how to use the following output of a command directly in another command?

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How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2] 

But, I feel that typing an output by hand again is not really an optimal method.

list-manipulation row do

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edited 9 mins ago

kglr

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asked 20 mins ago

veo

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up vote
3
down vote

favorite

How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2] 

But, I feel that typing an output by hand again is not really an optimal method.

list-manipulation row do

share|improve this question

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

up vote
3
down vote

favorite

up vote
3
down vote

favorite

How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2] 

But, I feel that typing an output by hand again is not really an optimal method.

list-manipulation row do

share|improve this question

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

How to use Row[Table[B[i],0,i,i,0,2],","] directly in Do command? I mean that the following command

Row[Table[B[i],0,i,i,0,2],","]

gives

B[0], 0, 0,B[1], 0, 1,B[2],0,2

But, the following command returns the error

"Do::nliter: Non-list iterator Row[Table[B[i], 0, i, i, 0, 2], ,] at position 2 does not evaluate to a real numeric value."

Do[Print[B[0]+B[1]+B[2]],Row[Table[B[i],0,i,i,0,2],","]]

Of course, one can type instead by hand the following:

Do[Print[B[0]+B[1]+B[2]],B[0],0,0,B[1],0,1,B[2],0,2] 

But, I feel that typing an output by hand again is not really an optimal method.

list-manipulation row do

list-manipulation row do

share|improve this question

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 9 mins ago

kglr

160k8184384

asked 20 mins ago

veo

1234

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

share|improve this question

edited 9 mins ago

kglr

160k8184384

edited 9 mins ago

kglr

160k8184384

edited 9 mins ago

kglr

160k8184384

160k8184384

asked 20 mins ago

veo

1234

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 20 mins ago

veo

1234

asked 20 mins ago

veo

1234

1234

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

New contributor

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

veo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

add a comment | 

2 Answers
2

active

oldest

votes

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

share|improve this answer

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

add a comment | 

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

or

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

share|improve this answer

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

share|improve this answer

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

add a comment | 

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

share|improve this answer

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

add a comment | 

up vote
3
down vote

up vote
3
down vote

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

share|improve this answer

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

What you actually want is to create a Sequence from the Table to be used as your iterators.

You can do this with

Do[Print[B[0] + B[1] + B[2]], Sequence @@ Table[B[i], 0, i, i, 0, 2] // 
Evaluate]

(*0
 1
 2
 1
 2
 3*)

Or, so you don't have to force evaluation,

Do[Print[B[0] + B[1] + B[2]], ##] & @@ Table[B[i], 0, i, i, 0, 2]

share|improve this answer

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

share|improve this answer

share|improve this answer

edited 6 mins ago

edited 6 mins ago

edited 6 mins ago

answered 12 mins ago

That Gravity Guy

40125

answered 12 mins ago

That Gravity Guy

40125

answered 12 mins ago

That Gravity Guy

40125

40125

add a comment | 

add a comment | 

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

or

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

share|improve this answer

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

add a comment | 

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

or

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

share|improve this answer

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

add a comment | 

up vote
1
down vote

up vote
1
down vote

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

or

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

share|improve this answer

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

Do[Print[B[0] + B[1] + B[2]], 
 Evaluate[Sequence @@ First@ Row[Table[B[i], 0, i, i, 0, 2], ","]]]

or

row = Row[Table[B[i], 0, i, i, 0, 2], ","];
Do[Print[B[0] + B[1] + B[2]], Evaluate[Sequence @@ row[[1]]]]

share|improve this answer

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

share|improve this answer

share|improve this answer

edited 5 mins ago

edited 5 mins ago

edited 5 mins ago

answered 12 mins ago

kglr

160k8184384

answered 12 mins ago

kglr

160k8184384

answered 12 mins ago

kglr

160k8184384

160k8184384

add a comment | 

add a comment | 

veo is a new contributor. Be nice, and check out our Code of Conduct.

 

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