Can a Single Supply Powered Op-Amp Handle Negative Input Voltage?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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3
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I have an input sine wave at 300mV peak to peak. I want to filter this sine wave to eliminate noise and distortion.



I am planning to use the LMx58-N op-amp family, powered using a single supply: 3V to 32V.



Circuitry proposed will be based on the Multiple-Feedback Topology, as shown:



enter image description here



Considering the input signal to be at 100kHz +-10%, I want the filter to work adequately and without any damage to the op-amp. I also want to adhere to good electronic design principles.



Can I pass the signal directly into the above circuit, or should I bias the input signal ?



Any tips and/or suggestions would be greatly appreciated.






voltage op-amp filter single-supply-op-amp







share|improve this question























  • Read the datasheet! Section 6.1 Absolute Maximum Ratings gives the absolute minimum input voltage. But that's to avoid damage, not necessarily for practical operation.
    – Finbarr
    5 hours ago











  • Some can. This one can't.
    – Felthry
    5 hours ago






  • 1




    This circuit is DC-blocked by Cin. Thus DC components do not matter.
    – analogsystemsrf
    5 hours ago














up vote
3
down vote

favorite












I have an input sine wave at 300mV peak to peak. I want to filter this sine wave to eliminate noise and distortion.



I am planning to use the LMx58-N op-amp family, powered using a single supply: 3V to 32V.



Circuitry proposed will be based on the Multiple-Feedback Topology, as shown:



enter image description here



Considering the input signal to be at 100kHz +-10%, I want the filter to work adequately and without any damage to the op-amp. I also want to adhere to good electronic design principles.



Can I pass the signal directly into the above circuit, or should I bias the input signal ?



Any tips and/or suggestions would be greatly appreciated.






voltage op-amp filter single-supply-op-amp







share|improve this question























  • Read the datasheet! Section 6.1 Absolute Maximum Ratings gives the absolute minimum input voltage. But that's to avoid damage, not necessarily for practical operation.
    – Finbarr
    5 hours ago











  • Some can. This one can't.
    – Felthry
    5 hours ago






  • 1




    This circuit is DC-blocked by Cin. Thus DC components do not matter.
    – analogsystemsrf
    5 hours ago












up vote
3
down vote

favorite









up vote
3
down vote

favorite











I have an input sine wave at 300mV peak to peak. I want to filter this sine wave to eliminate noise and distortion.



I am planning to use the LMx58-N op-amp family, powered using a single supply: 3V to 32V.



Circuitry proposed will be based on the Multiple-Feedback Topology, as shown:



enter image description here



Considering the input signal to be at 100kHz +-10%, I want the filter to work adequately and without any damage to the op-amp. I also want to adhere to good electronic design principles.



Can I pass the signal directly into the above circuit, or should I bias the input signal ?



Any tips and/or suggestions would be greatly appreciated.






voltage op-amp filter single-supply-op-amp







share|improve this question















I have an input sine wave at 300mV peak to peak. I want to filter this sine wave to eliminate noise and distortion.



I am planning to use the LMx58-N op-amp family, powered using a single supply: 3V to 32V.



Circuitry proposed will be based on the Multiple-Feedback Topology, as shown:



enter image description here



Considering the input signal to be at 100kHz +-10%, I want the filter to work adequately and without any damage to the op-amp. I also want to adhere to good electronic design principles.



Can I pass the signal directly into the above circuit, or should I bias the input signal ?



Any tips and/or suggestions would be greatly appreciated.






voltage op-amp filter single-supply-op-amp




voltage op-amp filter single-supply-op-amp






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago

























asked 5 hours ago









Rrz0

782219




782219











  • Read the datasheet! Section 6.1 Absolute Maximum Ratings gives the absolute minimum input voltage. But that's to avoid damage, not necessarily for practical operation.
    – Finbarr
    5 hours ago











  • Some can. This one can't.
    – Felthry
    5 hours ago






  • 1




    This circuit is DC-blocked by Cin. Thus DC components do not matter.
    – analogsystemsrf
    5 hours ago
















  • Read the datasheet! Section 6.1 Absolute Maximum Ratings gives the absolute minimum input voltage. But that's to avoid damage, not necessarily for practical operation.
    – Finbarr
    5 hours ago











  • Some can. This one can't.
    – Felthry
    5 hours ago






  • 1




    This circuit is DC-blocked by Cin. Thus DC components do not matter.
    – analogsystemsrf
    5 hours ago















Read the datasheet! Section 6.1 Absolute Maximum Ratings gives the absolute minimum input voltage. But that's to avoid damage, not necessarily for practical operation.
– Finbarr
5 hours ago





Read the datasheet! Section 6.1 Absolute Maximum Ratings gives the absolute minimum input voltage. But that's to avoid damage, not necessarily for practical operation.
– Finbarr
5 hours ago













Some can. This one can't.
– Felthry
5 hours ago




Some can. This one can't.
– Felthry
5 hours ago




1




1




This circuit is DC-blocked by Cin. Thus DC components do not matter.
– analogsystemsrf
5 hours ago




This circuit is DC-blocked by Cin. Thus DC components do not matter.
– analogsystemsrf
5 hours ago










1 Answer
1






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up vote
3
down vote













The bias is signposted already as Vcc/2 (mid-rail supply). In the quiescent state VOUT will be at Vcc too so you may need a DC-blocking capacitor on the output too.



R1 and R2 are a potential divider and form an input attenuator.



Read the datasheet carefully to understand what the maximum output voltage swing can be when operating at low voltage at the load resistance value you are proposing.






share|improve this answer




















  • Many thanks for your suggestions and pointers. I am a beginner when it comes to electronics and do not fully understand your last sentence. Are you referring to the voltage gain that can be achieved when operating at the proposed voltage and load resistance?
    – Rrz0
    5 hours ago







  • 1




    Yes. Operational amplifier circuits often have outputs that can not come close to the power supply rails. An output that can't drive closer than two diode drops is common (because of a double emitter follower in the output stage). This often comes as a surprise to the newbie (and sometimes even the experienced). There are op-amps that can swing the output from rail to rail -- but you have to find them.
    – TimWescott
    3 hours ago










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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote













The bias is signposted already as Vcc/2 (mid-rail supply). In the quiescent state VOUT will be at Vcc too so you may need a DC-blocking capacitor on the output too.



R1 and R2 are a potential divider and form an input attenuator.



Read the datasheet carefully to understand what the maximum output voltage swing can be when operating at low voltage at the load resistance value you are proposing.






share|improve this answer




















  • Many thanks for your suggestions and pointers. I am a beginner when it comes to electronics and do not fully understand your last sentence. Are you referring to the voltage gain that can be achieved when operating at the proposed voltage and load resistance?
    – Rrz0
    5 hours ago







  • 1




    Yes. Operational amplifier circuits often have outputs that can not come close to the power supply rails. An output that can't drive closer than two diode drops is common (because of a double emitter follower in the output stage). This often comes as a surprise to the newbie (and sometimes even the experienced). There are op-amps that can swing the output from rail to rail -- but you have to find them.
    – TimWescott
    3 hours ago














up vote
3
down vote













The bias is signposted already as Vcc/2 (mid-rail supply). In the quiescent state VOUT will be at Vcc too so you may need a DC-blocking capacitor on the output too.



R1 and R2 are a potential divider and form an input attenuator.



Read the datasheet carefully to understand what the maximum output voltage swing can be when operating at low voltage at the load resistance value you are proposing.






share|improve this answer




















  • Many thanks for your suggestions and pointers. I am a beginner when it comes to electronics and do not fully understand your last sentence. Are you referring to the voltage gain that can be achieved when operating at the proposed voltage and load resistance?
    – Rrz0
    5 hours ago







  • 1




    Yes. Operational amplifier circuits often have outputs that can not come close to the power supply rails. An output that can't drive closer than two diode drops is common (because of a double emitter follower in the output stage). This often comes as a surprise to the newbie (and sometimes even the experienced). There are op-amps that can swing the output from rail to rail -- but you have to find them.
    – TimWescott
    3 hours ago












up vote
3
down vote










up vote
3
down vote









The bias is signposted already as Vcc/2 (mid-rail supply). In the quiescent state VOUT will be at Vcc too so you may need a DC-blocking capacitor on the output too.



R1 and R2 are a potential divider and form an input attenuator.



Read the datasheet carefully to understand what the maximum output voltage swing can be when operating at low voltage at the load resistance value you are proposing.






share|improve this answer












The bias is signposted already as Vcc/2 (mid-rail supply). In the quiescent state VOUT will be at Vcc too so you may need a DC-blocking capacitor on the output too.



R1 and R2 are a potential divider and form an input attenuator.



Read the datasheet carefully to understand what the maximum output voltage swing can be when operating at low voltage at the load resistance value you are proposing.







share|improve this answer












share|improve this answer



share|improve this answer










answered 5 hours ago









Transistor

76.4k575167




76.4k575167











  • Many thanks for your suggestions and pointers. I am a beginner when it comes to electronics and do not fully understand your last sentence. Are you referring to the voltage gain that can be achieved when operating at the proposed voltage and load resistance?
    – Rrz0
    5 hours ago







  • 1




    Yes. Operational amplifier circuits often have outputs that can not come close to the power supply rails. An output that can't drive closer than two diode drops is common (because of a double emitter follower in the output stage). This often comes as a surprise to the newbie (and sometimes even the experienced). There are op-amps that can swing the output from rail to rail -- but you have to find them.
    – TimWescott
    3 hours ago
















  • Many thanks for your suggestions and pointers. I am a beginner when it comes to electronics and do not fully understand your last sentence. Are you referring to the voltage gain that can be achieved when operating at the proposed voltage and load resistance?
    – Rrz0
    5 hours ago







  • 1




    Yes. Operational amplifier circuits often have outputs that can not come close to the power supply rails. An output that can't drive closer than two diode drops is common (because of a double emitter follower in the output stage). This often comes as a surprise to the newbie (and sometimes even the experienced). There are op-amps that can swing the output from rail to rail -- but you have to find them.
    – TimWescott
    3 hours ago















Many thanks for your suggestions and pointers. I am a beginner when it comes to electronics and do not fully understand your last sentence. Are you referring to the voltage gain that can be achieved when operating at the proposed voltage and load resistance?
– Rrz0
5 hours ago





Many thanks for your suggestions and pointers. I am a beginner when it comes to electronics and do not fully understand your last sentence. Are you referring to the voltage gain that can be achieved when operating at the proposed voltage and load resistance?
– Rrz0
5 hours ago





1




1




Yes. Operational amplifier circuits often have outputs that can not come close to the power supply rails. An output that can't drive closer than two diode drops is common (because of a double emitter follower in the output stage). This often comes as a surprise to the newbie (and sometimes even the experienced). There are op-amps that can swing the output from rail to rail -- but you have to find them.
– TimWescott
3 hours ago




Yes. Operational amplifier circuits often have outputs that can not come close to the power supply rails. An output that can't drive closer than two diode drops is common (because of a double emitter follower in the output stage). This often comes as a surprise to the newbie (and sometimes even the experienced). There are op-amps that can swing the output from rail to rail -- but you have to find them.
– TimWescott
3 hours ago

















 

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