Restricting the domain of a StreamPlot to a non rectangular region

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First, I should say I am at best an advanced amateur at Mathematica, and that generally speaking my knowledge of programming (in any language) is more in computation than visualization.



There is a model I am working on for which I have recently shown there is a feasibility region: $$mathcalR = (x,y) in [0,infty)times[0, infty) : x+y leq L.$$ Of course this is a triangular subregion of the first quadrant. I wish to restrict the domain of the streamplots I am generating to $mathcalR$.



From looking at the documentation I have constructed the following code:



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L]


which works fine, but of course gives me a large amount of unneeded data that clutters up my attempted visualization. So then, my question is:



How do I restrict the domain of StreamPlot to $mathcalR $?






plotting







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  • Welcome to Mathematica.se! Full minimalistic code to demonstrate the issue, please! Then it is much easier for us to help you out!
    – Johu
    36 mins ago











  • Closely related to DensityPlot with equal mesh and a certain boundary
    – Johu
    30 mins ago















up vote
2
down vote

favorite












First, I should say I am at best an advanced amateur at Mathematica, and that generally speaking my knowledge of programming (in any language) is more in computation than visualization.



There is a model I am working on for which I have recently shown there is a feasibility region: $$mathcalR = (x,y) in [0,infty)times[0, infty) : x+y leq L.$$ Of course this is a triangular subregion of the first quadrant. I wish to restrict the domain of the streamplots I am generating to $mathcalR$.



From looking at the documentation I have constructed the following code:



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L]


which works fine, but of course gives me a large amount of unneeded data that clutters up my attempted visualization. So then, my question is:



How do I restrict the domain of StreamPlot to $mathcalR $?






plotting







share|improve this question









New contributor




GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Welcome to Mathematica.se! Full minimalistic code to demonstrate the issue, please! Then it is much easier for us to help you out!
    – Johu
    36 mins ago











  • Closely related to DensityPlot with equal mesh and a certain boundary
    – Johu
    30 mins ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











First, I should say I am at best an advanced amateur at Mathematica, and that generally speaking my knowledge of programming (in any language) is more in computation than visualization.



There is a model I am working on for which I have recently shown there is a feasibility region: $$mathcalR = (x,y) in [0,infty)times[0, infty) : x+y leq L.$$ Of course this is a triangular subregion of the first quadrant. I wish to restrict the domain of the streamplots I am generating to $mathcalR$.



From looking at the documentation I have constructed the following code:



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L]


which works fine, but of course gives me a large amount of unneeded data that clutters up my attempted visualization. So then, my question is:



How do I restrict the domain of StreamPlot to $mathcalR $?






plotting







share|improve this question









New contributor




GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











First, I should say I am at best an advanced amateur at Mathematica, and that generally speaking my knowledge of programming (in any language) is more in computation than visualization.



There is a model I am working on for which I have recently shown there is a feasibility region: $$mathcalR = (x,y) in [0,infty)times[0, infty) : x+y leq L.$$ Of course this is a triangular subregion of the first quadrant. I wish to restrict the domain of the streamplots I am generating to $mathcalR$.



From looking at the documentation I have constructed the following code:



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L]


which works fine, but of course gives me a large amount of unneeded data that clutters up my attempted visualization. So then, my question is:



How do I restrict the domain of StreamPlot to $mathcalR $?






plotting




plotting






share|improve this question









New contributor




GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 28 mins ago









Johu

3,4131033




3,4131033






New contributor




GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 41 mins ago









GeauxMath

132




132




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GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






GeauxMath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • Welcome to Mathematica.se! Full minimalistic code to demonstrate the issue, please! Then it is much easier for us to help you out!
    – Johu
    36 mins ago











  • Closely related to DensityPlot with equal mesh and a certain boundary
    – Johu
    30 mins ago

















  • Welcome to Mathematica.se! Full minimalistic code to demonstrate the issue, please! Then it is much easier for us to help you out!
    – Johu
    36 mins ago











  • Closely related to DensityPlot with equal mesh and a certain boundary
    – Johu
    30 mins ago
















Welcome to Mathematica.se! Full minimalistic code to demonstrate the issue, please! Then it is much easier for us to help you out!
– Johu
36 mins ago





Welcome to Mathematica.se! Full minimalistic code to demonstrate the issue, please! Then it is much easier for us to help you out!
– Johu
36 mins ago













Closely related to DensityPlot with equal mesh and a certain boundary
– Johu
30 mins ago





Closely related to DensityPlot with equal mesh and a certain boundary
– Johu
30 mins ago











2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










Try



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L, RegionFunction -> Function[x, y, x+y <= L]]





share|improve this answer




















  • Thank you very much for your help
    – GeauxMath
    25 mins ago

















up vote
2
down vote













StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, -3, 3, y, -3, 3, 
 RegionFunction -> Function[x, y, z, 2 < x^2 + y^2 < 9]]


enter image description here



or



StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, y [Element]


StadiumShape[0, 0, 2, 3, 2]]



enter image description here






share|improve this answer






















  • Thank you very much for your help. This code will be very helpful if I ever need to plot a circular region.
    – GeauxMath
    24 mins ago










  • Just to demonstrate that the solution is not limted to circlar region, I updated the answer with a more compelx shape.
    – Johu
    15 mins ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










Try



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L, RegionFunction -> Function[x, y, x+y <= L]]





share|improve this answer




















  • Thank you very much for your help
    – GeauxMath
    25 mins ago














up vote
1
down vote



accepted










Try



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L, RegionFunction -> Function[x, y, x+y <= L]]





share|improve this answer




















  • Thank you very much for your help
    – GeauxMath
    25 mins ago












up vote
1
down vote



accepted







up vote
1
down vote



accepted






Try



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L, RegionFunction -> Function[x, y, x+y <= L]]





share|improve this answer












Try



StreamPlot[dx/dt, dy/dt, x, 0, L, y, 0, L, RegionFunction -> Function[x, y, x+y <= L]]






share|improve this answer












share|improve this answer



share|improve this answer










answered 34 mins ago









That Gravity Guy

723410




723410











  • Thank you very much for your help
    – GeauxMath
    25 mins ago
















  • Thank you very much for your help
    – GeauxMath
    25 mins ago















Thank you very much for your help
– GeauxMath
25 mins ago




Thank you very much for your help
– GeauxMath
25 mins ago










up vote
2
down vote













StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, -3, 3, y, -3, 3, 
 RegionFunction -> Function[x, y, z, 2 < x^2 + y^2 < 9]]


enter image description here



or



StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, y [Element]


StadiumShape[0, 0, 2, 3, 2]]



enter image description here






share|improve this answer






















  • Thank you very much for your help. This code will be very helpful if I ever need to plot a circular region.
    – GeauxMath
    24 mins ago










  • Just to demonstrate that the solution is not limted to circlar region, I updated the answer with a more compelx shape.
    – Johu
    15 mins ago















up vote
2
down vote













StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, -3, 3, y, -3, 3, 
 RegionFunction -> Function[x, y, z, 2 < x^2 + y^2 < 9]]


enter image description here



or



StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, y [Element]


StadiumShape[0, 0, 2, 3, 2]]



enter image description here






share|improve this answer






















  • Thank you very much for your help. This code will be very helpful if I ever need to plot a circular region.
    – GeauxMath
    24 mins ago










  • Just to demonstrate that the solution is not limted to circlar region, I updated the answer with a more compelx shape.
    – Johu
    15 mins ago













up vote
2
down vote










up vote
2
down vote









StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, -3, 3, y, -3, 3, 
 RegionFunction -> Function[x, y, z, 2 < x^2 + y^2 < 9]]


enter image description here



or



StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, y [Element]


StadiumShape[0, 0, 2, 3, 2]]



enter image description here






share|improve this answer














StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, -3, 3, y, -3, 3, 
 RegionFunction -> Function[x, y, z, 2 < x^2 + y^2 < 9]]


enter image description here



or



StreamPlot[-1 - x^2 + y, 1 + x - y^2, x, y [Element]


StadiumShape[0, 0, 2, 3, 2]]



enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 16 mins ago

























answered 34 mins ago









Johu

3,4131033




3,4131033











  • Thank you very much for your help. This code will be very helpful if I ever need to plot a circular region.
    – GeauxMath
    24 mins ago










  • Just to demonstrate that the solution is not limted to circlar region, I updated the answer with a more compelx shape.
    – Johu
    15 mins ago

















  • Thank you very much for your help. This code will be very helpful if I ever need to plot a circular region.
    – GeauxMath
    24 mins ago










  • Just to demonstrate that the solution is not limted to circlar region, I updated the answer with a more compelx shape.
    – Johu
    15 mins ago
















Thank you very much for your help. This code will be very helpful if I ever need to plot a circular region.
– GeauxMath
24 mins ago




Thank you very much for your help. This code will be very helpful if I ever need to plot a circular region.
– GeauxMath
24 mins ago












Just to demonstrate that the solution is not limted to circlar region, I updated the answer with a more compelx shape.
– Johu
15 mins ago





Just to demonstrate that the solution is not limted to circlar region, I updated the answer with a more compelx shape.
– Johu
15 mins ago











GeauxMath is a new contributor. Be nice, and check out our Code of Conduct.









 

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