how to use the following output of a command directly in another command?

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3
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How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2]

But, I feel that typing an output by hand again is not really an optimal method.

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

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up vote
3
down vote

favorite

How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2]

But, I feel that typing an output by hand again is not really an optimal method.

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

add a commentÂ |Â

up vote
3
down vote

favorite

How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2]

But, I feel that typing an output by hand again is not really an optimal method.

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2]

But, I feel that typing an output by hand again is not really an optimal method.

list-manipulation row do

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

edited 9 mins ago

kglr

160k8184384

edited 9 mins ago

kglr

160k8184384

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

asked 20 mins ago

veo

1234

asked 20 mins ago

veo

1234

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

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2 Answers
2

active

oldest

votes

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

add a commentÂ |Â

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

add a commentÂ |Â

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

add a commentÂ |Â

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

add a commentÂ |Â

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

answered 12 mins ago

That Gravity Guy

40125

answered 12 mins ago

That Gravity Guy

40125

add a commentÂ |Â

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

add a commentÂ |Â

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

add a commentÂ |Â

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

answered 12 mins ago

kglr

160k8184384

answered 12 mins ago

kglr

160k8184384

add a commentÂ |Â

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