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Can any body be uniform in the universe?
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If take any body in the shape of a rod and Stretch that, after it reaches breaking dress it breaks at one point.even though we apply same stress on each and every part of the rod it broke at one point. If it's uniform it should break at all points because breaking stress is same for all the parts of body as it's uniform
stress-strain
asked 15 mins ago
Sai Charan Reddy
15219
add a comment |Â
up vote
2
down vote
favorite
If take any body in the shape of a rod and Stretch that, after it reaches breaking dress it breaks at one point.even though we apply same stress on each and every part of the rod it broke at one point. If it's uniform it should break at all points because breaking stress is same for all the parts of body as it's uniform
stress-strain
asked 15 mins ago
Sai Charan Reddy
15219
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
If take any body in the shape of a rod and Stretch that, after it reaches breaking dress it breaks at one point.even though we apply same stress on each and every part of the rod it broke at one point. If it's uniform it should break at all points because breaking stress is same for all the parts of body as it's uniform
stress-strain
asked 15 mins ago
Sai Charan Reddy
15219
If take any body in the shape of a rod and Stretch that, after it reaches breaking dress it breaks at one point.even though we apply same stress on each and every part of the rod it broke at one point. If it's uniform it should break at all points because breaking stress is same for all the parts of body as it's uniform
stress-strain
stress-strain
asked 15 mins ago
Sai Charan Reddy
15219
asked 15 mins ago
Sai Charan Reddy
15219
asked 15 mins ago
Sai Charan Reddy
15219
asked 15 mins ago
Sai Charan Reddy
15219
asked 15 mins ago
Sai Charan Reddy
15219
15219
add a comment |Â
add a comment |Â
2 Answers
2
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oldest
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up vote
1
down vote
Uniform bodies are idealizations like frictionless surfaces or no air resistance. They make the work easier. In reality there will be slight deviations in material properties (such as density) along various parts of the body. In your example this deviations become more and more important as the body is stretched (which the stretching method will also have some asymmetries as well) until we get a single breaking point.
answered 10 mins ago
Aaron Stevens
5,3432828
add a comment |Â
up vote
1
down vote
You could consider it as one more demonstration of the underlying quantum mechanical frame keeping atoms and molecules bonded together. Quantum mechanics is a probabilistic theory, and which bond will "break" depends on the square of the wavefunction describing the rod, with a probability which manifests in this one instance of breakage.
To get the probability curve for the rod would be a laborious process, as it consists of order of 10^23 atoms/molecules and the number of experiments needed to plot a probability of which atom or group of atoms "breaks" will take forever.
answered 9 mins ago
anna v
153k7146436
I'll take macroscopic, you take microscopic :) +1
– Aaron Stevens
7 mins ago
@AaronStevens yes, the macroscopic defects would have to be added to the probability also, and would be more important as a break has to cover a plane replete with atoms and molecules. I just thought it fun to go back to the basic quantum mechanical nature. even if it were completely uniform, there would still be a "random" probability of breakage due to the probabilistic nature of quantum mechanics.
– anna v
4 mins ago
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Uniform bodies are idealizations like frictionless surfaces or no air resistance. They make the work easier. In reality there will be slight deviations in material properties (such as density) along various parts of the body. In your example this deviations become more and more important as the body is stretched (which the stretching method will also have some asymmetries as well) until we get a single breaking point.
answered 10 mins ago
Aaron Stevens
5,3432828
add a comment |Â
up vote
1
down vote
Uniform bodies are idealizations like frictionless surfaces or no air resistance. They make the work easier. In reality there will be slight deviations in material properties (such as density) along various parts of the body. In your example this deviations become more and more important as the body is stretched (which the stretching method will also have some asymmetries as well) until we get a single breaking point.
answered 10 mins ago
Aaron Stevens
5,3432828
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Uniform bodies are idealizations like frictionless surfaces or no air resistance. They make the work easier. In reality there will be slight deviations in material properties (such as density) along various parts of the body. In your example this deviations become more and more important as the body is stretched (which the stretching method will also have some asymmetries as well) until we get a single breaking point.
answered 10 mins ago
Aaron Stevens
5,3432828
Uniform bodies are idealizations like frictionless surfaces or no air resistance. They make the work easier. In reality there will be slight deviations in material properties (such as density) along various parts of the body. In your example this deviations become more and more important as the body is stretched (which the stretching method will also have some asymmetries as well) until we get a single breaking point.
answered 10 mins ago
Aaron Stevens
5,3432828
answered 10 mins ago
Aaron Stevens
5,3432828
answered 10 mins ago
Aaron Stevens
5,3432828
answered 10 mins ago
Aaron Stevens
5,3432828
5,3432828
add a comment |Â
add a comment |Â
up vote
1
down vote
You could consider it as one more demonstration of the underlying quantum mechanical frame keeping atoms and molecules bonded together. Quantum mechanics is a probabilistic theory, and which bond will "break" depends on the square of the wavefunction describing the rod, with a probability which manifests in this one instance of breakage.
To get the probability curve for the rod would be a laborious process, as it consists of order of 10^23 atoms/molecules and the number of experiments needed to plot a probability of which atom or group of atoms "breaks" will take forever.
answered 9 mins ago
anna v
153k7146436
I'll take macroscopic, you take microscopic :) +1
– Aaron Stevens
7 mins ago
@AaronStevens yes, the macroscopic defects would have to be added to the probability also, and would be more important as a break has to cover a plane replete with atoms and molecules. I just thought it fun to go back to the basic quantum mechanical nature. even if it were completely uniform, there would still be a "random" probability of breakage due to the probabilistic nature of quantum mechanics.
– anna v
4 mins ago
add a comment |Â
up vote
1
down vote
You could consider it as one more demonstration of the underlying quantum mechanical frame keeping atoms and molecules bonded together. Quantum mechanics is a probabilistic theory, and which bond will "break" depends on the square of the wavefunction describing the rod, with a probability which manifests in this one instance of breakage.
To get the probability curve for the rod would be a laborious process, as it consists of order of 10^23 atoms/molecules and the number of experiments needed to plot a probability of which atom or group of atoms "breaks" will take forever.
answered 9 mins ago
anna v
153k7146436
I'll take macroscopic, you take microscopic :) +1
– Aaron Stevens
7 mins ago
@AaronStevens yes, the macroscopic defects would have to be added to the probability also, and would be more important as a break has to cover a plane replete with atoms and molecules. I just thought it fun to go back to the basic quantum mechanical nature. even if it were completely uniform, there would still be a "random" probability of breakage due to the probabilistic nature of quantum mechanics.
– anna v
4 mins ago
add a comment |Â
up vote
1
down vote
up vote
1
down vote
You could consider it as one more demonstration of the underlying quantum mechanical frame keeping atoms and molecules bonded together. Quantum mechanics is a probabilistic theory, and which bond will "break" depends on the square of the wavefunction describing the rod, with a probability which manifests in this one instance of breakage.
To get the probability curve for the rod would be a laborious process, as it consists of order of 10^23 atoms/molecules and the number of experiments needed to plot a probability of which atom or group of atoms "breaks" will take forever.
answered 9 mins ago
anna v
153k7146436
You could consider it as one more demonstration of the underlying quantum mechanical frame keeping atoms and molecules bonded together. Quantum mechanics is a probabilistic theory, and which bond will "break" depends on the square of the wavefunction describing the rod, with a probability which manifests in this one instance of breakage.
To get the probability curve for the rod would be a laborious process, as it consists of order of 10^23 atoms/molecules and the number of experiments needed to plot a probability of which atom or group of atoms "breaks" will take forever.
answered 9 mins ago
anna v
153k7146436
answered 9 mins ago
anna v
153k7146436
answered 9 mins ago
anna v
153k7146436
answered 9 mins ago
anna v
153k7146436
153k7146436
I'll take macroscopic, you take microscopic :) +1
– Aaron Stevens
7 mins ago
@AaronStevens yes, the macroscopic defects would have to be added to the probability also, and would be more important as a break has to cover a plane replete with atoms and molecules. I just thought it fun to go back to the basic quantum mechanical nature. even if it were completely uniform, there would still be a "random" probability of breakage due to the probabilistic nature of quantum mechanics.
– anna v
4 mins ago
add a comment |Â
I'll take macroscopic, you take microscopic :) +1
– Aaron Stevens
7 mins ago
@AaronStevens yes, the macroscopic defects would have to be added to the probability also, and would be more important as a break has to cover a plane replete with atoms and molecules. I just thought it fun to go back to the basic quantum mechanical nature. even if it were completely uniform, there would still be a "random" probability of breakage due to the probabilistic nature of quantum mechanics.
– anna v
4 mins ago
I'll take macroscopic, you take microscopic :) +1
– Aaron Stevens
7 mins ago
I'll take macroscopic, you take microscopic :) +1
– Aaron Stevens
7 mins ago
@AaronStevens yes, the macroscopic defects would have to be added to the probability also, and would be more important as a break has to cover a plane replete with atoms and molecules. I just thought it fun to go back to the basic quantum mechanical nature. even if it were completely uniform, there would still be a "random" probability of breakage due to the probabilistic nature of quantum mechanics.
– anna v
4 mins ago
@AaronStevens yes, the macroscopic defects would have to be added to the probability also, and would be more important as a break has to cover a plane replete with atoms and molecules. I just thought it fun to go back to the basic quantum mechanical nature. even if it were completely uniform, there would still be a "random" probability of breakage due to the probabilistic nature of quantum mechanics.
– anna v
4 mins ago
add a comment |Â
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