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Insert a link in lightning datatable Column Value
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I am trying to insert a link in a result column of lightning:datatable
Below is the code snippet :
Datatable Code:
<lightning:datatable data="! v.contactList "
columns="! v.mycolumns "
keyField="id"
onrowselection = "!c.checkboxFetch"
hideCheckboxColumn="false"
onrowaction="!c.checkboxFetch"
class="tableCss"
tabindex="1"/>
Controller Code:
label: 'Customer Name', fieldName: 'CustomerName__c', type: 'url',
sortable:"false",
typeAttributes:
label: 'Customer Name',
fieldName: 'CustomerName__c',
title: 'View',
disabled: false,
value: 'view',
iconPosition: 'left',
url: 'www.google.com',
, ,
However, in the result I am not able to link the column with the mentioned url and when clicking on the hyperlink it is redirecting to a localhost url like 172.9.0.1 (something like this)
Any idea on how to redirect to the url : www.google.com ? Also, the
customer result from the variable iteration
component.set('v.mycolumns'is not displaying the result.
Rather it displaying the static value : Customer Name
lightning lightning-experience slds datatable lightning-datatable
asked 4 hours ago
Jayati Jaiswal
238
add a comment |Â
up vote
1
down vote
favorite
I am trying to insert a link in a result column of lightning:datatable
Below is the code snippet :
Datatable Code:
<lightning:datatable data="! v.contactList "
columns="! v.mycolumns "
keyField="id"
onrowselection = "!c.checkboxFetch"
hideCheckboxColumn="false"
onrowaction="!c.checkboxFetch"
class="tableCss"
tabindex="1"/>
Controller Code:
label: 'Customer Name', fieldName: 'CustomerName__c', type: 'url',
sortable:"false",
typeAttributes:
label: 'Customer Name',
fieldName: 'CustomerName__c',
title: 'View',
disabled: false,
value: 'view',
iconPosition: 'left',
url: 'www.google.com',
, ,
However, in the result I am not able to link the column with the mentioned url and when clicking on the hyperlink it is redirecting to a localhost url like 172.9.0.1 (something like this)
Any idea on how to redirect to the url : www.google.com ? Also, the
customer result from the variable iteration
component.set('v.mycolumns'is not displaying the result.
Rather it displaying the static value : Customer Name
lightning lightning-experience slds datatable lightning-datatable
asked 4 hours ago
Jayati Jaiswal
238
You have to set the columntypeasurland in in data, you have to separately define the link you want the users to redirect to. Have a look at this example provided in the documentation, developer.salesforce.com/docs/component-library/bundle/…
– Ranga
3 hours ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am trying to insert a link in a result column of lightning:datatable
Below is the code snippet :
Datatable Code:
<lightning:datatable data="! v.contactList "
columns="! v.mycolumns "
keyField="id"
onrowselection = "!c.checkboxFetch"
hideCheckboxColumn="false"
onrowaction="!c.checkboxFetch"
class="tableCss"
tabindex="1"/>
Controller Code:
label: 'Customer Name', fieldName: 'CustomerName__c', type: 'url',
sortable:"false",
typeAttributes:
label: 'Customer Name',
fieldName: 'CustomerName__c',
title: 'View',
disabled: false,
value: 'view',
iconPosition: 'left',
url: 'www.google.com',
, ,
However, in the result I am not able to link the column with the mentioned url and when clicking on the hyperlink it is redirecting to a localhost url like 172.9.0.1 (something like this)
Any idea on how to redirect to the url : www.google.com ? Also, the
customer result from the variable iteration
component.set('v.mycolumns'is not displaying the result.
Rather it displaying the static value : Customer Name
lightning lightning-experience slds datatable lightning-datatable
asked 4 hours ago
Jayati Jaiswal
238
I am trying to insert a link in a result column of lightning:datatable
Below is the code snippet :
Datatable Code:
<lightning:datatable data="! v.contactList "
columns="! v.mycolumns "
keyField="id"
onrowselection = "!c.checkboxFetch"
hideCheckboxColumn="false"
onrowaction="!c.checkboxFetch"
class="tableCss"
tabindex="1"/>
Controller Code:
label: 'Customer Name', fieldName: 'CustomerName__c', type: 'url',
sortable:"false",
typeAttributes:
label: 'Customer Name',
fieldName: 'CustomerName__c',
title: 'View',
disabled: false,
value: 'view',
iconPosition: 'left',
url: 'www.google.com',
, ,
However, in the result I am not able to link the column with the mentioned url and when clicking on the hyperlink it is redirecting to a localhost url like 172.9.0.1 (something like this)
Any idea on how to redirect to the url : www.google.com ? Also, the
customer result from the variable iteration
component.set('v.mycolumns'is not displaying the result.
Rather it displaying the static value : Customer Name
lightning lightning-experience slds datatable lightning-datatable
lightning lightning-experience slds datatable lightning-datatable
asked 4 hours ago
Jayati Jaiswal
238
asked 4 hours ago
Jayati Jaiswal
238
edited 3 hours ago
asked 4 hours ago
Jayati Jaiswal
238
asked 4 hours ago
Jayati Jaiswal
238
asked 4 hours ago
Jayati Jaiswal
238
238
You have to set the columntypeasurland in in data, you have to separately define the link you want the users to redirect to. Have a look at this example provided in the documentation, developer.salesforce.com/docs/component-library/bundle/…
– Ranga
3 hours ago
add a comment |Â
You have to set the columntypeasurland in in data, you have to separately define the link you want the users to redirect to. Have a look at this example provided in the documentation, developer.salesforce.com/docs/component-library/bundle/…
– Ranga
3 hours ago
You have to set the column
type as url and in in data, you have to separately define the link you want the users to redirect to. Have a look at this example provided in the documentation, developer.salesforce.com/docs/component-library/bundle/…– Ranga
3 hours ago
You have to set the column
type as url and in in data, you have to separately define the link you want the users to redirect to. Have a look at this example provided in the documentation, developer.salesforce.com/docs/component-library/bundle/…– Ranga
3 hours ago
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
3
down vote
Your Type Attributes, and likely the underlying data, aren't set up properly for a url type entry.
Your url item should correspond to the column in your data that contains a URL value (not the link's title or the column title). You can use the typeAttributes map to supply three additional parameters:
- label
- target
- tooltip
Your columns entry should look something like this:
label: 'Customer Name',
fieldName: 'CustomerName__c', // This field should have the actual URL in it.
type: 'url',
sortable: "false",
typeAttributes:
label:
fieldName: 'UserReadableName__c'
// whatever field contains the actual label of the link
,
target: '_blank', // or as desired
tooltip: 'Open the customer page' // or as desired
Then, your CustomerName__c column in your data must contain an actual URL (not a Salesforce Id or anything else). If it doesn't, you can add a synthetic column to your data, such as
contactsList.forEach(function(contact)
contact.SearchURL = 'https://google.com/search?q=' + contact.CustomerName__c;
answered 1 hour ago
David Reed
20k21540
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
Your Type Attributes, and likely the underlying data, aren't set up properly for a url type entry.
Your url item should correspond to the column in your data that contains a URL value (not the link's title or the column title). You can use the typeAttributes map to supply three additional parameters:
- label
- target
- tooltip
Your columns entry should look something like this:
label: 'Customer Name',
fieldName: 'CustomerName__c', // This field should have the actual URL in it.
type: 'url',
sortable: "false",
typeAttributes:
label:
fieldName: 'UserReadableName__c'
// whatever field contains the actual label of the link
,
target: '_blank', // or as desired
tooltip: 'Open the customer page' // or as desired
Then, your CustomerName__c column in your data must contain an actual URL (not a Salesforce Id or anything else). If it doesn't, you can add a synthetic column to your data, such as
contactsList.forEach(function(contact)
contact.SearchURL = 'https://google.com/search?q=' + contact.CustomerName__c;
answered 1 hour ago
David Reed
20k21540
add a comment |Â
up vote
3
down vote
Your Type Attributes, and likely the underlying data, aren't set up properly for a url type entry.
Your url item should correspond to the column in your data that contains a URL value (not the link's title or the column title). You can use the typeAttributes map to supply three additional parameters:
- label
- target
- tooltip
Your columns entry should look something like this:
label: 'Customer Name',
fieldName: 'CustomerName__c', // This field should have the actual URL in it.
type: 'url',
sortable: "false",
typeAttributes:
label:
fieldName: 'UserReadableName__c'
// whatever field contains the actual label of the link
,
target: '_blank', // or as desired
tooltip: 'Open the customer page' // or as desired
Then, your CustomerName__c column in your data must contain an actual URL (not a Salesforce Id or anything else). If it doesn't, you can add a synthetic column to your data, such as
contactsList.forEach(function(contact)
contact.SearchURL = 'https://google.com/search?q=' + contact.CustomerName__c;
answered 1 hour ago
David Reed
20k21540
add a comment |Â
up vote
3
down vote
up vote
3
down vote
Your Type Attributes, and likely the underlying data, aren't set up properly for a url type entry.
Your url item should correspond to the column in your data that contains a URL value (not the link's title or the column title). You can use the typeAttributes map to supply three additional parameters:
- label
- target
- tooltip
Your columns entry should look something like this:
label: 'Customer Name',
fieldName: 'CustomerName__c', // This field should have the actual URL in it.
type: 'url',
sortable: "false",
typeAttributes:
label:
fieldName: 'UserReadableName__c'
// whatever field contains the actual label of the link
,
target: '_blank', // or as desired
tooltip: 'Open the customer page' // or as desired
Then, your CustomerName__c column in your data must contain an actual URL (not a Salesforce Id or anything else). If it doesn't, you can add a synthetic column to your data, such as
contactsList.forEach(function(contact)
contact.SearchURL = 'https://google.com/search?q=' + contact.CustomerName__c;
answered 1 hour ago
David Reed
20k21540
Your Type Attributes, and likely the underlying data, aren't set up properly for a url type entry.
Your url item should correspond to the column in your data that contains a URL value (not the link's title or the column title). You can use the typeAttributes map to supply three additional parameters:
- label
- target
- tooltip
Your columns entry should look something like this:
label: 'Customer Name',
fieldName: 'CustomerName__c', // This field should have the actual URL in it.
type: 'url',
sortable: "false",
typeAttributes:
label:
fieldName: 'UserReadableName__c'
// whatever field contains the actual label of the link
,
target: '_blank', // or as desired
tooltip: 'Open the customer page' // or as desired
Then, your CustomerName__c column in your data must contain an actual URL (not a Salesforce Id or anything else). If it doesn't, you can add a synthetic column to your data, such as
contactsList.forEach(function(contact)
contact.SearchURL = 'https://google.com/search?q=' + contact.CustomerName__c;
answered 1 hour ago
David Reed
20k21540
answered 1 hour ago
David Reed
20k21540
answered 1 hour ago
David Reed
20k21540
answered 1 hour ago
David Reed
20k21540
20k21540
add a comment |Â
add a comment |Â
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You have to set the column
typeasurland in in data, you have to separately define the link you want the users to redirect to. Have a look at this example provided in the documentation, developer.salesforce.com/docs/component-library/bundle/…– Ranga
3 hours ago