How can a node remember it's previous position?

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up vote
4
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Consider the following MWE:



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at (newnumber,current) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


Here is the output:



Screenshot



My question is: How can the green node remeber it's previous position, so that the desired result looks like a dotted green line?






tikz-pgf nodes code-review remember







share|improve this question

















  • 1




    This is probably suboptimal, but at each iteration you could do coordinate (greennoden) at (newnumber,current); then put the node in a foreach nn in 2,...,n and use node [...] at (greennodenn) ;... It's not remembering its last position, but you are saving every position and drawing them at each iteration.
    – Phelype Oleinik
    23 mins ago











  • Nice work, you could have started with a hexagon and stopped like Archimedes with a regular 96 side polygon.
    – AndréC
    5 mins ago














up vote
4
down vote

favorite












Consider the following MWE:



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at (newnumber,current) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


Here is the output:



Screenshot



My question is: How can the green node remeber it's previous position, so that the desired result looks like a dotted green line?






tikz-pgf nodes code-review remember







share|improve this question

















  • 1




    This is probably suboptimal, but at each iteration you could do coordinate (greennoden) at (newnumber,current); then put the node in a foreach nn in 2,...,n and use node [...] at (greennodenn) ;... It's not remembering its last position, but you are saving every position and drawing them at each iteration.
    – Phelype Oleinik
    23 mins ago











  • Nice work, you could have started with a hexagon and stopped like Archimedes with a regular 96 side polygon.
    – AndréC
    5 mins ago












up vote
4
down vote

favorite









up vote
4
down vote

favorite











Consider the following MWE:



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at (newnumber,current) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


Here is the output:



Screenshot



My question is: How can the green node remeber it's previous position, so that the desired result looks like a dotted green line?






tikz-pgf nodes code-review remember







share|improve this question













Consider the following MWE:



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at (newnumber,current) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


Here is the output:



Screenshot



My question is: How can the green node remeber it's previous position, so that the desired result looks like a dotted green line?






tikz-pgf nodes code-review remember




tikz-pgf nodes code-review remember






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 31 mins ago









current_user

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2,6411428







  • 1




    This is probably suboptimal, but at each iteration you could do coordinate (greennoden) at (newnumber,current); then put the node in a foreach nn in 2,...,n and use node [...] at (greennodenn) ;... It's not remembering its last position, but you are saving every position and drawing them at each iteration.
    – Phelype Oleinik
    23 mins ago











  • Nice work, you could have started with a hexagon and stopped like Archimedes with a regular 96 side polygon.
    – AndréC
    5 mins ago












  • 1




    This is probably suboptimal, but at each iteration you could do coordinate (greennoden) at (newnumber,current); then put the node in a foreach nn in 2,...,n and use node [...] at (greennodenn) ;... It's not remembering its last position, but you are saving every position and drawing them at each iteration.
    – Phelype Oleinik
    23 mins ago











  • Nice work, you could have started with a hexagon and stopped like Archimedes with a regular 96 side polygon.
    – AndréC
    5 mins ago







1




1




This is probably suboptimal, but at each iteration you could do coordinate (greennoden) at (newnumber,current); then put the node in a foreach nn in 2,...,n and use node [...] at (greennodenn) ;... It's not remembering its last position, but you are saving every position and drawing them at each iteration.
– Phelype Oleinik
23 mins ago





This is probably suboptimal, but at each iteration you could do coordinate (greennoden) at (newnumber,current); then put the node in a foreach nn in 2,...,n and use node [...] at (greennodenn) ;... It's not remembering its last position, but you are saving every position and drawing them at each iteration.
– Phelype Oleinik
23 mins ago













Nice work, you could have started with a hexagon and stopped like Archimedes with a regular 96 side polygon.
– AndréC
5 mins ago




Nice work, you could have started with a hexagon and stopped like Archimedes with a regular 96 side polygon.
– AndréC
5 mins ago










1 Answer
1






active

oldest

votes

















up vote
3
down vote













Just build up a list successively.



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 ifnumn=2
 xdefLstnewnumber/current
 else
 xdefLstLst,newnumber/current
 fi
 foreach X/Y in Lst
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at
 (X,Y) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


enter image description here






share|improve this answer




















  • I was just about to propose an uglier version of this ^^
    – BambOo
    15 mins ago










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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote













Just build up a list successively.



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 ifnumn=2
 xdefLstnewnumber/current
 else
 xdefLstLst,newnumber/current
 fi
 foreach X/Y in Lst
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at
 (X,Y) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


enter image description here






share|improve this answer




















  • I was just about to propose an uglier version of this ^^
    – BambOo
    15 mins ago














up vote
3
down vote













Just build up a list successively.



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 ifnumn=2
 xdefLstnewnumber/current
 else
 xdefLstLst,newnumber/current
 fi
 foreach X/Y in Lst
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at
 (X,Y) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


enter image description here






share|improve this answer




















  • I was just about to propose an uglier version of this ^^
    – BambOo
    15 mins ago












up vote
3
down vote










up vote
3
down vote









Just build up a list successively.



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 ifnumn=2
 xdefLstnewnumber/current
 else
 xdefLstLst,newnumber/current
 fi
 foreach X/Y in Lst
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at
 (X,Y) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


enter image description here






share|improve this answer












Just build up a list successively.



documentclass[border=5pt,tikz]standalone
begindocument
foreach n in 2,3,...,20

 begintikzpicture
 useasboundingbox (-6,-4) rectangle (2,1);
 pgfmathsetmacronumber2*n
 node at (1.5,.5) $n = pgfmathprintnumbernumber$;
 pgfmathsetmacrosamples360/n
 pgfmathsetmacrosampleslimit360-samples
 pgfmathsetmacropii3.14
 pgfmathsetmacrolimit360/samples-1
 pgfmathsetmacrocurrent(pii/n)*limit
 node[left] at (-1.5,.5) tiny
 begintabularlll
 $A_mathrmreal$ &=& 3.14 \
 $A_mathrmcurrent$ &=& pgfmathprintnumbercurrent
 endtabular
 ;
 foreach x in 0,samples,...,sampleslimit
 
 pgfmathsetmacroarcanglesamples/2
 fill[red] (x:1) arc(x:x+arcangle:1) -- (0,0) -- cycle;
 fill[blue] (x+arcangle:1) arc(x+arcangle:x+2*arcangle:1) -- (0,0) -- cycle;
 
 pgfmathsetmacrolimit360/samples-1
 foreach x in 0,1,...,limit
 
 pgfmathsetmacroshiftx*2*sin(samples/4)
 pgfmathsetmacrohshiftlimit*sin(samples/4)
 fill[xshift=-hshift cm,red,xshift=shift cm,yshift=-1.5cm] (-90-samples/4:1) arc(-90-samples/4:-90+samples/4:1) -- (0,0) -- cycle;
 fill[blue,yshift=-1.5cm,xshift=-hshift cm,xshift=shift cm] (-90-samples/4:1) -- (0,0) arc(90-samples/4:90+samples/4:1) -- cycle;
 
 draw[xshift=-6cm,yshift=-4cm,<->] (0,3.5) -- (0,0) -- (4,0);
 pgfmathsetmacronewnumbern/5
 ifnumn=2
 xdefLstnewnumber/current
 else
 xdefLstLst,newnumber/current
 fi
 foreach X/Y in Lst
 node[xshift=-6cm,yshift=-4cm,fill=green,circle,inner sep=1pt] at
 (X,Y) ;
 draw[xshift=-6cm,yshift=-4cm,red,dashed] (0,pii) --+ (3.7,0) node[above left] $A_mathrmreal = pi$;
 endtikzpicture

enddocument


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered 21 mins ago









marmot

63.8k468137




63.8k468137











  • I was just about to propose an uglier version of this ^^
    – BambOo
    15 mins ago
















  • I was just about to propose an uglier version of this ^^
    – BambOo
    15 mins ago















I was just about to propose an uglier version of this ^^
– BambOo
15 mins ago




I was just about to propose an uglier version of this ^^
– BambOo
15 mins ago

















 

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What does second last employer means? [closed]

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Clash Royale CLAN TAG #URR8PPP .everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0; up vote -3 down vote favorite Say, for example I have worked in the following companies, Company A => 2010 - 2011 Company B => 2011 - 2012 Company C => 2012 - Till Date Company D => Have offer Now assume Company D is asking to submit documents from my second last employer. So from the list of companies given, which company would be qualified as second last employer? software-industry employer share | improve this question asked Aug 10 '14 at 5:16 Rajaprabhu Aravindasamy 559 1 6 13 closed as off-topic by Jim G., jmort253 ♦ Aug 11 '14 at 1:58 This question appears to be off-topic. The users who voted to close gave this specific reason: "Questions seeking advice on company-specific regulations, agreements, or policies should be directed to your manager or HR department. Questions that address...
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List of Gilmore Girls characters

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The season three cast—(Back row): Lane, Michel, Paris, Emily, Richard, Sookie, Miss Patty, Kirk; Front row: Jess, Luke, Lorelai, Rory, Dean This is a list of characters for the comedy-drama television series Gilmore Girls . Contents 1 Main characters 1.1 Lorelai Gilmore 1.2 Rory Gilmore 1.3 Sookie St. James 1.4 Lane Kim 1.5 Michel Gerard 1.6 Luke Danes 1.7 Emily Gilmore 1.8 Richard Gilmore 1.9 Paris Geller 1.10 Dean Forester 1.11 Jess Mariano 1.12 Kirk Gleason 1.13 Jason Stiles 1.14 Logan Huntzberger 2 Major recurring characters 2.1 Christopher Hayden 2.2 Jackson Belleville 2.3 Mrs. Kim 2.4 Tristin DuGray 2.5 Max Medina 2.6 Taylor Doose 2.7 Dave Rygalski 2.8 Marty 3 Recurring characters 3.1 Stars Hollow 3.2 Chilton 3.3 Yale 3.4 Other 4 Notable guest stars 5 Unseen characters 6 Notes 7 References Main characters Actor Character Appearances Season 1 Season 2 Season 3 Season 4 Season 5 Season 6 Season 7 A Year in the Life Lauren Graham Lorelai Gilmore...
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Confectionery

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Prepared foods made with a lot of sugar or other cabohydrates "Sweetmeat" redirects here. For the racehorse, see Sweetmeat (horse). Not to be confused with Sweetbread. This Kransekake is a traditional Scandinavian baker's confection. Confectionery is the art of making confections , which are food items that are rich in sugar and carbohydrates. Exact definitions are difficult. [1] In general, though, confectionery is divided into two broad and somewhat overlapping categories, bakers' confections and sugar confections. [2] Bakers' confectionery, also called flour confections , includes principally sweet pastries, cakes, and similar baked goods. Sugar confectionery includes candies ( sweets in British English), candied nuts, chocolates, chewing gum, bubble gum, pastillage, and other confections that are made primarily of sugar. In some cases, chocolate confections (confections made of chocolate) are treated as a separate category, as are sugar-free versions of ...
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