 'name3', surname: 'Example3'
];
/*
name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']
*/
var result = arrayOfObjects.reduce((obj,current)=>
 (obj['name'] = obj['name'],);
console.log(result);

edited 1 hour ago

answered 1 hour ago

protoproto

47336

Short way with array reduce:

const arrayOfObjects = [
 name: "name1", surname: "surname1", name: 'Anne', surname: 'Example', name: 'name3', surname: 'Example3'
];
/*
name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']
*/
var result = arrayOfObjects.reduce((obj,current)=>
 (obj['name'] = obj['name'],);
console.log(result);

const arrayOfObjects = [
 name: "name1", surname: "surname1", name: 'Anne', surname: 'Example', name: 'name3', surname: 'Example3'
];
/*
name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']
*/
var result = arrayOfObjects.reduce((obj,current)=>
 (obj['name'] = obj['name'],);
console.log(result);

const arrayOfObjects = [
 name: "name1", surname: "surname1", name: 'Anne', surname: 'Example', name: 'name3', surname: 'Example3'
];
/*
name: ['Fred', 'Anne'], surname: ['Example', 'Shultz']
*/
var result = arrayOfObjects.reduce((obj,current)=>
 (obj['name'] = obj['name'],);
console.log(result);

edited 1 hour ago

answered 1 hour ago

protoproto

47336

edited 1 hour ago

answered 1 hour ago

protoproto

47336

answered 1 hour ago

protoproto

47336

answered 1 hour ago

protoproto

47336

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