Copy files from one folder to another folder within specific date range

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up vote
2
down vote

favorite

I am already using below command to copy files from a specific date.

Previously I used this command and it worked well but now it was showing an error:

-bash: /bin/cp: Argument list too long

Commends used:

cd /share/new/
cp `find . -type f -newermt '16 july 2018'` /share/test

I need to copy all files in the folder "new" from July 20th to today date. How can I achieve this?

command-line bash copy

share|improve this question

edited 18 mins ago

Videonauth

22.4k116897

asked 21 mins ago

Venki

204

add a comment | 

up vote
2
down vote

favorite

I am already using below command to copy files from a specific date.

Previously I used this command and it worked well but now it was showing an error:

-bash: /bin/cp: Argument list too long

Commends used:

cd /share/new/
cp `find . -type f -newermt '16 july 2018'` /share/test

I need to copy all files in the folder "new" from July 20th to today date. How can I achieve this?

command-line bash copy

share|improve this question

edited 18 mins ago

Videonauth

22.4k116897

asked 21 mins ago

Venki

204

add a comment | 

up vote
2
down vote

favorite

up vote
2
down vote

favorite

I am already using below command to copy files from a specific date.

Previously I used this command and it worked well but now it was showing an error:

-bash: /bin/cp: Argument list too long

Commends used:

cd /share/new/
cp `find . -type f -newermt '16 july 2018'` /share/test

I need to copy all files in the folder "new" from July 20th to today date. How can I achieve this?

command-line bash copy

share|improve this question

edited 18 mins ago

Videonauth

22.4k116897

asked 21 mins ago

Venki

204

I am already using below command to copy files from a specific date.

Previously I used this command and it worked well but now it was showing an error:

-bash: /bin/cp: Argument list too long

Commends used:

cd /share/new/
cp `find . -type f -newermt '16 july 2018'` /share/test

I need to copy all files in the folder "new" from July 20th to today date. How can I achieve this?

command-line bash copy

command-line bash copy

share|improve this question

edited 18 mins ago

Videonauth

22.4k116897

asked 21 mins ago

Venki

204

share|improve this question

edited 18 mins ago

Videonauth

22.4k116897

asked 21 mins ago

Venki

204

share|improve this question

share|improve this question

edited 18 mins ago

Videonauth

22.4k116897

edited 18 mins ago

Videonauth

22.4k116897

edited 18 mins ago

Videonauth

22.4k116897

22.4k116897

asked 21 mins ago

Venki

204

asked 21 mins ago

Venki

204

asked 21 mins ago

Venki

204

204

add a comment | 

add a comment | 

2 Answers
2

active

oldest

votes

up vote
3
down vote



accepted

Don't use cp directly with the output of find.

It might passes way many too files in a single step (and that's why you get the error Argument list too long).

Use the -exec parameter of find, which execute the given command passing a every matched file to cp, one at a time:

cd /share/new/
find . -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 16 mins ago

Mr Shunz

1,9361319

• 
  
  
  

  
  

  
  
  
  
  
  

  
  find: missing argument to `-exec'
  – Venki
  12 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Venki if you type find . -type f -newermt '16 july 2018' does any results appear? It might be that no files match your query. Pay attention to the last ; , too.
  – Mr Shunz
  7 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  its working :: "" find . -type f -newermt '16 july 2018' -exec cp /share/test/ ; "" missing "/" after test because test is a directory
  – Venki
  1 min ago
  
  

  
  
  
  

add a comment | 

up vote
3
down vote

use find -exec:

find /share/new/ -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 17 mins ago

RoVo

5,6341237

• 
  
  
  

  
  

  
  
  
  
  
  

  
  getting same error for your command also find: missing argument to `-exec'
  – Venki
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I think your missing the ; at the end.
  – RoVo
  6 mins ago
  
  

  
  
  
  

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
3
down vote



accepted

Don't use cp directly with the output of find.

It might passes way many too files in a single step (and that's why you get the error Argument list too long).

Use the -exec parameter of find, which execute the given command passing a every matched file to cp, one at a time:

cd /share/new/
find . -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 16 mins ago

Mr Shunz

1,9361319

• 
  
  
  

  
  

  
  
  
  
  
  

  
  find: missing argument to `-exec'
  – Venki
  12 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Venki if you type find . -type f -newermt '16 july 2018' does any results appear? It might be that no files match your query. Pay attention to the last ; , too.
  – Mr Shunz
  7 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  its working :: "" find . -type f -newermt '16 july 2018' -exec cp /share/test/ ; "" missing "/" after test because test is a directory
  – Venki
  1 min ago
  
  

  
  
  
  

add a comment | 

up vote
3
down vote



accepted

Don't use cp directly with the output of find.

It might passes way many too files in a single step (and that's why you get the error Argument list too long).

Use the -exec parameter of find, which execute the given command passing a every matched file to cp, one at a time:

cd /share/new/
find . -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 16 mins ago

Mr Shunz

1,9361319

• 
  
  
  

  
  

  
  
  
  
  
  

  
  find: missing argument to `-exec'
  – Venki
  12 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Venki if you type find . -type f -newermt '16 july 2018' does any results appear? It might be that no files match your query. Pay attention to the last ; , too.
  – Mr Shunz
  7 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  its working :: "" find . -type f -newermt '16 july 2018' -exec cp /share/test/ ; "" missing "/" after test because test is a directory
  – Venki
  1 min ago
  
  

  
  
  
  

add a comment | 

up vote
3
down vote



accepted

up vote
3
down vote



accepted

Don't use cp directly with the output of find.

It might passes way many too files in a single step (and that's why you get the error Argument list too long).

Use the -exec parameter of find, which execute the given command passing a every matched file to cp, one at a time:

cd /share/new/
find . -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 16 mins ago

Mr Shunz

1,9361319

Don't use cp directly with the output of find.

It might passes way many too files in a single step (and that's why you get the error Argument list too long).

Use the -exec parameter of find, which execute the given command passing a every matched file to cp, one at a time:

cd /share/new/
find . -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 16 mins ago

Mr Shunz

1,9361319

share|improve this answer

share|improve this answer

answered 16 mins ago

Mr Shunz

1,9361319

answered 16 mins ago

Mr Shunz

1,9361319

answered 16 mins ago

Mr Shunz

1,9361319

1,9361319

• 
  
  
  

  
  

  
  
  
  
  
  

  
  find: missing argument to `-exec'
  – Venki
  12 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Venki if you type find . -type f -newermt '16 july 2018' does any results appear? It might be that no files match your query. Pay attention to the last ; , too.
  – Mr Shunz
  7 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  its working :: "" find . -type f -newermt '16 july 2018' -exec cp /share/test/ ; "" missing "/" after test because test is a directory
  – Venki
  1 min ago
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  find: missing argument to `-exec'
  – Venki
  12 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Venki if you type find . -type f -newermt '16 july 2018' does any results appear? It might be that no files match your query. Pay attention to the last ; , too.
  – Mr Shunz
  7 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  its working :: "" find . -type f -newermt '16 july 2018' -exec cp /share/test/ ; "" missing "/" after test because test is a directory
  – Venki
  1 min ago
  
  

  
  
  
  

find: missing argument to `-exec'
– Venki
12 mins ago

find: missing argument to `-exec'
– Venki
12 mins ago

@Venki if you type find . -type f -newermt '16 july 2018' does any results appear? It might be that no files match your query. Pay attention to the last ; , too.
– Mr Shunz
7 mins ago

@Venki if you type find . -type f -newermt '16 july 2018' does any results appear? It might be that no files match your query. Pay attention to the last ; , too.
– Mr Shunz
7 mins ago

its working :: "" find . -type f -newermt '16 july 2018' -exec cp /share/test/ ; "" missing "/" after test because test is a directory
– Venki
1 min ago

its working :: "" find . -type f -newermt '16 july 2018' -exec cp /share/test/ ; "" missing "/" after test because test is a directory
– Venki
1 min ago

add a comment | 

up vote
3
down vote

use find -exec:

find /share/new/ -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 17 mins ago

RoVo

5,6341237

• 
  
  
  

  
  

  
  
  
  
  
  

  
  getting same error for your command also find: missing argument to `-exec'
  – Venki
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I think your missing the ; at the end.
  – RoVo
  6 mins ago
  
  

  
  
  
  

add a comment | 

up vote
3
down vote

use find -exec:

find /share/new/ -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 17 mins ago

RoVo

5,6341237

• 
  
  
  

  
  

  
  
  
  
  
  

  
  getting same error for your command also find: missing argument to `-exec'
  – Venki
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I think your missing the ; at the end.
  – RoVo
  6 mins ago
  
  

  
  
  
  

add a comment | 

up vote
3
down vote

up vote
3
down vote

use find -exec:

find /share/new/ -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 17 mins ago

RoVo

5,6341237

use find -exec:

find /share/new/ -type f -newermt '16 july 2018' -exec cp /share/test ;

share|improve this answer

answered 17 mins ago

RoVo

5,6341237

share|improve this answer

share|improve this answer

answered 17 mins ago

RoVo

5,6341237

answered 17 mins ago

RoVo

5,6341237

answered 17 mins ago

RoVo

5,6341237

5,6341237

• 
  
  
  

  
  

  
  
  
  
  
  

  
  getting same error for your command also find: missing argument to `-exec'
  – Venki
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I think your missing the ; at the end.
  – RoVo
  6 mins ago
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  getting same error for your command also find: missing argument to `-exec'
  – Venki
  9 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I think your missing the ; at the end.
  – RoVo
  6 mins ago
  
  

  
  
  
  

getting same error for your command also find: missing argument to `-exec'
– Venki
9 mins ago

getting same error for your command also find: missing argument to `-exec'
– Venki
9 mins ago

I think your missing the ; at the end.
– RoVo
6 mins ago

I think your missing the ; at the end.
– RoVo
6 mins ago

add a comment | 

 

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