Bamboozling Arithmetic!

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite












While creating some pgfmathsetmacro arithmetic macros, I stumbled upon a very perplexing result. Take the following example:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument

begintikzpicture
newcommandboxWidth6cm;
newcommandboxHeight1cm;

pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm %%%wtf
coordinate (Title) at (1cm + boxOffset,0);

draw [red] (0,0) -- (1,0);

node[draw, rounded corners=.3cm, color=red, minimum width=boxWidth, minimum height=boxHeight, text=black] at (Title) Hello;
endtikzpicture
enddocument


This outputs a very predictable result:
predictable result



However, if you remove * 1cm from my boxOffset macro, a totally unexpected result occurs:
unexpected output



What?! On the surface, this appears to be saying that 2 * 1 != 2 is a true statement!



To add to this, while I was playing around with creating an example LaTeX script for the following question on this forum, I stumbled upon a similar bamboozling arithmetic:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument
begintikzpicture
newcommandstrhello;

pgfmathsetmacronumOnewidth("str") * 1pt / 4cm; %%%wtf

node at (0, 0) str;
draw [color=black] (numOne, 0cm) -- (numOne,-1cm);

endtikzpicture
enddocument


The following example creates the very predictable output:



another predictable output



However, if I change the numOne to compute the following width("str") * 1pt / 2cm / 2cm, then I get a very unpredictable output:



another very unpredictable output



What?! This is telling me that the ridiculous statement x / 2 / 2 != x / 4 is true.



Can anyone shed some light on what is happening here? This is not the only time I have run into this bamboozling arithmetic and I am lost at what is happening.



bamboozle doggo



^This is how I feel right now.










share|improve this question







New contributor




Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • All arithmetic is performed internally in pt, so the 1cm is converted to 28.45274pt.
    – Phelype Oleinik
    5 hours ago










  • The result is stored in unit pt; with *1cm you get 85.35823, without it is 3.0; the quotient is 28.45274, which is the number of points in 1cm.
    – egreg
    5 hours ago














up vote
1
down vote

favorite












While creating some pgfmathsetmacro arithmetic macros, I stumbled upon a very perplexing result. Take the following example:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument

begintikzpicture
newcommandboxWidth6cm;
newcommandboxHeight1cm;

pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm %%%wtf
coordinate (Title) at (1cm + boxOffset,0);

draw [red] (0,0) -- (1,0);

node[draw, rounded corners=.3cm, color=red, minimum width=boxWidth, minimum height=boxHeight, text=black] at (Title) Hello;
endtikzpicture
enddocument


This outputs a very predictable result:
predictable result



However, if you remove * 1cm from my boxOffset macro, a totally unexpected result occurs:
unexpected output



What?! On the surface, this appears to be saying that 2 * 1 != 2 is a true statement!



To add to this, while I was playing around with creating an example LaTeX script for the following question on this forum, I stumbled upon a similar bamboozling arithmetic:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument
begintikzpicture
newcommandstrhello;

pgfmathsetmacronumOnewidth("str") * 1pt / 4cm; %%%wtf

node at (0, 0) str;
draw [color=black] (numOne, 0cm) -- (numOne,-1cm);

endtikzpicture
enddocument


The following example creates the very predictable output:



another predictable output



However, if I change the numOne to compute the following width("str") * 1pt / 2cm / 2cm, then I get a very unpredictable output:



another very unpredictable output



What?! This is telling me that the ridiculous statement x / 2 / 2 != x / 4 is true.



Can anyone shed some light on what is happening here? This is not the only time I have run into this bamboozling arithmetic and I am lost at what is happening.



bamboozle doggo



^This is how I feel right now.










share|improve this question







New contributor




Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • All arithmetic is performed internally in pt, so the 1cm is converted to 28.45274pt.
    – Phelype Oleinik
    5 hours ago










  • The result is stored in unit pt; with *1cm you get 85.35823, without it is 3.0; the quotient is 28.45274, which is the number of points in 1cm.
    – egreg
    5 hours ago












up vote
1
down vote

favorite









up vote
1
down vote

favorite











While creating some pgfmathsetmacro arithmetic macros, I stumbled upon a very perplexing result. Take the following example:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument

begintikzpicture
newcommandboxWidth6cm;
newcommandboxHeight1cm;

pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm %%%wtf
coordinate (Title) at (1cm + boxOffset,0);

draw [red] (0,0) -- (1,0);

node[draw, rounded corners=.3cm, color=red, minimum width=boxWidth, minimum height=boxHeight, text=black] at (Title) Hello;
endtikzpicture
enddocument


This outputs a very predictable result:
predictable result



However, if you remove * 1cm from my boxOffset macro, a totally unexpected result occurs:
unexpected output



What?! On the surface, this appears to be saying that 2 * 1 != 2 is a true statement!



To add to this, while I was playing around with creating an example LaTeX script for the following question on this forum, I stumbled upon a similar bamboozling arithmetic:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument
begintikzpicture
newcommandstrhello;

pgfmathsetmacronumOnewidth("str") * 1pt / 4cm; %%%wtf

node at (0, 0) str;
draw [color=black] (numOne, 0cm) -- (numOne,-1cm);

endtikzpicture
enddocument


The following example creates the very predictable output:



another predictable output



However, if I change the numOne to compute the following width("str") * 1pt / 2cm / 2cm, then I get a very unpredictable output:



another very unpredictable output



What?! This is telling me that the ridiculous statement x / 2 / 2 != x / 4 is true.



Can anyone shed some light on what is happening here? This is not the only time I have run into this bamboozling arithmetic and I am lost at what is happening.



bamboozle doggo



^This is how I feel right now.










share|improve this question







New contributor




Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











While creating some pgfmathsetmacro arithmetic macros, I stumbled upon a very perplexing result. Take the following example:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument

begintikzpicture
newcommandboxWidth6cm;
newcommandboxHeight1cm;

pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm %%%wtf
coordinate (Title) at (1cm + boxOffset,0);

draw [red] (0,0) -- (1,0);

node[draw, rounded corners=.3cm, color=red, minimum width=boxWidth, minimum height=boxHeight, text=black] at (Title) Hello;
endtikzpicture
enddocument


This outputs a very predictable result:
predictable result



However, if you remove * 1cm from my boxOffset macro, a totally unexpected result occurs:
unexpected output



What?! On the surface, this appears to be saying that 2 * 1 != 2 is a true statement!



To add to this, while I was playing around with creating an example LaTeX script for the following question on this forum, I stumbled upon a similar bamboozling arithmetic:



documentclassarticle
usepackagetikz
usepackagexstring

begindocument
begintikzpicture
newcommandstrhello;

pgfmathsetmacronumOnewidth("str") * 1pt / 4cm; %%%wtf

node at (0, 0) str;
draw [color=black] (numOne, 0cm) -- (numOne,-1cm);

endtikzpicture
enddocument


The following example creates the very predictable output:



another predictable output



However, if I change the numOne to compute the following width("str") * 1pt / 2cm / 2cm, then I get a very unpredictable output:



another very unpredictable output



What?! This is telling me that the ridiculous statement x / 2 / 2 != x / 4 is true.



Can anyone shed some light on what is happening here? This is not the only time I have run into this bamboozling arithmetic and I am lost at what is happening.



bamboozle doggo



^This is how I feel right now.







tikz-pgf pgfmath arithmetic






share|improve this question







New contributor




Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 5 hours ago









Dan Hoynoski

1517




1517




New contributor




Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Dan Hoynoski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • All arithmetic is performed internally in pt, so the 1cm is converted to 28.45274pt.
    – Phelype Oleinik
    5 hours ago










  • The result is stored in unit pt; with *1cm you get 85.35823, without it is 3.0; the quotient is 28.45274, which is the number of points in 1cm.
    – egreg
    5 hours ago
















  • All arithmetic is performed internally in pt, so the 1cm is converted to 28.45274pt.
    – Phelype Oleinik
    5 hours ago










  • The result is stored in unit pt; with *1cm you get 85.35823, without it is 3.0; the quotient is 28.45274, which is the number of points in 1cm.
    – egreg
    5 hours ago















All arithmetic is performed internally in pt, so the 1cm is converted to 28.45274pt.
– Phelype Oleinik
5 hours ago




All arithmetic is performed internally in pt, so the 1cm is converted to 28.45274pt.
– Phelype Oleinik
5 hours ago












The result is stored in unit pt; with *1cm you get 85.35823, without it is 3.0; the quotient is 28.45274, which is the number of points in 1cm.
– egreg
5 hours ago




The result is stored in unit pt; with *1cm you get 85.35823, without it is 3.0; the quotient is 28.45274, which is the number of points in 1cm.
– egreg
5 hours ago










2 Answers
2






active

oldest

votes

















up vote
3
down vote













Your assumption that multiplying by 1cm is the same as multiplying by 1 is wrong.



What about multiplying by 1in or 1mm?



The function pgfmathresult returns a number, not a dimension. For implementation reasons, the number 1 is stored as a length, precisely 1pt.



Therefore 3*1 is 3, but 3*1cm is 85.35823, because 1cm=28.45275pt (and then TeX’s rounding applies).






share|improve this answer



























    up vote
    2
    down vote













    The easiest way to address this is to see what the difference between the two calculations yield for boxOffset:



    enter image description here



    documentclassarticle

    usepackagetikz

    begindocument

    newcommandboxWidth6cm
    newcommandboxHeight1cm

    pgfmathsetmacroboxOffsetboxWidth / 2cm%
    verb|boxOffset| 1: boxOffset

    pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm%
    verb|boxOffset| 2: boxOffset

    enddocument


    In performing the division 6cm / 2cm, tikz converts the quantities to a uniform unit of measure (pts). However, in this case with similar measurements in the division, it results in merely "striping" the measurement, yielding in 3. This is understandable. Multiplying this result by 1cm, the value is first converted to pts (there are 28.45274 pts in every cm; see newlengthtemplen setlengthtemplen1cm thetemplen), yielding the desired result (3 x 28.45274 = 85.35822), with some floating point error.



    A similar argument would hold for your other calculations as lengths are converted to pts before performing the arithmetic.






    share|improve this answer




















      Your Answer







      StackExchange.ready(function()
      var channelOptions =
      tags: "".split(" "),
      id: "85"
      ;
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function()
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled)
      StackExchange.using("snippets", function()
      createEditor();
      );

      else
      createEditor();

      );

      function createEditor()
      StackExchange.prepareEditor(
      heartbeatType: 'answer',
      convertImagesToLinks: false,
      noModals: false,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: null,
      bindNavPrevention: true,
      postfix: "",
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      );



      );






      Dan Hoynoski is a new contributor. Be nice, and check out our Code of Conduct.









       

      draft saved


      draft discarded


















      StackExchange.ready(
      function ()
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f454835%2fbamboozling-arithmetic%23new-answer', 'question_page');

      );

      Post as a guest






























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote













      Your assumption that multiplying by 1cm is the same as multiplying by 1 is wrong.



      What about multiplying by 1in or 1mm?



      The function pgfmathresult returns a number, not a dimension. For implementation reasons, the number 1 is stored as a length, precisely 1pt.



      Therefore 3*1 is 3, but 3*1cm is 85.35823, because 1cm=28.45275pt (and then TeX’s rounding applies).






      share|improve this answer
























        up vote
        3
        down vote













        Your assumption that multiplying by 1cm is the same as multiplying by 1 is wrong.



        What about multiplying by 1in or 1mm?



        The function pgfmathresult returns a number, not a dimension. For implementation reasons, the number 1 is stored as a length, precisely 1pt.



        Therefore 3*1 is 3, but 3*1cm is 85.35823, because 1cm=28.45275pt (and then TeX’s rounding applies).






        share|improve this answer






















          up vote
          3
          down vote










          up vote
          3
          down vote









          Your assumption that multiplying by 1cm is the same as multiplying by 1 is wrong.



          What about multiplying by 1in or 1mm?



          The function pgfmathresult returns a number, not a dimension. For implementation reasons, the number 1 is stored as a length, precisely 1pt.



          Therefore 3*1 is 3, but 3*1cm is 85.35823, because 1cm=28.45275pt (and then TeX’s rounding applies).






          share|improve this answer












          Your assumption that multiplying by 1cm is the same as multiplying by 1 is wrong.



          What about multiplying by 1in or 1mm?



          The function pgfmathresult returns a number, not a dimension. For implementation reasons, the number 1 is stored as a length, precisely 1pt.



          Therefore 3*1 is 3, but 3*1cm is 85.35823, because 1cm=28.45275pt (and then TeX’s rounding applies).







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 5 hours ago









          egreg

          688k8518323080




          688k8518323080




















              up vote
              2
              down vote













              The easiest way to address this is to see what the difference between the two calculations yield for boxOffset:



              enter image description here



              documentclassarticle

              usepackagetikz

              begindocument

              newcommandboxWidth6cm
              newcommandboxHeight1cm

              pgfmathsetmacroboxOffsetboxWidth / 2cm%
              verb|boxOffset| 1: boxOffset

              pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm%
              verb|boxOffset| 2: boxOffset

              enddocument


              In performing the division 6cm / 2cm, tikz converts the quantities to a uniform unit of measure (pts). However, in this case with similar measurements in the division, it results in merely "striping" the measurement, yielding in 3. This is understandable. Multiplying this result by 1cm, the value is first converted to pts (there are 28.45274 pts in every cm; see newlengthtemplen setlengthtemplen1cm thetemplen), yielding the desired result (3 x 28.45274 = 85.35822), with some floating point error.



              A similar argument would hold for your other calculations as lengths are converted to pts before performing the arithmetic.






              share|improve this answer
























                up vote
                2
                down vote













                The easiest way to address this is to see what the difference between the two calculations yield for boxOffset:



                enter image description here



                documentclassarticle

                usepackagetikz

                begindocument

                newcommandboxWidth6cm
                newcommandboxHeight1cm

                pgfmathsetmacroboxOffsetboxWidth / 2cm%
                verb|boxOffset| 1: boxOffset

                pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm%
                verb|boxOffset| 2: boxOffset

                enddocument


                In performing the division 6cm / 2cm, tikz converts the quantities to a uniform unit of measure (pts). However, in this case with similar measurements in the division, it results in merely "striping" the measurement, yielding in 3. This is understandable. Multiplying this result by 1cm, the value is first converted to pts (there are 28.45274 pts in every cm; see newlengthtemplen setlengthtemplen1cm thetemplen), yielding the desired result (3 x 28.45274 = 85.35822), with some floating point error.



                A similar argument would hold for your other calculations as lengths are converted to pts before performing the arithmetic.






                share|improve this answer






















                  up vote
                  2
                  down vote










                  up vote
                  2
                  down vote









                  The easiest way to address this is to see what the difference between the two calculations yield for boxOffset:



                  enter image description here



                  documentclassarticle

                  usepackagetikz

                  begindocument

                  newcommandboxWidth6cm
                  newcommandboxHeight1cm

                  pgfmathsetmacroboxOffsetboxWidth / 2cm%
                  verb|boxOffset| 1: boxOffset

                  pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm%
                  verb|boxOffset| 2: boxOffset

                  enddocument


                  In performing the division 6cm / 2cm, tikz converts the quantities to a uniform unit of measure (pts). However, in this case with similar measurements in the division, it results in merely "striping" the measurement, yielding in 3. This is understandable. Multiplying this result by 1cm, the value is first converted to pts (there are 28.45274 pts in every cm; see newlengthtemplen setlengthtemplen1cm thetemplen), yielding the desired result (3 x 28.45274 = 85.35822), with some floating point error.



                  A similar argument would hold for your other calculations as lengths are converted to pts before performing the arithmetic.






                  share|improve this answer












                  The easiest way to address this is to see what the difference between the two calculations yield for boxOffset:



                  enter image description here



                  documentclassarticle

                  usepackagetikz

                  begindocument

                  newcommandboxWidth6cm
                  newcommandboxHeight1cm

                  pgfmathsetmacroboxOffsetboxWidth / 2cm%
                  verb|boxOffset| 1: boxOffset

                  pgfmathsetmacroboxOffsetboxWidth / 2cm * 1cm%
                  verb|boxOffset| 2: boxOffset

                  enddocument


                  In performing the division 6cm / 2cm, tikz converts the quantities to a uniform unit of measure (pts). However, in this case with similar measurements in the division, it results in merely "striping" the measurement, yielding in 3. This is understandable. Multiplying this result by 1cm, the value is first converted to pts (there are 28.45274 pts in every cm; see newlengthtemplen setlengthtemplen1cm thetemplen), yielding the desired result (3 x 28.45274 = 85.35822), with some floating point error.



                  A similar argument would hold for your other calculations as lengths are converted to pts before performing the arithmetic.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 5 hours ago









                  Werner

                  424k589281596




                  424k589281596




















                      Dan Hoynoski is a new contributor. Be nice, and check out our Code of Conduct.









                       

                      draft saved


                      draft discarded


















                      Dan Hoynoski is a new contributor. Be nice, and check out our Code of Conduct.












                      Dan Hoynoski is a new contributor. Be nice, and check out our Code of Conduct.











                      Dan Hoynoski is a new contributor. Be nice, and check out our Code of Conduct.













                       


                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function ()
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f454835%2fbamboozling-arithmetic%23new-answer', 'question_page');

                      );

                      Post as a guest













































































                      Comments

                      Popular posts from this blog

                      Long meetings (6-7 hours a day): Being “babysat” by supervisor

                      Is the Concept of Multiple Fantasy Races Scientifically Flawed? [closed]

                      Confectionery